Blank × 100 =23 find the missing number

[tex]\sf\large\underline{\star Given:-}[/tex]

[tex]\rightarrow[/tex] Length of rectangular prism = [tex]\sf\red{4m}[/tex]

[tex]\rightarrow[/tex] Width of rectangular prism = [tex]\sf\red{7m}[/tex]

[tex]\rightarrow[/tex] Height of rectangular prism = [tex]\sf\red{8.5m}[/tex]

[tex]\sf\large\underline{\star To \: Find:-}[/tex]

[tex]\sf\large\underline{\star Solution:-}[/tex]

[tex]\rightarrow[/tex] We can find the volume of given rectangular prism by using the formula:

[tex]\sf\blue{Length × Width ×Height}[/tex]

So, let's begin:

[tex]\rightarrow[/tex] Volume of rectangular prism = [tex]\sf{Length × Width ×Height}[/tex](putting the value of length, width and height from the above given)

[tex]\rightarrow[/tex][tex]\sf{=\:4× 7 ×8.5}[/tex]

[tex]\rightarrow[/tex][tex]\sf{=\:28×8.5}[/tex]

[tex]\rightarrow[/tex][tex]\sf{=\:238m^3}[/tex]

Therefore, volume of the given rectangular prism = [tex]\sf\purple{238m^3.}[/tex]

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Hope it helps you:)

Answer:

The power is 32 because that is what 2 to th 5 is , 2 is the base as its the number being multiplied 5 times which leaves 2 as the exponent.

Answer:

  A and C

Step-by-step explanation:

We can eliminate poor choices by estimating their relative sizes. And we can check the remaining choices by finding the exact volumes.

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A hemisphere with radius 2, or a cone with dimensions of 4 or less, will have a much smaller volume than a sphere with radius 14. A cylinder with dimesions smaller than those of the sphere will have a smaller volume.

So, the only figures that might have similar volumes are the hemisphere and the cone.

  V = 1/2(4/3)πr³ = 2/3π(2 cm)³ = 16/3π cm³

  V = 1/3πr²h = 1/3π(2 cm)²(4 cm) = 16/3πcm³

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The hemisphere (A) and the cone (C) have the same volume.

Answer:

63 km

Step-by-step explanation:

Given :

Solving :

Convert minutes into hours so that the units are equal, otherwise your answer will not be correct.

Calculating distance

Answer:

frist convert 315k/h into m/s

then convert 12min into sce

=12*60

=720

distance = v*t

=315*720

=226800m

Answer:

Jenna's line would be: C Line L

Step-by-step explanation:

The x coordinates and y coordinates from Jenna's table matches up with the points on Line L. Hope this helped! :)

Answer:

heya! ^^

we've been given an expression which is as follows -

[tex]4 {}^{2} - \sqrt{25} [/tex]

let's deal with this expression by dividing it into two separate parts which may help understand better.

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★ let's first deal with the first part which is - [tex]4 {}^{2} [/tex]

now ,

[tex]4 {}^{2} \: can \: also \: be \: written \: as \\ \\ 4 {}^{2} = 4 \times 4 \\ 4 {}^{2} = 16[/tex]

★ now , let's consider the second part which is - [tex] \sqrt{25} [/tex]

this can also be written as " 5 " since ,

[tex] \sqrt{25} = 5[/tex]

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let's have a look at the entire expression altogether now.

[tex]4 {}^{2} - \sqrt{25} \\ \\\dashrightarrow 16 - 5 \\ \\ \dashrightarrow \: 11[/tex]

hope helpful :D

Answer:

post your question and someone will respond

Answer:

Eleanor has made an error in Step 1

She clearly intended to multiply both sides by 2, but forgot to multiply the [tex]-9x[/tex] part of the RHS.

Step 1 should be:   [tex]x+18=8(2x-6)-18x[/tex]

Correct solution

Given:   [tex]\dfrac12(x+18)=4(2x-6)-9x[/tex]

Step 1:  [tex]x+18=8(2x-6)-18x[/tex]

Step 2:  [tex]x+18=16x-48-18x[/tex]

Step 3:  [tex]x+18=-48-2x[/tex]

Step 4:  [tex]66=-3x[/tex]

Step 5:  [tex]x=-22[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's solve ~

Take (3x + 5) common in there :

[tex]\qquad \tt \dashrightarrow \:x(3x + 5) - 4(3x + 5)[/tex]

[tex]\qquad \tt \dashrightarrow (3x + 5) (x - 4)[/tex]

So, choice D is correct

Answer:

college c

Step-by-step explanation:

bc its the least amount of money and has the second highest loan default

Step-by-step explanation:

Here,let x = 1,2,3 and 4

Then,

Domain =(1,2,3,4)

Again,

f(1)= 3*1 + 5

=3 + 5

=8

f(2)=3*2 + 5

=6 + 5

=11

f(3)=3*3 + 5

=9 + 5

=14

f(4)=3*4 + 5

=12 + 5

=17

Therefore, Range=(8,11,14,17)

[tex]\textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=5.7\\ h=10 \end{cases}\implies \begin{array}{llll} V=\pi (5.7)^2(10)\implies V=324.9\pi \\\\\\ V\approx 1020.7 \end{array}[/tex]

Answer: A sequence is a type of function. Remember, a function is any formula that can be expressed in "f(x) = x" format, but a sequence only contains integers at or greater than zero.

Hope this helps! Have a good day! :)

Step-by-step explanation:

p(x)=x³-1

p(-1)=(-1)³-1=(-1)-1=(-2)

p(-1)=(-2)

p(1)=(1)³-1=1-1=0

p(1)=0

Answer:

One triangle

Step-by-step explanation:

I hope this helps :)

Answer:

x² - 6x = 7

x² - 6x + 9 = 7 + 9

(x - 3)² = 16

x - 3 = ± 4

x - 3 = 4 and x - 3 = -4

x: {-1, 7}

Largest value of x = 7

Smallest value of x: -1

I hope this helps!

Answer:

The answer is true

Step-by-step explanation:

hope this helps

Answer:

  A, D

Step-by-step explanation:

You want to know the bound for the values of Sn and Tn, given their definitions as ...

  [tex]\displaystyle S_n=\sum_{k=1}^n{\dfrac{n}{n^2+kn+k^2}}\\\\T_n=\sum_{k=1}^{n-1}{\dfrac{n}{n^2+kn+k^2}}[/tex]

All we need to do to determine the correct answer choices is evaluate the sums for some value of n.

For n=2, the value of S2 is ...

  S2 = 2/(4+2+1) +2/(4+4+4) = 2/7 +2/12 = 19/42 ≈ 0.4524

For n=2, the value of T2 is ...

  T2 = 2/(4+2+1) = 2/7 ≈ 0.2857 . . . . . 1/(3n) less than the value of Sn

Both of these values are less than π/(3√3) ≈ 0.6046.

The correct answer choices are ...

  A) Sn < π/(3√3)

  D) Tn < π/(3√3)

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Additional comment

For the purpose here, it is not necessary to determine the limiting value of either Sn or Tn. It is only necessary to demonstrate which side of the given value the terms of either sequence lie.

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Answer:

Width = 10 inches

Step-by-step explanation:

A cube is a six-sided shape where each side consists of a square. Since the length of a square is the same measure of the width, then the cube will "work the same way", and the length, width, and height of the cube will all be the same length.

Answer:

Step-by-step explanation:

Circumference is given by the formulas :

[tex]2\pi r[/tex] or [tex]\pi d[/tex]

Since we are given the diameter we can use the second one :

We are told to use 3.14 for π :

C = (3.14)×(16)

C = 50.24

Area of a circle is given by the formula:

[tex]\pi r^{2}[/tex]

To work out r we simply half the diamter:

16÷2 = 8

Now we put this into the area formula:

π(8)² = 64π

We are told to use 3.14 as pi so:

64π = 64×3.14 = 200.96

Answer:

Circumference = 50.24 in

Area = 200.96 in²

Step-by-step explanation:

First, let us find the circumference of the circle.

For that, let us use this formula.

C = π d

Given that,

d ⇒ diameter ⇒ 16 in

Let us find now.

C = π d

C = 3.14 × 16

C =  50.24 in

And now let us find the area of the circle.

Before that, let us find the radius.

d = 2r

16 = 2r

Divide both sides by 2.

8 in ⇒ radius

Let us use the below formula to find the area of the circle.

A = π r²

A = 3.14 × 8 × 8

A = 200.96 in²

Answer:

Minimum

Step-by-step explanation:

The zeros of a quadratic equation are the points at which the parabola intersects the x-axis.

[tex]\sf x=3 \implies x-3=0[/tex]

[tex]\sf x=7 \implies x-7=0[/tex]

[tex]\sf \implies y=a(x-3)(x-7)[/tex]   (for some constant a)

[tex]\sf \implies y=ax^2-10ax+21a[/tex]

The optimal value is the y-coordinate of the vertex.  

[tex]\sf \implies vertex=(x,-3)[/tex]

The x-coordinate of the vertex is the midpoint of the zeros:

[tex]\sf x=\dfrac{7-3}{2}+3=5[/tex]

[tex]\sf \implies vertex=(5,-3)[/tex]

Therefore, the vertex will be in Quadrant IV and so the parabola opens upwards into Quadrant I.  

So the optimal value is a MINIMUM since the vertex is the minimum point of the curve.

Additional Information to create the equation of the quadratic

Vertex form of quadratic equation:  [tex]\sf y=a(x-h)^2+k[/tex]

where (h, k) is the vertex

[tex]\sf \implies y=a(x-5)^2-3[/tex]

[tex]\sf \implies y=ax^2-10ax+25a-3[/tex]

To find the value of a, compare the constants of both equations:

[tex]\sf 21a=25a-3[/tex]

[tex]\sf \implies -4a=-3[/tex]

[tex]\sf \implies a=\dfrac34[/tex]

So the final equation is:

[tex]\sf factor \ form \implies y=\dfrac34(x-3)(x-7)[/tex]

[tex]\sf standard \ form\implies y=\dfrac34x^2-\dfrac{15}{2}x+\dfrac{63}{4}[/tex]

[tex]\sf vertex \ form \implies y=\dfrac34(x-5)^2-3[/tex]

Answer: 907.46

Step-by-step explanation:

it goes through the point (2, 10), has a vertex at (5, 1) and goes through the point (8, 10)

Answer:

statements 2 & 5 are true

Step-by-step explanation:

1. False because is a quadratic nonlinear equation

2. True, 4 is the ordered to the origin

3. False, the rate not being linear is not constant

4. False, because when the input is -3 the output is 13

         [tex]y = (-3)^{2} +4=9+4=13[/tex]

5. True, y depends on x

Hope this helps

they easiest way to find the right answer is to look at the 2 first terms and checking if they equal 64x³

doing so:

A:

48x³+...

B:

64x³+...

C:

9x³-48x³+...

= -39x³+...

-> the answer should be B, to make sure this is the right answer, you can just solve B

B:

(4x+3)(16x²-12x+9)

= 64x³- 48x²+36x+48x²-36x+27

= 64x³+27

-> answer B is correct

Answer:

We know that to reverse a number, we should swap the numbers in TENS and ONES position. Therefore, the general form of its reverse 'ba' is (10 \times b) + a. Let us try to find the sum of both these numbers. Therefore, the sum of two-digit numbers and their reverse is always a multiple of 11.

Step-by-step explanation:

#carryonlearning

Brainlest me please