-Cesar the monkey observed the swinging behaviors of his parents. He is now able to swing from branch to branch after much practice. The observation of his parents swinging and practicing what he saw mainly involved _____ neurons; the neurons that are the basis of
Motor
Mirror
Sensory
Reticular

Answer:

24 km

Explanation:

9 + 9 + 6 = 24

Answer:

the conclusion is that the plant that had been given fertilizer B grew more than the plant with fertilizer A and the plant without fertilizer. so in conclusion fertilizer B is better for growing plants fastly.

the problem is that you noticed your tomatoes were not growing properly.

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Answer:

The work required is -515,872.5 J

Explanation:

Work is defined in physics as the force that is applied to a body to move it from one point to another.

The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.

Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:

[tex]Ec=\frac{1}{2} *m*v^{2}[/tex]

where kinetic energy is measured in Joules (J), mass in kilograms (kg), and velocity in meters per second (m/s).

The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:

[tex]W=\frac{1}{2} *m*v2^{2}-\frac{1}{2} *m*v1^{2}[/tex]

[tex]W=\frac{1}{2} *m*(v2^{2}-v1^{2})[/tex]

In this case:

Replacing:

[tex]W=\frac{1}{2} *2145 kg*((12\frac{m}{s} )^{2}-(25\frac{m}{s} )^{2})[/tex]

W= -515,872.5 J

The work required is -515,872.5 J

The amount of work needed by the vehicle to decrease its speed from 25 m/s to 12 m/s is 515872.5 J.

The amount of work required by the truck to decrease its speed can be calculated using the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The amount of work needed by the vehicle to decrease its speed from 25 m/s to 12 m/s is 515872.5 J.

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Answer:

A

Explanation:

Answer: B

Explanation: I got it right

Answer:

B is the correct answer

Explanation:

I just did this question

Answer:

The value is [tex]\mu  =0.4286[/tex]

Explanation:

From the question we are told that

   The mass of the steel cabinet is  [tex]m =  95 \  kg[/tex]

   The threshold angle is  [tex]\theta  =  23.2^o[/tex]

 Generally at the point just before the steel cabinet starts to slide

     The horizontal force on the steel cabinet is equal to the frictional  force that is

       [tex]F_f  =  F_h[/tex]

Here [tex]F_h[/tex] is the horizontal force which is mathematically represented as

       [tex]F_h  =  m * g cos (theta )[/tex]

and  [tex]F_f  =  \mu N[/tex]

Here N is the normal force acting on the steel cabinet and this is mathematically represented as

      [tex]N  =  mg sin (\theta )[/tex]

=>    [tex] m * g cos (theta )=  mg sin (\theta ) *  \mu  [/tex]

=>    [tex]\mu  = tan (\theta )[/tex]

=>    [tex]\mu  = tan (23.2)[/tex]

=>    [tex]\mu  =0.4286[/tex]

The coefficient of static friction between the bed of the truck and steel cabinet is 0.43.

The given parameters;

The coefficient of static friction between the bed of the truck and steel cabinet is calculated as follows;

[tex]\Sigma F = 0\\\\mg sin(\theta) - \mu mg cos(\theta) = 0\\\\\mu mg cos(\theta ) = mg sin(\theta)\\\\\mu cos(\theta) = sin(\theta)\\\\\mu = \frac{sin(\theta)}{cos(\theta)} \\\\\mu = tan (\theta)\\\\\mu = tan \ (23.2)\\\\\mu = 0.43[/tex]

Thus, the coefficient of static friction between the bed of the truck and steel cabinet is 0.43.

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Explanation:

wavelength=3.42m

velocity=330m/s

T=?

v=f×wavelength

f=330÷3.42

f=96.5Hz

T=1/f

=1/96.5

T=0.01s

Answer:

156 2/3 km/hr

Explanation:

Average speed is found by dividing total distance by total time.

180 km/hr in 2 hrs is 360 miles

200 km/hr in 4 hrs is 800 miles

120 km/hr in 6 hrs is 720 miles

Total time is 12 hrs; Total distance 1880 hrs

Divide distance by time and you have 156 2/3 km/hr. This is your average speed.

Answer:

symbolic solution for the coefficient of friction between the baby and the sled is  

   [tex] \mu  =  \frac{m + M_s}{m}  *  \frac{a}{g}[/tex]

Explanation:

From the question we are told that

   The  mass of the boy is  [tex]M_e  =[/tex]

   The  mass of the shed is  [tex]M_s[/tex]

    The mass of the baby is  [tex]m[/tex]

    The  maximum acceleration for the baby to stay is  a

Generally the frictional  force between the baby and the shed is mathematically represented as

     [tex]F_f  =  \mu  N[/tex]

Here  N is the normal force acting on the baby which is mathematically represented as

     [tex]N  =  m *  g[/tex]

=>   [tex]F_f  =  \mu *  m *  g[/tex]

Now for the baby not the slip off the shed the frictional  force between the baby and the shed must be equal to the the force applied by the child

The force applied by the child is mathematically represented as

    [tex]F  =  [M_s+m] * a[/tex]

So

     [tex] \mu *  m *  g  =  [M_s+m] * a[/tex]

=>    [tex] \mu  =  \frac{m + M_s}{m}  *  \frac{a}{g}[/tex]

Answer:

he needs more because he is doing more exercise this means he is working his body more and he needs more energy than someone he is sitting in an office. The computer operator would not need as much energy as the brick layer.

Answer:

The  motion of a transverse wave would be described as perpendicular to the wave direction.

Explanation:

The motion of a transverse wave is perpendicular to the wave propagation.

A transverse wave is an oscillating wave in physics that advances in the opposite direction of its oscillations. A longitudinal wave, on the other hand, moves in the direction of its oscillations. Transverse waves include water waves.

The waves that can be made on a horizontal length of string by anchoring one end and moving the other end up and down provide a straightforward example.  The waves that are produced on a drum's membrane serve as another illustration. Each point in the membrane moves up and down, perpendicular to the membrane plane, as the waves move in directions parallel to the membrane plane.

Another example of a transverse wave is light, which has electric and magnetic fields as oscillations.

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Answer:

mol

Explanation:

Answer:

Explanation:

Energy = [tex]6AT^4[/tex]

therefore,

[tex]\frac{E_1}{E_2} = \frac{T_1^4}{T_2^4}[/tex]

where [tex]E_2 = 2E_1[/tex]

therefore,

[tex]\frac{E_1}{2E_1} = \frac{(500+273)^4}{T_2^4}\\\\T_2 = 919.257k\\\\T_2 = 646.257^oC[/tex]

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Answer:

Explanation:

To find the force acting on an object given it's mass and acceleration we use the formula

From the question

mass = 0.314 kg

acceleration = 153 m/s²

We have

force = 0.314 × 153 = 48.042

We have the final answer as

Hope this helps you

Answer:

I believe whale fossils were found.

Answer:

through uv light

Answer:

acceleration is : 276 mi/s^2

(276 miles per second squared)

Explanation:

We use the formula for acceleration (a) which is the change in velocity divided by the time it took to change it:

a = (vf - vi) / t

where "vf" stands for final velocity, "vi" for initial velocity, and "t" for the time it took for the velocity to change.

In our case:

a = (69 - 0) / 0.25 = 276 mi/s^2

(276 miles per second squared)

Answer:

5.634004 × 10^7

Explanation:

the number 7 is for the numbers before the number 5

Answer:

(a) The ratio of the pressure amplitude of the waves is 43.21

(b) The ratio of the intensities of the waves is 0.000535

Explanation:

Given;

density of gas, [tex]\rho _g[/tex] = 2.27 kg/m³

density of liquid, [tex]\rho _l[/tex] = 972 kg/m³

speed of sound in gas, [tex]C_g[/tex] = 376 m/s

speed of sound in liquid, [tex]C_l[/tex] = 1640 m/s

The of the sound wave is given by;

[tex]I = \frac{P_o^2}{2 \rho C} \\\\P_o^2 = 2 \rho C I\\\\p_o = \sqrt{2 \rho CI}[/tex]

Where;

[tex]P_o[/tex] is the pressure amplitude

[tex]P_o_g= \sqrt{2 \rho _g C_gI} -------(1)\\\\P_o_l= \sqrt{2 \rho _l C_lI}---------(2)\\\\\frac{P_o_l}{P_o_g} = \frac{\sqrt{2 \rho _l C_lI}}{\sqrt{2 \rho _g C_gI}} \\\\\frac{P_o_l}{P_o_g} = \sqrt{\frac{2 \rho _l C_lI}{2 \rho _g C_gI} }\\\\ \frac{P_o_l}{P_o_g} = \sqrt{\frac{ \rho _l C_l}{ \rho _g C_g} }\\\\ \frac{P_o_l}{P_o_g} = \sqrt{\frac{ (972)( 1640)}{ (2.27)( 376)} }\\\\\frac{P_o_l}{P_o_g} = 43.21[/tex]

(b) when the pressure amplitudes are equal, the ratio of the intensities is given as;

[tex]I = \frac{P_o^2}{2 \rho C}\\\\I_g = \frac{P_o^2}{2 \rho _g C_g}-------(1)\\\\I_l = \frac{P_o^2}{2 \rho _l C_l}-------(2)\\\\\frac{I_l}{I_g} = (\frac{P_o^2}{2 \rho _l C_l})*(\frac{2\rho_gC_g}{P_o^2} )\\\\\frac{I_l}{I_g} = \frac{\rho _gC_g}{\rho_lC_l} \\\\\frac{I_l}{I_g} = \frac{(2.27)(376)}{(972)(1640)}\\\\ \frac{I_l}{I_g} = 0.000535[/tex]

Answer:

a = - 3 m/s^2 (negative 3 meters per second squared)

Explanation:

We use the formula for acceleration as the change in velocities (from initial velocity "vi" to final velocity "vf") divided the time "t" it took. In our case:

a = (vf - vi) / t = (0 - 10) / 3.3 = -10 /3.33 = -3 m/s^2

Answer:

Please see attached image

Explanation:

Answer:

Ok I might be wrong but I think its the screwdriver, screw, key and the fork

Explanation:

Why because they all have metal in them if am wrong am sorry buddy i was struggling on the same thing  

Answer:

a = 3.88 m/s^2  (3.88 meters per second squared)

Explanation:

The acceleration of the car can be obtained based of the change of velocities  (from initial velocity "vi" to final velocity "vf") in the given amount of time:

In our case:

a = (26.6 - 20) / 1.7 = 3.88 m/s^2

Answer:

Which most likely has the greatest conductivity?

a warm plastic rod

a cool rubber tube

a warm copper wire

Explanation:

The warm copper wire most likely has the greatest conductivity.

Conductivity is a measure of how easily a material can conduct electricity. Metals like copper are known for having high electrical conductivity due to the presence of free electrons that can move easily through the material when an electric field is applied.

Non-metallic materials like plastic and rubber generally have low electrical conductivity because they do not have free electrons available for conduction.

Additionally, the temperature of the material can also affect its conductivity. As temperature increases, the movement of atoms and molecules in the material also increases, which can cause a decrease in electrical conductivity.

Therefore, of the materials listed, the warm copper wire is most likely to have the greatest conductivity due to its metallic properties and elevated temperature.

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Answer:

The temperature of the low temperature thermal reservoir is 300 K.

Explanation:

All reversible power cycles are equivalent to the Carnot's cycle, whose equation for efficiency is:

[tex]\eta_{th} =1-\frac{T_{L}}{T_{H}}[/tex] (Eq. 1)

Where:

[tex]\eta_{th}[/tex] - Thermal efficiency, dimensionless.

[tex]T_{H}[/tex] - High temperature reservoir, measured in Kelvin.

[tex]T_{L}[/tex] - Low temperature reservoir, measured in Kelvin.

Now we proceed to clear the low temperature reservoir within:

[tex]\frac{T_{L}}{T_{H}} = 1-\eta_{th}[/tex]

[tex]T_{L} = (1-\eta_{th})\cdot T_{H}[/tex]

If [tex]\eta_{th} = 0.75[/tex] and [tex]T_{H} = 1200\,K[/tex], then:

[tex]T_{L} = (1-0.75)\cdot (1200\,K)[/tex]

[tex]T_{L} = 300\,K[/tex]

The temperature of the low temperature thermal reservoir is 300 K.

Answer:

a. their temperatures

Explanation:

Hello.

In this case, among the options:

a. their temperatures .

b. their internal energy contents .

c. their pressures .

d. whether they are in the solid, liquid, or gaseous state.

We must remember that the driving force assisting heat transfer is the temperature difference which states that the heat flows from higher temperatures to lower temperatures based on the second law of thermodynamics. Therefore answer is a. their temperatures .

Best regards.

Answer:

F₁ = 4.29 x 10⁵ N

Explanation:

The total force required to move the freight train with the given acceleration is given by the following formula:

F = ma + f

where,

F = Total Force Required from both engines = ?

m = equivalent mass of system = 2(8 x 10⁵ kg) + 5.5 x 10⁵ kg = 21.5 x 10⁵ kg

a = required acceleration = 5 x 10⁻² m/s²

f = force of friction = 7.5 x 10⁵ N

Therefore,

F = (21.5 x 10⁵ kg)(0.05 m/s²) + 7.5 x 10⁵ N

F = 8.575 x 10⁵ N

Now, for identical forces in each engine can be given as:

Force exerted by each engine = F₁ = F/2

F₁ = 8.575 x 10⁵ N/2

F₁ = 4.29 x 10⁵ N