The velocity of the nitrogen molecule immediately after the collision (in km/s) is -0.5064 km/s.
What is conservation of linear momentum?When there is no external force acting on the system, the initial momentum before collision is equal to the final momentum after collision.
According to the momentum conservation principle,
m₁u₁ +m₂u₂ =m₁v₁ +m₂v₂
here, u represents the initial velocities, v represents final velocities and m represents the masses.
Given is the mass of nitrogen molecule, m₁ =28u =28 x 1.66×10⁻²⁷kg = 46.48 x 10⁻²⁷kg
the mass of water molecule, m₂ =18u =18 x 1.66×10⁻²⁷kg = 29.88 x 10⁻²⁷kg
initial velocity of nitrogen molecule u₁ = 0.4390 km/s
initial velocity of water molecule u₂ = -0.7690 km/s
final velocity of water molecule v₂ = 0.7016 km/s
Substituting the values into the above expression, we get the final velocity of the nitrogen molecule
46.48 x 10⁻²⁷kg x 0.4390 km/s + 29.88 x 10⁻²⁷kg x (-0.7690 km/s) = 46.48 x 10⁻²⁷kg x v₁ + 29.88 x 10⁻²⁷kg x 0.7016 km/s
v₁ = -0.5064 km/s
Thus, the final velocity of nitrogen molecule is -0.5064 km/s (to left).
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The superhero Green Lantern steps from the top of a tall building. He falls freely from rest to the ground, falling half the total distance to the ground during the last 1.00 s of his fall (Fig. 2.30). What is the height h of the building?
SOLUTION GUIDE
IDENTIFY and SET UP
1. You’re told that Green Lantern falls freely from rest. What does this imply about his acceleration? About his initial velocity?
2. Choose the direction of the positive y -axis. It’s easiest to make the same choice we used for freely falling objects in Section 2.5.
3. You can divide Green Lantern’s fall into two parts: from the top of the building to the halfway point and from the halfway point to the ground. You know that the second part of the fall lasts 1.00 s. Decide what you would need to know about Green Lantern’s motion at the halfway point in order to solve for the target variable h. Then choose two equations, one for the first part of the fall and one for the second part, that you’ll use together to find an expression for h. (There are several pairs of equations that you could choose.)
EXECUTE
4. Use your two equations to solve for the height h. Heights are always positive numbers, so your answer should be positive.
Answer:
1) its initial velocity is zero, 2) the downward direction as positive
3) h = 25.66 m
Explanation:
This is a free fall exercise.
1) with falls, its initial velocity is zero and the acceleration is constant throughout the path and is equal to the acceleration due to gravity.
2) a widely used selection to estimate the downward direction as positive
3) We know that for the second part of the fall
y₀ -y = h/2 at t = 1 s
y = y₀ + v₁ t + ½ g t²
where v₁ is the initial velocity of this interval at the point y = h / 2
v₁ t = (y -y₀) - ½ g t²
v₁ = h / 2 - ½ g t²
v₁ = h/2 - g/2
now let's write the equation for the first interval
v₁² = v₀² + 2 g (y₁ - y₀)
in this interval v₀ = 0
v₁² = 2 g (y₁ -y₀)
v₁² = 2g h/2
we write our system of equations
v₁² = (h/2 - g/2)²
v₁² = (2g h / 2)
(h /2 - g/2)² = (2g h / 2)
h² / 4 - 2 g/2 h/2 + (g/2)² = g h
h² / 4 - g h/2 - g h + g²/4 = 0
h² - 3 g h + g² =0
h² - 29.4 h +96.04 = 0
we solve the quadratic equation
h = [29.4 ±√ (29.4² - 4 96.04)] / 2
h = [29.4 ± 21.91] / 2
h₁ = 25.66 m
h₂ = 3.75 m
As the system takes more than 1 S to fall, the correct answer for the height is h = 25.66 m
Answer 1)
This is a free fall exercise with falls, its initial velocity is zero and the acceleration is constant throughout the path and is equal to the acceleration due to gravity.
Answer B :
A widely used selection to estimate the downward direction as positive.
Answer 3:
We know that for the second part of the fall:
y₀ -y = h/2 at t = 1 s
y = y₀ + v₁ t + ½ g t²
where v₁ is the initial velocity of this interval at the point
y = h / 2
v₁ t = (y -y₀) - ½ g t²
v₁ = h / 2 - ½ g t²
v₁ = h/2 - g/2
Answer 4:
Now let's write the equation for the first interval
v₁² = v₀² + 2 g (y₁ - y₀)
in this interval v₀ = 0
v₁² = 2 g (y₁ -y₀)
v₁² = 2g h/2
we write our system of equations
v₁² = (h/2 - g/2)²
v₁² = (2g h / 2)
(h /2 - g/2)² = (2g h / 2)
h² / 4 - 2 g/2 h/2 + (g/2)² = g h
h² / 4 - g h/2 - g h + g²/4 = 0
h² - 3 g h + g² =0
h² - 29.4 h +96.04 = 0
we solve the quadratic equation
h = [29.4 ±√ (29.4² - 4 96.04)] / 2
h = [29.4 ± 21.91] / 2
h₁ = 25.66 m
h₂ = 3.75 m
As the height is h = 25.66 m.
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In order to climb up a mountainside, a train needs to start at a speed of 40 mph. The speed limit on the track, however, is 25 mph. How much time does the train need to get up to 40 mph if it can accelerate 4 mph per minute ?
Two dogs are running a race of 100m. The green dog runs the 100m in 10s. The
red dog runs the first half of the race in 3s and then turns around and runs back
to the starting line in 5s. Describe what the velocity time graph would look like of
the race.
Answer: What type of dog is green and red?
Explanation:
From the concepts you have learned in this module, how are you going to assess
the Earth's condition to support life? Explain your answer.
1. Temperature
2. Water
3. Atmosphere
4. Energy
5. Nutrients
Answer:
Find the explanation below.
Explanation:
Earth is properly designed to support life. This is seen in the favorable temperature that supports life, the water cycle that recycles water for plant and animal life, the atmosphere, energy, and nutrients.
1. Temperature: The temperature which is regulated by the different weather conditions such as the rains, snows, dry seasons all help to maintain a stable condition for life.
2. Water: The water cycle through processes like evaporation, condensation, precipitation, helps to ensure that there is never a lack of water in the earth. The numerous water bodies like the seas, oceans, rivers, lakes, also provide a habitat for some living things. Water makes up 70% of the earth.
3. Atmosphere: The atmosphere is a mixture of gases in the right proportions that are necessary for life. Oxygen, Nitrogen, Carbon, etc are released and inhaled by man and other living things. They are also involved in so many biochemical reactions that help in metabolism and catabolism.
4. Energy: Energy generated from the sun and within the earth is stored in various forms and is always conserved. This energy is converted to different states such as the potential, chemical, kinetic, mechanical forms to get work done and to release heat.
5. Nutrients: Though cycles such as the carbon, nitrogen, oxygen, and phosphorous cycles, the earth maintains its stock of essential nutrients that help to sustain life.
An interdisciplinary approach encompassing climatology, oceanography, environmental science, and other fields of study is necessary to evaluate the Earth's capacity to support life.
Temperature: Monitoring and analyzing climate data from numerous sources, including weather stations, satellites, and ocean buoys, is necessary to determine the Earth's temperature. To understand how temperature patterns vary over time, scientists look at long-term trends, seasonal variations, and severe events. They forecast future temperature increases and their possible effects on life and ecosystems using global climate models.
Water: Monitoring freshwater availability, water quality, and water distribution throughout various regions are all part of the assessment of Earth's water resources. Studies of precipitation patterns, data on ice melting from polar regions, and measurements of water levels in lakes, rivers, and aquifers are all conducted by researchers. Testing for toxins, pollutants, and chemical compositions is part of evaluating water quality to make sure it adheres to acceptable standards for both ecological and human health.
Atmosphere: scientists measure and research a number of factors, such as greenhouse gases, air quality, and atmospheric pressure, in order to evaluate the Earth's atmosphere. Carbon dioxide (CO2), methane (CH4), and other greenhouse gases are measured at monitoring sites throughout the globe to better understand how they contribute to climate change. Pollutants like particle matter and ozone, which have an influence on both human health and ecosystems, are measured by air quality monitoring stations.
Energy: studying diverse energy sources and their effects on the environment and ecosystems is necessary to evaluate the amount of energy present on Earth. Scientists assess the usage of non-renewable energy sources like fossil fuels as well as renewable energy sources like solar, wind, hydro, and geothermal energy. To create sustainable energy plans that support life on Earth, they examine energy consumption trends, carbon emissions, and energy efficiency.
Nutrients: studying nutrient cycles and availability in soils, oceans, and terrestrial ecosystems is necessary for evaluating the availability of nutrients in the Earth's ecosystems. To determine the nutrient levels for agriculture and plant growth, researchers examine soil samples. In order to gauge the productivity and availability of nutrients for marine life, they also research marine ecosystems.
Hence, an interdisciplinary approach encompassing climatology, oceanography, environmental science, and other fields of study is necessary to evaluate the Earth's capacity to support life.
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The answer pleaseeeeeee
If a car travels 600m west in 25 seconds, what is its velocity?
Answer:
The answer is 24 m/sExplanation:
The velocity of the car can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex]v = \frac{600}{25} \\ [/tex]
We have the final answer as
24 m/sHope this helps you
An Object is thrown straight up into the air with an initial velocity of 15m/s. What is its velocity at the peak of its flight?
Answer:
0
Explanation:
The initial velocity of an object is 15 m/s when it was thrown straight up into the air.
At maximum height, the velocity of the object is equal to 0. It starts coming downward after that and falls ground. Height attained by the object is given by :
[tex]h=\dfrac{v^2}{2g}[/tex]
Hence, its velocity at the peak of its flight is equal to 0.
Invisible fence for dogs. In this type of system, a wire is buried under the surface and a current at a given frequency passes through the wire. The dog wears a small unit made of a pickup coil and electronics that delivers a short high-voltage pulse to the dog through a couple of electrodes pressed against its skin. The pulse is not harmful, but it does provide a correction that encourages the dog to keep away. In an invisible fence, the wire carries a 10kHz sinusoidal current with an amplitude of 0.5 Amps. The dog carries a sensoron its collar made as a coil with 150 turns and 30 mm in diameter.If the detection level at the coil inside the collar is set at 200 μV RMS (i.e., the level at which the dog will receive a correction pulse), what is the furthest distance from the wire the dog will "feel" the presence of the fence?
Answer:
The distance is [tex] s = 2.3 \ m [/tex]
Explanation:
From the question we are told that
The frequency of the current is [tex]f = 10\ kHz = 10 *10^{3} \ Hz[/tex]
The magnitude of the current is [tex]I_o = 0.5\ Amps[/tex]
The number of turns is [tex]N = 150\ turns[/tex]
The diameter is [tex]d = 30 mm = 0.03 \ m[/tex]
The detection level is [tex]V_{rms} = 200 \mu V = 200 * 10^{-6} \ V[/tex]
Generally the radius is mathematically represented as
[tex]r = \frac{d}{2}[/tex]
=> [tex]r = \frac{0.03}{2}[/tex]
=> [tex]r 0.015 \ m [/tex]
Generally the magnetic field generated by the fence is mathematically represented as
[tex]B = \frac{\mu_o * N * I}{2 * \pi * s}[/tex]
Here s is the point where the do will feel the magnetic field
[tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2 [/tex]
So
[tex]B = \frac{ 4\pi * 10^{-7} * 150 * I}{2 * 3.142 * s}[/tex]
Generally the magnetic flux is mathematically represented as
[tex]\Phi = B * \pi * r^2[/tex]
=> [tex]\Phi = \frac{ 4\pi * 10^{-7} * 150 * I}{2 * 3.142 * s} * \pi * r^2[/tex]
=> [tex]\Phi = \frac{2.121 *10^{-8} * I }{s}[/tex]
Generally the induced emf is mathematically represented as
[tex]\epsilon =- \frac{d \Phi}{dt}[/tex]
=> [tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * \frac{d I}{dt}[/tex]
Generally the angular frequency is mathematically represented as
[tex]w = 2 \pi f[/tex]
=> [tex]w = 2 * 10*10^{3} \pi [/tex]
=> [tex]w = 20000 \pi [/tex]
So the current is mathematically represented as
[tex]I = I_o sin (wt)[/tex]
=> [tex]I = I_o sin ( 20000 \pi * t)[/tex]
So
[tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * \frac{d [ I_o sin ( 20000 \pi * t)]}{dt}[/tex]
[tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * I_o * 20000 \pi [ cos ( 20000 \pi * t) [/tex]
[tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * 0.5 * 20000 \pi [ cos ( 20000 \pi * t) [/tex]
[tex]\epsilon =- \frac{ 6.6*10^{-4} }{ s } [ cos ( 20000 \pi * t) [/tex]
Here the
[tex]\epsilon_{rms} = \frac{ \frac{ 6.6*10^{-4} }{ s }}{\sqrt{2} }[/tex]
=> [tex]\epsilon_{rms} = \frac{ 6.6*10^{-4} }{ s\sqrt{2} }[/tex]
But from the question we are told that [tex]V_{rms} = 200 \mu V = 200 * 10^{-6} \ V[/tex]
So
[tex]\frac{ 6.6*10^{-4} }{ s\sqrt{2} } = 200 * 10^{-6}[/tex]
=> [tex]6.6*10^{-4}= 2.8284 *10^{-4} * s[/tex]
=> [tex] s = 2.3 \ m [/tex]
A
A penny is dropped from the top of a 200 m building and is in free fall. How long will it take
the penny to hit the ground?
Answer:
The penny will hit the ground at 6.39 seconds
Explanation:
Free Fall
The penny is dropped from a height of y=200 m. The equation of the height on a free-fall motion is given by:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
Where [tex]g=9.8\ m/s^2[/tex], and t is the time.
Solving for t:
[tex]\displaystyle t=\sqrt{\frac{2y}{g}}[/tex]
Using the value y=200:
[tex]\displaystyle t=\sqrt{\frac{2*200}{9.8}}[/tex]
t=6.39 sec
The penny will hit the ground at 6.39 seconds
A building's 10th floor (34.5 m high) is blazing with fire. A fire truck arrived at the scene and the fire
men shoots water from their hose. The water leaves the hose at the speed of 29 m/s, at an angle
of
63° and is held at 0.90 m from the ground. Will the water reach the fire? If so, how far from the
building should the hose be so the fire could be put out?
Answer:
Yes, the water will be reach the fire.
The hose should be at 34.7 m from the building
Explanation:
Given that,
Height of building's =34.5 m
Speed = 29 m/s
Angle = 63°
Distance from the ground = 0.90 m
We need to calculate the actual height
Using formula of height
[tex]H=\dfrac{u^2\sin^2\theta}{2g}[/tex]
Put the value into the formula
[tex]H=\dfrac{29^2\sin^2{63}}{2\times9.8}[/tex]
[tex]H=34.0\ m[/tex]
The height from the ground will be
[tex]H'=34+0.90[/tex]
[tex]H'=34.9\ m[/tex]
We can say that, the water gun attained the maximum height that is 0.4 m more than the 10th floor.
So, yes, the water will be reach the fire.
We need to calculate the range
Using formula of range
[tex]R=\dfrac{u^2\sin2\theta}{g}[/tex]
Put the value into the formula
[tex]R=\dfrac{29^2\times\sin(2\times63)}{9.8}[/tex]
[tex]R=69.4\ m[/tex]
The house should be at half of R.
[tex]\dfrac{R}{2}=\dfrac{69.4}{2}[/tex]
[tex]\dfrac{R}{2}=34.7\ m[/tex]
Hence, Yes, the water will be reach the fire.
The hose should be at 34.7 m from the building
A sports car of mass 1.00x103 kg can accelerate from rest to 30.0 m/s in 7.00 s. What is the average forward force on the car?
Answer:
Explanation:
Before you can find the force, you need to find the acceleration.
Givens
vi = 0
vf = 30 m/s
t = 7 seconds
Formula
a = (vf - vi) / t
Solution
a = (30 - 0)/7
a = 4.28 m/s
Now you can look at the Force
F = m * a
F = 1.00*10^3 * 4.28
F = 4.28 * 10^3 N
why did you test the resistance of the wire
Answer:
What????
Explanation:
is there more to the problem???
give reasons with examples why houses are made up of bricks and cement instead of metal
Answer:
The most important is that the thermal conductivity of the armadillas several orders of magnitude lower than the thermal conductivity of the metal, therefore it is easier to maintain the temperature in winter
Explanation:
Cement and bricks are used in the construction of houses instead of metal, for several reasons
* The most important is that the thermal conductivity of the armadillas several orders of magnitude lower than the thermal conductivity of the metal, therefore it is easier to maintain the temperature in winter
* Metal has more oxidation problems than brick
* The cost of sheet metal is higher than the cost of cement brick.
Because mass is determined from protons
and neutrons, what conclusion can you
make?
Answer:
Electrons have virtually no mass
Explanation:
I had a test an this was the right answer^
Answer: Electrons have virtually no mass
Explanation: on edpuzzle that was the answer
True or false- Normally, all objects are electrically positively charged
A net force F accelerates a mass 'm' with an acceleration 'a'. what acceleration results if force 13F acts on mass 15m in terms of 'a'
Answer:
13a/15
Explanation:
According to newton's second law
F = ma
F is the force
m is the mass
a is the acceleration
From the formula:
a = F/m
Given
F = 13F
m = 15m
Substitute the given parameters into the formula:
a' = 13F/15m
a' = 13/15 * F/m
a' = 13/15 * a
a' = 13a/15
Hence the new acceleration a' that results in terms of a is 13a/15
What volume is represented by each small tick mark ? Help !!!
Answer:
In the taller, skinnier cylinder, each tick mark represents 2, while in the larger one, each tick mark represents 50.
Explanation:
If you count the tick marks between each big number, then you can divide, and figure out what amount each tick mark represents.
Before Collision Consider a system to be one train car moving toward another train car at rest When the train cars collide, the two cars stick together What is the total momentum of the system after the collision? O 800 kg . m/s m, = 600 kg V,= 4 m/s m = 400 kg v2 = 0 m/s 1,600 kg. m/s 0 2,400 kg • m/s 0 4,000 kg . m/s After Collision
Answer:
2,400kg * m/s
Explanation:
You are missing some information in the question but the rest could be found some where else.
The question gives the masses and starting velocity of each car.
Car 1: m = 600kg and sv = 4m/s
Car 2: m 400kg and sv = 0m/s
Find the momentum of both cars.
Car 1: 600 * 4 = 2400
Car 2: 400 * 0 = 0
Add both.
2400 + 0 = 2400
Best of Luck!
Answer: answer C
Explanation:
Your welcome
A automotive test driver travels due north in a prototype hybrid vehicle at 30 mi/h
for 2 hours. She then reverses her direction and travels due south at 60 mi/h for 1 hour.
What is the average speed of the vehicle?
a) 40 mi/h
b) 50 mi/h
c) zero mi/h
d) 60 mi/h
e) 30 mi/h
Answer:
Option A. 40 mi/h
Explanation:
To obtain the average speed of the vehicle, we'll begin by calculating the distance travelled by the vehicle in each case. This is illustrated below:
Case 1:
Speed = 30 mi/h
Time = 2 h
Distance =...?
Speed = Distance /Time
30 = Distance /2
Cross multiply
Distance = 30 × 2
Distance = 60 mi
Case 2:
Speed = 60 mi/h
Time = 1 h
Distance =...?
Speed = Distance /Time
60 = Distance /1
Cross multiply
Distance = 60 × 1
Distance = 60 mi
Finally, we shall determine the average speed of the vehicle as follow:
Total distance travelled = 60 + 60
Total distance travelled = 120 mi
Total time = 2 + 1
Total time = 3 h
Average speed =..?
Average speed = Total Distance travelled /Total time
Average speed = 120/3
Average speed = 40 mi/h
Therefore, the average speed of the vehicle is 40 mi/h
In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light? In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light? 214 nm 204 nm 224 nm 100 nm 234 nm
Answer:
The value is [tex]\lambda = 214.3 \ nm [/tex]
Explanation:
From the question we are told that
The slit separation is [tex]d = 3.00 * 10^{-5} m[/tex]
The distance of the screen is [tex]D = 2.00\ m[/tex]
The order of fringe is n = 7
The path difference is [tex]y = 10.0 \ cm = 0.1 \ m[/tex]
Generally the path difference is mathematically represented as
[tex]y = \frac{n * \lambda * D}{ d}[/tex]
=> [tex]0.1 = \frac{7 * \lambda * 2.00 }{ 3.00 * 10^{-5}}[/tex]
=> [tex]\lambda = \frac{0.1 *3.00 * 10^{-5} }{7 * 2.00 }[/tex]
=> [tex]\lambda = \frac{0.1 *3.00 * 10^{-5} }{7 * 2.00 }[/tex]
=> [tex]\lambda = 2.143 *10^{-7} \ m [/tex]
=> [tex]\lambda = 214.3 \ nm [/tex]
BLANK charges repel each other.
Answer:
like
Explanation:
Have a good day!!
Answer: negitive
Explanation:
You drive 200 miles in 3 hours before stopping
for 30 minutes for lunch and gas. After lunch,
you travel 150 miles in an hour and a half. What
was your average speed for the trip?
Answer 55.5mph
explanation
I WILL MARK YOU AS BRAINLIEST IF RIGHT
A car traveling north with a speed of 35 m/s slows down to a velocity of 10 m/s within 5 seconds. What is the car's deceleration?
Answer:
-5
Explanation:
10-35/5
-25/5
-5m/s^2it ask the deceleration this mean
vf<vi so it's negative it is the simplest way
A disc with moment of inertia 1.5 kg m2 is rotating with an angular speed of 800 rev/min on a shaft. A second disc, initially at rest and with moment of inertia 5.0 kg m2,is suddenly clamped together to the same shaft.
(a) Determine magnitude of angular momentum of the first disc.
(b) Determine the common angular speed of the combination of the two discs.
Answer:
Explanation:
Angular momentum p = Iw
I is the moment of inertia
w is the angular velocity
a) Angular momentum of the first disc
p1 = I1w1
Given
I1 = 1.5kg/m²
w1 = 800rev/min
Convert to rad/s
1 rev = 6.283rad
1 min = 60secs
800rev/min = 800(6.283)/60
= 83.77rad/s
p1 = 1.5×83.77
p1 = 125.66kgrad/s
Hence the magnitude of angular momentum of the first disc is 125.66kgrad/s
b) according to law of conservation of momentum
I1w1+I2w2 = (I1+I2)w
w is the common angular speed
Given
11w1 = 125.66
w2 = 0rad/s
I1 = 1.5kgm²
I2 = 5kgm²
Substitute
125.66+0 = (1.5+5)w
125.66 = 6.6w
w = 125.66/6.5
w = 19.33rad/s
Since 1rad/s = 9.549tev/min
19.33rad/s = 184.6rev/min
Hence the common angular speed of the combination of the two discs is 184.6rev/min
Calculate the dot product of D and E, where D=7i - 3j + 2k and E=4i + 5j - 3k.
please show working
Answer:
Since i dot i = 1 and j dot j = 1 and k dot k = 1 and the other terms are zero
(7 i - 3 j + 2 k) dot (4 i + 5 j - 3 k) = 28 - 15 -6 = 7
Which object has the greatest
inertia?
F- a falling leaf
G- a softball in flight
H-a seated high school student
J-a rising helium-filled toy balloon
Answer:
H-a seated high school student
Explanation:
"Inertia" is an important word in Physics. It is the resistance of an object to any change in motion. Measuring the amount of inertia largely relies on the "mass of an object." The heavier the object, the more likely it is able to resist any change in motion.
Among the choices above, the high school student is the heaviest and has greater mass than the leaf, softball or balloon. This means, it has the greatest inertia.
Thus, this explains the answer.
Which of the following is a characteristic of electromagnetic waves? (2 points)
A graph of kinetic energy vs the mass of an object is ______________?
Answer:
The shape of the MASS vs ENERGY graph has a NON-LINEAR RELATIONSHIP.
Explanation:
Your Welcome Friend! :)
A graph of kinetic energy vs the mass of an object is non-linear.
What is the nonlinear relationship?
Changes in the output are not proportional to changes in any of the inputs in a nonlinear connection.
When a linear connection is plotted on a graph, it produces a straight line; however, when a nonlinear relationship is plotted on a graph, it produces a curve.
When graphed, motion energy is proportional to the mass of the moving item, resulting in a linear connection, and it expands with the square of its speed, resulting in a non-linear relationship.
Hence a graph of kinetic energy vs the mass of an object is non-linear.
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1. Why is it important to use units in any graph?
2. Why does any graph need a title on it?
Answer:
so its easier to understand for the reader
Explanation:
2) Labelling. Graphs are used to present data. They must be clearly labelled if the reader is to understand them. By labelling we are referring to the text inside the graph itself, and not the title.
If an object starts out at rest and accelerates to 100 m/s what is its initial speed?
Answer:0m/s
Explanation.
The initial velocity is 0 because when the object starts moving its speed is zero
