Put these numbers in descending order.
0.308
0.193
0.26
0.6

Answers

Answer 1

Answer:

0.6

0.308

0.26

0.193

Step-by-step explanation:

0.6

0.308

0.26

0.193


Related Questions

Given that ƒ(x) = 3^x, identify the function g(x) shown in the figure. A) g(x) = −3^-x
B) g(x) = −(1∕3)^x
C) g(x) = 3^−x
D) g(x) = −3^x

Answers

Answer:

Option (D)

Step-by-step explanation:

From the graph attached,

Function 'f' is the reflected across x-axis to get the graph function 'g'.

Therefore, by definition of reflection across x-axis,

g(x) = -f(x)

g(x) = [tex]-3^x[/tex]

Option (D) will be the answer.

Find the area of the circle around your answer to the nearest 10th

Answers

Answer:

A= π ( 3.8)^2

A= 45.36

OAmalOHopeO

Step-by-step explanation:

area is 2xr(times your answer)

One third of number is four times eleven. What is half of that number

Answers

Answer:

One third of a number is four times eleven. What is the half of that number?

Explanation:

Four times 11 = 11 X 4 = 44

One third (1/3) of the number = 44

The number is = 44 X 3 = 132

Therefore half of the number 132 = 66

Answer:

66

Step-by-step explanation:

11 X 4 = 44

One third (1/3) of the number = 44

The number is = 44 X 3 = 132

Therefore half of the number 132 = 66

What is the quotient ? -4/2 divided by 2

Answers

Answer:

[tex]\frac{-\frac{4}{2} }{2} =-\frac{4}{2} *\frac{1}{2} =-\frac{4}{4} =-1[/tex]

Find the missing length indicated

Answers

Answer:

what's the question? ke

The graph of y= -2x + 10 is:
O A. a line that shows only one solution to the equation.
O B. a point that shows the y-intercept.
O C. a line that shows the set of all solutions to the equation.
O D. a point that shows one solution to the equation.
SUBM

Answers

9514 1404 393

Answer:

  C. a line that shows the set of all solutions to the equation.

Step-by-step explanation:

Any graph shows the set of all solutions to the equation being graphed.

The graph of a linear function is a straight line.

PLEASE HELP!!!
Evaluate each expression.
(252) =

Answers

Answer:

1/5

Step-by-step explanation:

***URGENT***
PLEASE HELP ME ASAP, ITS DUE TODAY!!!
............................................................

T is the point on AB such that AT:TB = 5: 1. Show that ot is parallel to the vector a + 2b.

Answers

Step-by-step explanation:

SO, OT is parallel to the vector a+2b

A basketball player averages 22.5 points scored per game with a standard deviation of 6.2 points. In one game, the athlete scored 10 points. What is the z-score for the points scored in this game?

–2.02
–1.63
1.63
2.02

Answers

Answer:

Step-by-step explanation:

Z -2.02

x 10

µ 22.5

σ 6.2

Use the graph to complete the statement. O is the origin. Ry−axis ο Ry=x: (-1,2)
A. (2, -1)
B. (-2, -1)
C. (-1, -2)
D. (1, -2)

Answers

Answer:

[tex](x,y) = (1,2)[/tex] -------- [tex]R_{y-axis}[/tex]

[tex](x,y)=(2,-1)[/tex] --------- [tex]R_{y=x}[/tex]

Step-by-step explanation:

Given

[tex](x,y) = (-1,2)[/tex]

Required

[tex]R_{y-axis}[/tex]

[tex]R_{y=x}[/tex]

[tex]R_{y-axis}[/tex] implies that:

[tex](x,y) = (-x,y)[/tex]

So, we have: (-1,2) becomes

[tex](x,y) = (1,2)[/tex]

[tex]R_{y=x}[/tex] implies that

[tex](x,y) = (y,x)[/tex]

So, we have: (-1,2) becomes

[tex](x,y)=(2,-1)[/tex]

Work out the surface area of this solid quarter cylinder. give your answer in terms of pi. r:8cm h:15cm​

Answers

Answer:

248 pi cm^2

Step-by-step explanation:

The surface area of a cylinder is given by

SA = 2 pi r^2 + pi rh  where r is the radius and h is the height

   = 2 pi( 8)^2 + pi (8)(15)

    128 pi +120pi

   248pi

Alice and Bob each choose a number uniformly (and independently) from the interval [0, 10]. What is the probability that the absolute value of the difference between their two numbers is less than 1/4

Answers

Answer:

The probability is zero (0)

Step-by-step explanation:

Given;

interval of numbers to be chosen = 0, 1, 2, 3 , 4, 5, 6, 7, 8, 9 , 10

total possible outcome = 11

The possible numbers whose absolute difference is greater than ¹/₄ includes the following;

(0,1), (1,2), (2,3), (3,4), (4,5), (5,6), (6,7), (7,8), (8,9), (9,10), (10,0)

The probability of this = 11 / 11 = 1

The probability that the absolute value of the difference between their two numbers is less than 1/4

[tex]P(less \ than \ \frac{1}{4} ) = 1 - P(greater \ than \ \frac{1}{4} )\\\\P(less \ than \ \frac{1}{4} ) = 1 - 1 \\\\P(less \ than \ \frac{1}{4} ) = 0[/tex]

Question
Express all real numbers less than -2 or greater than or equal to 3 in interval notation.

Answers

Real numbers can be expressed using the following interval,

[tex]\mathbb{R}=(-\infty,\infty)[/tex]

Of course infinities are not just normal infinities but thats out of the scope of this question.

Real numbers less than two can be expressed with,

[tex](-\infty,\infty)\cap(-\infty,-2)=\boxed{(-\infty,-2)}[/tex]

The [tex]\cap[/tex] is called intersection ie. where are both intervals valid. First we took real numbers then we intersected them with real numbers valued less than -2 and we got real numbers which are less than -2.

Similarly we can perform with "greater than or equal to 3" real numbers,

[tex](-\infty,\infty)\cap[3,\infty)=\boxed{[3,\infty)}[/tex]

So we have one interval stretching from negative infinity to (but not including) -2, and another interval stretching from including 3 to positive infinity.

If we want numbers in both intervals we can express this two ways,

First way is to use [tex]\cup[/tex] union operator to denote we want numbers from two intervals,

[tex]\boxed{(-\infty,2)\cup[3,\infty)}[/tex]

The second way is to specify which numbers we do not want, we do not want -2 and everything up to but not including 3, which is expressed with the following interval

[tex][-2,3)[/tex]

Now we just take out the not wanted interval from real numbers and we will remain with all wanted numbers,

[tex]\boxed{(-\infty,\infty)-[-2,3)}[/tex]

Hope this helps.

I purchased a new Apple iPad on Amazon for $249.00. The tax rate is 8.625%. What is the total purchase price of the iPad?

Answers

Answer:

270.47625

Step-by-step explanation:

249 is the original price

(249/100) · 8.625 = 21.47625 the tax total

249 + 21.47625 = 270.47625

Question 3 of 10
Which angle in ABC has the largest measure?
2
С
A ZA
B. 8
C. 20
O O
D. Cannot be determined

Answers

Answer:

Option C

Angle C has the largest measure

Consider rolling a fair die twice and tossing a fair coin nineteen times. Assume that all the tosses and rolls are independent.

The chance that the total number of heads in all the coin tosses equals 9 is(Q)_____ , and the chance that the total number of spots showing in all the die rolls equals 9 is(Q)__________ The number of heads in all the tosses of the coin plus the total number of times the die lands with an even number of spots showing on top (Q)______(Choose A~E)

a. has a Binomial distribution with n=31 and p=50%
b. does not have a Binomial distribution
c. has a Binomial distribution with n=21 and p=50%
d. has a Binomial distribution with n=21 and p=1/6
e. has a Binomial distribution with n=31 and p=1/6

Answers

Answer:

Hence the correct option is option c has a Binomial distribution with n=21 and p=50%.

Step-by-step explanation:

1)  

A coin is tossed 19 times,  

P(Head)=0.5  

P(Tail)=0.5  

We have to find the probability of a total number of heads in all the coin tosses equals 9.  

This can be solved using the binomial distribution. For binomial distribution,  

P(X=x)=C(n,x)px(1-p)n-x  

where n is the number of trials, x is the number of successes, p is the probability of success, C(n,x) is a number of ways of choosing x from n.  

P(X=9)=C(19,9)(0.5)9(0.5)10  

P(X=9)=0.1762  

2)  

A fair die is rolled twice.  

Total number of outcomes=36  

Possibilities of getting sum as 9  

S9={(3,6),(4,5)(5,4),(6,3)}  

The total number of spots showing in all the die rolls equals 9 =4/36=0.1111  

3)  

The event of getting a good number of spots on a die roll is actually no different from the event of heads on a coin toss since the probability of a good number of spots is 3/6 = 1/2, which is additionally the probability of heads. the entire number of heads altogether the tosses of the coin plus the entire number of times the die lands with a good number of spots has an equivalent distribution because the total number of heads in 19+2= 21 tosses of the coin. The distribution is binomial with n=21 and p=50%.

Please help me with this

Answers

9514 1404 393

Answer:

1+3x = -89x = -30

Step-by-step explanation:

If we let x represent "a number", then "three times a number" is 3x. The usm of that and 1 is ...

  1 +3x . . . . . . the sum of 1 and 3 times a number

That is said to be -89, so we have the equation ...

  1 +3x = -89

__

To solve this equation, we can subtract 1 from both sides:

  3x = -90

Then we can divide by 3 to find x.

  (3x)/3 = -90/3

  x = -30

What is the equation of the line that passes through (-3,-1) and has a slope of 2/5? Put your answer in slope-intercept form

A: y= 2/5x -1/5
B: y= 2/5x +1/5
C: y= -2/5x -1/5

Answers

Answer:

y = 2/5x + 1/5

Step-by-step explanation:

y = 2/5x + b

-1 = 2/5(-3) + b

-1 = -6/5 + b

1/5 = b

If a and b are positive numbers, find the maximum value of f(x) = x^a(2 − x)^b on the interval 0 ≤ x ≤ 2.

Answers

Answer:

The maximum value of f(x) occurs at:

[tex]\displaystyle x = \frac{2a}{a+b}[/tex]

And is given by:

[tex]\displaystyle f_{\text{max}}(x) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

We are given the function:

[tex]\displaystyle f(x) = x^a (2-x)^b \text{ where } a, b >0[/tex]

And we want to find the maximum value of f(x) on the interval [0, 2].

First, let's evaluate the endpoints of the interval:

[tex]\displaystyle f(0) = (0)^a(2-(0))^b = 0[/tex]

And:

[tex]\displaystyle f(2) = (2)^a(2-(2))^b = 0[/tex]

Recall that extrema occurs at a function's critical points. The critical points of a function at the points where its derivative is either zero or undefined. Thus, find the derivative of the function:

[tex]\displaystyle f'(x) = \frac{d}{dx} \left[ x^a\left(2-x\right)^b\right][/tex]

By the Product Rule:

[tex]\displaystyle \begin{aligned} f'(x) &= \frac{d}{dx}\left[x^a\right] (2-x)^b + x^a\frac{d}{dx}\left[(2-x)^b\right]\\ \\ &=\left(ax^{a-1}\right)\left(2-x\right)^b + x^a\left(b(2-x)^{b-1}\cdot -1\right) \\ \\ &= x^a\left(2-x\right)^b \left[\frac{a}{x} - \frac{b}{2-x}\right] \end{aligned}[/tex]

Set the derivative equal to zero and solve for x:

[tex]\displaystyle 0= x^a\left(2-x\right)^b \left[\frac{a}{x} - \frac{b}{2-x}\right][/tex]

By the Zero Product Property:

[tex]\displaystyle x^a (2-x)^b = 0\text{ or } \frac{a}{x} - \frac{b}{2-x} = 0[/tex]

The solutions to the first equation are x = 0 and x = 2.

First, for the second equation, note that it is undefined when x = 0 and x = 2.

To solve for x, we can multiply both sides by the denominators.

[tex]\displaystyle\left( \frac{a}{x} - \frac{b}{2-x} \right)\left((x(2-x)\right) = 0(x(2-x))[/tex]

Simplify:

[tex]\displaystyle a(2-x) - b(x) = 0[/tex]

And solve for x:

[tex]\displaystyle \begin{aligned} 2a-ax-bx &= 0 \\ 2a &= ax+bx \\ 2a&= x(a+b) \\ \frac{2a}{a+b} &= x \end{aligned}[/tex]

So, our critical points are:

[tex]\displaystyle x = 0 , 2 , \text{ and } \frac{2a}{a+b}[/tex]

We already know that f(0) = f(2) = 0.

For the third point, we can see that:

[tex]\displaystyle f\left(\frac{2a}{a+b}\right) = \left(\frac{2a}{a+b}\right)^a\left(2- \frac{2a}{a+b}\right)^b[/tex]

This can be simplified to:

[tex]\displaystyle f\left(\frac{2a}{a+b}\right) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b[/tex]

Since a and b > 0, both factors must be positive. Thus, f(2a / (a + b)) > 0. So, this must be the maximum value.

To confirm that this is indeed a maximum, we can select values to test. Let a = 2 and b = 3. Then:

[tex]\displaystyle f'(x) = x^2(2-x)^3\left(\frac{2}{x} - \frac{3}{2-x}\right)[/tex]

The critical point will be at:

[tex]\displaystyle x= \frac{2(2)}{(2)+(3)} = \frac{4}{5}=0.8[/tex]

Testing x = 0.5 and x = 1 yields that:

[tex]\displaystyle f'(0.5) >0\text{ and } f'(1) <0[/tex]

Since the derivative is positive and then negative, we can conclude that the point is indeed a maximum.

Therefore, the maximum value of f(x) occurs at:

[tex]\displaystyle x = \frac{2a}{a+b}[/tex]

And is given by:

[tex]\displaystyle f_{\text{max}}(x) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b[/tex]

There is a swimming pool which has a length of 15 m and a width of 12 m. There is a 2 m wide path around the pool. If the cost of the path is $5 per , what is the cost of the path? Use words, numbers, and/or symbols to justify your answer.

Answers

Answer:

15m+12m+15m+13m=54m

2m×12m=24m

9+1+10+6×5+9+8×9+8+8+7+6+6+9+6+8+69+85+86+86+97+86+87+86+68

Answers

939

Step-by-step explanation:

hope it will help u

hope it will help u please mark me as brillient...

Answer:

939 is the answer

Step-by-step explanation:

plz Mark me as the brainlist

Find the area of a rectangle that is 4-inches-wide and 15-inches-long.

Answers

Answer:

the area of a rectangle that is 4-inches-wide and 15-inches-long =15*4=60 square inches

Width=4inLength=15in

[tex]\\ \sf\longmapsto Area=Length\times width[/tex]

[tex]\\ \sf\longmapsto Area=4(15)[/tex]

[tex]\\ \sf\longmapsto Area=60in^2[/tex]


QUESTION 2
A board is 86 cm. in lenght and must be cut so that one piece is 20 cm. longer than the other piece
Find the lenght of each piece.

A26 cm and 60 cm
b. 33 cm and 53 cm
C 30 cm and 56 cm
d. 70 cm and 16 cm

Answers

One piece will be length x and the other piece will be 20 cm longer, so it will be x + 20 cm long.  

Added together the length of these two boards will equal 86 cm. So you can write an equation:  

x + (x + 20) = 86  

Remove the parentheses and add the two x's together to get:  

2x + 20 = 86

Subtract 20 from both sides:  

2x = 66  

Divide both sides by 2 and you have:  

x = 33  

The short piece is 33 cm and the other piece is 20 cm longer or 33 + 20 = 53 cm.

Which expression is equivalent to the following complex fraction?
-25
245 5
+
y
3 2
у

Answers

Step-by-step explanation:

[tex] \longrightarrow \sf{ \dfrac{ \cfrac{ - 2}{x} + \cfrac{ 5}{y}}{\cfrac{ 3}{y} -\cfrac{ 2}{x} }} \\ \\ \longrightarrow \sf{ \dfrac{ \cfrac{ - 2y + 5x}{xy}}{\cfrac{ 3x - 2y}{xy} }} \\ \\ \longrightarrow \sf{ \cfrac{ - 2y + 5x}{xy}} \times{\cfrac{ xy}{3x - 2y} } \\ \\ \longrightarrow \boxed{ \sf{ \cfrac{ - 2y + 5x}{3x - 2y}}}[/tex]

Option A is correct!

The expression into an equivalent form would be; A [-2y + 5x ] / [3 x- 2y]

What are equivalent expressions?

Those expressions that might look different but their simplified forms are the same expressions are called equivalent expressions.

To derive equivalent expressions of some expressions, we can either make it look more complex or simple. Usually, we simplify it.

[-2/x + 5/y] / [3/y - 2/x]

This expression could also be given by;

[-2y + 5x /xy] / [3 x- 2y /xy]

Now, we know that x would cancel out;

[-2y + 5x ] / [3 x- 2y]

Hence, the expression into an equivalent form would be; A [-2y + 5x ] / [3 x- 2y]

Learn more about expression here;

brainly.com/question/14083225

#SPJ2

what is the least common factor between 9 8 and 7

Answers

7 is prime so the answer is 1

Answer:

504

Step-by-step explanation:

Using LCM the common multiple is 504 as shown in the image above.

The length L of the base of a rectangle is 5 less than twice its height H. Write the algebraic expression to model the area of the rectangle.

Answers

Answer:

Area of rectangle = 2H² - 5H

Step-by-step explanation:

Let the length be L.Let the height be H.

Translating the word problem into an algebraic expression, we have;

Length =2H - 5

To write the algebraic expression to model the area of the rectangle;

Mathematically, the area of a rectangle is given by the formula;

Area of rectangle = L * H

Where;

L is the Length.H is the Height.

Substituting the values into the formula, we have;

Area of rectangle = (2H - 5)*H

Area of rectangle = 2H² - 5H

Solve for x

X-8 = -10

A) X = 2
B) X = -2
C) X = 18
D) X = -18

Answers

Answer:

x=–2

Step-by-step explanation:

x-8=-10

x=-10-8

x=–2

Answer:

-8= -10

, = -10+8

, = -2

You need 675 mL of a 90% alcohol solution. On hand, you have a 25% alcohol mixture. How much of the 25% alcohol mixture and pure alcohol will you need to obtain the desired solution?

Answers

Answer:

90 ml of the 25 percent mixture and 585 of pure alcohol

Step-by-step explanation:

Firstly, you should find the quantity of alcohol in the desired mixture.

675:100*90= 675*0.9= 607.5

Firstly,  define all the 25 percents mixure as x, the pure alcohol weight is y.

1. x+y= 675 (because the first and the second liquid form a desired liquid).

Then find the equation for spirit

The first mixture contains 25 percents. It is x/100*25= 0.25x

When the second one consists of pure alcohol, it contains 100 percents of spirit,  so it is x.

2. 0.25x+y=607.5

Then you have a system of equations ( 1.x+y= 675 and 2. 0.25x+y= 607.5)

try 2-1 to get rid of y

x+y- (0.25x+y)= 675-607.5

0.75x= 67.5

x= 90

y= 675-x= 675-90= 585

It means that you need90 ml of the 25percents mixture and 585 0f pure alcohol

Now there is a square city of unknown size with a gate at the center of each side. There is a tree 20 b from the north gate. That tree can be seen when one walks 14 bu from the south gate, turns west and walks 1775 bu. Find the length of each side of the city.

Answers

Answer:

The length of each side of the city is 250b

Step-by-step explanation:

Given

[tex]a = 20[/tex] --- tree distance from north gate

[tex]b =14[/tex] --- movement from south gate

[tex]c = 1775[/tex] --- movement in west direction from (b)

See attachment for illustration

Required

Find x

To do this, we have:

[tex]\triangle ADE \sim \triangle ACB[/tex] --- similar triangles

So, we have the following equivalent ratios

[tex]AE:DE = AB:CB[/tex]

Where:

[tex]AE = 20\\ DE = x/2 \\ AB = 20 + x + 14 \\ CB = 1775[/tex]

Substitute these in the above equation

[tex]20:x/2 = 20 + x + 14: 1775[/tex]

[tex]20:x/2 = x + 34: 1775[/tex]

Express as fraction

[tex]\frac{20}{x/2} = \frac{x + 34}{1775}[/tex]

[tex]\frac{40}{x} = \frac{x + 34}{1775}[/tex]

Cross multiply

[tex]x *(x + 34) = 1775 * 40[/tex]

Open bracket

[tex]x^2 + 34x = 71000[/tex]

Rewrite as:

[tex]x^2 + 34x - 71000 = 0[/tex]

Expand

[tex]x^2 + 284x -250x - 71000 = 0[/tex]

Factorize

[tex]x(x + 284) -250(x + 284)= 0[/tex]

Factor out x + 284

[tex](x - 250)(x + 284)= 0[/tex]

Split

[tex]x - 250 = 0 \ or\ x + 284= 0[/tex]

Solve for x

[tex]x = 250 \ or\ x =- 284[/tex]

x can't be negative;

So:

[tex]x = 250[/tex]

The domain of a composite function (fog)(x) is the set of those inputs x in the domain of g for which g(x) is in the domain of f.

True

False

Answers

true, the correct answer is true.
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