[tex] - x ^{2} + 2x - 6 = 0[/tex]
how to do,I don't know the step

answer is
[tex]x = 1 - \sqrt{5} i \: \: \: \: \: or \: \: 1 + \sqrt{5} i[/tex]

Answers

Answer 1

Answer:

there are several methods to "solve a quadratic"

you can look them all up...

Graphing, factoring, completing the square, taking roots, quadratic formula are the common methods....

given the way you are asking the question I think that you are supposed to use the quadratic formula ..

please look at the image of the formula and

realize that you problem has

a=-1

b=2

c=6

just plug in those numbers into the formula and you will get the results in the "answer"

NOTE [tex]\sqrt{-x}[/tex] is written as ix ( [tex]\sqrt{-25} = 5i[/tex] )

Step-by-step explanation:

x= -2+√ (2)²- (4)(-1)(-6)  

                 (2)(-1)  

and

x= -2-√ (2)²- (4)(-1)(-6)  

             (2)(-1)  

[tex] - X ^{2} + 2x - 6 = 0[/tex]how To Do,I Don't Know The Stepanswer Is[tex]x = 1 - \sqrt{5} I \: \:

Related Questions

You are dealt two cards successively without replacement from a standard deck of 52 playing cards. Find the probability that the first card is a two and the second card is a ten.

Answers

Answer:

[tex]\frac{4}{52} \times \frac{4}{51} = \frac{16}{2652} = 0.00603 = 0.603\%[/tex]

Step-by-step explanation:

There are 52 cards in a standard deck, and there are 4 suits for each card. Therefore there are 4 twos and 4 tens.

At first we have 52 cards to choose from, and we need to get 1 of the 4 twos, therefore the probability is just

[tex]\frac{4}{52}[/tex]

After we've chosen a two, we need to choose one of the 4 tens. But remember that we're now choosing out of a deck of just 51 cards, since one card was removed. Therefore the probability is

[tex]\frac{4}{51}[/tex]

Now to get the total probability we need to multiply the two probabilities together

[tex]\frac{4}{52} \times \frac{4}{51} = \frac{16}{2652} = 0.00603 = 0.603\%[/tex]

Which correlation best describes the data below. no correlation weak positive weak negative strong positive

Answers

There is no picture of the data

Hi,there,can you solve this equation.
4x*sqrt(2x-x²)=2x-1

Answers

Answer:

Step-by-step explanation:

4x*sqrt(2x-x²)=2x-1

sqrt(2x-x²)=(2x-1)/4x

2x-x² = 4x^2 -4x + 1 /(16x^2)

32x^3 - 16x^4 =  4x^2 -4x + 1

[tex]-16x^4+32x^3-4x^2+4x-1=0\\[/tex]

[tex]x = 1.92887[/tex]

Derive the explicit rule for the pattern: 3, 0, - 3, - 6, - 9, ...

Answers

Answer:

Step-by-step explanation:

a1 = 3

d = -3

an = a1 + (n - 1)*d

an = a1 + (n - 1)*-3

Try it

Let n = 5

a5 = 3 + (5 - 1)*-3

a5 = 3 + 4*-3

a5 = 3 - 12

a5 = - 9 which is exactly what it should be.

The interesting one to try is n = 2

a2 = a1 + (2 - 1)*-3

a3 = 3  + 1(-3)

a3 = 3 - 3

a3 =0

Which is exactly what the second term is. It's interesting because you would never guess that 0 is what you get.

A newsletter publisher believes that less than 61% of their readers own a laptop. Is there sufficient evidence at the 0.02 level to substantiate the publisher's claim? State the null and alternative hypotheses for the above scenario.

Answers

Answer: See explanation

Step-by-step explanation:

From the information given in the question, we are informed that a newsletter publisher believes that less than 61% of their readers own a laptop.

The null hypothesis will be: H0: p ≥ 0.61

The alternative hypothesis will be: Ha: p < 0.61.

What is the shortest distance Jill can travel is she leaves her house, goes to City Hall, to the Post Office, and then returns home?

A. 9 miles
B. 16 miles
C. 38 miles
D. 48 miles

Answers

Can you post an image of the map?

Answer:

i believe that the answer is 38 please trust me

Lynbrook West, an apartment complex, has 100 two-bedroom units. The monthly profit (in dollars) realized from renting out x apartments is given by the following function. p(x)=-12x^2+2160x-59000 To maximize the monthly rental profit, how many units should be rented out? units What is the maximum monthly profit realizable?

Answers

Answer:

To maximize the monthly rental profit, 90 units should be rented out.

The maximum monthly profit realizable is $38,200.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

[tex]f(x) = ax^{2} + bx + c[/tex]

It's vertex is the point [tex](x_{v}, y_{v})[/tex]

In which

[tex]x_{v} = -\frac{b}{2a}[/tex]

[tex]y_{v} = -\frac{\Delta}{4a}[/tex]

Where

[tex]\Delta = b^2-4ac[/tex]

If a<0, the vertex is a maximum point, that is, the maximum value happens at [tex]x_{v}[/tex], and it's value is [tex]y_{v}[/tex].

In this question:

Quadratic equation with [tex]a = -12, b = 2160, c = -59000[/tex]

To maximize the monthly rental profit, how many units should be rented out?

This is the x-value of the vertex, so:

[tex]x_{v} = -\frac{b}{2a} = -\frac{2160}{2(-12)} = \frac{2160}{24} = 90[/tex]

To maximize the monthly rental profit, 90 units should be rented out.

What is the maximum monthly profit realizable?

This is p(90). So

[tex]p(90) = -12(90)^2 + 2160(90) - 59000 = 38200[/tex]

The maximum monthly profit realizable is $38,200.

What would be an appropriate domain if the function hin) gives the number
of man-hours it takes to assemble n engines in a factory in a day, subject to a
maximum of 300 engines?

Answers

Answer:

assuming that you are NOT allowed to build 1/2 of an engine or that you dont destroy any of them in the process of building them ...

"all positive integers less than or equal to 300"

Step-by-step explanation:

Using a profit P1 of $5,000, a profit P2 of $4,500, and a profit P3 of $4,000, calculate a 95% confidence interval for the mean profit per customer that SoftBus can expect to obtain. (Round your answers to one decimal place.) Lower Limit Upper Limit

Answers

Answer:

Confidence Interval

Lower Limit = $4,233.3

Upper Limit = $4,766.7

With 95% confidence, the mean profit per customer that SoftBus can expect to obtain is between $4,233.30 and $4,766.7 based on the given sample data.

Step-by-step explanation:

The z-score of 95% = 1.96

             Profit         Mean      Square Root

                          Difference    of MD

P1        $5,000       $500        $250,000

P2         4,500          0              0

P3         4,000       -500         $250,000

Total $13,500                        $500,000

Mean $4,500 ($13,500/3)    $166,667 ($500,000/3)

Standard Deviation = Square root of $166,667 = 408.2

Margin of error = (z-score * standard deviation)/n

= (1.96 * 408.2)/3

= 266.7

= $266.7

Confidence Interval = Sample mean +/- Margin of error

= $4,500 +/- 266.7

Lower Limit = $4,233.3 ($4,500 - $266.7)

Upper Limit = $4,766.7 ($4,500 + $266.7)

Solve this pleaseeeeeeeeeee

Answers

Answer:

10d

Step-by-step explanation:

5d on 1 side, double it to get 10d cuz from Point O to Point D, y increases from 0 to 5d and since the triangles are congruent, we can add another 5d (or in total 10d).

find x

please help!!​

Answers

Answer:  [tex]9\sqrt{3}[/tex]

==========================================================

Explanation:

For any 30-60-90 triangle, the short leg is always half the hypotenuse.

This makes the short leg to be 18/2 = 9 units long.

We then multiply this by [tex]\sqrt{3}[/tex] to get the length of the long leg.

[tex]\text{long leg} = (\text{short leg})*\sqrt{3}\\\text{long leg} =9\sqrt{3}[/tex]

Or you could use the pythagorean theorem to solve [tex]x^2+9^2 = 18^2[/tex] and you should get [tex]x = \sqrt{243} = 9\sqrt{3}[/tex]

Please help!!

Find BD​

Answers

Answer:  [tex]8\sqrt{2}[/tex]

==========================================================

Work Shown:

Focus entirely on triangle ABD (or on triangle BCD; both are identical)

The two legs of this triangle are AB = 8 and AD = 8. The hypotenuse is unknown, so we'll say BD = x.

Apply the pythagorean theorem.

[tex]a^2 + b^2 = c^2\\\\c = \sqrt{a^2 + b^2}\\\\x = \sqrt{8^2 + 8^2}\\\\x = \sqrt{2*8^2}\\\\x = \sqrt{8^2*2}\\\\x = \sqrt{8^2}*\sqrt{2}\\\\x = 8\sqrt{2}\\\\[/tex]

So that's why the diagonal BD is exactly [tex]8\sqrt{2}\\\\[/tex] units long

Side note: [tex]8\sqrt{2} \approx 11.3137[/tex]

A biologist was interested in determining whether sunflower seedlings treated with and an extract from Vinca minor roots resulted in a lower average height of sunflower seedlings that the standard height of 15.7 cm. The biologist treated a random sample of 33 seedlings with the extract and subsequently measured the height of those seedlings. At the 0.01 significance level, is there evidence that the true average height of the seedlings treated with an extract from Vinca minor roots is less than 15.7 cm?

Height
15.5
15.8
15.7
15.1
15.1
15.5
15.2
15.7
15.8
15.4
16.2
15.5
16.2
15.5
15.4
16.3
14.9
15.3
15.1
16.1
15.3
15.4
15.1
15.3
14.6
15.1
15.0
15.3
15.8
15.5
14.8
15.2
14.8

a. State the null and alternative hypotheses.
b. Report the value of the test statistic. Round answer to 2 decimal places. (Either calculate or use software such as minitab)
c. Using the p-value, do you reject the null hypothesis or fail to reject the null hypothesis? Explain your decision.
d. Based on your decision in part (c), write a conclusion within the context of the problem.

Answers

Answer:

Kindly check explanation

Step-by-step explanation:

H0 : μ = 15.7

H1 : μ < 15.7

This is a one sample t test :

Test statistic = (xbar - μ) ÷ (s/√(n))

n = sample size = 33

Using calculator :

The sample mean, xbar = 15.41

The sample standard deviation, s = 0.419

Test statistic = (15.41 - 15.70) ÷ (0.419/√(33))

Test statistic = - 3.976

Using the Pvalue calculator :

Degree of freedom, df = n - 1 ; 33 - 1 = 32

Pvalue(-3.976, 32) = 0.000187

Decison region :

Reject H0 if Pvalue < α

Since Pvalue < α ; we reject H0

There is significant evidence to conclude that the true average height of the seedlings treated with an extract from Vinca minor roots is less than 15.7 cm.

*20 points*
how do you get the weighted average from this table?

Answers

Answer:

it is

[(2+3+4+6)-2*4]:4=1.75

I THINK

Step-by-step explanation:

A sailor on a trans-Pacific solo voyage notices one day that if he puts 625.mL of fresh water into a plastic cup weighing 25.0g, the cup floats in the seawater around his boat with the fresh water inside the cup at exactly the same level as the seawater outside the cup (see sketch at right).
Calculate the amount of salt dissolved in each liter of seawater. Be sure your answer has a unit symbol, if needed, and round it to 2 significant digits.


You'll need to know that the density of fresh water at the temperature of the sea around the sailor is 0.999/gcm3. You'll also want to remember Archimedes' Principle, that objects float when they displace a mass of water equal to their own mass.

Answers

Answer:

can you say again please

Find the Antilog of 547.840​

Answers

Answer:

It's impossible because the figure is greater than 10

Step-by-step explanation:

[tex]{ \boxed{ \bf{antilog \: of \: x = \frac{x}{ log} = {10}^{x} }}}[/tex]

Therefore:

[tex]{ \sf{anti(547.840) = {10}^{547.840} }} \\ { \tt{ \red{math \: error \: !}}}[/tex]

You are offered two stocks. The beta of A is 1.4 while the beta of B is 0.8. The growth rates of earnings and dividends are 10% and 5%, respectively. The dividend yields are 5% and 7%, respectively.
Since A offers higher potential growth, should it be purchased?
Investments- Individual Work 2 Page 3
Since B offers a higher dividend yield, should it be purchased?
If the risk-free rate of return were 7% and the return on the market is expected to be 14%, which of these stocks should be bought?

Answers

Answer:

a) Yes , Cause The Expected Returns of stock A is Higher than that of B

b) No,  Cause The Expected Returns of stock B is Lower than that of A

Step-by-step explanation:

From the question we are told that:

Beta A \beta A=1.4

Beta B \beta B=0.8

Stock 1 Growth rates of earnings and dividends G_1=10\%

Stock 2 Growth rates of earnings and dividends  G_2=5\%

Stock 1  Dividend yields D_1=5\%

Stock 2 Dividend yields  D_2=7\%

Generally the equation for Expected Returns is mathematically given by

Expected Returns =Growth rates+Dividend yields

For Stock 1

Expected\ Returns =G_1+D_1

Expected\ Returns =5%+10%

Expected\ Returns =15%

For Stock 2

Expected\ Returns =G_2+D_2

Expected\ Returns =7%+5%

Expected\ Returns =12%

Therefore

a) Yes , Cause The Expected Returns of stock A is Higher than that of B

b) No,  Cause The Expected Returns of stock B is Lower than that of A

Max needs to paint a wall that is shaped like a square. He knows that the area of the wall is 75 ft2 . He needs to find the height of the wall. Find the height of the wall to the nearest tenth of a foot.

Answers

Answer:

8.7 feet

Step-by-step explanation:

Use the square area formula, a = s², where s is the side length of the square.

Plug in the area and solve for s:

a = s²

75 = s²

√75 = s

8.7 = s

So, to the nearest tenth of a foot, the height is 8.7 feet

Which of the following theorems verifies that abc wxy

Answers

Answer:

C.    AA

Step-by-step explanation:

Since m<Y = 27°, then m<W = 27°.

We have two angles of one triangle (A and B) congruent to two angles of the other triangle (W and X).

Answer: C.   AA

which lines are parallel?

Answers

Answer:

Lines 'p' and 'q' are parallel I believe!

Step-by-step explanation:

They are the only two lines relating to angles 8 and 11 of the three listed pairs.

Answer:

p and q are parallel

Step-by-step explanation:

Dogsled drivers, known as mushers, use several different breeds of dogs to pull their sleds. One proponent of Siberian Huskies believes that sleds pulled by Siberian Huskies are faster than sleds pulled by other breeds. He times 47 teams of Siberian Huskies on a particular short course, and they have a mean time of 5.2 minutes. The mean time on the same course for 39 teams of other breeds of sled dogs is 5.5 minutes. Assume that the times on this course have a population standard deviation of 1.4 minutes for teams of Siberian Huskies and 1.1 minutes for teams of other breeds of sled dogs. Let Population 1 be sleds pulled by Siberian Huskies and let Population 2 be sleds pulled by other breeds. Step 1 of 2 : Construct a 95% confidence interval for the true difference between the mean times on this course for teams of Siberian Huskies and teams of other breeds of sled dogs

Answers

Answer:

The 95% confidence interval for the true difference between the mean times on this course for teams of Siberian Huskies and teams of other breeds of sled dogs is (-0.8276, 0.2276).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.  

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Siberian Huskies:

Sample of 47, mean of 5.2 minutes, standard deviation of 1.4. So

[tex]\mu_1 = 5.2[/tex]

[tex]s_1 = \frac{1.4}{\sqrt{47}} = 0.2042[/tex]

Others:

Sample of 39, mean of 5.5 minutes, standard deviation of 1.1. So

[tex]\mu_2 = 5.5[/tex]

[tex]s_2 = \frac{1.1}{\sqrt{39}} = 0.1761[/tex]

Distribution of the difference:

[tex]\mu = \mu_1 - \mu_2 = 5.2 - 5.5 = -0.3[/tex]

[tex]s = \sqrt{s_1^2+s_2^2} = \sqrt{0.2042^2+0.1761^2} = 0.2692[/tex]

Confidence interval:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = zs[/tex]

In which s is the standard error. So

[tex]M = 1.96(0.2692) = 0.5276[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is -0.3 - 0.5276 = -0.8276.

The upper end of the interval is the sample mean added to M. So it is -0.3 + 0.5276 = 0.2276

The 95% confidence interval for the true difference between the mean times on this course for teams of Siberian Huskies and teams of other breeds of sled dogs is (-0.8276, 0.2276).

Jagroop is building a dock at his cottage. The length of the doc is 3 times the width, plus 2. Determine a simplified expression for the perimeter of the doc

Answers

Answer:

Step-by-step explanation:

Let length = y    width = x

y = 3x + 2

Perimeter = Sum of all sides (or sum of both lengths and both widths)

2y + 2x

2(3x + 2) + 2x

6x + 4 + 2x

8x + 4

Write a simple algorithm to add two numbers

Answers

Answer:

Write an algorithm to add two numbers entered by user. Step 2: Declare variables num1, num2 and sum. Step 3: Read values num1 and num2. Step 4: Add num1 and num2 and assign the result to sum.

Hope it helped . Here is the answer.

find the area of the shaded regions. ANSWER IN PI FORM AND DO NOT I SAID DO NOT WRITE EXPLANATION

Answers

Answer: 18π

okokok gg

Step-by-step explanation:

Here angle is given in degree.We have convert it into radian.

[tex] {1}^{\circ} =( { \frac{\pi}{180} } )^{c} \\ \therefore \: {80}^{\circ} = ( \frac{80\pi}{180} ) ^{c} = {( \frac{4\pi}{9} })^{c} \: = \theta ^{c} [/tex]

radius r = 9 cm

Area of green shaded regions = A

[tex] \sf \: A = \frac{1}{2} { {r}^{2} }{ { \theta}^{ c} } \\ = \frac{1}{2} \times {9}^{2} \times \frac{4\pi}{9} \\ = 18\pi \: {cm}^{2} [/tex]

The value of 4√(10) -2 is​

Answers

Answer:

8√2

Step-by-step explanation:

4√(10) -2

= 4√8

=4√4×2

=4×2√2

=8√2

Nancy left a bin outside in her garden to collect rain water. She notices the 1/2 gallon fills 2/3 of the bin. Write and solve an equation to find the amount of water that will fill the entire bin. Show your work. Explain your answer in words.

Answers

Here we want to solve a question involving fractions, we will find that:

3/4 gallon fils the complete bin.

Ok, so we know that 1/2 gallon of water, fills 2/3 of the bin.

We want to find the total amount of water that would fill the entire bin.

So we could write an equation like:

amount of water =  amount of the bin that it fills.

Then, using the above information, we have:

1/2 gal  = 2/3 of a bin

Now we want to get at 1 on the right side, this would mean "1 bin"

Then we multiply both sides by (3/2)

(3/2)*(1/2) gal = (3/2)*(2/3) of a bin

3/4 gal = 1 bin

From this, we can conclude that (3/4) gallons of water would fill the complete bin.

If you want to learn more about algebra, you can read:

https://brainly.com/question/4837080

x = 0,75 gallons      or       x  = 3/4   gallons      The volume of the bin

The volume of the bin is: In terms of a fraction

1  =  3/3      or any unitary fraction   5/5    7/7    9/9

We will take 3/3 since we have the information that 2/3 of the volume of the bin was filled with 2/3 of a gallon

If  2/3 of the volume of the bin was filled with 1/2 gallon then we make a rule of three according to:

If     0,5  gal.         fill    2/3 of the volume of the bin   then

          x   gal         fill     3/3  ( the volume of the bin)

solving

0,5 (gal) * 3/3    =   (2/3)*x       ( The equation)

0,5*3 = 2*x

x  =  (0,5*3)/2

x = 0,75 gallons      or       x  = 3/4   gallons

An office manager has received a report from a consultant that includes a section on equipment replacement. The report indicates that scanners have a service life that is normally distributed with a mean of 41 months and a standard deviation of 4 months. On the basis of this information, determine the proportion of scanners that can be expected to fail within plus or minus 6 months of the mean. (Enter your answer as a percentage without the percent sign; keep 2 decimal places)

Answers

Answer:

The answer is "36.14%"

Step-by-step explanation:

The complete question is given in the attached file please find it.

[tex]\mu =41\\\\\sigma= 4\\\\P(42<\bar{x}<48)= p(\bar{x}<48)-p(\bar{x}<42)\\\\Z =\frac{(42-41)}{4} = \frac{1}{4} =0.25\\\\Z =\frac{(48-41)}{4} = \frac{7}{4} = 1.75\\\\[/tex]

Using z-table to find the value.

[tex]\to P(41<\bar{x}<48) = 0.9599- 0.5987 = 0.3614\times 100= 36.14\%[/tex]

This means that between 42 and 48 months, 36.14 % of scanners could be predicted will break down.

Which of the following is equivalent to the expression below

Answers

Answer:

Could you add a picture or answer choices so we know what to choose from?

Catherine Chao, Director of Marketing Research, needs a sample of households to participate in the testing of a new toothpaste package. She chooses thirty-six of her closest friends. Catherine's sample is a _____________.

Answers

Answer:

Convenience sampling.

Step-by-step explanation:

In Statistics, sampling can be defined as a process used to collect or select data (objects, observations, or individuals) from a larger statistical population using specific procedures.

There are various types of sampling used by researchers and these are;

1. Random sampling.

2. Systematic sampling.

3. Stratified sampling.

4. Cluster sampling.

5. Quota sampling.

6. Convenience (opportunity) sampling.

Convenience sample can be defined as a sampling technique in which the representatives to be used are easily accessible. For example, a researcher using a social media poll such as Twitter polls.

In this scenario, Catherine Chao, Director of Marketing Research, chooses thirty-six of her closest friends to participate in the testing of a new toothpaste package. Thus, Catherine's sample is a convenience sampling.

Scores on a national English test are Normally distributed, with a mean score of 510 and a standard deviation of 75. Sixty-eight percent of English tests were less than which score, rounded to the nearest whole number?


A) 475

B) 529

C) 545

D) 561

Answers

Answer:

Should be (C). Can't verify.

545

ED2021

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