A car is traveling at a rate of 72 miles per hour. What is the car's rate in feet per second? How many feet will the car travel in 2 seconds? In your computations,
use the fact that I mile is equal to 5280 feet. Do not round your answers,

Answer:

6.) No, you do not agree with Ted.

7.) x = 34 degrees

Step-by-step explanation:

6.) For a triangle to be valid, it must meet these requirements:

a+b>c

a+c>b

b+c>a

If it fails a single one, then it is invalid.

For example: 6+11 is not greater than 4. Therefor, Ted is incorrect

7.) Though you see a square, or rectangle (whatever you want to call it), you can break it up into 2 triangle, only 1 of which you need to solve for.

We have these clues:

angle 1 = x

angle 2 = 56 degrees

angle 3 is a right angle

Any triangle must have its angles sum to 180 degrees

We also know that right angles are equal to 90 degrees.

Our updated clues:

angle 1 = x

angle 2 = 56 degrees

angle 3 = 90 degrees

angles 1+2+3 must equal 180

So we can make this equation:

x+56+90=180

Add like terms and solve for x:

x = 34

[tex] {\large\underline{\sf{Solution-}}}[/tex]

Given function is

[tex]\rm \longmapsto\:y = \sqrt{ {x}^{2} - 4} [/tex]

We know

Domain of a function is defined as set of those real values of x for which function is well defined.

So, y is defined when

[tex]\rm \longmapsto\: {x}^{2} - 4 \geqslant 0[/tex]

[tex]\rm \longmapsto\: {x}^{2} - {2}^{2} \geqslant 0[/tex]

[tex]\rm \longmapsto\: (x - 2)(x + 2) \geqslant 0[/tex]

[tex]\rm\implies \:x \leqslant - 2 \: \: or \: \: x \geqslant 2[/tex]

[tex]\rm\implies \:x \: \in \: ( - \infty , \: - 2] \: \cup \: [2, \: \infty )[/tex]

Now, To find the range of function

We know,

Range of a function is defined as set of those real values which is obtained by assigning the values to x.

So,

[tex]\rm \longmapsto\:y = \sqrt{ {x}^{2} - 4} [/tex]

On squaring both sides, we get

[tex]\rm \longmapsto\: {y}^{2} = {x}^{2} - 4[/tex]

[tex]\rm \longmapsto\: {y}^{2} + 4= {x}^{2}[/tex]

[tex]\rm \longmapsto\:x = \sqrt{ {y}^{2} + 4 } [/tex]

Now, x is defined when

[tex]\rm \longmapsto\: {y}^{2} + 4 \geqslant 0 \: which \: is \: always \: true \: \forall \: y \in \: real \: number[/tex]

But,

[tex]\rm \longmapsto\:y \geqslant 0[/tex]

Hence,

[tex]\rm\implies \:Range \: of \: function \: = [0, \: \infty )[/tex]

So, we have

[tex]\rm\implies \:Domain \: of \: function : x \: \in \: ( - \infty , \: - 2] \: \cup \: [2, \: \infty )[/tex]

and

[tex]\rm\implies \:Range \: of \: function \: = [0, \: \infty )[/tex]

Answer:

£4.52

Step-by-step explanation:

£13.56/3

*What you should know*

Point slope form,

y-y1=m(x-x1)

Parallel lines have the same slope.

1. Points (4,2)

y=2

x=4

m=-3/4

substitute this information into the point-slope form formula,

》y-2=-3/4(x-4)

2.

y=-3

x=-3

m=7/3

》y-(-3)=7/3(x-(-3))

3.(-4,0)

y=0

x=4

m=3/4

》y-0=3/4(x-4)

4. (-1,4)

y=4

x=-1

m=-5

》y-4=-5(x-(-1))

brianlist me?

Answer:

OK so I don't know the answer but there is something called calculator soup and it has a million kinds of calculators lemme give u the link

Step-by-step explanation:

calculatorsoup.com

Answer:

420

Step-by-step explanation:

130/100x = 546

x=54600/130

x=5460/13

x=420

Answer:

switched signs around

Step-by-step explanation:

I believe that s/he switched the signs around so

|x|>5 is solved by x<-5 and x>5

but I'm not quite sure, sorry

Answer:

A. 248 square CM

B. 240 cubic CM

Step-by-step explanation:

length of missing side = sqrt(5^2 + 12^2) = sqrt(169) = 13

distance = sqrt(50^2 +25^2) =sqrt(3125)= 55.90metres

Answer:

always first sum

Step-by-step explanation:

for example: 1+2/1-2=3

                     2+2/2-1=4

Answer:

B

Step-by-step explanation:

untuk p'

gerak kebawah dr garisan x sebanyak 3 kotak

p'= (-3,10)

untuk p''

disebabkan y=x

terbalikkan nilai p'

p''=(10,-3)

Answer:

shorter piece is 28.8 inches

Step-by-step explanation:

Answer28.8

Step-by-step explanation:

28.8 x 5 = 144

Answer:

Below.

Step-by-step explanation:

7)  c^2 = a^2 + b^2

15^2 = 11^2 + b^2

b^2 = 225 - 121 = 104

b = √104

= √4√26

= 2√26.m

8). 4^2 = a^2 + (√6)^2

a^2 = 16 - 6

a^2 = 10

a =  √10.

Answer:

7

Step-by-step explanation:

Answer:

A Benjamin Franklin

B George Washington

C Abraham Lincoln

D John Adams

Answer:

ATC is congruent to DOG by ASA axiom for congruency

Answer: ATC = DOG

Step-by-step explanation:

3(x - 2) = 22 - x

3x - 6 = 22 - x

3x + x = 22 + 6

4x = 28 / : 4

x = 7

Only one solution

Answer:

-72

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]a^{-m}=\dfrac{1}{a^{m}}\\\\8^{-3}=\dfrac{1}{8^{3}}=\dfrac{1}{8*8*8}=\dfrac{1}{512}[/tex]

Answer:

If joint frequency isn't an option it is Marginal frequency

Answer:

a

Step-by-step explanation:

[tex]c^{3} - 10[/tex]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

Answer:

Simplifying

-5 + -1(3a + b) + (2a + -7b) = 0

-5 + (3a * -1 + b * -1) + (2a + -7b) = 0

-5 + (-3a + -1b) + (2a + -7b) = 0

Remove parenthesis around (2a + -7b)

-5 + -3a + -1b + 2a + -7b = 0

Reorder the terms:

-5 + -3a + 2a + -1b + -7b = 0

Combine like terms: -3a + 2a = -1a

-5 + -1a + -1b + -7b = 0

Combine like terms: -1b + -7b = -8b

-5 + -1a + -8b = 0

Solving

-5 + -1a + -8b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '5' to each side of the equation.

-5 + -1a + 5 + -8b = 0 + 5

Reorder the terms:

-5 + 5 + -1a + -8b = 0 + 5

Combine like terms: -5 + 5 = 0

0 + -1a + -8b = 0 + 5

-1a + -8b = 0 + 5

Combine like terms: 0 + 5 = 5

-1a + -8b = 5

Add '8b' to each side of the equation.

-1a + -8b + 8b = 5 + 8b

Combine like terms: -8b + 8b = 0

-1a + 0 = 5 + 8b

-1a = 5 + 8b

Divide each side by '-1'.

a = -5 + -8b

Simplifying

a = -5 + -8b

Step-by-step explanation:

Answer:

Hundreds :)

Step-by-step explanation:

Answer:

3rd option

Step-by-step explanation:

a point (0, y ) lies on the y- axis

a point (x, 0 ) lies on the x- axis

a point (x, y ) lies in I quadrant

a point (- x, y ) lies in II quadrant

a point (- x, - y ) lies in III quadrant

a point (x, - y ) lies in IV quadrant

Then

point (2, - 5 ) lies in IV quadrant

-----------------------------------------------------------------

We require 2 equations with the repeating digit 7 placed after the decimal point.

let x = 0.427777... ( multiply both sides by 100 and 1000 )

100x = 42.777..... (1)

1000x = 427.777.... (2)

Subtract (1) from (2), thus eliminating the repeating digits

900x = 385 ( divide both sides by 900 )

x = [tex]\frac{385}{900}[/tex] = [tex]\frac{77}{180}[/tex]

d= 1- 4bh

Step-by-step explanation:

- 8b = 2d - 2/h

Multiply both sides of the equation by h.

- 8bh = 2d - 2

Swap sides so that all variable terms are on the left-hand side.

2d - 2 = - 8bh

Add 2 to both sides.

2d = - 8bh + 2

The equation is in standard form.

2d = 2 - 8bh

Divide both sides by 2.

2d/2 = 2 - 8bh/2

Dividing by 2 undoes the multiplication by 2.

d = 2 - 8bh/2

Divide -8bh + 2 by 2.

Therefore: d = 1 - 4bh

Answer:

87w

Step-by-step explanation:

If she has $76 in her accoumt

and receives $11every week

76+11=$87

she would have$87xw in w amount of weeks

Answer:

Step-by-step explanation:

Mira has $76 in her bank account and receives $11 in allowance every week. Write and expression to represent how much money she after w amount of weeks

----------------------------

76 + (11w)

Answer:

18

Step-by-step explanation:

The boys collected:

12 · 16 = 192

The girls collected:

15 · 14 = 210

So the girls collected 18 more cans more than the boys.

(Integers calculation)

Answer: no.of days in 5 weeks= 5× 7= 35

ratio of 5 days to 5 weeks= 5/35

=1/7

answer= 1:7

Step-by-step explanation: .

Answer:

D

Step-by-step explanation:

Side andle side