BRAINLIEST
1. What does the percent difference between GPE and KE tell you about the efficiency of energy transformations in this experiment?
2. Use a computer or graphing calculator to graph the percent difference in data table 1 versus mass, and the percent difference in data table 2 versus change in height (Δh). Based on your results that you see plotted for the two rounds of experiments, how would you adjust the mass and height so that the design of the system leads to GPE and KE values that are as close as possible? Explain why you think this design would achieve the desired result.
btw are my datas in the graph right? i added the gpe ke and %diff
Answers
The percent difference between GPE and KE in the experiment illustrates that the higher the percentage, the more efficient the energy transfer.
What is energy transformation?It should be noted that energy transformation simply means the process of changing energy from one form to another form.
In this case, the percent difference between GPE and KE in the experiment illustrates that the higher the percentage, the more efficient the energy transfer.
Also, the mass and height should be adjusted in such a way that the design of the system leads to GPE and KE values that are as close as possible.
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The experiment's percent difference between GPE and KE shows that the efficiency of energy transfer increases with percentage.
Thus, It should be emphasized that the term "energy transformation" simply refers to the act of altering energy's form.
The experiment's percent difference between GPE and KE in this instance demonstrates that the more significant the percentage, the more effectively energy is transferred.
The experiment's percent difference between GPE and KE in this instance demonstrates that the more significant the percentage, the more effectively energy is transferred.
Thus, Energy is capable of changing its forms. For instance, your body stores chemical energy from the food you eat until you can use it as kinetic energy when working or playing.
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Related Questions
Loosing weight without diet require moving to the top of a mountain explain using weight and gravitational force
Answers
Answer:
You would weigh very slightly more at sea level than at the top of a mountain, not enough for you to notice, but a measurable amount. Weight, which really means gravitational force, is proportional to the product of the masses of two objects acting on each other, in this case the giant earth and the minuscule you.
Explanation:
Can someone help with this
Answers
Hi there!
A.
We can use the work-energy theorem to solve.
Initially, both blocks have gravitational potential energy, which is then converted to kinetic energy.
Recall:
[tex]U = mgh \\[/tex]
U = Potential Energy (J)
m = mass (kg)
g = acceleration due to gravity (m/s²)
h = height (m)
And at the end, block 2 has both kinetic and potential energy. Kinetic is defined as:
[tex]KE = \frac{1}{2}mv^2[/tex]
v = velocity (m/s)
We can do a summation of initial and final forces.
Initial:
[tex]E_i = m_2g\frac{h}{2} + m_1gh[/tex]
Final:
[tex]E_f = \frac{1}{2}m_2 v^2 + m_2g\frac{3h}{2} + \frac{1}{2}m_1 v^2[/tex]
Set the two equal (no energy loss in this situation) and solve for velocity.
[tex]m_2g\frac{h}{2} + m_1gh = \frac{1}{2}m_2 v^2 + m_2g\frac{3h}{2} + \frac{1}{2}m_1 v^2\\\\m_2g\frac{h}{2} + m_1gh - m_2g\frac{3h}{2} = \frac{1}{2}m_2 v^2 + \frac{1}{2}m_1 v^2\\\\v^2 = \frac{gh(\frac{m_2}{2} + m_1 - \frac{3m_2}{2})}{\frac{1}{2}m_2 + \frac{1}{2}m_1}\\\\v = \sqrt{\frac{gh(\frac{m_2}{2} + m_1 - \frac{3m_2}{2})}{\frac{1}{2}m_2 + \frac{1}{2}m_1}}\\\\v = \boxed{3.704 \frac{m}{s}}[/tex]
**This can be solved in a simpler way using a summation of forces.
B.
Now, we can do a summation of forces to solve. First, we must solve for the acceleration of the system now that we have found the velocity. Use the kinematic equation:
[tex]v_f^2 = v_i^2 + 2ad[/tex]
Initial velocity is 0 m/s, so:
[tex]v_f^2 = 2ad\\\\a = \frac{v_f^2}{2d} = \frac{(3.704^2)}{2(2.10)} = 3.267 \frac{m}{s^2}[/tex]
Now, we can use a summation of forces for any block. We can do block 1:
[tex]\Sigma F = m_1g - T[/tex]
Using Newton's Second Law:
[tex]m_1a = m_1g - T\\\\T = m_1g - m_1a \\T = m_1 (g - a) = 4.10(9.8 - 3.267) = \boxed{26.828 N}[/tex]
Conceptual Example 14 provides useful background for this problem. A playground carousel is free to rotate about its center on frictionless bearings, and air resistance is negligible. The carousel itself (without riders) has a moment of inertia of 105 kg·m2. When one person is standing at a distance of 1.57 m from the center, the carousel has an angular velocity of 0.512 rad/s. However, as this person moves inward to a point located 0.507 m from the center, the angular velocity increases to 0.795 rad/s. What is the person's mass?
Answers
For one person standing at a distance of 1.57 m from the center, the carousel has an angular velocity of 0.512 rad/s, the person's mass is mathematically given as
m = 24.2 kg
What is the person's mass?Generally, the equation for the conservation angular momentum is mathematically given as
(I + m * r0^2) * w0 = (I + m * r^2) * w^2
Therefore
(105 + m * 1.78^2) * 0.517 = (105 + m * 0.524^2) * 0.841
m = 24.2 kg
In conclusion, the mass
m = 24.2 kg
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[tex]Question: $x_{1}=\frac{5}{2}[\sin (2 \pi t)+\cos (2 \pi t)], x_{2}=5\left[\sin \left(2 \pi t+\frac{\pi}{4}\right)\right]$[/tex]
Find the ratio of the amplitude of the given motion?
Options:
[tex](a) $\sqrt{2}: 1$\\(b) $2: 1$\\(c) $1: \sqrt{2}$\\(d) $1: 2$[/tex]
Answers
Condense x₁ to get
sin(2πt) + cos(2πt) = √2 • (sin(2πt) + cos(2πt))/√2
… = √2 (cos(2πt) cos(π/4) + sin(2πt) sin(π/4))
… = √2 cos(2πt - π/4)
So the amplitude of x₁ is (5/2) • √2 = 5/√2, while the amplitude of x₂ is 5. The ratio between them is then 5/√2 : 5, or equivalently 1/√2 : 1 or 1 : √2.
The sound intensity at a distance of 19 m from a noisy generator is measured to be 0.24 W/m2. What is the sound intensity at a distance of 27 m from the generator
Answers
Answer:
0.1111 W/m²
Explanation:
If all other parameters are constant, sound intensity is inversely proportional to the square of the distance of the sound. That is,
I ∝ (1/r²)
I = k/r²
Since k can be the constant of proportionality. k = Ir²
We can write this relation as
I₁ × r₁² = I₂ × r₂²
I₁ = 0.25 W/m²
r₁ = 16 m
I₂ = ?
r₂ = 24 m
0.25 × 16² = I₂ × 24²
I₂ = (0.25 × 16²)/24²
I₂ = 0.1111 W/m²
Match the missions with their objectives.
NEAR
Lunar Prospector
Deep Impact
SETI
mapping the Moon's surface composition,
looking for possible deposits of polar ice,
and examining the Moon's resources,
structure, and origins
first space probe to orbit and perform
an in-depth Investigation of an asteroid
searching for extraterrestrial life in the universe
probing beneath the surface of a comet to
obtain clues about its internal composition
and structure
Answers
Matching the missions with their objectives
NEAR -------> First space probe to orbit and perform an in-depth Investigation of an asteroid. Lunar prospector ----- > mapping the Moon's surface composition,looking for possible deposits of polar ice,and examining the Moon's resources,structure, and origins.Deep Impact -------> probing beneath the surface of a comet to obtain clues about its internal composition and structureSETI -----> searching for extraterrestrial life in the universeThe Mission OverviewThe NEAR ( Near Earth Asteroid Rendezvous ) is a mission whose objective is to study origin and nature of objects near the earth such as asteroids and comets.
Lunar prospector was a mission designed to perform an orbit investigation of the moon.
The deep impact mission created by NASA was to probe beneath the comet and discover the structure and composition. The deep impact projected lasted for 9 years in space.
Hence we can conclude that the missions and their objectives are as listed above.
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If a snowboarder’s initial speed is 4 m/s and comes to rest when making it to the upper level. With a slightly greater initial speed of 5 m/s, the snowboarder is moving to the right on the upper level. His final speed in this case is 3 m/s. Suppose this situation is repeated on planet Epsilon, where gravity is less than gravity on earth.
A. Would the height of the hill on Epsilon cause a reduction in speed from 4 m/s to 0 greater than, less than, or equal to the height of the corresponding hill on earth? Explain.
B. Consider the hill on Epsilon discussed in part A. If the initial speed at the bottom of the hill is 5 m/s, will the final speed at the top of the hill be greater than, less than, or equal to 3 m/s? Explain.
Answers
(a) At a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).
(b) If the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.
Conservation of mechanical energy
The effect of height and gravity on speed on the given planet Epislon is determined by applying the principle of conservation of mechanical energy as shown below;
ΔK.E = ΔP.E
¹/₂m(v²- u²) = mg(hi - hf)
¹/₂(v²- u²) = g(0 - hf)
v² - u² = -2ghf
v² = u² - 2ghf
where;
v is the final velocity at upper levelu is the initial velocityhf is final heightg is acceleration due to gravitywhen u² = 2gh, then v² = 0,
when gravity reduces, u² > 2gh, and v² > 0
Thus, at a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).
Final speedv² = u² - 2ghf
where;
u is the initial speed = 5 m/sg is acceleration due to gravity and its less than 9.8 m/s²v is final speedhf is equal heightSince g on Epislon is less than 9.8 m/s² of Earth;
5² - 2ghf > 3 m/s
Thus, if the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.
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The two basic properties of all matter are ______ and ______.
options for first blank
a. length B. volume
options for second blank
a. density B. mass
Answers
Answer:
volume , mass
Explanation:
the 3 basic properties of a matter is volume, mass and shape.
6. A spring is originally 1.5 m long. It is stretched so that it is 1.8 m long. The spring constant is 50 N/m.
Find the potential energy stored in the spring.
Answers
Answer:
PE = 1/2 K X^2
K = 50 N/m
X = .3 m
PE = 1/2 * 50 * .3^2 = 2.25 Joules
list down the general of the office of guardian and tutor
Answers
Answer:
legal guardians, the four types: personal guardians, financial guardians, conservators, and pet “guardians”
What is the centripetal acceleration of 30 kg child standing 5 meters from the center of a
rotating carousel? The carousel is rotating at a linear velocity of 20 m/s.
Answers
Answer:
80m/s2
Explanation:
m=30kg. r = 5meter v = 20m/s2 a= ? centripetal acceleration = v*v/r
20*20/5=80m/s2
centripetal acceleration=80 m/s2
For the statements based on whether they are described as outcomes of results from thermal energy being added or removed particles move faster particles move slower temperature increases temperature decreases kinetic energy increases kinetic energy decreases thermal energy added thermal energy removed
Answers
Thermal energy removed: particles move slower, temperature decreases, kinetic energy decreases
the dimensions of a cuboidal block are 2.5 m * 2m * 1.2m its weight 900 n what is the minimum presseure exerted by the block on the surface of its support.?
Answers
Answer:
your answer is here 180
Explanation:
900/2.5 * 2 = 180
Answer:
The answer is 180 Pa.
Explanation:
Given;Here, weight = thrust = 900 N,
dimensions are 2.5 m × 2 m × 1.2 m
To Find;Pressure exerted by the block on the surface of its support.Formula;Pressure = Thrust ÷ AreaWe know that, Pressure is inversely proportional to area. For the minimum pressure the area must be more.
So, if the block is resting with 2.5 m × 2 m surface on the support, the pressure will be minimum.
Pressure = 900 N ÷ 2.5 × 2.0 m² = 180 Pa
Thus, The pressure exerted by the block on the support is 180 Pa.
1) How many joules of heat are required to raise the temperature of 550 g of water from
12.7 °C to 28.8°C ? Specific heat of liquid water is 4.184 J/g °C.
Answers
Answer:
Explanation:
You can use [tex]Q = mc\Delta T=(550)(4.184)(28.8-12.7)=37049.32[/tex] joule.
Year
Carbon Dioxide (CO2) in Atmosphere (ppm*)
2010
2011
Copyright © Enginuity Inc.
Copyright © Enginuity Inc.
Global Temperature Change – Student Guide
2012
2013
2014
2015
2016
2017
Answers
Answer:
Theres a diagram missing for Q
Explanation:
What is all this?
Could you add a question so I can answer it :)
1. A person walks 20 meters toward the east and then walks 30 meters toward the west. What is the total distance covered? What is the displacement? with explaination
2. What is the average speed of a car that travels 2000 meters in 5 minutes in meters/second? with explaination
Answers
Answer:
1.) 30 m is the total distance covered 10m is the displacement you
2.)24,000m/h (24km/h or 6.67m/s) Average speed is calculated by dividing the total distance that something has traveled by the total amount of time it took it to travel that distance
Explanation:
A DJ is setting up their equipment and measures the sound level near a speaker to be 55.65dB. They decide to add two more speakers next to the first. What would they measure the new sound level to be?
Answers
For a DJ is setting up their equipment and measures the sound level near a speaker to be 55.65dB, the new sound level is mathematically given as
L=50.470dB
What would they measure the new sound level to be?Generally, the equation for the sound level is mathematically given as
l=10logl/io
Therefore
logl/io=5.57
Hence
I=3.715*10^−8
In conclusion
L'=10log(3*3.715*10^−8)/10^{-12}
L=50.470dB
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is this right lol i think it is but im not so sure XD
Answers
[tex]\bold{Heya!}[/tex]
Yup. your answer is correct!
→ EXPLANATION :-1. just put the numbers in order [tex]^1^6^, ^1^8^,^2^3^,^2^4^,^2^9^,^3^0[/tex]2. Cross off high/low pairs, we left with the numbers :-[tex]23,24.[/tex]
3. Add the leftover numbers.[tex]23 \: + 24 = 47.[/tex]
Divide the sum of 2.[tex]\frac{47}{2} = 23.5[/tex]
Hopefully This Helps ! ~
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[tex]\underline{Answer :}[/tex]
Jaceysan ~
Answer:
GIVE HIM BRAINLEST
What is the cycle of a breaststroke?
Answers
Answer:
Breaststroke can be divided up into 4 distinct phases, which consists of the out sweep, in sweep, breathing phase, and lunge, extension, or recovery phase.
Explanation:
pa follow po
Spring
The pulling force acting on an object is 350.0 N. It also is being affected by a 50.0 N
kinetic friction force. As a result, its acceleration is 3.0 m/s?, what is its mass?
A. 67 kg
B. 83 kg
C. 100 kg
D. 600 kg
E. 0.0 kg
If the gravitational force of the Farth nulling you"down" in th
Answers
Answer:
100 kg
Explanation:
Net force = 350 - 50 = 300 N
F= ma
300 N = m * 3 m/s^2
100 kg = mass
Consider the two-slit interference experiment. Electromagnetic radiation passes through the two slits that are a distance of 0.0170 nm apart. A fourth-order bright fringe forms at an angle of 8.0 degrees relative to the incident beam. What is the wavelength of the light? (1 point)
O 581 nm
O 420 nm
O 789 nm
O 591 nm
Answers
Answer:
The answer is 581
Explanation:
I just took the Quick Check and got it right.
If a→=3i^-2j^-k^ and b→=i^+4j^+k^, find a unit vector n^ normal to the plane containing a→ and b→ such that a→, b→ and n^, in this order, form a right-handed system.
Answers
The unit vector normal to the plane is ; n = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]
Given data :
The unit vectors
a→=3i^-2j^-k^ and b→=i^+4j^+k^
Determine the unit vector normal to the planeThe unit vector normal to the plane is calculated as
n = [tex]\frac{a*b}{|b*b|}[/tex] ---- ( 1 )
where ; a→ * b→ = 2i - 4j + 14k and |b * b| = [tex]\sqrt{216}[/tex]
back to equation ( 1 )
n = ( 2i - 4j + 14k ) / [tex]\sqrt{216}[/tex]
= [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]
Hence we can conclude that The unit vector normal to the plane is ; n = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]
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The measured value of mass M in an experiment is M = 0.743 ± 0.005kg. The error in 2M is
Select one:
dM
3dM
2.5 dM
2dM
Answers
Given the measured value of mass M in the experiment the error in 2M is ; dM
Given data :
Measured value of mass M = ( 0.743 ± 0.005 ) kg
The error in 2M in the measured valueThe error in 2M in the measured value M = 0.743 ± 0.005 kg is dM while the error in M² will be 2dM
Hence we can conclude that the measured value of mass M in the experiment the error in 2M is ; dM.
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.
Which of the following is not true about the lymphatic system?
it drains white blood cells away from tissue
it brings nutrients to the tissue
it builds muscle cells
it fights infection
Answers
Answer:
it builds muscle cells
Explanation:
took test
A 3 Hz wave has a wavelength of 0.4 m. Calculate the speed of the wave (in m/s).
Answers
The speed of the wave with the given frequency and wavelength is 1.2m/s.
Given the data in the question;
Wavelength of the wave; [tex]\lambda = 0.4m[/tex]Frequency; [tex]f = 3Hz = 3s^{-1}[/tex]Speed of the wave; [tex]v = \ ?[/tex]WavelengthWavelength is the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.
It is expressed as;
[tex]\lambda = \frac{v}{f}[/tex]
Where v is velocity/speed and f is frequency.
Now, we can easily get the speed of the wave by substituting our given values into the expression above.
[tex]\lambda = \frac{v}{f} \\\\0.4m = \frac{v}{3s^{-1}}\\ \\v = 0.4m * 3s^{-1}\\\\v = 1.2ms^{-1}\\\\v = 1.2m/s[/tex]
Therefore, the speed of the wave with the given frequency and wavelength is 1.2m/s.
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If electromagnetic radiation acted like particles in the double-slit experiment, what would be observed? (1 point)
O A series of light and dark bands would appear on the screen.
O Two bright bands would appear on the screen in line with the slits.
O The screen would remain dark because no radiation would reach the screen.
O One bright band would appear in the center of the screen.
Answers
If electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.
Bahavior of particles in double-slit experimentIn a double-slit experiment, single particles, such as photons, pass one at a time through a screen containing two slits.
The photons behave like wave and the constructive interfernce of the waves of these photons will generate a high amplitude wave seen as a bright band in the center of the screen.
Thus, if electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.
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6. When can you say that an object is accelerating?
A. when the speed remains the same
B. When the speed is changing
C. when the instantaneous velocity is the same
D. When there is a uniform motion
give explanation
Answers
Answer:
When the speed is changing is the correct answer
Explanation:
Because acceleration is rate of change of velocity
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The Empire State Building is about 381m high. If you threw a baseball downward at 25 m/s from the top of the building how fast would it be traveling just before it landed?
Answers
Answer:
Explanation:
You can use that [tex]v = v_{o}+gt[/tex] or [tex]v^{2}=v_{o}^{2}+2gh=(25)^{2}+(2)(10)(381)=8245 \rightarrow v \approx 90.8[/tex] m/s.
Which statement about the observed results of the double-slit experiment is true?
O Waves that are out of phase constructively interfere to create bright bands.
O Waves that are in phase destructively interfere to create bright bands.
O Waves that are in phase constructively interfere to create bright bands.
O Waves that are out of phase constructively interfere to create bright bands.
Answers
Waves that are in phase constructively interfere to create bright bands was observed in the double-slit experiment.
What is Interference?This is defined as the phenomenon which occurs when two waves meet while traveling along the same medium.
A wave when in phase undergoes constructive interference while out of phase undergoes destructive interference which is why option C was chosen as the most appropriate choice.
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Which statement about the interference behavior of electromagnetic radiation seen in the double-slit test experiment is true? (1 point)
O Waves that make up the radiation collide with each other so that they add together or cancel each other out.
O Particles that make up the radiation collide with each other so that they add together or cancel each other out.
O Particles that make up the radiation collide with each other and scatter randomly.
O Waves that make up the radiation do not interact with each other.
Answers
Waves that make up the radiation collide with each other so that they add together or cancel each other out.
What is Interference?This is the phenomenon which occurs when two waves meet while traveling along the same medium.
In the double-slit test experiment, bright and dark fringes was observed which was caused by the superposition of overlapping light waves originating from the two slits which is why option A was chosen as the most appropriate choice.
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