Where on the periodic table are nonmetal elements mostlikely found?
A. Along the stairstep line
B. On the right side
C. On the left side
D. At the bottom

F = m.a

a = F/m

a = 1850/500

a = 3.7 m/s²

Answer:

the first one, The object moving through air

Answer:

The charge is believed to be from the charge of the quarks that make up the nucleons (protons and neutrons). A proton is made of two Up quarks, with 2/3 positive charge each and one Down Quark with a negative 1/3 charge (2/3 + 2/3 + -1/3 = 1).

Explanation:

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When an object is thrown at an angle from the horizontal, the path followed by the body is called the projectile motion. The duration in seconds that the object is above the height of 14 m is 4.698 s.

Speed is the time rate at which velocity is changing.

Vertical speed component is

V₀y = 52sin 30°= 26 m/s

Given is the height h=14m

Using second equation of motion,

S=ut+ 1/2 at²

Substituting the values, we get

14 = 26t - 4.9t²

4.9t² - 26t +14 =0  

Solving the quadratic equation, we get the time as

taking the positive sign, t =4.698 s

taking the negative sign , t = 0.6082 s

Thus, the duration in seconds that the object is above the height of 14 m is 4.698s.

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The power dissipate due to internal resistor​ is 400 W.

The power dissipate due to internal resistor​ is calculated as follows;

P = IV

P = (V/r)V

P = V²/r

where;

P = (20²)/(1)

P = 400 W

Thus, the power dissipate due to internal resistor​ is 400 W.

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Answer:

0.5 m

Explanation:

To find wavelength (λ) : apply the formula

Solving :

The charge on the capacitor in an LRC-series circuit is 2.8907 C.

The first time at which the charge on the capacitor is equal to zero is 0.1409s.

The capacitor consists of two parallel plates used to store the charge when current flows through it, and provides energy when shuts off.

By the Kirchoff's second  law,

Lq'' +Lq' +q/C =E(t)

Where, L =0.05h, R = 6 Ω, C = 0.005 f, E(t) = 0 V, q(0) = 4 C, and i(0) = 0 A.

Equations becomes q''+120q' +4000 =0

The auxiliary equation is m² +120m+4000 =0

Solving this quadratic equation, we have

m =-6± 20i

Then , q(t) = Ae^(-60t)cos 20t + Be^(-60t)sin 20t    where, A and B are constants.

At t=0, q(0) =7 =A

and q'(t) = A [ -20e^(-60t)sin 20t - 60e^(-60t)cos 20t ] +B  [ 20e^(-60t)cos 20t - 60e^(-60t)sin 20t ]

So, i(0)= q'(0) =0 =-60A +20 B

Putting the value of A=7 above, we have B =21.

So,  q(t) = 7e^(-60t)cos 20t + 21e^(-60t)sin 20t  

The charge on the capacitor at time t =0.015

q(0.015) = 2.8907 C

Thus the charge on capacitor is  2.8907 C.

q(t) = 7e^(-60t)cos 20t + 21e^(-60t)sin 20t  =0

Solve for t, we get

e^(-60t)cos 20t + 3e^(-60t)sin 20t\

-1/3 = sin 20t /cos20t

t =1/20 arctan(-1/3)

As, arctan is defined within -90 to +90,

So, 20t = -0.3218 +π =2.8197

t =0.1409s

Thus the first time at which the charge is zero is 0.1409s.

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When you receive prescriptions that contain some abbreviations, you have to translate it into plain language that the patient can understand.

A pharmacy technician is a skilled personnel who assists a pharmacist in a health facility. The pharmacy technician usually writes out prescriptions for patients.

When you receive prescriptions that contain some abbreviations, you have to translate it into plain language that the patient can understand. If you are not clear about the abbreviation you can ask the pharmacist for help or the doctor.

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The angle will the first diffraction minimum be found will be 0.034895°.

A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.

The equation of diffraction grating is given as

[tex]\rm d= \frac{m \lambda}{sin \theta }[/tex]

The angle between the incident ray and the point of the occurrence of the diffraction is found as;

[tex]\theta = sin^{-1}(\frac{m\lambda}{d} )\\\\\ \lambda= (2.0))(\frac{1.00 \times 10^{-12}}{1\ pm} )\\\\\ \lambda=2.00 \times 10^{-12}[/tex]

The angle will the first diffraction minimum be found is;

[tex]\theta = sin^{-1}(\frac{m\lambda}{d} )\\\\\ \theta = sin^{-1}(\frac{1 \times 2.000 \times 10^{-12}}{1\times 10^{-12}} )\\\\\ \theta= 0.0348995^0[/tex]

Hence,the angle will the first diffraction minimum be found will be 0.034895°.

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Answer:

x = 4 t + 2 t^2      

the displacement is x which is zero at t = 0 and then increases indefinitely as t increases indefinitely

Answer:

Assume a node at the left end and the right end

N-A-N-A-N-A-N-A-N-A-N    shows nodes and anti-nodes

10 quarter wavelengths are shown  (or 2.5 wavelengths)

30 / 2.5 = 12 cm wavelength      since there is 1/4 wavelength between node and anti-node

Nodes and anti-nodes are displayed in N-A-N-A-N-A-N-A-N.

The difference between the node and the anti-node exists 12 cm wavelength.

Standing waves are created when two identical waves move in opposition to one another along a line. Despite being composed of two waves that are moving in opposition to one another, standing waves do not travel through space or along a string.

A wave that is stationary is one that is not moving, is at a standstill, or is in a relaxed position. A standing wave is created whenever two waves with nearly identical frequencies, wavelengths, and amplitudes that are traveling in opposite directions collide.

A waveform signal that is carried in space or down a wire has a wavelength, This is the distance between two identical locations (contiguous crests) in the following cycles. This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm).

The distance over which a periodic wave's shape repeats is known as the wavelength in physics.

Assume that there exists a node at both the left and right ends.

Nodes and anti-nodes are displayed in N-A-N-A-N-A-N-A-N.

it displays 10 quarter wavelengths.

Since there exists a 1/4 wavelength difference between the node and the anti-node, 30 / 2.5 = 12 cm wavelength.

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Answer:

The greater the period the faster the wave moves (Figure 10.5).

Explanation:

The upward force F exerted by the biceps on the forearm will be 583 N.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

The torque balancing equation is found as;

[tex]\rm \tau_i=\tau_R+\tau_F+\tau_{BB}=0\\\\ R(0)+F(0.0300)-(50.0)(0.350)\\\\ F=583 \ N[/tex]

Hence,the upward force F exerted by the biceps on the forearm will be 583 N.

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Answer:

047.1

Explanation:

frequency equals velocity over lambda

The incidence is maybe 26=9

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration.

Explanation:

sine's law

h/sin 30 = 50/sin 60

h/0.5 = 50/(0.5√3)

h=28.9 m

Answer:

es lo que es

Explanation:

es lo que es es que slep vaka vee

the angle ϕ= will be equal to angle of refraction and it is equal to 49.4°C.

When a light is going from medium 1 to medium 2. The refractive index is defined as a ratio of velocity of light in medium 1 to velocity of light in medium 2. Refractive index is the factor which deals with the amount of bending of light. More refractive index means more it will bend in the medium 2. When it is 1 we can say that light has not been bent.

By Snell's law, Refractive index is given by,

sin (i) ÷ sin (r) = μ₂÷μ₁

where i is the the angle of incidence

r is the angle of refraction

μ₂ & μ₁ are refractive index of medium 2 and 1 resp.

Hence it is due to Refractive index.

In this problem the light is going from prism to air, the refractive index of air is 1. From figure it is clear that the angle of incidence is 30°C.

From snell's law,

sin (30) ÷ sin (r) = μ₂÷1.52

0.5 ÷ sin (r) = 1÷1.52

0.5×1.52 = 1×sin (r)

0.76 = sin (r)

The angle of refraction r = sin⁻¹(0.76) =49.4°C

Hence angle ∅ = 49.4°C.

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Answer:

It has a central nucleus composed of 29 protons and 35 neutrons, surrounded by an electron cloud containing 29 electrons

Explanation:

Atoms Composition:

Calculation:

a)A spherical convex mirror form the image at image distance is 8.57cm.

b) Mirror forms the image of height is 12.855 cm.

c)The magnification of the spherical convex lens is 0.4285.

The mirror which is a part of sphere with radius R is painted from inside forms the convex mirror.

The focal length of convex lens,  f = R/2

Given , the radius of mirror is R =30cm, the focal length will be

f =30cm/2 = 15cm

a) Object distance u =20 cm, object height =0.30m, then the image distance will be 1/f = 1/u + 1/v where v is the image distance from the lens.

1/15 = 1/20 + 1/v

v= 8.57 cm

Thus, the image distance is 8.57cm.

b) Ratio of image distance to the object distance is equal to the ratio of image height to the object height.

Substitute the values into the expression, we get the image height as

h(image) = 8.57/20 x 30

h(image) = 12.855 cm

Thus, the image height is 12.855 cm.

c) The magnification is the ratio of image height to the object height.

Putting the values, we have

= 12.855/30

= 0.4285

Thus, the magnification is 0.4285.

d) Size of object is large as compared to the size of image. Object distance is small as compared to the image distance. The image formed is virtual.

e)  The setup drawing is attached.

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Answer:

1482m/s

Explanation:

velocity equals frequency x lamdha

Answer:

which picture please,I don't get you

Answer:

In a simplest terms,

temperature is how hot or cold an object is, while heat is the energy that flows from a hotter object to cooler one

Answer:

Longitudinal

Explanation:

I searched it up.

Answer:

5941m/s

Explanation:

velocity equals frequency x lamdha