can u pls help me with this question ​

Answer:

20 kg

Explanation:

From the question given above, the following data were obtained:

Volume (V) of substance = 2.50 L

Density (D) of substance = 8.00 g/mL

Mass (m) of substance =?

Next, we shall convert 2.50 L to millilitres (mL). This can be obtained as follow:

1 L = 1000 mL

Therefore,

2.50 L = 2.50 L × 1000 mL / 1 L

2.50 L = 2500 mL

Thus, 2.50 L is equivalent to 2500 mL.

Next, we shall determine the mass of the substance. This can be obtained as follow:

Volume (V) of substance = 2500 mL

Density (D) of substance = 8.00 g/mL

Mass (m) of substance =?

D = m / V

8 = m / 2500

Cross multiply

m = 8 × 2500

m = 20000 g

The mass of the substance is 20000 g.

Finally, we shall convert 20000 g to Kg

This can be obtained as follow:

1000 g = 1 kg

Therefore,

20000 g = 20000 g × 1 kg / 1000 g

20000 g = 20 kg

Therefore, the mass of the substance is 20 Kg

B. I think im probly wrong

Answer:

Explanation:

Let the protein contained in pizza be m gram .

calories contained by 17 g of fat = 17 x 9  kcals = 153  kcals .

calories contained by 25 g of carbohydrate = 25 x 4  kcals = 100 kcals .

calories contained by m  g of protein  = m  x 4  kcals = 4 m  kcals .

Total calories of slice of pizza = 153 + 100 + 4m kcals

= 253 + 4m kcals

Given ,

253 + 4m = 750

4m = 497

m = 124.25 g .

120 g ( rounded to two significant  figures )

Answer:

A

Explanation: Your answer is A true

Answer:

The hypothesis becomes a theory if the results support it is answer.

Explanation:

I hope it's helpful!

Viewed simply, electrons are arranged in shells around an atom's nucleus. Electrons closest to the nucleus will have the lowest energy. Electrons further away from the nucleus will have higher energy. ... In a more realistic model, electrons move in atomic orbitals, or subshells.

By definition:

The Electronic Configuration of the elements is the arrangement of all electrons of an element in energy levels and sub-levels (orbitals).  

There are 7 energy levels, numbered from 1 to 7, and in which electrons are distributed, logically in order according to their energy level. Electrons with less energy will be spinning at level 1.

Each level is divided into sub-levels. These sub-levels into which each level is divided can be up to 4. These 4 sub-levels are called: s, p, d, f.

In the sub-level s there can only be a maximum of 2 electrons, in sub-level p there can be a maximum of 6 electrons, in the sub-level d 10 electrons and finally in the sub-level f there can be a maximum of 14 electrons.

Aufbau's principle is a principle of atomic physics, which explains how electrons are accommodated in their orbits around the nucleus of the atom. This principle states that the filling of these orbitals occurs in increasing order of energy, that is, from the orbitals of lower energy to those of higher energy.

The simplest of the sub-levels is 1s. If you fill the 1s you can start filling the 2s. After the 2s sub-level is satisfied, the 2p can begin to fill and so on. The order is:  

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶7s²5f¹⁴6d¹⁰7p⁶

In this way, taking into account the atomic number Z of the element (which represents the number of protons of the element, and in a neutral atom it also indicates the number of electrons), the electrons that it has in the orbitals will be placed following the previously established.

For example, for hydrogen, whose atomic number is Z = 1, its electronic configuration would be: 1s¹.

Remember that the number 1 that precedes the representative letter of the orbital indicates the level of energy where the electron is located, the letter s indicates the type of orbital where the electron is located, and the exponent 1 indicates the number of electrons that are located in said orbital.

In summary:

Learn more:

Answer:

1.14kg of chalcopyrite

Explanation:

In 1 mole of chalcopyrite, CuFeS₂, there is 1 mole of Cu. Thus, to solve this question we need to convert the mass of pure Cu to moles using molar mass (Cu = 63.546g/mol). Then, the moles of Cu are equal to moles of chalcopyrite that must be converted to grams and then to kg (CuFeS₂: 183.54g/mol)

Moles Cu:

395g Cu * (1mol / 63.546g) = 6.216 moles Cu = 6.216 moles CuFeS₂

Mass chalcopyirite:

6.216 moles CuFeS₂ * (183.54g/mol) = 1140.9g

In kilograms:

1140.9g * (1kg / 1000g) =

you have to not let your past or your sad thoughts get the best of you.. that what I do i do get sad sometimes but dont let that get u down

Answer:

focus on whats ahead of u, not behind u ok?

Explanation:

hope this helps

Ivermectin is present at doses of 10 mg per mL, which is adequate to treat 110 lb (50 kg) of body weight (maximum 10 mL per injection site.).

Antiparasitic medication ivermectin is used. It was first used in veterinary medicine to prevent and treat heartworm and acariasis after being discovered in 1975.

A steroid is not ivermectin. Drugs called steroids behave similarly to cortisol and work to reduce edoema in the body. Prednisolone, betamethasone, and other typical steroids are listed below. Ivermectin, on the other hand, is an anthelmintic medication.

Barbiturates (such as phenobarbital and butalbital), benzodiazepines (such as clonazepam and lorazepam), sodium oxybate (GHB), and valproic acid are a few of the medications that may interact with this medication.

Thus, Ivermectin is present at doses of 10 mg per mL, which is adequate to treat 110 lb (50 kg) of body weight (maximum 10 mL per injection site.)

To learn more about Ivermectin, follow the link;

https://brainly.com/question/28524204

#SPJ2

Answer:

go to hellfhshahahahahahahahahaha  aha

Explahhhhahah

Answer:

[tex]0.75\ \text{mM}[/tex]

Explanation:

Concentration of [tex]HCO_3^-[/tex] = [tex][HCO_3^-]=7.5\ \text{mM}[/tex]

[tex]pK_a[/tex] for [tex]HCO_3^-[/tex] = 6.1

[tex]pH[/tex] of  blood = 7.1

The reaction is as follows

[tex]H_2CO_3+H_2O\rightarrow HCO_3^-+H_3O^+[/tex]

From the Henderson equation we get

[tex]pH=pK_a+\log\dfrac{[HCO_3^-]}{[H_2CO_3]}\\\Rightarrow 7.1=6.1+\log \dfrac{7.5}{[H_2CO_3]}\\\Rightarrow 1=\log\dfrac{7.5}{[H_2CO_3]}\\\Rightarrow 10^1=\dfrac{7.5}{[H_2CO_3]}\\\Rightarrow [H_2CO_3]=\dfrac{7.5}{10}\\\Rightarrow [H_2CO_3]=0.75\ \text{mM}[/tex]

[tex]CO_2(g)+H_2O(l)\rightarrow H_2CO_3(aq)[/tex]

Concentration of [tex]H_2CO_3[/tex], [tex][H_2CO_3]=[CO_2][/tex]

Concentration of [tex]CO_2[/tex], [tex][CO_2]=[H_2CO_3]=0.75\ \text{mM}[/tex].

Answer:

3 m/s2

Explanation:

i looked it up on quizizz and it showed 3 m/s2

Answer:

Explanation:

The nucleus of an atom is about 10-15 m in size; this means it is about 10-5 (or 1/100,000) of the size of the whole atom. ... (10-15 m is typical for the smaller nuclei; larger ones go up to about 10 times that.) Mass. Although it is very small, the nucleus is massive compared to the rest of the atom.

Answer:

The nucleus of an atom is about 10-15 m in size; this means it is about 10-5 (or 1/100,000) of the size of the whole atom. ... (10-15 m is typical for the smaller nuclei; larger ones go up to about 10 times that.) Mass. Although it is very small, the nucleus is massive compared to the rest of the atom.

Explanation:

Answer:

3843.96 × 10²³ atoms

Explanation:

Given data:

Mass of Li = 4430 g

Number of atoms = ?

Solution:

We will calculate the number of moles first.

Number of moles =mass/molar mass

Number of moles = 4430 g/ 6.94 g/mol

Number of moles = 638.32 mol

1 mole contain 6.022 × 10²³ atoms

638.32 mol × 6.022 × 10²³ atoms / 1 mol

3843.96 × 10²³ atoms

Answer:

1.09 × 10⁻⁷ m

UV region

Explanation:

Step 1: Given and required data

Energy of the photon of light (E): 1.83 × 10⁻¹⁸ J

Planck's constant (h): 6.63 × 10⁻³⁴ J.s

Speed of light (c): 3.00 × 10⁸ m/s

Step 2: Calculate the wavelength (λ) of this photon of light

We will use the Planck-Einstein's relation.

E = h × c/λ

λ = h × c/E

λ = 6.63 × 10⁻³⁴ J.s × (3.00 × 10⁸ m/s)/1.83 × 10⁻¹⁸ J = 1.09 × 10⁻⁷ m

This wavelenght falls in the UV region of the electromagnetic spectrum.

Answer:

I'm sorry I couldn't find it, I looked all over the internet

Answer:

Greek's Model used stars while Ptolemy did not use stars.

Explanation:

The Greek model had stars as part of the system and they revolved around the Earth. Ptolemy's model did not include the stars, but it did include the moons that revolves around the planets.

Answer:

1st order

Explanation:

because magnesium has a coefficient of 1, it is first order

hydrochloric acid has a coefficient of 2, so it is second order

overall the reaction is third order (1+2)

Answer:

Molecular formulas describe the exact number and type of atoms in a single molecule of a compound. The constituent elements are represented by their chemical symbols, and the number of atoms of each element present in each molecule is shown as a subscript following that element's symbol.

Explanation:

hope this helped !

Answer:

[tex]velocity = \frac{displacement}{time} \\ v = \frac{3000}{4.5} \\ v = 666.67 \: miles \: per \: hour \\ or \\ v = 666 \frac{2}{3} \: miles \: per \: hour[/tex]

Answer:

The correct option is a

Explanation:

First ionization energy is the minimum amount of energy required to remove the most loosely bound electron (valence electron) from the outermost shell of a gaseous or neutral atom. Since it takes more amount of energy to remove more electrons, it (ionization energy) generally increases across the period and decreases down a group because the closer the outermost shell is to the nucleus, the more difficult/energy required to remove electrons in that shell.

Since magnesium and phosphorus are on the same period (period 3), it can be deduced from the explanation above that phosphorus has a greater first ionization energy than magnesium because phosphorus (5 valence electrons) has more electrons in it's outermost shell than magnesium (2 valence electrons).

Answer:

The tension in the string is 78.73 N.

Explanation:

The tension in the string can be determined from the expression;

v = [tex]\sqrt{\frac{T}{m} }[/tex]

where: v is the speed of the wave in the sting, T is the tension in the string and m is the mass per unit length of the sting.

Given that: v = 16.2 m/s, and m = 0.3 kg/m.

Then;

16.2 = [tex]\sqrt{\frac{T}{0.3} }[/tex]

Square both sides to have,

[tex](16.2)^{2}[/tex] = [tex]\frac{T}{0.3}[/tex]

T = [tex](16.2)^{2}[/tex] x 0.3

  = 252.44 x 0.3

  = 78.732

T = 78.732 N

The tension in the string is 78.73 N.

Answer: Sound waves

The wave pattern that i observed in sound waves are longitudinal wave patterns.

The mathematical graph function looks like is a sine function graph. The pattern that i observed in the amplitude of the wave is longitudinal wave pattern

When you increase the frequency of the sound waves the wave moves faster but the wavelength becomes shorter. The higher the frequency results in higher the pitch of the sound.

If you increase the frequency the velocity of the sound wave remains constant for all valuses of frequencies.

i am currently completing this assigment. i am not usre if the answer are correct but i tried my best  

I also got this from course hero it's your choise to put the one you want.

The wave pattern is identical to the pattern of the water. The graph is the same as the water except the wave height isn’t as big. Increasing the frequency increases the wavelength. Increasing the frequency also increases the velocity of the waves by a lot. With two sources the waves pass through each other. The wave pattern with a single slit barrier is the same as the water pattern.

Explanation:

Answer: Sound waves

The wave pattern that i observed in sound waves are longitudinal wave patterns.

The mathematical graph function looks like is a sine function graph. The pattern that i observed in the amplitude of the wave is longitudinal wave pattern

When you increase the frequency of the sound waves the wave moves faster but the wavelength becomes shorter. The higher the frequency results in higher the pitch of the sound.

If you increase the frequency the velocity of the sound wave remains constant for all valuses of frequencies.

i am currently completing this assigment. i am not usre if the answer are correct but i tried my best  

I also got this from course hero it's your choise to put the one you want.

The wave pattern is identical to the pattern of the water. The graph is the same as the water except the wave height isn’t as big. Increasing the frequency increases the wavelength. Increasing the frequency also increases the velocity of the waves by a lot. With two sources the waves pass through each other. The wave pattern with a single slit barrier is the same as the water pattern.

Explanation:

Answer:

Explanation:

Many tests to distinguish aldehydes and ketones involve the addition of an oxidant. Only aldehydes can be easily oxidized because there is a hydrogen atom next to the carbonyl and oxidation does not require oxygen

Answer:

1 sulfur

Explanation:

1 mole is equal to 1 moles Sulfur, or 32.065 grams

Answer:

[tex]\boxed {\boxed {\sf 1.24727159 \ moles \ of \ sulfur }}[/tex]

Explanation:

To convert from grams to moles, we must use the molar mass found on the Periodic Table of Elements.

1. Molar Mass

This is a sample of sulfur, so look for S on the table.

2. Convert from Grams to Moles

Use the molar mass as a ratio.

[tex]\frac { 32.07 \ g \ S}{ 1 \ mol \ S }[/tex]

Multiply by the given number of grams: 40

[tex]40 \ g \ S * \frac { 32.07 \ g \ S}{ 1 \ mol \ S }[/tex]

Flip the fraction so the grams of sulfur will cancel each other out.

[tex]40 \ g \ S * \frac {1 \ mol \ S }{ 32.07 \ g \ S}=40* \frac {1 \ mol \ S }{ 32.07 }[/tex]

[tex]\frac {40 \ mol \ S } { 32.07 } = 1.24727159 \ mol \ S[/tex]

There are 1.24727159 moles of sulfur.

Answer:

yes; and because of how roughly they are played.

Explanation: