Can anybody help me with these three problems thank you

Answer:

One Solution

Step-by-step explanation:

x + 3y = 3      

x - y = -3        

4y = 6           Subtract to solve by elimination.

y = [tex]\frac{3}{2}[/tex]              Divide by 4.

x - [tex]\frac{3}{2}[/tex]  = -3      Substitute [tex]\frac{3}{2}[/tex] for y in the original equation.

x = -[tex]\frac{3}{2}[/tex]            Add [tex]\frac{3}{2}[/tex].

Answer:

Ig 200 miles

Step-by-step explanation:

I am guessing

Answer:

Ms G ran 3/25 mile per minute

Mr H ran 1/5 mile per minute

Step-by-step explanation:

Ms G:

create a proportion from mile/minutes = mile/minutes

let 'm' = amount of miles

3/5÷5 = m÷1

cross-multiply to get:

3/5 = 5m

m = 3/5 × 1/5 = 3/25

Mr H:

3/5÷3 = m÷1

cross-multiply to get:

3/5 = 3m

15m = 3

m = 3/15 or 1/5

Answer:

-1/3 or 1/-3 (it doesn't matter which one you pick because its still the same)

Step-by-step explanation:

You find slope by doing rise over run. Its left to right so you start on the left dot and go down one. This makes it -1 because you're going down, not up. You move 3 to the right which makes it positive. Once you do this itll lead you right the the 2nd point. 1 down= -1

                                       3 right=   3  

                                                -1/3

Answer:



h

=

3

r

=

4



h

=

2

r

=

6



h

=

4

l

=

4

w

=

4

Step-by-step explanation:

Answer:

[tex]\frac{d\theta}{dt}=-\frac{2}{5}[/tex] at [tex]x=12[/tex]

Step-by-step explanation:

[tex]\frac{dx}{dt}=2[/tex]

[tex]\frac{d\theta}{dt}=?[/tex]

[tex]x=12[/tex]

[tex]cos(\theta)=\frac{adjacent}{hypotenuse}[/tex]

[tex]cos(\theta)=\frac{x}{13}[/tex]

[tex]\frac{d}{dt}cos(\theta)=\frac{d}{dt}\frac{x}{13}[/tex]

[tex]-sin(\theta)\frac{d\theta}{dt}=\frac{1}{13}\frac{dx}{dt}[/tex]

[tex]-sin(\theta)\frac{d\theta}{dt}=\frac{1}{13}(2)[/tex]

[tex]-sin(\theta)\frac{d\theta}{dt}=\frac{2}{13}[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-13sin(\theta)}[/tex]

[tex]cos(\theta)=\frac{x}{13}[/tex]

[tex]cos(\theta)=\frac{12}{13}[/tex]

[tex]\theta=cos^{-1}(\frac{12}{13})[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-13sin(\theta)}[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-13sin(cos^{-1}(\frac{12}{13}))}[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-13(\frac{5}{13})}[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-5}[/tex]

[tex]\frac{d\theta}{dt}=-\frac{2}{5}[/tex]

The value of θ is given by the inverse sine function, from which the rate of

change of θ with respect to x can be derived.

Reasons:

[tex]\displaystyle \frac{dx}{dt} = \mathbf{2 \ units \ per \ second}[/tex]

[tex]\displaystyle cos(\theta) = \frac{x}{13}[/tex]

[tex]\displaystyle \theta = arccos \left(\frac{x}{13}\right)[/tex]

[tex]\displaystyle \frac{d}{dx} \theta = \frac{d\left(arccos \left(\frac{x}{13}\right)\right)}{dx} = \mathbf{\frac{\sqrt{169-x^2} }{x^2-169}}[/tex]

Using chain rule of differentiation, we have;

[tex]\displaystyle \frac{d\theta}{dt} = \mathbf{ \frac{d\theta}{dx} \times \frac{dx}{dt}}[/tex]

Therefore;

[tex]\displaystyle \frac{d\theta}{dt} =\frac{\sqrt{169-x^2} }{x^2-169}\times \frac{dx}{dt} = \mathbf{\frac{\sqrt{169-x^2} }{x^2-169}\times 2}[/tex]

When x = 12, we get;

[tex]\displaystyle \frac{d\theta}{dt} =\frac{\sqrt{169-12^2} }{12^2-169}\times 2 = -\frac{2}{5} = -0.4[/tex]

The rate of change of the angle, θ, with time at the instant when x = 12 is -0.4 rad/s

Learn more about rate of change here:

https://brainly.com/question/24686935

Answer:

88% decrease

Step-by-step explanation:

3 is only 12% of 25 so there was a 88% decrease

Answer:

The formula of the nth term is a₇=48(1/2)⁷⁻¹=48×1/64=3/4

Step-by-step explanation:

Answer:

[tex]x=\frac{3b}{2} +\frac{5a}{2}[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

5(x - a) = 3(x + b)

5x - 5a = 3x + 3b

      2x = 5a + 3b

        x = 2.5a + 1.5b

Step-by-step explanation:

sum was the first name of integral

and the median is something in the middle

for example :

A . B . C

the median is B

Answer:

The answer is 90.

Step-by-step explanation:

90 is in the middle

Answer:

d

Step-by-step explanation:

cause i said so

[tex]-5x -16 = 8x -1\\\\\implies 8x +5x = -16 +1 \\\\\implies 13x = -15\\\\\implies x = -\dfrac{15}{13}[/tex]

Hey there!

(3)(4)(-3.5)

= 12(-3.5)

= -42

Therefore, your answer SHOULD be: -42

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

I am not exactly sure of the answer, i am just trying to help

I think the angle O is 135

The triangle BOC is a right angle triangle which means that O is 90 degrees so when K splits it in half it becomes 45 degrees in both BOK and COK. The triangle you are asked to find the angle of is AOK so the 45 degrees from the BOK triangle and add it to the the 90 degrees from the BOA triangle you will get 135 degrees for the angle O in the triangle AOK.

I dont know if you understan what i am trying to say

Answer:

First, let's look at some polynomials of even degree (specifically, quadratics in the first row of pictures, and quartics in the second row) with positive and negative leading coefficients:❤

Answer:

C

Step-by-step explanation:

standard form is ax + by = c, which is true for the third option.

The exponential equation is given by y = 700(2)ˣ

An exponential function is given by:

y = abˣ

where y, x are variables, a is the initial value of y and b is the multiplier.

Let y represent the population of fish after x hours.

Given that he starts with 700 fishes, hence

a = 700

The population of the fish doubles every year, hence:

b = 2

The exponential equation becomes:

y = 700(2)ˣ

Find out more at: https://brainly.com/question/12490064

Answer:

61 m²

Step-by-step explanation:

Find the area of the whole rectangle and subtract the part that is cut off

Area =  [tex]11 *8 - 9 *(8-5)[/tex]

        = [tex]88 - 9*3[/tex]

        = [tex]88 - 27[/tex]

        = [tex]61[/tex]

Units = m * m or m²

61 m²

-Chetan K

Answer:

F= ma

m = F/a

m = 50/2

m = 25

Answer equal 25

The statement, The hypotenuse is NOT located across from the right angle is false.

A right-angled triangle is a type of triangle that has an angle that measures 90 degrees. The triangle has three sides. The hypotenuse is the longest side of a right-angled triangle. Other sides are the base and the length. The sum of sides in a a right-angled triangle is 180 degrees.

Please find attached an image of a right-angled triangle. To learn more about  a triangle, please check: https://brainly.com/question/9329354

Answer:

Its ethier a switch or magnet

Answer:

Answer below

Step-by-step explanation:

Time can not be negative from any perspective. Hence, the correct answer is 10.16 seconds.

The equation of the path of a rocket is given that is  y= x^2 + 153x + 98

We need to determine the time that the rocket will hit the ground.

Now, if the rocket hits the ground after the launching then the overall displacement at the time of hitting the ground will be zero.

Therefore, the value of y is 0.

Thus,  -16x^2 +153x + 98 = 0

Now, the formula for finding the roots of the quadratic equation  

 ax^2 +bx +c = 0 is given as:

 [tex]x^{1} =\frac{-b+\sqrt{b^2 -4ac} }{2a}[/tex]

[tex]x^2 = \frac{-b -\sqrt{b^2 -4ac} }{2a}[/tex]

Comparing the expression with the standard form of the equation.

a = -16b = 153 and c = 98

By applying the formula there are two values are come that is,

x^1 = -0.602555

x^2 = 10.1651  

Time can not be negative from any perspective.

Hence, the correct answer is 10.16 seconds.

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(Hope this helps can I pls have brainlist (crown)☺️)

you search the LCD then you subtracted the top and left the bottom the same

Step-by-step explanation:

im not sure

The amount by which the length and width of a shed can be increased to

more than double the area, depends on the initial dimensions.

Reasons:

The given parameters of the shed are;

The length of the shed = 12 m

Width of the shed = 5 m

The amount by which the length and the width are increased = The same amount

The new area after the increase in the length and width of the shed = More than double the initial area

Required:

The amount of increase in the length.

Solution:

Let the amount by which the length and width are increased = x

We have;

Initial area of the shed = 12 m × 5 m = 60 m²

The new area = (12 + x) × (5 + x) > 2 × 60

By multiplication, we get;

(12 + x) × (5 + x) = x² + 17·x + 60 > 2 × 60 = 120

x² + 17·x + 60 - 120 > 120 - 120 = 0

x² + 17·x - 60 > 0

By factorization, we get;

(x + 20)·(x - 3) > 0

x > -20, or x > 3

The increase (positive) amount of the solution is x > 3

Therefore, the amount by which both the length and the width can be increased to more than double the area is x > 3 meters

Learn more about the area of a rectangle here:

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Answer:

11/3 = 3 2/3 innings

Step-by-step explanation:

3 pitchers = 11 innings

1 pitcher = x innings

in the first equation, divide both sides by 3 to get 1 pitcher on one side

1 pitcher = 11/3 innings = 3 2/3 innings

Answer:

8/15

Step-by-step explanation:

1/5 + 1/3 = 3/15 + 5/15 = 8/15