Please help me, I need it asap

The missing step is to subtract 12 from both sides of the equation.

The step would be:

3x = -9

Answer:

x = 67 *272    = 364.48 = 364 (rounded as requested).  

Step-by-step explanation:

Use the proportion

   50 = 272  

    67      x

Answer:

I believe it is B

Step-by-step explanation:

Answer:

5 days

Step-by-step explanation:

This problem is an inverse proportion case. Having two variables: number of workers and time (in days); when we increase the number of workers, the time needed decreases; vice versa. Therefore, we can use the multiplication method: (workers * time) will always stay constant.

Let's say the time (in days) needed by the eleven workers is t,

5*20 = (3*10) + (14*t)

100 = 30+14t

70 = 14t

5 = t

It will take the eleven-workers 5 more days to finish the road.

Answer:

Step-by-step explanation:

[tex]\mathrm{Critical\:Points\:of}\:45\frac{x^4}{5}+\frac{x^9}{5}:[/tex] [tex]x=-\sqrt[5]{20},\:x=0[/tex]

Critical Point Definition:

Find where [tex]f'(x)[/tex] is equal to zero or undefined

[tex]x=-\sqrt[5]{20},\:x=0[/tex]

Identify critical points not in [tex]f(x)[/tex] domain

Domain of [tex]45\frac{x^4}{5}+ \frac{x^9}{5}: -{ \infty} < x < { \infty}[/tex]

All critical points are in domain

[tex]x=-\sqrt[5]{20},\:x=0[/tex]

Step-by-step explanation:

[tex] {x}^{2} + 2x - 2 = 0[/tex]

Now Adding three on both sides we get

[tex]{x}^{2} + 2x - 2 + 3 = 0 + 3[/tex]

[tex] {x}^{2} + 2x + 1 = 3[/tex]

[tex] {(x + 1)}^{2} = 3[/tex]

Answer:

1 day = 1440min

so 36min of a day = 36/1440 = 1/40

Answer:

Step-by-step explanation:

what percent of 7 is 3.5

3.5 is half of 7, so 100%: 2 = 50%

Answer: 50%

I have shown two methods, both work well and can be used to solve other scenarios as well.

[Method One]

     We will set up a proportion and solve.

-> A percent divided by 100 is a decimal. This means 100% = 1 in our proportion

[tex]\frac{1}{7} =\frac{x}{3.5}[/tex]

7x = 3.5

x = 0.5

0.5 * 100 = 50%

[Method Two]  

     We will put the whole value in the denominator, and the "what percent of" value is the numerator.

[tex]\displaystyle \frac{3.5}{7}[/tex]

0.5

0.5 * 100 = 50%

A) the price of the bag without discount was $120, and B) the discount on the wallet was 45%.

Given that Farhan bought a bag and a wallet at a discount from a store, and he was given a discount of 30% for the bag, and for the wallet, a discount was also given, and he saved a total of $66.60, and he paid a total of $121.40 for the 2 items and paid $46.60 more for the bag than the wallet, to determine A) what was the price of the bag without discount, and B) what was the percentage discount given for the wallet, the following calculations must be performed:

Therefore, A) the price of the bag without discount was $120, and B) the discount on the wallet was 45%.

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Answer:A) the price of the bag without discount was $120, and B) the discount on the wallet was 45%.

Step-by-step explanation:

Answer:

were is the circle to be to be equated

The  Indication of the position of port Q on the drawing is shown by using the example of the image attached.

To Indicate the position of port Q on the drawing (use the x tool).

12 * 5  = 60km

Note that S=  VT

Because 1cm represent 3km

1/3 =x/60

3x = 60

x= 60/3

x= 20

So therefore, 60km needs 20cm.

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Answer:

17, 27, 37, 47, 57, 67, 87, 97.
8

Step-by-step explanation:

all are 2 digit numbers with exactly one 7 in each.

Answer:

8

Step-by-step explanation:

Answer:

P(Not a 3)=0.85. This is option C.

Step-by-step explanation:

P(Not a 3) would include values 1,2 and 4.

Therefore, P(Not a 3) would be the combined totals of the probabilities of P(1), P(2) and P(4).

P(Not a 3)= P(1)+P(2)+P(4)

P(Not a 3)= 0.30+0.40+0.15

P(Not a 3)=0.85

Alternate method

P(Not a 3) is the same as 1-P(3)

P(Not a 3)=1-P(3)

P(Not a 3)= 1-0.15

P(Not a 3)=0.85

Answer:

559.01 i think that is rounded correctly

Step-by-step explanation:

so it did $615.99 - 9.25% = 559.010925

Hope This Is Good And Helped Sorry If i Did It Worng

Done

[tex] \pink{\underline{\boxed{8a²+a-7}}}[/tex]

Solution :-

[tex]\Longrightarrow\sf{(3a ^2 + 2a) + (5a^2 -a-7)}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex]\Longrightarrow\sf{3a^2+ 2a + 5a^2-a-7}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex]\Longrightarrow\sf{8a^2+2a-a-7}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex] \Longrightarrow\sf{8a^2+1a-7}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex]\Longrightarrow\sf{8a^2+a-7}[/tex]

[tex]\red{━━━━━━━━━━━━━━━━━━━━━━}[/tex]

Answer:

42

Step-by-step explanation:

well , here we can find the unknown variable which is X

127 = 3X+2 ( vertically opposite angles are equal)

127 = 3X+2

3x+2= 127

collecting like terms

3x = 127-2

3x = 125

dividing bothsides by 3

3x/3 = 125/3

x = 41.66

x = 42 (approximately)

Answer:

25%

Step-by-step explanation:

4 days of 16 days is 25% or 1/4

Hope this helps! ;-)

Answer:

B and D

Step-by-step explanation:

hope it helps in some way possible

Answer:

1. False

2. True

3. True

4. True

Step-by-step explanation:

A rational number is a number that can be written as a fraction of two integers. An irrational number can not be written as a fraction of two integers.

(Remember that an integer and a whole number are the same).

This means that...

All whole numbers/integers are rational.

3 is true for reasons mentioned above.

4 is just asking the same as 3.

Answer:

~36 units apart

Step-by-step explanation:

~36 units

Figure a: The area of the triangle is 13.3 sq. km.

Figure b: The area of the rectangle is 57.4 sq. cm.

Figure c: The area of the parallelogram is 45.5 sq. km.

Figure d: The area of the trapezoid is 24.36 sq. m.

The area of a two-dimensional closed figure is the total space within its boundary.

In the question, we are asked to find the area of the given shapes.

Figure a:-

It is showing a triangle.

The area of a triangle is calculated using the formula:

Area = (1/2)*Base*Height.

Thus, the area of the triangle

= (1/2)*7*3.8 sq. km

= 13.3 sq. km.

Figure b:-

It is showing a rectangle.

The area of a rectangle is calculated using the formula:

Area = Length*Width.

Thus, the area of the rectangle

= 8.2*7 sq. cm

= 57.4 sq. cm.

Figure c:-

It is showing a parallelogram.

The area of a parallelogram is calculated using the formula:

Area = Base*Height.

Thus, the area of the parallelogram

= 9.1 * 5 sq. km

= 45.5 sq. km.

Figure d:-

It is showing a trapezoid.

The area of a trapezoid is calculated using the formula:

Area = (1/2)*(Sum of parallel sides)*(height).

Thus, the area of the trapezoid

= (1/2)*(2.7 + 8.9)*4.2 sq. m.

= 11.6 * 2.1 sq. m.

= 24.36 sq. m.

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Answer:

Ricky had 1201 hits and

Pedro hade 1481 hits

Step-by-step explanation:

Let Ricky be 'y'.

Since, Pedro hit 280 mroe than Ricky.

Pedro is 'y+ 280'

Thus,

y + y+ 280 = 2682

2y = 2402

y = 1201

Ricky had 1201 hits and

Pedro hade 1201 + 280 = 1481 hits

Answer:

See below ~

Step-by-step explanation:

Let :

Solving :

Solution :

Answer:

{y,x} = {-8,-2}

Step-by-step explanation:

Hope this helps.

Answer:

A = $14,745.544

Step-by-step explanation:

The equation for compound interest is 

A = P (1+i)t 

A = final value

P = amount invested (principal) (10000)

i = interest rate, expressed as a decimal (.05)

t = number of years invested (8)

This formula assumes annual compounding.

Plugging in what we know.

A = 10000(1.05)^8

A = 10000 (1.47745544)

A = $14,745.544

Answer:

1

Step-by-step explanation:

⠀

⠀

[tex] \Large \frac{ {x}^{p(q - r)} }{ {x}^{q(p - r)} } \div {( \frac{ {x}^{q} }{{x}^{p} } })^{r} [/tex]

⠀

⠀

⠀

⠀

[tex] \sf \Large{ \frac{ {x}^{pq - pr} }{ {x}^{pq - qr} } } \div \frac{ {x}^{qr} }{ {x}^{pr} } [/tex]

⠀

⠀

⠀

[tex] \sf\Large{ \frac{ {x}^{pq - pr} }{ {x}^{pq - qr} } } \times \frac{ {x}^{pr} }{ {x}^{qr} } [/tex]

⠀

⠀

⠀

[tex] \sf {x}^{pq - pr - pq + qr} \times {x}^{pr - qr} \\ \\ \sf {x}^{qr - pr} \times {x}^{pr - qr} \\ \\ \sf {x}^{qr - qr + pr - pr} [/tex]

⠀

⠀

⠀

[tex] \sf \Large{ {x}^{0} } \\ \\ \boxed {\large {\rightarrow1 }}[/tex]

Answer:

1

Step-by-step explanation:

Solving :

⇒ [tex]\frac{x^{p(q-r)} }{x^{q(p-r)} }[/tex] ÷ [tex](\frac{x^{q} }{x^{p} })^{r}[/tex]

⇒ [tex]\frac{x^{p(q-r)} }{x^{q(p-r)} }[/tex] ÷ [tex][ ({x^{q-p} })^{r}| or| x^{r(q-p)} ][/tex]

⇒ [tex]{x}^{pq-pr-qp+qr}[/tex] ÷ [tex]x^{rq-rp}[/tex]

⇒ [tex]x^{pq-pq+qr-qr+pr-pr}[/tex]

⇒ x⁰

⇒ 1

Answer:

Step-by-step explanation:

x² + 10x + 21 = x² + (3x + 7x) + 21

                    = (x² + 3x) + (7x + 21)

                    = x(x + 3) + 7(x + 3)

                    = (x + 3)(x + 7)