Brainiest?!?! Please help me I'm running out of time??​

Answer:

Michael's daily income is $96

Step-by-step explanation:

Given

john's income=$120

by question

John's income is 20%more than Micheal's

so,. Micheal's income= John's income - 20%of John's income

=$120 - 20%of $120

=$120 -20/100*$120

=$120 - $24

=$96

Answer:

100

Step-by-step explanation:

[tex]x + \frac{20x}{100} = 120 \\ x + \frac{x}{5} = 120 \\ 5x + x = 600 \\ 6x = 600 \\ x = 100[/tex]

Answer: $48.93

Step-by-step explanation: 789.18 x 0.062

Answer:

$48.93

Step-by-step explanation:

789.18 x (0.062)  = 48.92916      $48.93

took the test

Answer:

p = 10.9

Step-by-step explanation:

Answer:

yes in this problem u would multiply the exponents due to the parenthesis, equaling 5^18

Answer:

x=3

Step-by-step explanation:

Subract the x from the left side and add it to the right side and then you got your answer

Answer: b

Step-by-step explanation:

Answer:

cheating in exam mmmmmmmm

Step-by-step explanation:

3(6k+5)+ 3(6k+4)

open the bracket

18k+15+18k+12=0

collect like terms

18k+18k+15+12=0

36k + 27 =0

36k=-27

k=-27/-36

divide through by 3

k= -9/-12

still divide through by 3

k=-3/-4

minus cancel minus

k=3/4

Answers:

T1 = 59.5677879151077 N

T2 = 45.7583538175564  N

The values are approximate. Round the values however you need to.

=========================================================

Explanation:

Refer to the diagram below. I have added red and blue lines to break up each tension vector into the x and y components. For tension T1 in red, we have x1 and y1 as the horizontal and vertical components respectively. Note that x1 points to the left and y1 points upward.

For T2 in blue, we have x2 point to the right and y2 point upward. The horizontal components x1 and x2 must be equal, and point in opposite directions, so that we have horizontal balance. Otherwise, the object would accelerate to one side rather than be stationary.

Applying a bit of trig, we can say

cos(angle) = adjacent/hypotenuse

cos(45) = (x1)/(T1)

x1 = T1*cos(45)

and also

sin(angle) = opposite/hypotenuse

sin(67) = (x2)/(T2)

x2 = T2*sin(67)

----------------------

Again, the x1 and x2 vectors must be equal in magnitude, allowing us to say this

x1 = x2

T1*cos(45) = T2*sin(67)

T1 = T2*sin(67)/cos(45)

which we'll use later.

----------------------

Doing a bit more trig set up, we know that

sin(45) = (y1)/(T1)

y1 = T1*sin(45)

and

cos(67) = (y2)/(T2)

y2 = T2*cos(67)

Adding those two y components together will yield the total upward force that the ropes apply

y1+y2 = T1*sin(45)+T2*cos(67)

y1+y2 = (T2*sin(67)/cos(45))*sin(45)+T2*cos(67)

y1+y2 = T2*( sin(67)*sin(45)/cos(45) + cos(67) )

y1+y2 = T2*( sin(67)*tan(45) + cos(67) )

y1+y2 = T2*( sin(67)*1 + cos(67) )

y1+y2 = T2*( sin(67) + cos(67) )

This combined upward pull must be equal to 60 newtons or else we wouldn't have vertical equilibrium. If the upward pull was smaller than the downward pull, then the object would be falling. If the other way around, then the object would be pulled upward at some accelerated speed (think of a spring action).

So we'll set y1+y2 equal to 60 and solve for T2

y1+y2 = 60

T2*( sin(67) + cos(67) ) = 60

T2 = 60/( sin(67) + cos(67) )

T2 = 45.7583538175564

That value is approximate. The units for T2 are in newtons. This is the amount of pull or force along the T2 line in the upper right direction.

Side note: make sure your calculator is in degree mode.

----------------------

The last thing to do is to compute T1

T1 = T2*sin(67)/cos(45)

T1 = 45.7583538175564*sin(67)/cos(45)

T1 = 59.5677879151077

That value is approximate as well. The units are also newtons here. This represents the amount of pull in the upper left direction as the diagram shows.

----------------------

Finding such values for T1 and T2 is useful to determine if a rope can handle a certain stress load. Let's say we had a rope that was rated for only 40 newtons. Anything beyond 40 N for this hypothetical rope would mean the rope breaks. We found T1 and T2 beyond this threshold which would indicate that such a rope isn't up to the task of holding this object up (at least not with the angles shown in the diagram).

Answer:

C

Step-by-step explanation:

Answer:

Step-by-step explanation:

The difference in the heights of the two pyramids:

Lets see

d is difference between the heights

So

Answer:

8

Explaining :

4/12 is 8

8+4=12

12-4=8

I hope it work :)

Answer: OO! i remember this but i forgot

Step-by-step explanation: ඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞ.

amogusඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞ.ඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞ.ඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞඞ.

Answer:

8 weeks

Step-by-step explanation:

i just divided 120 and 15

Answer:

It's 8 weeks

Step-by-step explanation:

because you basically take 120/15= answer or amount due divided by amount payed per (time choice)= time taken

I hope this helped!

All cross-sectional shapes that are parallel or perpendicular to one of the bases of a Cube.

A cross section in mathematics is the illustration of the intersection of an entity by a plane.

In a cube, all the faces which is parallel or perpendicular to one of the faces are congruent to one another.

So, out of all cross-sectional shapes that are parallel or perpendicular to one of the bases of a Cube, are also congruent to one another.

Hence, the cross-sectional shapes that are parallel or perpendicular to one of the bases of a Cube.

Learn more about cross-sections, click;

https://brainly.com/question/15541891

#SPJ5

Answer:

.

Step-by-step explanation:

sorry i can't help

Answer:

Im not

sure but i think its (B) i really hope its right

Step-by-step explanation:

Answer:To write a linear expression in standard form, rearrange the terms in alphabetical order.

7384000000

Step-by-step explanation:

Answer:

738400000.0

Step-by-step explanation:

738400000.0*10^10

Answer:

6=7y-8

6+8=7y-8+8(addition inverse operation)

14=7y

14/7=7y/7(division inverse operation)

2=y

Step-by-step explanation:

Answer:

y=2

Step-by-step explanation:

6=7y-8

(to get all the numbers on the right side and the letters on left side we can swap 6 with 7y)

-7y= -6-8

(since both were positive before we used the inverse method to turn both into a negative number)

-7y= -14

÷7 ÷7

(to get y on its own we divide both sides by 7)

y=2

Hope this helped you- have a good day bro cya)

Answer:

D

Step-by-step explanation:

First, we will move the variable to the left-hand side and change its sign: 5x + 3 - 10x = -17

Next, we need to collect like terms: -5x = -20

Finally, we will divide both sides of the equation by -5 to give us the answer of x = 4.

Answer:

x=21, y= 35

Step-by-step explanation:

3x+7=5x-35

(subtract seven from -35)

3x=5x-42

(subtract 5 from 3)

-2x=-42

(-42/-2= positive number)

x=21

y+75=3y+5

(subtract 75 from 5)

y=3y-70

(subtract 3y from y)

-2y=-70

y=35

Answer:

Step-by-step explanation:

Answer: y = -4

Step-by-step explanation:

If x = 1

1 = 2y + 9

1 - 9 = 2y

-8 = 2y

y = -8/2

y = -4

please give me a brainliest answer

Answer:

[tex]y = ( - 4)[/tex]

Step-by-step explanation:

Given that,

[tex]x = 1[/tex]

Question :

[tex]x = 2y + 9[/tex]

You have to find the value of y. So, make the y as the Subject

[tex]x = 2y + 9 \\ x - 9 = 2y \\ \frac{x - 9}{2} = \frac{2y}{2} \\ \frac{x - 9}{2} = y[/tex]

Now replace 1 instead of x

[tex]y = \frac{x - 9}{2} \\ y = \frac{1 - 9}{2} \\ y = \frac{ - 8}{2} \\ y = - 4[/tex]

Hope this helps you.

Let me know if you have any other questions :-)

Answer:

[tex]\frac{1}{\sqrt[n]{64}}[/tex]

Step-by-step explanation:

[tex]\frac{1}{\sqrt[1]{64}} =\frac{1}{64}[/tex]

[tex]\frac{1}{\sqrt[2]{64}} =\frac{1}{16}[/tex]

[tex]\frac{1}{\sqrt[3]{64}} =\frac{1}{4}[/tex]

[tex]\frac{1}{\sqrt[4]{64}} =\frac{1}{1}[/tex]

[tex] \green{\large\underline{\sf{Solution-}}}[/tex]

Given expression is

[tex]\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } [/tex]

can be rewritten as

[tex]\rm \:  =  \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} } [/tex]

We know,

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\ [/tex]

And

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\ [/tex]

So, using this identity, we

[tex]\rm \:  =  \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} } [/tex]

can be further rewritten as

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{25 - 1} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{24} [/tex]

[tex]\rm \:  =  \: \dfrac{1}{6} [/tex]

Hence,

[tex]\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}[/tex]

x/17.1 = 1.7/1.8

x = 17.1*1.7 /1.8

Height of tree = 16.15 m