Answer:
the temperature in the troposphere decreases while the temperature in the stratosphere increases because of the density of air molecules.
Explanation:
sorry ima little late
A 40.0 kg objects is subject to two forces, one of +18.0 N and one of -6.0 N. What is the acceleration the crate undergoes?
A. 0.3 m/s2 B. 1.67 m/s2 C. 3.3 m/s2 D. 4.0 m/s2 E. 480 m/s2
∑F=m.a
18 - 6 = 40 x a
12 = 40a
a = 0.3 m/s²
A student shakes a rope such that 36 complete vibrations are
made in 9.00 seconds. determine the vibrational period of
the rope, along with the corresponding unit.
The vibrational period of the rope, when a student shakes it is 0.25 s.
What is the frequency?Frequency is the number of oscillations per second.
Given is the number of vibrations =36 in time t = 9s, then frequency will be
f = 36/9 =4Hz
The time period is the reciprocal of the frequency.
T = 1/f
Plug the frequency value, we get
T = 1/4 Hz = 0.25 seconds
Thus, the vibrational time period is 0.25s.
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Exercises
Question-5 (doable)
A magnified, inverted image is located a distance of 38.0 cm from a converging lens with a focal
length of 10.0 cm. Determine the object distance and tell whether the image is real or virtual
[ 13.6 cm )
[tex]\\ \rm\Rrightarrow \dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{1}{-10}+\dfrac{1}{38}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{-19+5}{190}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{-14}{190}[/tex]
[tex]\\ \rm\Rrightarrow u=\dfrac{190}{-14}[/tex]
[tex]\\ \rm\Rrightarrow u=13.6cm[/tex]
Real
The powertrain of many machines consists of _____
gears - answer
linkages
trusses
splines
Answer:
gears - answer
Explanation:
Hope it helps
At time t = 0 s, an object is moving to the right
with a velocity v that can be modeled by the
equation v=(4.2 m/s)-(1.4 m/s?)t. At what time,
if any, does the object change its direction of
motion?
This object should not change its direction of motion because despite its velocity it will be still moving to the right.
What does the equation describe?The equation describe the velocity of an object and how this velocity changes depending on time.
How is the direction of motion relate?The equation does not describe the direction of motion. Due to this, it is expected the direction is the same and does not change.
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In a tug of war, team A is pulling the rope with a force of 60N towards the right and team B also applies 60N towards the left, what is the net force?
Answer:
[tex]f_n_e_t=0[/tex]
Explanation:
[tex]f_1+f_2=f_n_e_t[/tex]
because there are two different forces in different directions (left: negative, right: positive, down: negative, up: positive) so 60N left will be negative, and 60N right will be positive:
[tex]60+(-60)=0[/tex]
when two same forces apllied then the net force is zero.
If the volume of a container increases what
effect will this have on pressure? Why?
As the volume of the container increases the pressure inside will decrease because the atoms have more room to move around in.
Answer:
In a container of the same volume, a greater number of molecules results in greater pressure. Gas pressure increases as container volume decreases.
Hope this helps you!!
Please Mark me Brainleast if am correct!!
Thankyou for joining Brainly Communicty!!Which statements must be true about the two congruent, shaded figures? select two options. the figures are rectangles because they are formed inside a rectangle. the figures are rhombi because they are formed by four congruent line segments. the figures are trapezoids because each has exactly one pair of parallel sides. the figures are parallelograms because their opposite sides are parallel. the figures are quadrilaterals because each has four sides.
The true statements about the two congruent, shaded figures are:
D. The figures are parallelograms because their opposite sides are parallelE. The figures are quadrilaterals because each had four sidesWhat is Congruence?This refers to the name that is given if two figures or objects have the same shape and size.
Hence, we can see from the complete text that four parallel lines are drawn in a rectangular sign and painted using two colors in an alternating pattern, then they are parallelograms because their opposites are parallel.
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what are the characteristics of images formed by plane mirrors
Answer:
the image is erectthe image is laterally invertedimage is formed at the same distance from the mirror as the object is in front of itthe image is of same size as that of the objectthe image is virtual (cannot be obtained on a screen)
How much force is needed to accelerate a 100 kg car at a rate of 3 m/s
A sample contains 16 g of a radioactive isotope. how much radioactive
isotope remains in the sample after 1 half-life?
After one half-life, 8 g of radioactive isotope will remain in the sample.
What is radioactivity?The act of producing radiation spontaneously is known as radioactivity. This is accomplished by an unstable atomic nucleus that want to give up some energy in order to move to a more stable form.
The following formula is used to compute the number of half lives elapsed:
[tex]\rm N=\frac{N_0}{2^n} \\\\ N=\frac{16}{2} \\\\ N= 8 \ gram[/tex]
Hence,8 gram of radioactive isotope remains in the sample after 1 half-life.
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Answer:
Answer is below
Explanation:
8 g
A student measured the length of a wire four times using a meter rule and obtained the following readings: 18.6cm, 18.5cm 18.6cm and 18.5cm. Determine the length the student should record.
The length the student should record as correct is 18.55 centimeters (cm) because it is the average value.
What is the average value?The average value is a number associated with the middle amount for a given number of measured samples.
In this case, the median value results less useful to describe a set of data when compared to the average.
In conclusion, the length the student should record as correct is 18.55 centimeters (cm) because it is the average value.
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The mass of 1 dozen dimes is 27.22 g. the numerical value of the mass of 5 dozen dimes can be obtained by
Answer:
by obtaining the total mass of the dimes present:
d = 27.22 g / dozen the density of dimes
M = n * d = 5 dozen * 27.22 g / dozen = 126.1 g
Which picture shows an example of no work being done? A man and a woman hold a child in the air by the child's hands. A man pushes a shopping cart down the aisle of a grocery store. A child holds the bar of a set of weights without moving. A woman pulls a rolling suitcase.
Answer:
A child holds the bar of a set of weights without moving I think
You want to design a rollercoaster that will be able to go around a loop-the-loop on earth (where the value of g is 10 N/kg). If the mass of the rollercoaster is 6,000 kg and it is going 40 m/s at the bottom of the loop, calculate the maximum height of the top of the loop. Assume there is no energy input (motors, etc) or friction or any other energy waste in this system.
Answer:
[tex]64\; {\rm m}[/tex], assuming that the rollercoaster is not attached to the track.
Explanation:
Let [tex]r[/tex] denote the radius of the loop. The height of the top of the loop would be [tex]2\, r[/tex].
Let [tex]a[/tex] denote the acceleration of the rollercoaster. At any position in the loop, if the speed of the rollercoaster is [tex]v[/tex], the (centripetal) acceleration of the rollercoaster would be:
[tex]\displaystyle a = \frac{v^{2}}{r}[/tex].
Let [tex]m[/tex] denote the mass of the rollercoaster. The net force on the rollercoaster would then be:
[tex]\displaystyle F_\text{net} = m\, a = \frac{m\, v^{2}}{r}[/tex].
The rollercoaster would stay on the track (and goes around the loop without falling off) only if the normal force [tex]F_\text{normal}[/tex] between the track and the rollercoaster is non-negative. In other words: it is necessary that [tex]F_\text{normal} > 0[/tex] for the rollercoaster to stay on the track.
At the top of the loop, [tex]F_\text{normal}[/tex] and the weight of the rollercoaster [tex]m\, g[/tex] are in the same direction as the centripetal acceleration (downwards towards the center of the loop.) Hence:
[tex]F_\text{net} = F_\text{normal} + m\, g[/tex].
Let [tex]v_\text{top}[/tex] denote the speed of the rollercoaster at the top of the loop.
[tex]\begin{aligned} F_\text{normal} &= F_\text{net} - m\, g \\ &= \frac{m\, v_\text{top}^{2}}{r} - m\, g\end{aligned}[/tex].
If [tex]F_\text{normal} > 0[/tex] at the top of the loop, then:
[tex]\displaystyle \frac{m\, v_\text{top}^{2}}{r} - m\, g > 0[/tex].
[tex]\displaystyle v_{\text{top}}^{2} > g\, r[/tex].
At the same time, by the conservation of energy, the sum of the kinetic energy [tex]\text{KE}[/tex] and gravitational potential energy [tex]\text{GPE}[/tex] of the rollercoaster should stay the same during the entire ride. Assuming that [tex]\text{GPE}\![/tex] is [tex]0[/tex] at the bottom of the loop:
[tex]\begin{aligned}& \text{KE at the bottom}\\ &= \text{KE at the top} + \text{GPE at the top}\end{aligned}[/tex].
Let [tex]v_{0}[/tex] denote the speed of the rollercoaster at the bottom of the loop.
[tex]\begin{aligned}\text{KE at the bottom} = \frac{1}{2}\, m\, {v_{0}}^{2}\end{aligned}[/tex].
The speed of the rollercoaster at the top of the loop [tex]v_\text{top}[/tex] is at least [tex](g/r)[/tex]. Therefore:
[tex]\begin{aligned}& \text{KE at the top}= \frac{1}{2}\, m\, {v_{\text{top}}}^{2} > \frac{1}{2} \, m\, g\, r\end{aligned}[/tex].
Since the height of the loop is [tex]2\, r[/tex], the [tex]\text{GPE}[/tex] of the rollercoaster at the top of the loop would be:
[tex]\text{GPE at the top} = m\, g\, h = 2\, m\, g\, r[/tex].
Thus:
[tex]\begin{aligned} \frac{1}{2}\, m\, {v_{0}}^{2} &= \text{KE at the bottom}\\ &= \text{KE at the top} + \text{GPE at the top} \\ & > \frac{1}{2}\, m\, g\, r + \text{GPE at the top}\\ & = \frac{1}{2}\, m\, g\, r+ 2\, m\, g\, r \\ &= \frac{5}{2}\, m\, g\, r\end{aligned}[/tex].
In other words:
[tex]\displaystyle \frac{1}{2}\, m\, {v_{0}}^{2} > \frac{5}{2}\, m\, g\, r[/tex].
Rearrange and simplify to obtain a bound on [tex]r[/tex]:
[tex]\begin{aligned} r < \frac{(1/2)\, m\, {v_{0}}^{2}}{(5/2)\, m\, g}\end{aligned}[/tex].
[tex]\begin{aligned} r < \frac{{v_{0}}^{2}}{5\, g}\end{aligned}[/tex].
Given that [tex]v_{0} = 40\; {\rm m\cdot s^{-1}[/tex] and [tex]g = 10\; {\rm N \cdot kg^{-1}} = 10\; {\rm m\cdot s^{-2}[/tex]:
[tex]\begin{aligned} r & < \frac{{v_{0}}^{2}}{5\, g} \\ &= \frac{(40\; {\rm m\cdot s^{-1}})^{2}}{5 \times (10\; {\rm m\cdot s^{-2}})} \\ &= 32\; {\rm m}\end{aligned}[/tex].
Hence, the radius of this loop is at most [tex]32\; {\rm m}[/tex], such that the height of the top of this loop is at most [tex]2 \times 32\; {\rm m} = 64\; {\rm m}[/tex].
A crowbar moves a distance of .35 meter to lift a load .05 meters off the ground.
what is the ideal mechanical advantage of the crowbar?
The ideal mechanical advantage of the crowbar will be 0.7.IMA is also equal to the distance traveled by the load divided by the distance traveled by the effort.
What is ideal mechanical advantage?The ideal mechanical advantage of a lever is equal to the length of the effort arm divided by the length of the resistance arm.
The ideal mechanical advantage is found as;
[tex]\rm IMA=\frac{0.35}{0.5} \\\\ IMA=0.7[/tex]
Hence,the ideal mechanical advantage of the crowbar will be 0.7.
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1.
Why does a balloon rubbed on your hair stick to the ceiling? What is this called? Why
does the balloon stay there?
Answer:
Static Electricity.
Explanation:
The rubbing of hair (object) onto the balloon creates a negative charge that is carried by electrons, the electrons will soon build higher to create static electricity, thus keeping it onto the ceiling.
Hope this helps!
1. Use the picture on page 3 of the lesson in Connexus to help you label each part of the wave below:
a.
b.
c.
d.
[tex] \large\textbf{Question } [/tex]~
[tex] \textsf{How many images will be formed when two plane } [/tex][tex] \textsf{mirrors are inclined on each other by an angle of 60° ?} [/tex]
[tex] \texttt{[ Need explanation ]} [/tex]
[tex] \bold{\underline{\underline{\underbrace{Answer}}}} [/tex]
5 images
Explanation:
⠀
⠀
⠀⠀⠀⠀▦ NoteWhat is reflection of light?
The reflection of light is the phenomenon in which the rays of light falls on the object and change it's path.
⠀
How image is formed in plane mirror?
When you look at the mirror the image is formed behind the mirror and it is virtual. The light from the object which reaches the mirror gets reflected back.
⠀
⠀
⠀⠀⠀⠀SolutionThe formula to find the no. of images between the 2 plane mirror at any angle θ.
[tex] \sf No. \: of \: images = \frac{360 \degree}{ \theta} - 1[/tex]
According to the question the plane mirror is inclined at 60° angle.
Substituting the required values.
[tex] \sf \large \frac{ \cancel{360} \small \: \: 6}{ \cancel{60}} - 1 \\ \\ \sf \large 6 - 1 \\ \\ \boxed{ \frak{ \implies 5} }[/tex]
The 2 plane mirror will form 5 images inclined at 60° angle.
Which physical activity would an augmented reality resource help you with? Diving High jumping Walking Weight lifting
Answer:
Keeping up your healthy lifestyle also means keeping up exercising. Exercise helps control your weight. It helps maintain it, or helps you loose weight. Even though having a healthy lifestyle, exercise also helps battle the chance of getting diseases and other illnesses. Exercise can help improve your energy level, as well as making sure you get the right amount of sleep. And besides all these, exercise can make you feel great in general, and help improve your overall mood.
Explanation:
Answer:
Diving, as it's not as accessible as the others.
Explanation:
a bus velocity 20m/s towards the east and another bus has velocity 15m/s in west direction.if they start to move from a point simultaneously.what distance do they cover in 2 minutes. what will be their separation.
Answer:
Velocity towards east = 20m/s
Distance in 2 min(120 sec) = 20 x 120= 2400m = 2km
Velocity towards west = 15m/s
Distance in 2 min(120 sec) = 15 x 120 = 1800m = 1.8km
Separation= 2+1.8 = 3.8km
Explanation:
Hope it helps you:))))))
have a good day
In reality, the kinetic energy at the bottom of the ramp will always be less than the gravitational potential energy at the top of the ramp. Does this disprove the law of conservation of energy? Where did the "lost" energy go?
Answer:
Conservation of energy still holds - so somewhere in traversing some of the potential energy was converted into something other than kinetic energy.
The loss of energy can be attributed to several things - friction on the ramp, air resistance, friction within the item descending the ramp; in general one would say that some of the initial PE was lost during the descent of the ramp. and did not show up as KE.
would you consider caffeine to be more or less toxic then arsenic explain
the earth had a mass of 6,000,000,000,000,000,000,000,000 kg. and a radius of 6,371,000 m, what will be the gravitational force experienced by a puppy with a mass of 4.6 kg playing on the earth sur face
Answer:
Mass of Earth (M1) = 6×10^24 kg
Mass of Puppy (M2) = 3.6 kg
Radius (R) = 6371000 m
Universal Gravitational Constant (G) = 6.67 × 10^11
Now,
Gravitational Force = G×M1×M2 / R^2
GF = 6.67 × 10^11 × 6 × 10^24 × 3.6 / (6371000)^2
GF = 144.072 × 10^35 / 40,589,641,000,000
GF = 3549.477 × 10^20
the speedodemeter of a car moving northward reads 60 km/hr. it passes another car that travels south at 60 km/hr. do both cars have the same speed and velocity?
Answer:
It passes another car that travels southward at 60 km/h. Do both cars have the same speed? Do they have the same velocity? Answer: Both cars have the same speed, but they have opposite velocities because they are moving in opposite directions.
Explanation:
Answer:
See below ~
Explanation:
As the magnitude (absolute numerical value) of both cars are equal, they both have the same speed.
But, as they are travelling in opposite ways, they have different directions. Hence, they have different velocities.
A body which is uniformly decelerated comes to rest in 5s after travelling of 10m. What is its initial velocity a distance
Answer:
4 m/s
Explanation:
v=u+ at and v^2=u^2+2as.
It is given that v=0,t=5 s and s=10 m.
⇒0=u+5a and 0=u^2+20a.
⇒a=−u/5 and a=−u^2/20.
⇒u/5 = u^2/20⇒u=4 m/s.
⇒ The initial velocity is 4 m/s.
What type of waves do not require a medium to travel?.
Answer:
electromagnetic waves
how is newton’s first law of motion used for a person in a stationary car during a car crash
Answer:
When the car crashes, there is no unbalanced force acting on the person, so they continue forward (Newton's First Law). The person moves against the seat belt, exerting a force on it.
You want to reduce your energy bills.
A) calculate the power of a lightbulb that transfers 6000 joules every minute.
B) calculate the power of a different lightbulb that has a current of 0.05 amps through it when there is a potential difference of 240 volts across it.
C) both bulbs are equally bright. State and explain which lightbulb you should use.
Answer:
A) P = W / t = 6000 / 60 = 100 J/s == 100 watts
B) P = I V = .05 * 240 = 12 watts
C) Bulb B) uses much less power
What causes trash islands to form
Answers:
Suface winds
Tropical storms
Ocean currents
Answer:
ocean currents
Explanation:
