(b) Express the prime number 43 as the difference of two squares? 43 =​

Answer:

-4y^2 + 4x +4

Step-by-step explanation:

add -y^2 and -3y^2 = -4y^2

add 2x + 2x = 4x

add 3+1 = 4

and then rearrange

Answer:

The answer is in the picture below

Step-by-step explanation:

Sorry just realised the answers were different ;-;

Answer:

The arm spans for Class A are roughly symmetric, while those for Class B are skewed left.

Step-by-step explanation:

Answer: Choice A) M = 0.25n + 100

=============================================================

Explanation:

For now, I'll treat n as x, and M as y.

In other words,

Let's select two points from this graph. I'll pick (200,150) and (400,200)

The slope of the line through those points is

m = (y2-y1)/(x2-x1)

m = (200-150)/(400-200)

m = 50/200

m = 0.25

Now we'll use the point (x,y) = (200,150) along with that slope value to find the y intercept b

y = mx+b

150 = 0.25*200+b

150 = 50+b

150-50 = b

100 = b

b = 100

You could also use (x,y) = (400,200) and you should get the same b value.

In fact, any other point from this graph works as well.

------------------------------

Since m = 0.25 and b = 100, we go from y = mx+b to y = 0.25x+100

This then translates over to M = 0.25n + 100 which is choice A

To help verify this, let's say we plugged in n = 100

M = 0.25*n + 100

M = 0.25*100 + 100

M = 25 + 100

M = 125

Which is confirmed by what the graph shows. I'll let you check the other points as well.

Answer:

Yes, because there are two pairs of congruent corresponding angles

Step-by-step explanation:

Two triangles are similar if they have the same angles. For triangle UVT on the left, we know that the sum of angles in a triangle is 180 degrees. There is one missing angle there, so the sum of angles is

80 + 55 + missing angle = 180

subtract 80+55 = 135 from both sides

45 = missing angle

Therefore, the angles in UVT are 45, 55, and 80

Similar, for XWY,

missing angle + 45 + 55 = 180

subtract 45 + 55= 100 from both sides

missing angle = 80

The angles for XWY are 45, 55, and 80. The angles are the same for both triangles, and there are three pairs of congruent corresponding angles (45, 55, and 80). Therefore, the triangles are similar

Answer:

(2,0)

Step-by-step explanation:

the x intercept is when 'y' is equal to 0 :

0 = 3x - 6

6 = 3x

x = 2

Answer:

(2,0)

Step-by-step explanation:

y = 3x-6

The x intercept is found by setting y = 0 and solving for x

0 = 3x-6

Add 6 to each side

6 = 3x-6+6

6 =3x

Divide each side by 3

6/3 = 3x/3

2 =x

The x intercept is

(2,0)

Step-by-step explanation:

Hey there!

[tex]f(x) = 3. {4}^{x} [/tex]

Then;

[tex]f(3) = 3. {4}^{3} [/tex]

[tex]f(3) = 192[/tex]

Therefore, f(3) = 192.

Hope it helps!

9514 1404 393

Answer:

  24

Step-by-step explanation:

The front face is an 8-sided star, so has 8 edges. We presume the back face is the same, so it also has 8 edges. Each of the front vertices is connected by an edge to each of the corresponding back vertices, so there are 8 more edges connecting front and back.

The total number of edges is 8 + 8 + 8 = 24.

Answer:

The figure is not symmetrical

Answered by GAUTHMATH

Answer:

It's too short. Write at least 20 characters to explain it well.

Answer:

Step-by-step explanation:

one angle is 50

9514 1404 393

Answer:

  [tex]\left[\begin{array}{ccc}0&-1&-2\\0&-3&5\end{array}\right][/tex]

Step-by-step explanation:

The rotation matrix for 90° CCW is ...

  [tex]\left[\begin{array}{cc}0&-1\\1&0\end{array}\right][/tex]

Then the rotated coordinates are ...

  [tex]\left[\begin{array}{ccc}0&-1\\1&0\end{array}\right]\cdot\left[\begin{array}{ccc}0&-3&5\\0&1&2\end{array}\right]=\left[\begin{array}{ccc}0&-1&-2\\0&-3&5\end{array}\right][/tex]

_____

The transformation of each ordered pair is ...

  (x, y) ⇒ (-y, x)

Answer:

Step-by-step explanation:

Answer:

hope u will understand...if u like this answer plz mark as brainlist

Answer:

[tex]\displaystyle p(x) + q(x) = \frac{2x}{(x+1)(x-1)}[/tex]

The result is indeed another rational expression.

Step-by-step explanation:

We are given the two functions:

[tex]\displaystyle p(x) = \frac{1}{x+1}\text{ and } q(x) = \frac{1}{x-1}[/tex]

And we want to perform the operation:

[tex]\displaystyle p(x) + q(x)[/tex]

And show that the result is another rational expression.

Add:

[tex]\displaystyle = \frac{1}{x+1} + \frac{1}{x-1}[/tex]

To combine the fractions, we will need a common denominator. So, we can multiply the first fraction by (x - 1) and the second by (x + 1):

[tex]\displaystyle = \frac{1}{x+1}\left(\frac{x-1}{x-1}\right) + \frac{1}{x-1}\left(\frac{x+1}{x+1}\right)[/tex]

Simplify:

[tex]=\displaystyle \frac{x-1}{(x+1)(x-1)} + \frac{x+1}{(x+1)(x-1)}[/tex]

Add:

[tex]\displaystyle = \frac{(x-1)+(x+1)}{(x+1)(x-1)}[/tex]

Simplify. Hence:

[tex]\displaystyle p(x) + q(x) = \frac{2x}{(x+1)(x-1)}[/tex]

The result is indeed another rational expression.

Answer:

-2 <× <35

i hop i helped you sold the question

9514 1404 393

Answer:

  x = √2

Step-by-step explanation:

A graph indicates the only solution is near x=√2.

__

Square both sides, separate the radical and do it again.

  [tex]\displaystyle(2-x)\sqrt{\frac{x+2}{x-1}}=\sqrt{x}+\sqrt{3x-4}\qquad\text{given}\\\\(2-x)^2\cdot\frac{x+2}{x-1}=x+(3x-4)+2\sqrt{x(3x-4)}\qquad\text{square}\\\\\frac{(2-x)^2(x+2)}{x-1}-4x+4=2\sqrt{x(3x-4)}\qquad\text{isolate radical}\\\\\left(\frac{(2-x)^2(x+2)-4(x-1)^2}{x-1}\right)^2=x(3x-4)\qquad\text{square}\\\\(x^3-6x^2+4x+4)^2=4(x-1)^2(3x^2-4x)\qquad\text{multiply by $(x-1)^2$}[/tex]

Now, we can put this polynomial equation into standard form and factor it.

  [tex]x^6 -12x^5+32x^4-76x^2+48x+16=0\\\\(x-2)^2(x^2-2)(x^2-8x-2)=0\qquad\text{factor it}\\\\x\in \{2,\pm\sqrt{2},4\pm3\sqrt{2}\}[/tex]

The original equation requires that we restrict the domain of possible solutions. In order for the radicals to be non-negative, we must have x ≥ 4/3. In order for the left side of the equation to be non-negative, we must have x ≤ 2. So, the only potential solutions will be in the interval [4/3, 2].

The only values in the above list that match this requirement are {√2, 2}. We know that the right side of the equation cannot be zero, so the value x=2 is also an extraneous solution.

The only solution is x = √2.

_____

Additional comment

For solving higher-degree polynomials, I like to use a graphing calculator to help me find the roots. The second attachment shows the roots of the 6th-degree polynomial. They can help us factor the equation. (There are also various machine solvers available that will show factors and roots.)

Answer:

1.

An extraneous solution is a root of a transformed equation that is not a root of the original equation as it was excluded from the domain of the original equation.

It emerges from the process of solving the problem as a equation.

2.I begin like:

The vertical asymptotes will occur at those values of x for which the denominator is equal to zero:

for example:

x² − 4=0

x²= 4

doing square root on both side

x = ±2

Thus, the graph will have vertical asymptotes at x = 2 and x = −2.

To find the horizontal asymptote, the degree of the numerator is one and the degree of the denominator is two.

Answer:

53.68

Step-by-step explanation:

tan54 = bc/39

bc = 39tan54

Step-by-step explanation:

Hey there!

From the given figure;

Angle CAB = 54°

Side AC = 39

To find: side BC

Taking Angle CAB as reference angle;

Perpendicular (p) = BC = ?

Base (b) = AC = 39

Hypotenuse (h) = AB

Taking the ratio of tan;

[tex] \tan( \alpha ) = \frac{p}{b} [/tex]

Keep value;

[tex] \tan(54) = \frac{bc}{39} [/tex]

Simplify it;

1.376381*39 = BC

Therefore, BC = 53.678.

Hope it helps!

Given:

The given expression is:

[tex]6x^2y-3xy-24xy^2+12y^2[/tex]

To find:

Part A: The expression by factoring out the greatest common factor.

Part B: Factor the entire expression completely.

Solution:

Part A:

We have,

[tex]6x^2y-3xy-24xy^2+12y^2[/tex]

Taking out the highest common factor 3y, we get

[tex]=3y(2x^2-x-8xy+4y)[/tex]

Therefore, the required expression is [tex]3y(2x^2-x-8xy+4y)[/tex].

Part B:

From part A, we have,

[tex]3y(2x^2-x-8xy+4y)[/tex]

By grouping method, we get

[tex]=3y(x(2x-1)-4y(2x-1))[/tex]

[tex]=3y(x-4y)(2x-1)[/tex]

Therefore, the required factored form of the given expression is [tex]3y(x-4y)(2x-1)[/tex].

QUESTION:- SOLVE EQUATION BY FACTORISATION

EQUATION:-

[tex] {x}^{2} + x - 72 = 0[/tex]

ANSWER:-

[tex] {x}^{2} + x - 72 = 0\\{x}^{2} + 9x - 8x - 72 = 0 \\ x(x + 9) - 8(x +9) = 0 \\ (x - 8)(x + 9) = 0 \\ [/tex]

NOW FOR VALUE OF X ->

[tex]x - 8 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x + 9 = 0\\ x = 8 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = - 9[/tex]

Answer:

where is your diagram?

Step-by-step explanation:

Answer:

the answer is 56 cubic units

Hey there! Is there more text to this? I would love to help, but there is no question.

a-7=3(b+2)

1. Simplify/Combine like terms

a-7=3b+6

2. Remove a variable

a-7-a=3b+6-a

7=2b+6

3. Isolate the variable

7-6=2b-6

1=2b

4. Divide

1/2=2b/2

b=1/2

1/2g?

9514 1404 393

Answer:

  smaller : larger = 3 : 4

Step-by-step explanation:

The scale factor is the ratio of corresponding dimensions. If we use the width dimensions, we have ...

  smaller/larger = 9/12 = 3/4

The scale factor is 3/4.

Answer:

Z = (42-20)/4 = 5.5

Z = X-μ / σ

Step-by-step explanation:

The z-score for the data value of 42 is 5.5.

A z-score is defined as the fractional representation of data point to the mean using standard deviations.

Formula of z-score = (X - μ) / σ

Given,

μ = 20

σ = 4

X = 42

z-score = (X - μ) / σ

Substitute the values,

z-score =  (42-20)/4

z-score = 22/4

z-score =  5.5

Hence, the z-score for the data value of 42 is 5.5.

Learn more about z-score here:

brainly.com/question/13793746

#SPJ5

Answer:

12 sundaes

Step-by-step explanation:

Answer:AE=EC và BF=FC => EF là đường trung bình của tam giác ABC

=> EF // và bằng 1/2 AB

=> AB = 16

Step-by-step explanation:

Answer:

AB=16

Step-by-step explanation:

Midsegment Theorem states that the segment connecting the midpoints of two sides of a triangle is parallel to the third side and half as long.

The mid-segment of a triangle, which joins the midpoints of two sides of a triangle, is parallel to the third side of the triangle and half the length of that third side of the triangle.

AD=DB

AD+DB=AB=2EF

AB=2×8=16

We have to figure out what the product of DA is,

[tex]\begin{bmatrix}-1&2&3\\8&-4&0\\6&7&1\\ \end{bmatrix}\begin{bmatrix}1\\3\\5\\ \end{bmatrix}=\begin{bmatrix}a\\b\\c\\ \end{bmatrix}[/tex]

We know that,

[tex]\begin{bmatrix}a&b&c\\d&e&f\\g&h&i\\\end{bmatrix}\begin{bmatrix}x\\y\\z\\\end{bmatrix}=\begin{bmatrix}ax+by+cz\\dx+ey+fz\\gx+hy+iz\\\end{bmatrix}[/tex]

So,

[tex]a=-1\cdot1+2\cdot3+3\cdot5=-1+6+15=20[/tex]

[tex]b=8\cdot1+(-4)\cdot3+0\cdot5=8-12=-4[/tex]

[tex]c=6\cdot1+7\cdot3+1\cdot5=6+21+5=32[/tex]

So the solution is,

[tex]a,b,c=\boxed{20,-4,32}[/tex]

Hope this helps :)

Pythagorean Theorem: a^2 + b^2 = c^2

a = 5

b = ?

c = [tex]\sqrt{61}[/tex]

5^2 + b^2 = ([tex]\sqrt{61}[/tex])^2

25 + b^2 = 61

b^2 = 36

b = 6

Hope this helps!