The woman-canoe system has zero initial momentum. When the woman jumps from the canoe, the total momenta of the woman and canoe is conserved, so that
0 = (49 kg) (4.5 m/s) + (78 kg) v
where v is the velocity of the canoe. Solving for v, we find
(78 kg) v = - (49 kg) (4.5 m/s)
v = - 49/78 (4.5 m/s)
v ≈ -2.8 m/s
which is to say, the boat is given a velocity of 2.8 m/s to the left.
what happens to light when it travels from air into water
Answer:
Water is more dense than air. When water goes through a denser thing, the light is "bent" more towards the "normal" which is a straight, vertical line.
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A swimming pool of width 9.0 m and length 12.0 m is filled with water to a depth of 3.0 m. Calculate pressure on the bottom of the pool due to the water.
Hint: 1 m^3 of water has a mass of 1000 kg.
With the use of the formula, the pressure on the bottom of the pool due to the water is 29400 Pascal
Given that a swimming pool of width 9.0 m and length 12.0 m is filled with water to a depth of 3.0 m.
Volume = Length x Width x Height
Volume = 9 x 12 x 3
Volume = 324 [tex]m^{3}[/tex]
Since 1 m^3 of water has a mass of 1000 kg,
Mass = 324 x 1000
mass = 324000 kg
To calculate the pressure on the bottom of the pool due to the water, let us use the pressure formula below
P = δgh
where
P = pressure
δ = density of the water = 1000 kg/[tex]m^{3}[/tex]
g = Acceleration due to gravity = 9.8 m/[tex]s^{2}[/tex]
h = height = 3m
Substitute all the parameters into the formula
P = 1000 x 9.8 x 3
P = 29400 Pascal
Therefore, the pressure on the bottom of the pool due to the water is 29400 Pascal
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10. What do you think the effect is of jet airplanes on global warming?
Answer:
Like other emissions resulting from fossil fuel combustion, aircraft engines produce gases, noise, and particulates, raising environmental concerns over their global effects and their effects on local air quality.[2]Jet airliners contribute to climate change by emitting carbon dioxide (CO2), the best understood greenhouse gas, and, with less scientific understanding, nitrogen oxides, contrails and particulates. Their radiative forcing is estimated at 1.3–1.4 that of CO2 alone, excluding induced cirrus cloud with a very low level of scientific understanding. In 2018, global commercial operations generated 2.4% of all CO2 emissions.
Between 1940 and 2018, aviation CO2 emissions grew from 0.7% to 2.65% of all CO2 emissions.[1]
Jet airliners have become 70% more fuel efficient between 1967 and 2007, and CO2 emissions per Revenue Ton-kilometer (RTK) in 2018 were 47% of those in 1990. In 2018, CO2 emissions averaged 88 grams of CO2 per revenue passenger per km. While the aviation industry is more fuel efficient, overall emissions have risen as the volume of air travel has increased. By 2020, aviation emissions were 70% higher than in 2005 and they could grow by 300% by 2050.
Aircraft noise pollution disrupts sleep, children's education and could increase cardiovascular risk. Airports can generate water pollution due to their extensive handling of jet fuel and deicing chemicals if not contained, contaminating nearby water bodies. Aviation activities emit ozone and ultrafine particles, both of which are health hazards. Piston engines used in general aviation burn Avgas, releasing toxic lead.
Aviation's environmental footprint can be reduced by better fuel economy in aircraft or Air Traffic Control and flight routes can be optimised to lower non-CO2 effects on climate from NO
x, particulates or contrails. Aviation biofuel, emissions trading and carbon offsetting, part of the ICAO's CORSIA, can lower CO2 emissions. Aviation usage can be lowered by short-haul flight bans, train connections, personal choices and aviation taxation and subsidies. Fuel-powered aircraft may be replaced by hybrid electric aircraft and electric aircraft or by hydrogen-powered aircraft.
A weightlifter lifts a 350 N set of weights over his head a vertical distance of 2.5 meters above the floor. Calculate the work the athlete does on the weights, assuming he lifts them at a constant speed.
A. 525 J
B. 750 J
C. 1005 J
D. 700 N•m
E. 875 J
Help please!
3. A 75 kg linebacker moving at 6 m/s is running towards an 80 kg tackle moving 4 m/s. If they collide and stick together, how fast will they be moving after the collision?
5. A 6 kg bowling ball and a 4 kg bowling ball are rolled toward each other. The 6 kg ball is initially moving at 5.1 m/s and the 4 kg ball is moving in the opposite direction at 1.3 m/s. If the 6 kg ball slows to 1.5 m/s, what is the final speed of the 4 kg ball?
3. The sum of the players' momenta is equal to the momentum of the players when they're stuck together:
(75 kg) (6 m/s) + (80 kg) (-4 m/s) = (75 kg + 80 kg) v
where v is the velocity of the combined players. Solve for v :
450 kg•m/s - 320 kg•m/s = (155 kg) v
v = (130 kg•m/s) / (155 kg)
v ≈ 0.84 m/s
4. The total momentum of the bowling balls prior to collision is conserved and is the same after their collision, so that
(6 kg) (5.1 m/s) + (4 kg) (-1.3 m/s) = (6 kg) (1.5 m/s) + (4 kg) v
where v is the new velocity of the 4-kg ball. Solve for v :
30.6 kg•m/s - 5.2 kg•m/s = 9 kg•m/s + (4 kg) v
v = (16.4 kg•m/s) / (4 kg)
v = 4.1 m/s
The region of the globe directly beneath the Sun is warmer because it ____. A. sees more intense wavelengths reaching the surface B. is closer to the Sun C. has more yearly daylight than other parts of Earth D. receives direct sunlight
electromagnetic radiation at its maximum wavelength is:
Answer:
the radio wave. - The frequency ranges between 300 gigahertz (GHz) to 30 hertz (Hz).
Explanation:
Suppose you drop a 10-pound weight and a 5-pound weight on the Moon, both from the same height at the same time. What will happen? The 10-pound weight will hit the ground before the 5-pound weight. The 5-pound weight will hit the ground before the 10-pound weight. Both weights will float freely because everything is weightless on the Moon. Both will hit the ground at the same time.
Answer:
Both will hit the ground at the same time.
NEED HELP ASAP 40 POINTS L!!!! Jaden is interested in learning more about the basics of astrono ny and looking more closely at the sky all by himself. He wantS to get a basic starter telescope to help him with this endeavor, and his teacher SuggestS an organization that might be able to help him with this. What organization is Jaden's teacher likely referring to? The Little Astronomers Celestial Sightseeing Group The Beginning Astronomy Organization Astronomers Without BordersS
Dan is working as a family resources coordinator. Which of these statements are true about him?
Dan is responsible for overseeing the administrative functions and daily operations of a childcare center. He also helps families with children
who have special needs to uphold the rights of the children. He assists daycare teachers in carrying out their everyday duties. He also helps
families make use of early intervention services.
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The true statement about Dan is that "he also helps families make use of early intervention services."
Family resource coordinators are experts whose job it is to help families to ensure that children get along in early intervention services. They always work with families and school age children.
If Dan is working as a family resources coordinator, then a true statement about him is that "he also helps families make use of early intervention services."
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Answer:
-He also helps families make use of early intervention services.
-He also helps families with children who have special needs to uphold the rights of the children
Explanation:
Got it right on plato.
Part A
As an object moves around, on which quantities does the change in its gravitational potential energy depend? Choose all that
apply.
On average, how many stars would we have to search before we would expect to hear a signal? assume there are 500 billion stars in the galaxy.
We would have to search at least 5,000,000,000 (5 billion) stars before we would expect to hear a signal.
To find out the number of stars that we will need to search to find a signal, we need to use the following formula:
total of stars/civilizations500,000,000,000 (500 billion) stars / 100 civilization = 5,000,000,000 (5 billion)
This shows it is expected to find a civilization every 5 billion stars, and therefore it is necessary to search at least 5 billion stars before hearing a signal from any civilization.
Note: This question is incomplete; here is the complete question.
On average, how many stars would we have to search before we would expect to hear a signal? Assume there are 500 billion stars in the galaxy.
Assuming 100 civilizations existed.
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a -0.06 C charge is placed in a uniform electric field with a strength of 200 N/C. what is the magnitude and direction of the force on the charge
The magnitude and direction of the force on the charge is -12 N opposite the electric field
To calculate the force on a charge in an electric field, we make use of the formula below.
Formula
F = E×Q .......................... Equation 1
Where:
F = Force on the chargeE = Electric FieldQ = chargeFrom the question,
Given:
E = 200 N/CQ = -0.06 CSubstitute these values into equation 1
F = 200(-0.06)F = -12 NNote: The negative sign indicates that the force is in the direction negative of the electric field.
Hence, The magnitude and direction of the force on the charge is -12 N opposite the electric field
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Answer: A edge 202694020
Explanation:
Calculate the elastic potential energy stored in a spring if it has a force constant of 150 N/m. the spring is extended to a length of 0.30m
Answer:
6.75J
Explanation:
U=1/2KΔx²
U=0.5* 150*0.30^2
What is an example of bad energy efficiency but good energy conservation?
Answer:
Energy conservation relies on people cutting back on activities that consume energy—by turning off lights or driving less or using appliances less often.
Explanation:
hope this helps
A position versus time graph is shown:
Position vs. Time
1 15
10
10
Time (seconds) ->
Which statement accurately describes the motion of the object in the graph above?
O It is at rest for 3 seconds before moving at constant speed for 10 seconds.
It is at rest for 3 seconds before moving at constant speed for 4 seconds.
Olt is moving from 0 cm to 5 cm at constant speed of 7 cm/s.
O it is moving from 0 cm to 3 cm at a constant speed of 3 cm/s.
Answer: Answer: The object moves forward at 5 m/s, stops, and then changes velocity.
Explanation:
With the information given in the question we can graph the points (image attached).
As we can observe, in the first segment of the graph the velocity is increasing linearly (at a constant rate) and is 5 m/s, then in the second segment we can see the position of the object remains the same from second 2 to second 4, which means the object is stopped.
Finally, in the third and last segment, we can observe a change in velocity (at a negative constant rate, because is decreasing), which is decreasing until the object stops.
Explanation:
Chapter Name :- Vector
Question :-
A car is moving at Vc speed. Rain is falling vertically at a speed of 10 m / s. What is the value of Vc in this case,if the front glass of the car will get wet?
Answer :- Vc ≥ 10
I need Explanation! Please Don’t do copy from net! If you don’t know then no need to answer!
The value of the speed of the car, for the front glass of the car to get wet, [tex]V_c \geq 10 \ m/s[/tex].
The given parameters:
Speed of the car, = VcSpeed of the rain, = 10 m/sThe relative velocity of the car with respect to the falling rain is calculated as;
[tex]V_{C/R} = V_C- V_R[/tex]
If the speed of the car equals the speed of the rain, the rain will fall behind the car.If the speed of the rain is greater than speed of the car, the rain will fall far in front of the car.If the speed of the car is greater than speed of the rain, the rain will fall on the car.Thus, for the front glass of the car to get wet, [tex]V_c \geq 10 \ m/s[/tex].
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What is the sum of 130+125+191? A. 335. B. 456. C. 446. D. 426.
If we minus 712 from 1500, how much do we get? A. 788. B. 778. C. 768. D. 758.
50 times of 8 is equal to: A. 80. B. 400. C. 800. D. 4000.
110 divided by 10 is: A. 11. B. 10. C. 5. D. None of these.
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what is a velocity of an object with a momentum of 300 kg m/s and the mass of 100 kg
Answer:
v = 3 m/s
Explanation:
P is the momentum
m is the mass
v is the velocity
P = m•v
300 = 100•v Divide both sides per 100
300/100 = v
v = 3 m/s
[tex]\text{Given that,}\\\\\text{Momentum, p = 300 kg m s}^{-1}\\\\\text{Mass, m = 100 kg}\\\\\text{We know that,}\\\\p = mv\\\\\implies v = \dfrac pm = \dfrac{300}{100} = 3 ~ \text{m s}^{-1}[/tex]
how many band is the parametric microphone equalizer?
Answer:
3 bands
Explanation:
Basically, the Parametric EQ divides the audio spectrum into three bands, allowing you to enhance (or suppress) the level in that range.
When a projectile is launched horizontally, what is true of its acceleration as it travels through the air?
What is the centripetal acceleration?
Answer:
centripetal acceleration is when an object accelerates going in a circular motion.
the probe used in a medical ultrasound examination emits sound waves in air that have a wavelength of 0.12 mm.
Answer:
IF GOD IS TEIIING YOU SOMETHING JUST DO IT
Explanation:
In which scenario is work being done on an object?
a) A force is applied to an object to hold it at rest on an inclined plane.
b) Sitting on a box.
c) An upward force is applied to an object to move it upward at a constant speed.
d) An upward force is applied to an object to suspend it motionless in mid-air.
Answer:c
Explanation:
To solve this, we must know each and every concept related to work. Therefore, the correct option is option C that is "an upward force is applied to an object to move it upward at a constant speed."
What is work?Work in physics is the energy delivered to or out of an item by applying force across a displacement. It is frequently expressed in its most basic form as the combination of displacement and force.
When a force is applied, it is said to produce positive work if it has a portion in the directions of the movement of the site of application. Work is done on a body is equivalent to an increase in the body's energy, because work transmits energy to the body. If, on the other hand, the force acting is in the opposite direction as the item's motion, the work is regarded negative, suggesting that energy is withdrawn from the object.
Therefore, the correct option is option C that is "an upward force is applied to an object to move it upward at a constant speed."
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What is the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s2?
Answer:
This is the answer that I got.
Explanation:
Hope it is right.
A type of matter in which two or more elements are combined
chemically is called a _______
Answer:
COMPOUND
Explanation:
what do i do on this rubixs cube
Answer:
You solve it
Explanation:
Answer:
you just spin it and spin it and spin it and spin it
and spin it
and spin it
and spin it
and spin it
until you get mad then throw it at the wall
Explanation:
ya then you look up a vid that is called rubix cube meme and there should be a pink animal its funny you should watch it!!!!!!!!!
1) A blinking light of constant period is situated on a lab cart. Which diagram best represents a photograph of
the light as the cart moves with constant velocity?
How do I solve this?
Option C with uniform displacement at each time interval represents the photograph of light as the cart moves with constant velocity.
At constant velocity, the change in displacement with time is uniform. The displacement of the given object in motion increases at equal rate.
At constant velocity, the initial velocity is equal to the final velocity.
v₁ = v₂
The acceleration of the object at constant velocity is zero, because the change in velocity with time will be zero.
[tex]a = \frac{\Delta v}{\Delta t} \\\\a = \frac{v_2- v_1}{t} \\\\v_2 = v_1\\\\a = \frac{v_1 - v_1}{t} \\\\a = 0[/tex]
Thus, from the given options we can conclude that option C with uniform displacement at each time interval represents the photograph of light as the cart moves with constant velocity.
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Hi, please help! •_•
One workman is measured as having a power of 528W. His weight is 800N. He can develop the same power climbing a ladder, whose rungs are 30cm apart. How many rungs can he climb in 5s?
Answer:
He can climb 11 rungs
Explanation:
Power = 528W, Force = 800N, Time= 5s Total Distance moved = 30x cm or 0.3x m, where x is the number of rungs he climbed
Power = Work done/time
Work done = Power × time
= 528 × 5
= 2640Joules
Also Work done = Force × total distance moved
Total Distance moved = Work done/force
0.3x = 2640/800
0.3x = 33
x = 3.3/0.3
x = 11
An object’s mechanical energy is
a
its energy of motion.
b
the sum of its potential (position) energy and kinetic (motion) energy.
c
the waste energy it produces by friction.
d
not related to the object’s mass.
Explanation:
the sum of its potential (position) energy and kinetic (motion) energy.
