determine if a sentence is an argument?​

Answers

Answer 1

Answer:

The tone really matters and if there are any exclamation marks also.

Explanation:


Related Questions

If the intensity of radiation from an x-ray tube at 2 feet is 100 mR/min, the intensity at a distance of 5 feet will
be?

Answers

Answer:

100 mR

Explanation:

What is the kinetic energy of a 1375 kg car that travels at 8.5 m/s

Answers

Answer:

49671.875

Explanation:

KE = [tex]\frac{1}{2}m[/tex][tex]v^{2}[/tex]

KE = 0.5(1375)(8.5)

= 49671.875 J

please answer this question​

Answers

Answer:

The circuits that were made previously were large and bulky, consisting of circuit components like resistor, capacitor, inductor, transistor, diodes, etc., which were connected with copper wires.

Explanation:

I am in confusion with mono electronic circuit and I am not want to made u confused person.

I am really sorry brother.

:-befrank

Calculate the power developed by a 68.0 kg athlete who, in 20.0 seconds. runs up stairs that have a vertical height of 8.00 m

Answers

Mass=m=68kgHeight=h=8mg=10m/s^2(Acceleration due to gravity)

Potential energy:-

mgh68(8)(10)680(8)5440J

Now

time=t=20s

So

Power:-

PE/t5440/20272W

1- Show that the equation d=vt2
dimensionally correct or not?

Answers

- Show that the equation d=vt2 dimensionally correct or not? ... nalsn7 is waiting for your help. Add your answer and earn points.

You ride your bike north for 100 m at a constant speed of 5 m/Your acceleration is…

Answers

Answer:

our acceleration is 0 because there is a constant speed..

a = final speed - initial speed / time

final speed = initial speed ( since speed is constant)

therefore acceleration is 0

15C of charge flow through the filament of a light bulb in 22 seconds. What is the strength of the current in the filament?

Answers

Answer:

Current(I)= charge(q)/time

I=15/22

I=0.680.68A

Explanation:

Current is flow of charge per unit time. Always make sure the time is in seconds. istthe

Two particles each with a charge of 1μC are separated a distance of 0.4 m. A test charge is placed just above them but directly between them. (b) What is the direction of the resultant electric field on the test charge?

Answers

Answer:

Forces on the test (test is positive) charge

Σ Fx = 0       net result of x-compoment charges is zero

Σ Fy = 2 F sin θ      where F is the force due to the distance of the test charge from one of the charges and sin θ  is the component of that force that is perpendicular to the line separating the charges

The direction of the force is perpendicular to the line separating the two given charges

Give Reason during change of state,the temperature remains constant

Answers

Answer:

the substance has lost or gained an ion

Explanation:

I say substance be cause I'm referring to the item are the same are similar to the substances that make up make matter like the ones on the periodic table!

Hello, please help!
Physics teacher asked us to answer and give explanation to why:
Can light bend around corners?
THNX SO MUCH

Answers

Answer:

Yes, light can bend around corners.

Explanation: In fact, light always bends around corners to some extent. This is a basic property of light and all other waves. The amount of light that bends around a corner depends on the exact situation.

Thanks for asking the question!!

How does the scintillation detector work?

Answers

Answer:

In scintillation detectors the material of the detector is excited to luminescence (emission of visible or near-visible light photons) by the absorbed photons or particles. The number of photons produced is proportional to the energy of the absorbed primary photon. The light pulses are collected by a photo- cathode.

Explanation:

Hope this helps :-)

Enjoy your day or night!

Have fun with your studies and assignments

ps. please don't give full credit to me I used references from other sites

<3 simplysun

What is the effect of the Least Count on the precision/sensitivity of Vernier Callipers?​

Answers

Answer:

Least count of vernier caliper=.1/50=.002 CM=.02 MM Least count and precision The least count is directly linked with precision. The smaller is the least count number, the more precise the instrument is.

Explanation:

Is a vernier scale accurate or precise? Every instrument has its accuracy defined as the least count of the instrument.As the least count of vernier callipers is 0.01mm,hence it is not accurate beyond the size measurement of 0.01mm.For which it may be called for vernier scale has presize measurement up to 0.01mm.Ans.. What is a vernier caliper?

what’s is the vertical colum of the elements in the periodic table called

Answers

it is called groups or families.

Answer:

groups or families

Explanation:

The vertical column of the periodic table are called groups or famileis because of their similar chemical behavior.

Jaden rides his motorcycle at an average speed of 21 meters/second for 520 seconds , how far did he ride?

Answers

Answer:

10,920 meters

Explanation:

distance = speed × time

which is, d = 21 × 520

Answer:

10920

Explanation:

distance traveled= 21 (speed) ×520 (time)

=10920

A total charge of Q coulomb is uniformly distributed along a rod 40cm in length.find find the electric field intensity 20cm away from the rod along its perpendicular bisector?

Answers

For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length,  the electric field intensity 20cm away from the rod is mathematically given as

E1=1.598*10^11v/m

What is the electric field intensity 20cm away from the rod along its perpendicular bisector?

Generally, the equation for the  initial electric field intensity   is mathematically given as

[tex]dEp=\int{kd/r}cosd\theta[/tex]

Therefore

[tex]e1=kd/r{sin\theta2+sinR1}[/tex]

Hence

[tex]E1=(9*10^9/20*10^{-2})({sin45+sin45})*B/40*10^-2[/tex]

E1=B*9*10^{13})/(10*110)*[tex]\sqrt{2}[/tex]

E1=1.598*10^11v/m

In conclusion, the electric field intensity

E1=1.598*10^11v/m

Read more about Electric field

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Which property of matter is conserved in chemical reactions and shown by balanced equations?
O mass
O volume

O density
O shape

Answers

Answer:

Mass.

Explanation:

I took the quiz and got the answer right

Your answer would be density

The force of a hammer drives a nail into wood. This is an example of. A. An unbalanced force. B. Gravitational force. C. Friction. D. Balanced forces​

Answers

B gravitational force sorry if I’m wrong!

Answer:

What i got was A. An unbalanced force.

Hope This Helps

PLEASE HELP, WILL MARK BRAINLIEST!!!!!!!
A mass m is dropped from height h above the top of a spring of constant k mounted vertically on the floor.
Find the spring's maximum compression.
Express your answer in terms of some or all of the variables: m , h , k , and gravitational constant g .

m*g/k (1 + √(1 + 2k*h/m*g))
Is this answer correct and why? Or is it something else?

Answers

I think your answer may be wrong.

The mass's potential energy at the start is mgh; this gets converted to kinetic energy as it falls (assuming no air resistance), so that by conservation of energy,

mgh = 1/2 mv²   ⇒   v = √(2gh)

where v is the velocity of the mass when it first comes into contact witht he spring.

As the spring is compressed, it performs work on the mass as it slows to a rest at maximum compression. If x is the maximum compression, then the spring does -1/2 kx² of work. (negative since it opposes the downward fall)

By the work-energy theorem (total work is equal to change in kinetic energy),

-1/2 kx² = 0 - 1/2 mv²

Plug in v and solve for x :

kx² = m (√(2gh))²

x² = 2mgh/k

x = √(2mgh/k)

Find the Product or expression of:
(6x+4)2​

Answers

Answer:

20 or 12

Explanation:

if it is 20 u will have to multiple 6 by 4 and the answer u will multiple it by2 and when it is 12 u will have to add 6 +4 and the answer u will add it to 2

Which of the following objects would have the greatest: A. momentum if they were all moving with the same velocity? B. Inertia?

A compact car B school bus
C Pick-up truck D road bicycle

Answers

B. because a school bus has the most mass and that Carries over to momentum where it has the most energy over all the other answers

A potter's wheel is spinning with an initial angular velocity of 11 rad/s . It rotates through an angle of 80.0 rad in the process of coming to rest.
What was the angular acceleration of the wheel?
How long does it take for it to come to rest?

Answers

The angular acceleration of the wheel approximately -0.76 rad/s² or proportionally as deceleration approximately 0.76 rad/s.It need approximately 14.474 s to come to rest.

Introduction

Hi ! I will help you to discuss about Proportionally Changes in Circular Motion. The analogy of proportionally changes in circular motion is same as the analogy of proportionally changes in direct motion. Here you will hear again the terms acceleration and change in speed, only expressed in the form of a certain angle coverage. Before that, in circular motion, it is necessary to know the following conditions:

1 rotation = 2π rad1 rps = 2π rad/s1 rpm = [tex] \sf{\frac{1}{60} \: rps}[/tex] = [tex] \sf{\frac{1}{30}\pi \: rad/s}[/tex]

Formula Used

The following equations apply to proportionally changes circular motion:

Relationship between Angular Acceleration and Change of Angular Velocity

[tex] \boxed{\sf{\bold{\omega_t = \omega_0 + \alpha \times t}}}[/tex]

With the following conditions:

[tex]\sf{\omega_t}[/tex] = final angular velocity  (rad/s)[tex]\sf{\omega_0}[/tex] =  initial angular velocity (rad/s)[tex]\sf{\alpha}[/tex] = angular acceleration (rad/s²)t = interval of the time (s)Relationship between Angular Acceleration and Change of [tex]\sf{\theta}[/tex] (Angle of Rotation)

[tex] \boxed{\sf{\bold{\theta = \omega_0 \times t + \frac{1}{2} \times \alpha \times t^2}}}[/tex]

Or

[tex] \boxed{\sf{\bold{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta}}}[/tex]

With the following condition :

[tex]\sf{\theta}[/tex] = change of the sudut (rad)[tex]\sf{\alpha}[/tex] = angular acceleration (rad/s²)t = interval of the time (s)[tex]\sf{\omega_t}[/tex] = final angular velocity  (rad/s)[tex]\sf{\omega_0}[/tex] =  initial angular velocity (rad/s)

Problem Solving

We know that :

[tex]\sf{\omega_t}[/tex] = final angular velocity  = 0 rad/s >> see in the sentence "in the process of coming to rest."[tex]\sf{\omega_0}[/tex] =  initial angular velocity = 11 rad/s[tex]\sf{\theta}[/tex] = change of the sudut = 80.0 rad

What was asked :

[tex]\sf{\alpha}[/tex] = angular acceleration = ... rad/s²t = interval of the time = ... s

Step by step :

[tex]\sf{\alpha}[/tex] = ... rad/s²

[tex] \sf{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta} [/tex]

[tex] \sf{0^2= (11)^2 + 2 \times \alpha \times 80} [/tex]

[tex] \sf{0 = 121 + 160 \alpha} [/tex]

[tex] \sf{-160 \alpha = 121} [/tex]

[tex] \sf{\alpha = \frac{121}{-160}}[/tex]

[tex] \sf{\alpha = -0.75625 \: rad/s^2 \approx \boxed{-0.76 \: rad/s^2}}[/tex]

t = ... s

[tex] \sf{\alpha = \frac{\omega_0 - \omega_t}{t}}[/tex]

[tex] \sf{-0.76 = \frac{0 - 11}{t}}[/tex]

[tex] \sf{-0.76t = -11}[/tex]

[tex] \sf{t = \frac{- 11}{-0.76}}[/tex]

[tex] \boxed{\sf{t \approx 14.474 \: s}}[/tex]

Conclusion

So :

The angular acceleration of the wheel approximately -0.76 rad/s² or proportionally as deceleration approximately 0.76 rad/s.It need approximately 14.474 s to come to rest.

A rock is suspended from the lower end of a light string. When the rock is totally immersed in water, the tension in the string is 1.20 N. When the rock is totally immersed in ethanol, the tension in the string is 1.60 N. Calculate the weight of the rock.

Answers

For a rock is suspended from the lower end of a light string,  the weight of the rock is mathematically given as

W = 3.10 N

What is the weight of the rock.?

Generally, the equation for the W = Fh1+  is mathematically given as

W = Fh+T1

Where

PiVg+T1 = P2V9+T

(1000) V(9.8) + 1.2 = (790) V(9.8) + 1.6

V = 1.944* 10^-4 m3

In conclusion

W = Fh+T1

W = (1000) (1.944 * 10-4) (9.8) + 1.2

W = 3.10 N

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A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is 5.0 × 10 seconds, what is the value of impulse
A.
0.26 newton seconds
B.
0.58 newton seconds
C.
1.82 newton seconds
D.
2.20 newton seconds

Answers

Maybe the question is :

A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is [tex] \sf{5.0 \times 10^{-4}} [/tex] seconds, what is the value of impulse ?

So, the value of impulse is (A). 0.26 newton seconds.

Introduction

Hi ! Here, I will help you about the impulse. Impulse is described as a quantity which expresses the integral of the amount force respect to time. The amount of impulse will be proportional to the amount of force or time (the greater  value of the force or the value of time, the value of impuls is greater too). The relationship between impulse, force, and time is expressed in this equation :

[tex] \boxed{sf{\bold{I = F \times \Delta t}}} [/tex]

With the following condition:

I = impulse that occurs (N.s)F = force that given (N)[tex] \sf{\Delta t} [/tex] = interval of the time (s)

Problem SolvingWe know that :F = force that given = 520 N[tex] \sf{\Delta t} [/tex] = interval of the time = [tex] \sf{5.0 \times 10^{-4} \: s}[/tex]

What was asked :

I = impulse that occurs = ... N.s

Step by step :

[tex] \sf{I = F \times \Delta t} [/tex]

[tex] \sf{I = 520 \times (5.0 \times 10^{-4}} [/tex]

[tex] \sf{I = 2,600 \times 10^{-4}} [/tex]

[tex] \sf{I = 2.60 \times 10^3 \times 10^{-4}} [/tex]

[tex] \sf{I = 2.60 \times 10^{3 + (-4)}} [/tex]

[tex] \sf{I = 2.60 \times 10^{-1} = \boxed{0.26 \: N.s}} [/tex]

Conclusion :

So, the value of impulse is (A). 0.26 newton seconds

Which of the following examples of the streets Newton second law of motion

Answers

Explanation:

Newton’s second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

In the image, not to scale, which phase of the moon would you observe from earth?​

Answers

Answer:

The "new" moon phase is being shown because the moon shown is directly between the sun and earth and is not visible from the earth because of the brightess of the sun.

5. What is the potential energy of a spring if the spring constant is 25.0 N/m and it is compressed to .5 m past its resting position?

Answers

Explanation:

Given: Required: solution:

k=25N/m PE ? PE= 1/2 × KX²

X= 5m 1/2 × (25)(5)²

= 312.5 J

7- A gas is contained in a vertical, frictionless piston-cylinder device. The piston has a mass of 4 kg and a cross-sectional area of 35 cm^2. A compressed spring above the piston exerts a force of 60 N on the piston. If the atmospheric pressure is 95 kPa, Determine the pressure inside the cylinder.​

Answers

It’s odd you bufón hub fix up novio j in on big big job half got food rush gc junk church John non mom K on KB vivid Tatars watch giving him

A wave has a frequency of 5hz and a wave speed of 25m/s what is the wavelength?

25 m
5 m
25 m/s
125 m

Answers

25 m because adding 5hz and 25 m would give 49 kg of mass and volume

what does a snow leopard eat?

Answers

Answer:

They eat Himalayan blue sheep, boar, deers, wild mountain goats, pikas etc.

Explanation:

What is the momentum of a 35–kilogram cart moving at a speed of 1.2 meters/second

Answers

Answer:

42

Explanation:

P = M × V

so

P = 35 × 1.2

P = 42

Answer:

42kg•m/s

Explanation:

p=m*v

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