How would speed change if the wave period increase
Answer:
The greater the period the faster the wave moves (Figure 10.5).
Explanation:
A stationary sound waves has a series of nodes. The distance between the first and the 6th node is 30cm. What is the wavelength of the sound wave
Answer:
Assume a node at the left end and the right end
N-A-N-A-N-A-N-A-N-A-N shows nodes and anti-nodes
10 quarter wavelengths are shown (or 2.5 wavelengths)
30 / 2.5 = 12 cm wavelength since there is 1/4 wavelength between node and anti-node
Nodes and anti-nodes are displayed in N-A-N-A-N-A-N-A-N.
The difference between the node and the anti-node exists 12 cm wavelength.
What is meant by stationary sound waves?Standing waves are created when two identical waves move in opposition to one another along a line. Despite being composed of two waves that are moving in opposition to one another, standing waves do not travel through space or along a string.
A wave that is stationary is one that is not moving, is at a standstill, or is in a relaxed position. A standing wave is created whenever two waves with nearly identical frequencies, wavelengths, and amplitudes that are traveling in opposite directions collide.
A waveform signal that is carried in space or down a wire has a wavelength, This is the distance between two identical locations (contiguous crests) in the following cycles. This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm).
The distance over which a periodic wave's shape repeats is known as the wavelength in physics.
Assume that there exists a node at both the left and right ends.
Nodes and anti-nodes are displayed in N-A-N-A-N-A-N-A-N.
it displays 10 quarter wavelengths.
Since there exists a 1/4 wavelength difference between the node and the anti-node, 30 / 2.5 = 12 cm wavelength.
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If a sound wave has a wavelength of 7 m and travels at a speed of 330 m/s, what is the
frequency of the sound?
O 47.1 hz
O2.12 hz
2.31 hz
23.1 hz
Answer:
047.1
Explanation:
frequency equals velocity over lambda
Find the period of small oscillations of a barbell of length l with balls of mass m, located along a homogeneous electric field of intensity E. The charge of the barbell balls is ±q.
Ray X strikes a flat mirror at an angle of 0 = 26 degrees. What is the incidence?
The incidence is maybe 26=9
A tree is at a distance of 50 meters from a place on earth. From this place, the Angle of the tree's peak is 30. Find out the height of the tree.
sine's law
h/sin 30 = 50/sin 60
h/0.5 = 50/(0.5√3)
h=28.9 m
How does the weight of an object relate to how fast it falls with a parachute?
Two identical pucks of equal but unknown mass head straight towards each other with velocities
of 8.0 m/s and -6.0 m/s. They collide and stick together. What is their resulting velocity?
inelastic collision
m.8 - m.6 = 2mv'
2m = 2mv'
v' = 1 m/s
Answer:
1 m/s
Explanation:
According to the Law of Conservation of Momentum, (for inelastic collisions)
v = m₁v₁ + m₂v₂ / m₁ + m₂v = 8m - 6m / 2mv = 2m/2mv = 1 m/sA battery of emf 20v and internal resistance 1 ohms connected in series with an external resistor4 ohms what is
a power dissipate due to ineternal resistor
The power dissipate due to internal resistor is 400 W.
Power dissipated in a circuit
The power dissipate due to internal resistor is calculated as follows;
P = IV
P = (V/r)V
P = V²/r
where;
V is emf of the batteryr is internal resistorP = (20²)/(1)
P = 400 W
Thus, the power dissipate due to internal resistor is 400 W.
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What type of wave is illustrated below?
Longitudinal
Transverse
Surface wave
Seismic wave
Answer:
Longitudinal
Explanation:
I searched it up.
Which of the objects below would experience lift?
Answer:
the first one, The object moving through air
an ldeal gas with internal energy U at 202°C is heated to 410°C.its internal energy then will be?
Internal energy is directly proportional to temperature
U1T2=U2T1U(273+410)=U2(273+202)683U=475U_2U_2=1.44UA proton has a charge , what gives it a charge?
Answer:
The charge is believed to be from the charge of the quarks that make up the nucleons (protons and neutrons). A proton is made of two Up quarks, with 2/3 positive charge each and one Down Quark with a negative 1/3 charge (2/3 + 2/3 + -1/3 = 1).
Explanation:
Hope this helps :)
10. As a pharmacy technician, you will receive prescription orders with many different abbreviations, which will require conversions to calculate the dose. Now that you have learned about conversions and abbreviations, what would you do to fill a prescription with abbreviations? Also, what would you do with conversions you were not sure how to convert to the required dose. Explain
When you receive prescriptions that contain some abbreviations, you have to translate it into plain language that the patient can understand.
Who is a pharmacy technician?A pharmacy technician is a skilled personnel who assists a pharmacist in a health facility. The pharmacy technician usually writes out prescriptions for patients.
When you receive prescriptions that contain some abbreviations, you have to translate it into plain language that the patient can understand. If you are not clear about the abbreviation you can ask the pharmacist for help or the doctor.
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is it second or first law
Answer:
In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration.
Explanation:
73. Integrated Concepts
An electron microscope produces electrons with a 2.00-pm wavelength. If these are passed through a 1.00-nm single slit, at what angle will the first diffraction minimum be found?
The angle will the first diffraction minimum be found will be 0.034895°.
What is diffraction grating?A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.
The equation of diffraction grating is given as
[tex]\rm d= \frac{m \lambda}{sin \theta }[/tex]
The angle between the incident ray and the point of the occurrence of the diffraction is found as;
[tex]\theta = sin^{-1}(\frac{m\lambda}{d} )\\\\\ \lambda= (2.0))(\frac{1.00 \times 10^{-12}}{1\ pm} )\\\\\ \lambda=2.00 \times 10^{-12}[/tex]
The angle will the first diffraction minimum be found is;
[tex]\theta = sin^{-1}(\frac{m\lambda}{d} )\\\\\ \theta = sin^{-1}(\frac{1 \times 2.000 \times 10^{-12}}{1\times 10^{-12}} )\\\\\ \theta= 0.0348995^0[/tex]
Hence,the angle will the first diffraction minimum be found will be 0.034895°.
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A triangular prism made of crown glass (n=1.52) with base angles of 30.0 is surrounded by air. If parallel rays are incident normally on its base as shown in fig., what is the angle of ϕ between the two emerging rays?
Answer:
es lo que es
Explanation:
es lo que es es que slep vaka vee
the angle ϕ= will be equal to angle of refraction and it is equal to 49.4°C.
What is refractive index ?When a light is going from medium 1 to medium 2. The refractive index is defined as a ratio of velocity of light in medium 1 to velocity of light in medium 2. Refractive index is the factor which deals with the amount of bending of light. More refractive index means more it will bend in the medium 2. When it is 1 we can say that light has not been bent.
By Snell's law, Refractive index is given by,
sin (i) ÷ sin (r) = μ₂÷μ₁
where i is the the angle of incidence
r is the angle of refraction
μ₂ & μ₁ are refractive index of medium 2 and 1 resp.
Hence it is due to Refractive index.
In this problem the light is going from prism to air, the refractive index of air is 1. From figure it is clear that the angle of incidence is 30°C.
From snell's law,
sin (30) ÷ sin (r) = μ₂÷1.52
0.5 ÷ sin (r) = 1÷1.52
0.5×1.52 = 1×sin (r)
0.76 = sin (r)
The angle of refraction r = sin⁻¹(0.76) =49.4°C
Hence angle ∅ = 49.4°C.
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Need help asap!!science foundations
A sound wave travelling through water has a wavelength of 0.08m and a frequency of 18525 HZ. What is the speed of the wave?
a. 343 m/s
b. 1482 m/s
c. 5941 m/s
Answer:
1482m/s
Explanation:
velocity equals frequency x lamdha
It is often said the media can make or break a person especially, sports personalities. Explain how that happens.
I'm going to school tomorrow so I can get the best of it
An object is being shot from a horizontal ground at an incline angle of 30 degree with respect to the ground at a speed of 52 m/s. Find the duration in seconds that the object is above the height of 14 m. Give your answer with one decimal place.
When an object is thrown at an angle from the horizontal, the path followed by the body is called the projectile motion. The duration in seconds that the object is above the height of 14 m is 4.698 s.
What is speed?Speed is the time rate at which velocity is changing.
Vertical speed component is
V₀y = 52sin 30°= 26 m/s
Given is the height h=14m
Using second equation of motion,
S=ut+ 1/2 at²
Substituting the values, we get
14 = 26t - 4.9t²
4.9t² - 26t +14 =0
Solving the quadratic equation, we get the time as
taking the positive sign, t =4.698 s
taking the negative sign , t = 0.6082 s
Thus, the duration in seconds that the object is above the height of 14 m is 4.698s.
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The expression of x=4t+2t^2 Where x is distance and t=time What is displecement ?
Answer:
x = 4 t + 2 t^2
the displacement is x which is zero at t = 0 and then increases indefinitely as t increases indefinitely
A 50.0-N bowling ball is held in a person’s hand with the forearm horizontal. The biceps muscle is attached 0.030 0 m from the joint, and the ball is 0.350 m from the joint. Find the upward force F exerted by the biceps on the forearm (the ulna) and the downward force R exerted by the humerus on the forearm, acting at the joint.
The upward force F exerted by the biceps on the forearm will be 583 N.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size of the body.
Force is defined as the product of mass and acceleration. Its unit is Newton.
The torque balancing equation is found as;
[tex]\rm \tau_i=\tau_R+\tau_F+\tau_{BB}=0\\\\ R(0)+F(0.0300)-(50.0)(0.350)\\\\ F=583 \ N[/tex]
Hence,the upward force F exerted by the biceps on the forearm will be 583 N.
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Find the charge on the capacitor in an LRC-series circuit at t = 0.03 s when L = 0.05 h, R = 6 Ω, C = 0.005 f, E(t) = 0 V, q(0) = 4 C, and i(0) = 0 A. (Round your answer to four decimal places.)
Determine the first time at which the charge on the capacitor is equal to zero. (Round your answer to four decimal places.)
The charge on the capacitor in an LRC-series circuit is 2.8907 C.
The first time at which the charge on the capacitor is equal to zero is 0.1409s.
What is capacitor?The capacitor consists of two parallel plates used to store the charge when current flows through it, and provides energy when shuts off.
By the Kirchoff's second law,
Lq'' +Lq' +q/C =E(t)
Where, L =0.05h, R = 6 Ω, C = 0.005 f, E(t) = 0 V, q(0) = 4 C, and i(0) = 0 A.
Equations becomes q''+120q' +4000 =0
The auxiliary equation is m² +120m+4000 =0
Solving this quadratic equation, we have
m =-6± 20i
Then , q(t) = Ae^(-60t)cos 20t + Be^(-60t)sin 20t where, A and B are constants.
At t=0, q(0) =7 =A
and q'(t) = A [ -20e^(-60t)sin 20t - 60e^(-60t)cos 20t ] +B [ 20e^(-60t)cos 20t - 60e^(-60t)sin 20t ]
So, i(0)= q'(0) =0 =-60A +20 B
Putting the value of A=7 above, we have B =21.
So, q(t) = 7e^(-60t)cos 20t + 21e^(-60t)sin 20t
The charge on the capacitor at time t =0.015
q(0.015) = 2.8907 C
Thus the charge on capacitor is 2.8907 C.
q(t) = 7e^(-60t)cos 20t + 21e^(-60t)sin 20t =0
Solve for t, we get
e^(-60t)cos 20t + 3e^(-60t)sin 20t\
-1/3 = sin 20t /cos20t
t =1/20 arctan(-1/3)
As, arctan is defined within -90 to +90,
So, 20t = -0.3218 +π =2.8197
t =0.1409s
Thus the first time at which the charge is zero is 0.1409s.
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How much work is done on the object as it moves from 6.0m to 9.0m
Answer:
W = 3F
Explanation:
Work is defined as the inner product between force and displacement. The inner product picks out the force components which point in the same direction as the displacement. The vertical components do not matter in the horizontal displacement. I am assuming you're dealing with 1-dimensional motion? Then the work would be:
[tex]W=Fd[/tex]
The displacement is 3 meters. Therefore, the work is:
[tex]W=3F[/tex]
You haven't gave the force being applied to the object, so I cannot give an explicit answer. Just multiply the force by 3 to get the work.
A certain FM radio station broadcasts electromag-
netic waves at a frequency of 60,050,000 Hz. These
waves travel at a velocity of 30,000,000 m/s. What is
the wavelength of these radio waves?
v = λ x f
λ = v/f f=v/λ
Answer:
0.5 m
Explanation:
To find wavelength (λ) : apply the formula
λ = wave speed (v) / frequency (f)Solving :
λ = 30,000,000 m/s / 60,050,000 Hzλ = 0.5 m (approximately)A sound travelling through some unknown medium has a wavelength of 0.05m and a frequency of 118,820 Hz. What is the speed of the wave?
a. 5941 m/s
b. 1482 m/s
c. 343 m/s
Answer:
5941m/s
Explanation:
velocity equals frequency x lamdha
Define the concept of heat. What is heat?
Answer:
In a simplest terms,
temperature is how hot or cold an object is, while heat is the energy that flows from a hotter object to cooler one
A spherical convex mirror has a radius of 30 cm. An object with a height of 0.30 m is placed 20 cm from the mirror. Note that in +/- sign conventions, f is negative (–) if the mirror is a convex mirror. a. Calculate the image distance. b. Calculate the image height. c. Calculate the magnification. d. Summarize the properties of the image formed in terms of its LOST (location, orientation, size, and type). e. Draw the set-up using graphical methods (ray diagramming). Apply scale drawing. Make sure that your illustration matches well with what you have calculated and presented in a-d.
a)A spherical convex mirror form the image at image distance is 8.57cm.
b) Mirror forms the image of height is 12.855 cm.
c)The magnification of the spherical convex lens is 0.4285.
What is convex mirror?The mirror which is a part of sphere with radius R is painted from inside forms the convex mirror.
The focal length of convex lens, f = R/2
Given , the radius of mirror is R =30cm, the focal length will be
f =30cm/2 = 15cm
a) Object distance u =20 cm, object height =0.30m, then the image distance will be 1/f = 1/u + 1/v where v is the image distance from the lens.
1/15 = 1/20 + 1/v
v= 8.57 cm
Thus, the image distance is 8.57cm.
b) Ratio of image distance to the object distance is equal to the ratio of image height to the object height.
Substitute the values into the expression, we get the image height as
h(image) = 8.57/20 x 30
h(image) = 12.855 cm
Thus, the image height is 12.855 cm.
c) The magnification is the ratio of image height to the object height.
Putting the values, we have
= 12.855/30
= 0.4285
Thus, the magnification is 0.4285.
d) Size of object is large as compared to the size of image. Object distance is small as compared to the image distance. The image formed is virtual.
e) The setup drawing is attached.
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a) First write down what you see in the picture.
Answer:
which picture please,I don't get you
