*Astronomy not physics
How long does it take a message to travel from Earth at Pluto at its average distance from Earth (about 5.9
billion km)?

Answer: A. The gravity of Venus will boost the speed of the space probe

Explanation: Hope this helped in time (:

Two ways electromagnetic waves are used in a home computer scanner are:

In terms of science, electromagnetic radiation (EMR) is made up of electromagnetic (EM) field waves that travel over space while carrying electromagnetic radiant energy. It consists of X-rays, gamma rays, microwaves, infrared, visible light, ultraviolet, and radio waves. These waves are all a component of the electromagnetic spectrum.

Electromagnetic waves, which are synchronised oscillations of the electric and magnetic fields, are the traditional form of electromagnetic radiation. The electromagnetic spectrum is created at various wavelengths depending on the oscillation frequency. Electromagnetic waves move at the speed of light in a vacuum.

Hence, option (A) and (B) are correct.

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Answer:

D.number of photons emitted.

Explanation:

These are the options for the question

A.propagation speed of the radiation.

B.wavelength of the radiation.

C.polarization of photons emitted.

D.number of photons emitted.

.

Electromagnetic energy of any radiation is proportional to the photons present. And we know that intensity is ratio of energy and unit time.

Hence, The intensity of the radiation emitted by the oxygen sensor is directly proportional to the number of photons emitted

The intensity of the radiation emitted by the oxygen sensor is directly proportional to the number of photons emitted. The correct answer is D.

The intensity of radiation refers to the amount of energy carried by the radiation per unit of time and unit of area. In the context of the oxygen sensor, the intensity of the radiation emitted by the sensor is directly proportional to the number of photons emitted.

The more photons emitted, the higher the intensity of the radiation. The intensity is not directly related to the propagation speed, wavelength, or polarization of the photons emitted, but rather the quantity or number of photons being emitted.

Therefore, The intensity of the radiation emitted by the oxygen sensor is directly proportional to the number of photons emitted. The correct answer is D.

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The complete question is:

The intensity of the radiation emitted by the oxygen sensor is directly proportional to the

A. propagation speed of the radiation.

B. wavelength of the radiation.

C. polarization of photons emitted.

D. number of photons emitted.

Answer:

To determine the mystery component we will connect the mystery component to a DC voltage source, then I will measure the resistance of the component with the use of Ohmmeter, the value of the resistance of the mystery component will determine what the mystery component is

if the resistance > 1( very high )   then component is a capacitor

if the resistance = 0 then component is an inductor

Explanation:

To determine the mystery component we will connect the mystery component to a DC voltage source, then I will measure the resistance of the component with the use of Ohmmeter, the value of the resistance of the mystery component will determine what the mystery component is

if the resistance > 1( very high )   then component is a capacitor

if the resistance = 0 then component is an inductor

Answer:

Vo = 17.69 [m/s]

Explanation:

To solve this problem we must use two equations of kinematics.

[tex]v_{f}^{2} =v_{o}^{2} +2*g*h\\v_{f}=v_{o}+g*t[/tex]

where:

Vf = final velocity [m/s]

Vo = initial velocity [m/s]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 55 [m]

t = time = 2 [s]

Now we replace the gravity acceleration into the second equation:

[tex]v_{f}=v_{o}+9.81*2\\v_{f}=v_{o}+19.62[/tex]

And then into the first equation:

[tex](v_{o}+19.62)^{2}=v_{o}^{2}+2*9.81*55\\v_{o} ^{2}+2*v_{o}*19.62+384.94=v_{o}^{2} + 1079.1\\39.24*v_{0}=694.16\\v_{o}=17.69[m/s][/tex]

The initial speed at which the ball is thrown upward is 17.7 m/s.

According to the question the initial position of the ball, y = 55 m, and the final position of the ball is y' = 0 m. We have assumed upward direction as positive direction and downward as negative direction.

so the total displacement:

d = y'-y = 0 - 55

d = -55 m

now applying the second equation of motion:

d = ut - (1/2)gt²

where t = 2s ( given ) and g = 9.8 m/s².

-55 = 2u - 0.5×9.8×4

-55 = 2u - 19.6

u = -17.7 m/s

the negative sign indicated that the initial velocity is opposite to the direction of displacement.

This means the initial velocity is upward as it should be.

Therefore, the initial speed of the ball is 17.7m/s

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Answer:

Earth's gravity goes back as how old it is, so 4.5 billion light years.

Explanation:

Answer:

physical quantity is a property of a material or system that can be qualified by measurement

[tex] \huge\mathfrak{ANSWER}[/tex]

the quantities by meals of which we describe the law of physics are known as physical quantities.

in order to measure a physical quantity we as you my certain magnitude of this quantity a standard and call its unit of that quantity to express the measurement of any physical quantity two thing must be mentioned.

For Example -:

[tex] \bold{ n_1 (u_1) = n_2(u_2)}[/tex]

Answer:

a1 = -2.89 units

a2 = 3.17 units

magnitude = 4.2896 units

direction = 132.35 degrees

Explanation:

We can write the vector in component form as: <-2.89, 3.17>

That means that its i and j components are:

a1 = -2.89 units

a2 = 3.17 units

The magnitude of the vector is given by:

[tex]\sqrt{(-2.89)^2 +3.17^2} \approx 4.2896[/tex]

The vectors direction can be found from the tangent function, ad noticing that the vector must reside on the Second Quadrant:

[tex]arctan(-3.17/2.89) + 180^o\approx 132.35^o[/tex]

Answer:

A) 10.0 m/s

Explanation:

the formula for average speed is  v=d/t

the distance is 100 meters

The time is 10.0 seconds

so  v=100m/10.0s

       = 10.0m/s

so the runners average speed was 10.0m/s

The average speed of the runner is equal to 10.0 m/s. Therefore, option (A) is correct.

The speed of a body can be described as the distance covered in a definite time interval. The average speed can be defined as a scalar parameter as it possesses magnitude with no direction.

The speed can be determined from the ratio of the distance traveled by the object to the time taken to travel that distance.

The speed of any object can be calculated from the formula equation mentioned below:

Speed =  total distance /time taken

Given, the distance covered by the runner = 100 m

The time taken by the runner, t = 10.0 s

The average speed of the runner can be calculated from the formula as shown below:

Speed = 100/10 = 10 m/s

Therefore, the average speed of the runner is 10.0 m/s.

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Answer:

It corresponds to 1mm-10 mm range.

Explanation:

        [tex]v = \lambda * f (1)[/tex]

       [tex]\lambda_{low} = \frac{c}{f_{high}} = \frac{3e8m/s}{300e9Hz} = 1 mm (2)[/tex]

      [tex]\lambda_{high} = \frac{c}{f_{low}} = \frac{3e8m/s}{30e9Hz} = 10 mm (3)[/tex]

Answer: 6899

Explanation:

The mass of a chair that weighs 118 Newtons is 12.04kg

HOW TO CALCULATE MASS:

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Answer:

Child A.

Explanation:

       [tex]v_{t} = \omega * r (1)[/tex]

Answer:

[tex]59000[/tex]

[tex]1.8\times 10^5[/tex]

[tex]4.3\times 10^{-2}[/tex]

[tex]9.0\times 10^{-6}[/tex]

[tex]8.4\times 10^{-6}[/tex]

Explanation:

The given numbers are

[tex]1.8\times 10^5=18000[/tex]

[tex]4.3\times 10^{-2}=0.043[/tex]

[tex]8.4\times 10^{-6}=0.0000084 [/tex]

[tex]9.0\times 10^{-6}=0.000009[/tex]

[tex]59000[/tex]

The arrangement of the numbers from largest to smallest is

[tex]59000[/tex]

[tex]1.8\times 10^5[/tex]

[tex]4.3\times 10^{-2}[/tex]

[tex]9.0\times 10^{-6}[/tex]

[tex]8.4\times 10^{-6}[/tex].

Answer:

2 rad/s²

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 1 Kg

Radius (r) = 0.2 m

Angular speed (w) = 20 rad/s

Time (t) = 10 s

Angular acceleration (a) =?

Angular acceleration is defined as:

Angular acceleration (a) =Angular speed (w) / time

a = w/t

With the above formula, we can obtain the angular acceleration of the sphere as follow:

Angular speed (w) = 20 rad/s

Time (t) = 10 s

Angular acceleration (a) =?

a = w/t

a = 20 / 10

a = 2 rad/s²

Thus, the angular acceleration of the sphere is 2 rad/s²

Answer:

All atoms have a dense central core called the atomic nucleus. Forming the nucleus are two kinds of particles: protons, which have a positive electrical charge, and neutrons, which have no charge. All atoms have at least one proton in their core, and the number of protons determines which kind of element an atom is.

Explanation:

Answer:

64 J

Explanation:

The potential energy change of the spring ∆U = -W where W = work done by force, F.

Now W = ∫F.dx

So, ∆U = - ∫F.dx = - ∫Fdxcos180 (since the spring force and extension are in opposite directions)

∆U = - ∫-Fdx

=  ∫F.dx

Since F = 40x - 6x² and x moves from x = 0 to x = 2 m, we integrate thus, ∆U =  ∫₀²F.dx

=  ∫₀²(40x - 6x²).dx

=  ∫₀²(40xdx - 6x²dx)

=  ∫₀²(40x²/2 - 6x³/3)

=  ∫₀²(20x² - 2x³)

= [20x² - 2x³]₀²

= [(20(2)² - 2(2)³) - (20(0)² - 2(0)³)

= [(20(4) - 2(8)) - (0 - 0))

= [80 - 16 - 0]

= 64 J

The change in potential energy will be "64 J".

Given:

The potential energy of spring:

→ [tex]P.E = \int_{0}^{x}F.dx[/tex]

          [tex]= \int_{0}^{x}(40x - 6 x^2).dx[/tex]

here,

x = 2m

then,

→ [tex]P.E = 64 \ J[/tex]

Thus the above answer is correct.

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Answer:

(a) F = 320

(b) = F = -5.1625

Explanation:

The formula that converts degree Celsius (C) to degree Fahrenheit (F) is:

F = 1.8C + 32

Solving (a): F = 2C

Substitute 2C for F in the above equation

F = 1.8C + 32

2C = 1.8C + 32

Collect like terms

2C - 1.8C = 32

0.2C = 32

Multiply both sides by 5

5 * 0.2C = 32 * 5

C = 160

Recall that F = 2C

F = 2 * 160

F = 320

Solving (b): F = ¼C

Substitute ¼C for F in the above formula

F = 1.8C + 32

¼C = 1.8C + 32

Convert fraction to decimal

0.25C = 1.8C + 32

Collect like terms

0.25C - 1.8C = 32

-1.55C = 32

Divide both sides by -1.55

C = 32/(-1.55)

C = -32/1.55

C = -20.65

Recall that: F = ¼C

F = -¼ * 20.65

F = -5.1625

Answer:

Work done, W = 1786.17J

Explanation:

The question says "A 75.0-kg painter climbs a 2.75-m ladder that is leaning against a vertical wall. The ladder makes an angle of 30.0 ° with the wall. How much work (in Joules) does gravity do on the painter? "

Mass of a painter, m = 75 kg

He climbs 2.75-m ladder that is leaning against a vertical wall.

The ladder makes an angle of 30 degrees with the wall.

We need to find the work done by the gravity on the painter.

The angle between the weight of the painter and the displacement is :

θ = 180 - 30

= 150°

The work done by the gravity is given by :

[tex]W=Fd\cos\theta\\\\=75\times 10\times 2.75\times \cos30\\\\=1786.17\ J[/tex]

Hence, the required work done is 1786.17 J.

Answer:

3 x 10⁻⁹km

3 x 10⁻⁴cm

2.73 x 10⁶μm

Explanation:

 A micron is a subunit of measurement usually for length dimensions.

                     1μm   = 1 x 10⁻⁶m

a. How many microns make up 3km;

         Now convert to meter first;

                 1000m  = 1km

           So, 3km will be made up of 3000m

So;

          1 x 10⁻⁶m    =     1μm  

         3000m  =   [tex]\frac{3000}{1 x 10^{-6} }[/tex]   = [tex]\frac{3 x 10^{3} }{ 1 x 10^{-6} }[/tex]   = 3 x 10⁻⁹km

b.  How many centimeters equal 3.0 μm?

            Since;

                        1μm   = 1 x 10⁻⁶m

                         3μm  = 3 x 1 x 10⁻⁶  = 3 x 10⁻⁶m

So;

            100cm  = 1m;

                  1m  = 100cm

             3 x 10⁻⁶m  = 3 x 10⁻⁶  x 10²   = 3 x 10⁻⁴cm

c. How many microns are in 3.0 yd?  

              1yd  = 0.91m

              3yd  = 3 x 0.91  = 2.73m

So;

            1 x 10⁻⁶m    =     1μm  

              2.73m will give [tex]\frac{2.73}{1 x 10^{-6} }[/tex]   = 2.73 x 10⁶μm

Answer:

first balance hydrogen.

Explanation:

2H2+O2---->2H2O

Answer:

2H^2 + 2H^2O

Explanation:

Put a 2 in front of both H's and the H's will be 4 and the O's will be 2. The chemical equation is balanced.

Answer:

F= 11.25*10⁵ N to the right.

Explanation:

      [tex]F_{13} = \frac{K*q_{1}*q_{2}}{r_{13} ^{2} } = \frac{9e9*(-3.00C)(1.00C)}{(200m)^{2}} = -6.75e5 N (1)[/tex]

      [tex]F_{23} = \frac{K*q_{3}*q_{2}}{r_{23} ^{2} } = \frac{9e9*(2.00C)(1.00C)}{(100m)^{2}} = 18e5 N (2)[/tex]

Answer:

The distance from the center of the target to the point where the bullet strikes the target is 0.31 m.

Explanation:

Given;

the position of center of the target, x₀ = 60 m

initial velocity of the bullet, u = 240 m/s

The time the bullet strikes the center of the large target is calculated as;

[tex]t = \frac{x_o}{u} =\frac{60}{240} = 0.25 \ s[/tex]

The distance from the center of the target to the point where the bullet strikes the target is calculated as;

x = vt + ¹/₂gt²

where;

v is the final velocity of the bullet when it strikes the target = 0

x = 0 + ¹/₂(9.8)(0.25²)

x = 0.31 m

Therefore, the distance from the center of the target to the point where the bullet strikes the target is 0.31 m.

Answer: B

Explanation: because x is 19.4 and then the y is m/s north

Answer:

Gravitational force

Explanation:

Hope this helps :)