Answer:
240
Explanation:
vector u has a magnitude of 20 and direction of 0°.vector v has amagnitude of 40and a direction of 60°.find the magnitude and direction of the resultant
Addition of vectors:
vector u
has a magnitude of 20 and a direction of 0º with respect to the horizontal, vector v has a magnitude of 40 and a direction of 60º with respect to the horizontal.
a) Find the magnitude and direction of the resultant to the nearest whole
number.
Vector Sum:
The resultant of two vectors is simply the vector sum of the vectors. There are a handful of ways to present the resultant factor; the notation that shows the vector magnitude and direction is called the polar vector notation. An example of a vector presented in polar vector notation is
a∠θ where a is the magnitude and θis the angle that the vector makes with the horizontal axis.
Answer and Explanation:
Let's first present the vectors in rectangular vector notation.
For the vector →u of magnitude 20 and direction 0∘ to the horizontal axis, the vector is →u=^i20.
For the vector →v
of magnitude 40 and direction 60∘ to the horizontal axis, the vector is →v=^i40cos60∘+^j40sin60∘.
The resultant vector →w is the vector sum of the vectors, i.e.
→w=→u+→v
=^i20+^i40cos60∘+^j40sin60∘
=^i(20+40cos60∘)+^j(40sin60∘)
=^i40+^j20√3
For a vector ^ix+^jy, the magnitude of the vector is √x2+y2 and the direction above the horizontal axis is θ=tan−1(yx).
Let's use the formulas:
|→w|∠θ=√(40)2+(20√3)2∠tan−1(20√340)≈52.9∠40.9∘
The magnitude of the vector is about 53 units in the direction 41-degrees above the horizontal axis.
The magnitude of the resultant vector would be 60 units, and its direction will be 0°.
To find the magnitude and direction of the resultant vector when adding vectors u and v, we can use vector addition formulas:
Magnitude of the Resultant Vector (R):
R = √(u^2 + v^2 + 2uv * cosθ)
where:
u = magnitude of vector u (20)
v = magnitude of vector v (40)
θ = angle between vectors u and v (60°)
Plugging in the values:
R = √(20^2 + 40^2 + 2 * 20 * 40 * cos(60°))
≈ √(400 + 1600 + 1600)
≈ √3600
= 60
Direction of the Resultant Vector (θR):
Use the Law of Cosines to find the angle θR between the resultant vector R and vector u:
cosθR = (v^2 + R^2 - u^2) / (2 * v * R)
Plugging in the values:
cosθR = (40^2 + 60^2 - 20^2) / (2 * 40 * 60)
= (1600 + 3600 - 400) / 4800
= 1
Since cos(0°) = 1, we have θR = 0°.
So, the magnitude of the resultant vector is 60 units, and its direction is 0°.
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The gravitational field on Saturn is 10.4 times its value on Earth.
a. What would a 100.0-kg mass weigh on Saturn?
b. If the gravitational field on the surface of Pluto is 0.08 times that of Mercury, what would a 7.0-kg mass weigh on Pluto?
Show all work!!
The weight of 100 kg mass on Saturn is 10,192 N.
The weight of 7.0 kg mass on Pluto is 2.01 N.
The given parameters;
acceleration due to gravity, = 10.4gmass of the Saturn, m = 100 kgacceleration due to gravity on mercury, = 3.59 m/s²The weight of 100 kg mass on Saturn is calculated as follows;
W = mg
W = 100 x 10.4 x 9.8
W = 10,192 N
The weight of 7.0 kg mass on Pluto is calculated as follows;
W = 7 x 0.08 x 3.59
W = 2.01 N
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Your car can brake with a deceleration of 6 m/s2. The car is initially going at 40 m/s.
a) How long will it take the car to come to a full stop?
b) If the car is 5 meters long, about how many car lengths should be kept between you and the car in front of you (assume the car in front of you comes to a stop immediately).
We have that for the Question "" it can be said that how long will it take the car to come to a full stop and the car lengths before a stop is
t=6.67L=27cars
From the question we are told
Your car can brake with a deceleration of 6 m/s2. The car is initially going at 40 m/s.
a) How long will it take the car to come to a full stop?
b) If the car is 5 meters long, about how many car lengths should be kept between you and the car in front of you (assume the car in front of you comes to a stop immediately).
Generally the equation for the Velocity is mathematically given as
[tex]v=u+at\\\\Therefore\\\\40=0+6t\\\\t=6.667s\\\\[/tex]
b)
s=ut+1/2at^2
Therefore
[tex]S=0+1/2(6)(6.7)^2\\\\S=134.67m[/tex]
Therefore
The car lengths before a stop is
L=134.67m/5
L=27cars
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jane pushed a box with 15 N force (an action) what force does the box have on Jane? which law is this?
Answer:
This is Newton’s third law (forces due to friction). There would be 15N being pushed back at Jane.
Explanation:
Newton’s third law states that for every action there is an equal and opposite reaction. So if Jane pushed with a force of 15N, 15N would be pushed back at her. Hope this helps! :)
why does chelsea see sparks as she removes her clothes from the clothes dryer? conduction. induction. static discharge. loss of protons.
This is electrostatic phenomenon. Chelsea see sparks as she removes her clothes from the clothes dryer because of static discharge.
What is Static Electricity ?Static electricity is produced by friction when two materials are rubbed together.
Why does Chelsea see sparks as she removes her clothes from the clothes dryer?
The correct answer is because of static discharge.
For instance, when a glass rod is rubbed with silk or cellulose acetate with silk, the glass will become positively charged by loosing electron to the silk whereby becoming negatively charged.
Static discharge occurs during thunder and lightning, and when combing our hair during harmattan season.
Therefore, Chelsea see sparks as she removes her clothes from the clothes dryer because of static discharge.
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Answer:
C) Static Discharge
Explanation:
what is the main deterrant to switching to electrically powered cars?
Answer:
Availability of charging
Explanation:
Assuming the car is not a hybrid and your traveling a very long distance far from civilization, you wouldn't be able to charge the car if it runs out of power as no outlets would be around.
What does a higher value of k and a lower value of k tell about the strength of the spring? (Hint: In which case is it soft or stiff?)
Answer:
' In layman's terms, the k variable in Hooke's law (F = -kx) indicates stiffness and strength. The higher the value of k, the more force is needed to stretch an object to a given length. This value is dependent on the object's material alongside its shape and Proportons
Explanation:
identify the types of elements in the schematic diagram give the number of each types
Where's the diagaram?
an empty boat floats in water with 10% of its volume submerged. and when it is loaded with 1200kg , the volume submerged will increase to 70% of the total volume . calculate the mass of the empty boat
Let volume of empty boat be = 100% = 1V
and mass of boat be M
In water 10%, 0.1V of the volume is submerged.
Mass, m of 1200kg increases the submerging from 10%, 0.1V to 70%, 0.7V
M leads to 0.1V boat submerging
boat submerging.
M + 1200kg leads to 0.7V boat submerging.
This is 60%, 0.6 V increase
By comparison
(M+1200kg) * 0.1V = 0.7V * M
0.1M + 120kg = 0.7M
120kg = 0.7M - 0.1M
120kg = 0.6M
M = (120/0.6)kg
M = 200kg.
The mass of the boat is 200kg.
I WILL MARK U HELP PLZ
The free body diagram for an object is projected. Calculate the net force acting on the object. If this object is 10 kg, how/where will it accelerate?
Explanation:
By the end of the section, you will be able to:
Apply problem-solving techniques to solve for quantities in more complex systems of forces
Use concepts from kinematics to solve problems using Newton’s laws of motion
Solve more complex equilibrium problems
Solve more complex acceleration problems
Apply calculus to more advanced dynamics problems
through this steps you will get the answer.thank youa.
In what ways do human beings contribute to the greenhouse effect? Select all that apply.
by using renewable energy
b. by driving gas -powered cars
by studying extreme weather events
d. by making things out of plastic
C.
Is it possible to burn a paper using lens? How?
Answer:
NO Y
Explanation:
MMMMMMMMM
an open steel can of volume 216 L is filled to the top with gasoline at 13.5 C. when it warms to 36.0 C, how much gas spills over? (don't forget, both the can and the gasoline are expanding.)
[tex]\\ \sf\longmapsto Q=mc\Delta T[/tex]
[tex]\\ \sf\longmapsto c=\dfrac{Q}{m\Delta T}[/tex]
[tex]\\ \sf\longmapsto c=\dfrac{1320}{5.61(274)}[/tex]
[tex]\\ \sf\longmapsto c=\dfrac{1320}{1537.14}[/tex]
[tex]\\ \sf\longmapsto c=0.85J/kgK[/tex]
4.44J (creds to commenter on the post, just making it bigger)
Why should anybody care about sexual harassment?
Answer:
Explanation:
People should care about sexual harassment for many reasons. such as, sexual harassment is a very serious and touchy topic. Sexual harassment should not be tolerated and can ruin many peoples mental health.
Zeb was moving his dresser. He pushed with 1000N and the resulting acceleration was 200m/s2. What was its mass?
Answer:
5
Explanation:
Formula for Mass (for this question)
[tex]mass=\frac{Force}{Acceleration}[/tex]
mass= 1000N/200[tex]m^{2}[/tex]=5
(pls do correct me if I have any mistakes it would rlly help others!)
Kevin and Kisha are ice skating. Kisha has a mass of 60 kg, and Kevin has a mass of 45 kg. As they face each
other, Kevin pushes off Kisha with a force of 54 N. Assume the friction between the skaters and the ice is
negligible.
t
Determine the magnitude of Kevin's acceleration.
Write your answer to two significant figures.
m/s
m
If Kevin with mass 45kg pushes Kisha with a force of 54N, the magnitude of Kevin's acceleration is 1.2 m/s²
Kisha's mass = 60 kg
Kevin's mass = 45 kg
Kevin pushes off Kisha with a force of 54 N
Since it was Kevin that pushed Kisha, and the required force is 54N, we can look for Kevin's acceleration using the equation below
F = ma
The considered mass is Kevin's mass
54 = 45a
a = 54/45
a = 1.2 m/s²
The magnitude of Kevin's acceleration is 1.2 m/s²
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Q1. A 130 N horizontal force keeps a 30 kg chair moving at a constant velocity. Find the
coefficient of kinetic friction between the chair and the floor.
The coefficient of kinetic friction between the chair and the floor is 0.442.
The given parameters;
horizontal force on the chair, F = 130 Nmass of the chair, m = 30 kgThe normal force on the chair is calculated as follows;
Fₙ = mg
Fₙ = 30 x 9.8 = 294 N
The frictional force between the chair and the floor is calculated as follows;
Fk = μFₙ
The net force on the chair is calculated as follows;
[tex]\Sigma F_x = 0\\\\F- \mu_k F_n = 0\\\\130 - \mu_k (294) = 0\\\\\mu_k = \frac{130}{294} \\\\\mu_k = 0.442[/tex]
Thus, the coefficient of kinetic friction between the chair and the floor is 0.442.
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Wile E. Coyote is holding a "HEAVY DUTY ACME™ ANVIL" on a cliff that is 40.0 meters high. The Roadrunner (beep-beep), who is 1.0 meter tall, is running on a road toward the cliff at a constant velocity of 10.0 m/s. Wile E. Coyote wants to drop the anvil on the Roadrunner's head. How far away should the Roadrunner be when Wile E. drops the anvil?
Answer:
53.8
Explanation: I plugged it on the formula
Coyote should drop the anvil when the Roadrunner is 20.3 meters away from the cliff.
What is velocity?The velocity of the object is defined as the fraction of the displacement of the object over a period of time.
We can solve this problem by finding the time it takes for the anvil to fall from the cliff to the ground, and then using that time to find how far the Roadrunner has travelled during that time.
First, we need to find the time it takes for the anvil to fall from the cliff. We can use the equation:
d = 1/2 x g x t²
where d is the distance (40.0 meters), g is the acceleration due to gravity (9.81 m/s^2), and t is the time.
Solving for t, we get:
t = √(2d/g)
t = √(2 x 40.0/9.81)
t = 2.03 seconds
So it takes 2.03 seconds for the anvil to fall from the cliff to the ground.
During this time, the Roadrunner has travelled a distance equal to its velocity multiplied by the time:
distance = velocity x time
distance = 10.0 m/s x 2.03 s
distance = 20.3 meters
Therefore, Wile E. Coyote should drop the anvil when the Roadrunner is 20.3 meters away from the cliff.
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a car travels west for 240km in 4 hr what is the car velcity
a person lifts a package weighing 75 N if she lifts it 1.2m off the floor what work has she done ?
Answer:
W = 90 J
Explanation:
Data:
Force (F) = 75 NDistance (d) = 1.2 mWork (W) = ?Use the formula:
W = F * dReplace and solve:
W = 75 N * 1.2 mW = 90 JThe work done was 90 Joules.
Greetings.
A 2300-kg car slows down at a rate of 3.0 m/s2 when approaching a stop sign. What is the magnitude of the net force causing it to slow down?
The magnitude of the net force causing the 2300kg car to slow down is 6900N
HOW TO CALCULATE FORCE:
The net force applied on a moving object can be calculated by multiplying the mass of the object by its acceleration. That is;Force (N) = mass (kg) × acceleration (m/s²)According to this question, a 2300-kg car slows down at a rate of 3.0 m/s2 when approaching a stop sign. The net force causing the car to stop can be calculated as follows:F = 2300kg × 3m/s²
F = 6900N
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If the activity of a source is 70 Bq after 2 years, and 35 Bq after 15 years. How long will be until the activity is 8.75 Bq?
Answer:
So if the half-life is two days, four half-lives is 8 days. Suppose a sample has a count rate of 3,200 Becquerel (Bq) at the start, then its count rate after 8 days would be 1/16th of 3,200 Bq = 200 Bq.
Using Newton’s first law of physics, which explains why it is harder to swim in water with a current (like the ocean) than in contained water (like a pool)?
A.
Perpetual motion can only be interrupted by an unbalanced force.
B.
The current will interfere with perpetual motion more than still water.
C.
It takes much more strength to swim if there is a current than in a pool.
D.
Still water is an immovable object, but currents have their own momentum.
Answer:
It isn't A.
Explanation:
I got it wrong with the answer A.
it is harder to swim in water with a current (like the ocean) than in contained water (like a pool) because Still water is an immovable object, but currents have their own momentum. The correct option is D.
What is Newton's first law of motion?Newton's first law of motion, also known as the law of inertia, states that "an object at rest will remain at rest, and an object in motion will remain in motion with a constant velocity unless acted upon by an unbalanced force."
This means that an object will continue to move in a straight line at a constant speed unless an unbalanced force acts upon it. In addition, if an object is at rest, it will remain at rest unless acted upon by an unbalanced force.
The law of inertia can be applied to many situations. For example, if a book is sitting on a table, it will remain at rest until a force is applied to it. Similarly, if a ball is rolling on a flat surface, it will continue to roll at a constant speed in a straight line unless a force, such as friction, slows it down or changes its direction.
This law is fundamental to understanding the behavior of objects in motion, and it forms the basis for the other two laws of motion formulated by Sir Isaac Newton.
Here in the Question,
Swimming in a pool versus swimming in the ocean, the difference lies in the presence of a current in the ocean.
The current in the ocean has its own momentum, and when a swimmer enters the water, they are faced with an additional force that they must overcome to move forward. This means that the swimmer must apply more force and use more energy to overcome the force of the current and move forward in the water.
In still water, on the other hand, there is no external force acting on the swimmer, so they only have to overcome the resistance of the water itself to move forward.
Therefore, The correct answer is D i.e Still water is an immovable object, but currents have their own momentum.
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Which of the following is an example of a buoyant force acting on an object?
A. The object remains still despite an applied force.
B. The object travels with straight-line horizontal acceleration.
C. The object floats on top of a fluid.
D. The object travels in uniform circular motion.
Answer:
option c theobject floats on top of a fluid1)
The red arrow is pointed at different locations of an atom of nitrogen Where is it pointing to the GREATEST concentration of
atomic mass?
A
B.
В
C
Answer:
A) A (displays the nucleus)
The Nucleus holds a majority of the mass within an atom
it is important to realize that an element’s line spectrum can include emissions at wavelengths throughout the electromagnetic spectrum including ultraviolet, visible, and infrared. according to the procedure in section 2, where will you be collecting data on hydrogen and helium’s line spectra?
Answer:
visible region
Explanation:
According to the procedure in section 2, in visible region the data collected on hydrogen and helium’s line spectra.
What is electromagnetic spectrum?Electromagnetic spectrum are the wave which is form of energy and includes the waves such as radio waves, gamma waves, visible light waves etc.
An element’s line spectrum can include emissions at wavelengths throughout the electromagnetic spectrum including ultraviolet, visible, and infrared.
Types of electromagnetic spectrum-
Radio waves-Radio waves are used to broadcast the signal and television signals.Microwaves-Microwaves are used in the mobile signals, Radar and in cooing the food.Infrared-Infrared transmit heat from difference sourced of fire.Visible light-This is the type of electromagnetic radiation, which is visible to the human eye.Ultraviolet-Ultraviolet electromagnetic radiation used in florescent tubes.X-rays- X-rays are used to see throughout the objects and the bodies.Gamma rays- Used in medical, to kill the cell causes cancer.
The hydrogen line spectra fall between wavelength, 410 nm to 656 nm. The helium line spectra fall between wavelength, 400 nm to 781 nm.This two fall in the visible region of line spectra.
According to the procedure in section 2, in visible region the data collected on hydrogen and helium’s line spectra.
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what phase change occurs as the substance at .75 atm is heated from 0 C to 25 C
When does the object have potential energy?
Answer:
To summarize, potential energy is the energy that is stored in an object due to its position relative to some zero position.
Explanation:
An object possesses gravitational potential energy if it is positioned at a height above (or below) the zero height.
A drag racer starts at rest and reaches a speed of 386.0 km/h with an average acceleration of 16.5 m/s2. How long does this acceleration take?
Answer:
about 16.5 by-
wait DO UR OWN MATH lol
Explanation:
How is kinetic energy used in dribbling a basketball
