The conditions needed for an ideal pendulum are;
The mass of the rod of the pendulum is evenly distributed along the rod. The pivot on which the pendulum swings is frictionless. The pendulum swings through its equilibrium position as a result of inertiaWhat is an ideal pendulum?An ideal pendulum is a type of pendulum that satisfies the following conditions,
The mass of the pendulum rod should be evenly distributed throughout the rod.The pendulum must move in a frictionless medium.The pendulum must move from the equilibrium position.Thus, the correct statements are second, third and the fourth.
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Answer:
b, c and d are correct ;)
Explanation:
A stone of mass 6kg is released from a height of 30m, calculate the velocity before the impact (take gravity=10m/s)
Answer:
23,49 m/s
Explanation:
Ep= Ek
mgh=mv2/2
6×10×30=6v2/2
1800=6 v2/2
6 v2=3600
v2 =600
v=24,49 m/s
The velocity of the stone, if a stone of mass 6 kg is released from a height of 30 m, is 24.5 m/s.
What is velocity?When something is moving, its velocity shows how quickly its location is changing as seen from a certain angle and as measured by a particular unit of time.
If a point moves a certain distance along its path in a predetermined length of time, its average speed throughout that time is equal to the distance traveled divided by the travel time. For instance, a train traveling 100 km in two hours is doing it at an average speed of 50 km/h.
Given:
The mass of the stone, m = 6 kg,
The height of the release, h = 30 m,
The value of gravity, g = 10 m/s,
Calculate the velocity using energy conservation as shown below,
The kinetic energy = potential energy (Energy conservation)
1/2 × 6 × v² = 6 × 10 × 30
v² = 300 × 2
v² = 600
v = √600
v = 10√6
v = 10 × 2.45
v = 24.49 or 24.5 m/s
Thus, the velocity is 24.5 m/s.
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If the half-life of iodine-131 is 8.10 days, how long will it take a 50.00 g sample to decay to 6.25 g?
The time it will take to decay 6.25 grams is 24.4684 days.
What is Half life period?A radioactive substance's half-life is often described as the amount of time it takes for one of its atoms to break apart or transform into another. Ernest Rutherford originally examined the theory in 1907. This is typically represented by the sign Ug or t1/2.
To make the concept clearer, let's use a radioactive element with an hour-long half-life.
Now according to the question the given values are :
T(1/2) for iodine-131 is 5.10 days,
[A]₀ for iodine-131 is 50 grams and,
[A] for iodine-131 is 6.25 grams.
T(1/2)=0.693/k
⇒8.10=0.693/k
⇒k=0.865 [tex]days^{-1}[/tex].
2.303 log [A]₀/[A]= kt
2.303 log(50.00/6.25)= 0.085×t
⇒t=1/0.085×2.303×log8
t=24.4684 days
Hence, the time it will take to decay is 24.4684 days.
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In Alberta, which of the following statements is true?
A. Only adults must be restrained in a vehicle.
B.All children must have booster seats.
C.Babies must be restrained in the front seat only.
D.All occupants must be restrained in a vehicle.
A nearsighted eye has a far point of 100 cm. Objects further than 100 cm are not seen clearly. A diverging lens is used to permit clear vision of an object placed at infinity. Find the focal length of the lens.
A diverging lens is used to permit clear vision of an object placed at infinity. The focal length of the lens is -100 cm.
What is focal length?The focal length is half of the radius of curvature of the focal lens.
By the lens maker formula,
1/f = 1/v +1/u
where, v is the image distance and u is the object distance.
Give, the object is at infinity and the image must form at 100 cm, the the focal length will be
1/f = 1/ -100 + 1/∞
f = -100 cm
The focal length must be -100 cm for the diverging lens.
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what temperature change is required to change the length of a 5.5-m steel beam by 0.0012m?
Answer:
Length of steel = 5.5 m
Increase in length = 0.0012 m
α of steel = 12 x 10-6/K
To find:
Temperature change needed ?
Calculation:
Let the required temperature change be ∆T. (in the photo)
So, temperature change of 18.1 Kelvin is required
I hope I have helped you and go to my profile to help me with my question, I really need It, thanks.
pls help in these 2 questions
Answer:
Taking forces along the plane
F cos θ - M g sin θ -100 = M a net of forces along the plane
F = (M a + M g * .5 + 100) / .866 solving for F
F = (80 * 1.5 + 80 * 9.8 * .5 + 100) / .866 = 707 N
F = 707 N acting along the plane
Fn = F sin θ + M g cos θ forces acting perpendicular to plane
Fn = 707 * 1/2 + 80 * 9.8 * .866 = 1030 Newtons forces normal to plane
(this would give a coefficient of friction of 100 / 1030 = .097 = Fn)
Calculate the power if work is 9000 joules and time is 60 seconds
Answer:
150w
Explanation:
power = workdone/time
9000/60
150w
Transverse waves travel at in a string that is subjected to a tension of if the string is long, what is its mass?
The mass of the string is 0.515 kg.
Calculations and Parameters:Given that:
Tension= 60.5NLength of string= 15.9mv= 43.2 m/sm=?To solve for the mass of the string,
v=√(T/ρ) ,(v=43.2m/s , T=60.5N , L=15.9m )43.2= √(60.5/ρ)60.5/ρ= 1866.24ρ= 0.032418Therefore, the mass would be[tex]15.9*0.03242= 0.515448= 0.515[kg][/tex]
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The half-life of Calcium-47 is 3.91 x 105 seconds. A sample contains 4.11 x 1076 nuclei. How much of the sample is left after 7.82 x 10 seconds?
2.57 x 1015 nuclei
5.14 x 1015 nuclei
1.03 x 1016 nuclei
2.06 x 1016 nuclei
Remember the formula
[tex]\\ \rm\Rrightarrow A(t)=A_o(0.5)^{\frac{t}{h}}[/tex]
h is half life[tex]\\ \rm\Rrightarrow A(7.82\times 10)=A(78.2)[/tex]
[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{\frac{78.2}{3.91\times 10^{5}}}[/tex]
[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{20\times 10^{-5}}[/tex]
[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{0.0002}[/tex]
[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.998)[/tex]
[tex]\\ \rm\Rrightarrow 4.10178\times 10^{76}[/tex]
Why no options matched?
That time given in end i.e 7.82×10
10 should contain some power to match our options .The number of nuclei of calcium-47 left after 7.82 x 10⁵s is 1.03 x 10¹⁶.
This can be found out using half life and laws of radioactive disintegration.
What are the laws of radioactive disintegration?
The Law of radioactive disintegration states the number of radioactive decay per unit time is proportional to the number of nuclei present in the sample initially.
So, ΔN/Δt = λN
Where, ΔN = number of radioactive nuclei decayed
Δt = time taken for decay
N = No of nuclei present initially
λ= decay constant
What is Half life?Half life is the time taken for the radioactive nuclei to reach half of its initial value.
Half life is given by
[tex]t_{1/2}[/tex] = λ/t
Given here, [tex]t_{1/2}[/tex] = 3/91 x 10.⁵s
N = 4.11 x 10¹⁶.
t = 7.82 x 10.⁵s
We see here that t = 2([tex]t_{1/2}[/tex])
Now, number of radioactive nuclei left undecayed in one half life is N/2
So number of nuclei left undecayed in 2 half lives will be 1/2(N/2) = N/4
So number of nuclei left in the sample will be N/4 = (4.11 x 10¹⁶.)/4
So Number of nuclei left in the sample = 1.03 x 10¹⁶.
Hence 1.03 x 10¹⁶is the correct answer.
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Any sound with a frequency that is too low for humans to hear is called:
Answer:
infrasound
Explanation:
Aluminum is often melted down for recycling purposes. Assuming 1 kg of aluminum is at room temperature, what is the minimum amount of heat needed to melt it to a liquid? The specific heat capacity of aluminum is 899 J/kg°C, the melting point is 660°C, and the latent heat of fusion is 3.97 x 105 J/kg.
60 points
The minimum amount of heat needed to melt it to a liquid will be 569.067 kJ.
What is enthalpy of fusion?The minimum amount of heat needed to melt it to a liquid is known as the enthalpy of fusion.
The formula for the enthalpy of the fusion is;
[tex]\rm L_f=Q/m \\\\ L_f=mCdt/m \\\\ L_f= Cdt \\\\ L_f= 899 J/kg^0C \times (660^0-27^0) \\\\ L_f= 569,067 \ J \\\\\ L_f=569.067 \ kJ[/tex]
Hence, the minimum amount of heat needed to melt it to a liquid will be 569.067 kJ.
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A 5.0-kg block is pulled horizontally across a floor by a string attached to it with an acceleration of 2 m/s2. What is the tension in the string if the coefficient of sliding kinetic friction between the block and floor is 0.2
The tension on the string when the coefficient of sliding kinetic friction between the block and floor is 0.2 is calculated as 19.8N
What is the tension on the string?The force acting on the block in the horizontal direction is given by:
F_net = ma
where F_net is the net force acting on the block, m is the mass of the block, and a is its acceleration.
The force of friction opposing the motion of the block is given by:
F(friction) = μKN
where μK is the coefficient of kinetic friction between the block and the floor, and N is the normal force acting on the block due to the floor.
Since the block is pulled horizontally, the normal force acting on the block is equal and opposite to the weight of the block, which is given by:
N = mg
where g is the acceleration due to gravity.
Therefore, the net force acting on the block is:
Fnet = T - F (friction) = ma
where T is the tension in the string.
Substituting the expressions for F (friction), N, and Fnet, we get:
T - μKmg = ma
Solving for T, we get:
T = ma + μKmg
Substituting the given values, we get:
T = (5.0 kg)(2 m/s^2) + (0.2)(5.0 kg)(9.8 m/s^2)
Simplifying, we get:
T ≈ 19.8 N
Therefore, the tension in the string is approximately 19.8 N.
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Why is calcium chloride an ionic bond
Answer:
lonic compounds generally form between elements that are metals and elements that are nonmetals. For example, the metal calcium (Ca) and the nonmetal chlorine (Cl) form the ionic compound calcium chloride (CaCl2). In this compound, there are two negative chloride ions for each positive calcium ion.
Explanation:
Answer:Ionic compounds generally form between elements that are metals and elements that are nonmetals. For example, the metal calcium (Ca) and the nonmetal chlorine (Cl) form the ionic compound calcium chloride (CaCl2). In this compound, there are two negative chloride ions for each positive calcium ion.
Explanation:
NAME:
A room has a 60 Watt, a 100 Watt and a 150 Watt light bulb. How much does it
cost to use all the lamps for 2.5 hours at $0.08/ kWh?
E-60
Answer:
$ .0248 or 2.48 cents
Explanation:
60 + 100 + 150 = 310 watts
for one hour = 310 watt- hr or .31 kw- hr
.31 kw-hr * .08 / kw-hr = .0248
When charging a fully depleted battery with a 220/240-volt charging dock, 2023 leaf s can be fully charged in about ________.
When charging a fully depleted battery with a 220/240-volt charging dock, Nissan LEAF can be fully charged in about 7.5h.
What is battery?It converts the electro chemical energy to the electrical energy when connected across the two ends of the conductor.
The Nissan LEAF comprises of a standard 120-V charging cable. In order to charge it fully, we need a 220/240Volts battery. The time take take n to fully charge is 7.5 hours.
Thus, when charging a fully depleted battery with a 220/240-volt charging dock, Nissan LEAF can be fully charged in about 7.5 h.
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Select the correct location on the image.
Answer:
Violet (Shortest Wave Length)
Explanation:
Violet waves have the highest frequencies. The highest frequencies have the shortest wave length.
The sun will spend most of its lifetime in which stage?.
The diagram shows a roller-coaster track. Assume that the system is closed. At point D, the roller-coaster is upside-down and at the top of the vertical loop.
which statement best describes the potential and kinetic energies of a roller-coaster car at point D?
How does the force of gravity
affect objects on Earth?
A. It pulls objects towards the center of Earth.
B. It pushes objects to Earth's surface.
C. It pushes objects away from Earth.
D. It causes objects to bounce off each other.
Answer:
A. It pulls objects towards the center of Earth.
Explanation:
Think about dropping something, where does it go? If you are on earth, this goes down towards the ground due to the attractive force of gravity on every object (to pull everything to center of earth). Like Newton's apple.
How energy efficiency can reduce energy consumption?
Answer:
The energy efficiency represents the things you can do with some amount of energy, and if you can do more with less, than it reduces the energy consumption.
Explanation:
The answer to this question is actually very simple. Imagine that you use only the half of the energy you produce, an efficiency of 50%. Lets say you need 5kJ, so you would need to produce 10kJ, because you can consume only the half. Now, imagine you increase the efficiency, you use exactly what you can generate, (efficiency of 100%). In this case, if you needed only 5kJ you would need to generate only 5kJ.
How would a parachute fall on the surface of the moon ? Describe. The mass of the Jupiter is
[tex]19 \times 10 ^{27} kg[/tex]
and that of the sun is
[tex]2 \times 10 ^{30} kg[/tex]
If the gravitational force acting between them is
[tex]4.166 \times 10 ^{23} newton[/tex]
calculate the distance between their centres.
Explanation:
the answer is 2.46 × 10^12
Wind turbines are becoming an increasingly popular method of generating a community’s electricity. In wind turbines, wind is used to power electric generators. How will an increase in the use of wind turbines affect the availability of wind in the future?
Answer:
It will not. The thing with wind is as long as the earth rotates and creates and uneven heating of the atmosphere, there will be infinite wind.
Explanation:
If the scientific method was not used in forensic science at all, what do you think some potential problems could be?
#2. If we have a 9V battery connected to a 100 resistor , what is the current ?
Answer:
90 mAmps
Explanation:
V=IR
V/R = I
9 v / 100 ohm = .09 amps = 90 mAmps
An automobile moves on a level horizontal road in a circle of radius 40.0 m. The coefficient of friction between tires and road is 0.60. The maximum speed with which this car can round this curve is
Answer:
Approximately [tex]15\; {\rm m\cdot s^{-1}}[/tex] (assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].)
Explanation:
Let [tex]m[/tex] denote the mass of this vehicle, and let [tex]g[/tex] denote the gravitational field strength.
Since the road is level, the normal force that the road exerts on the vehicle would be equal in magnitude to the weight [tex]m\, g[/tex] of this vehicle. That is: [tex]F_\text{normal} = m\, g[/tex].
Let [tex]\mu_{k}[/tex] denote the coefficient of (kinetic) friction between the tires of this vehicle and the road. The maximum friction that the road could exert on this vehicle would be:
[tex]\begin{aligned}& F_\text{max. friction} && (\text{max. friction}) \\ =\; &\mu_{k}\, F_\text{normal} && (\text{coefficient of friction}) \,(\text{normal force}) \\ =\; & \mu_{k}\, m\, g\, \end{aligned}[/tex].
Also because this road is level, the only unbalanced force on this vehicle would be friction. Thus, the net force on this vehicle would be equal to the friction that the road exerts on the vehicle, which is at most [tex]\mu_{k}\, m\, g[/tex]:
[tex]\begin{aligned}& F_\text{net} && (\text{net force}) \\ =\; & F_\text{friction} && (\text{friction}) \\ \le \; & F_\text{max. friction} && (\text{max. friction})&\\ =\; & \mu_{k}\, m\, g\, \end{aligned}[/tex].
In other words, [tex]F_\text{net} < \mu_{k}\, m\, g[/tex]. This inequality could provide an upper bound on the acceleration of this vehicle:
[tex]\begin{aligned}& a && (\text{acceleration}) \\ =\; & \frac{F_\text{net}}{m} && \genfrac{}{}{0em}{}{(\text{net force})}{(\text{mass})}\\ \le \; & \frac{\mu_{k}\, m\, g}{m} \\ =\; & \mu_{k}\, g\end{aligned}[/tex].
Thus, the maximum acceleration of this vehicle on this road would be [tex]a_\text{max} = \mu_{k}\, g[/tex].
Let [tex]r[/tex] denote the radius of this circle. When the vehicle is moving around this circle at a speed of [tex]v[/tex], the (centripetal) acceleration of this vehicle would continuously be [tex]a = (v^{2} / r)[/tex].
Since the upper bound of the acceleration of this vehicle is [tex]a_\text{max} = \mu_{k}\, g[/tex], rearrange the equation [tex]a = (v^{2} / r)[/tex] to find an upper bound on speed [tex]v[/tex]:
[tex]\begin{aligned}\frac{v^{2}}{r} &= a \\ & \le a_{\text{max}} \\ &= \mu_{k}\, g\end{aligned}[/tex].
[tex]v^{2} \le \mu_{k}\, g\, r[/tex].
[tex]v \le \sqrt{\mu_{k}\, g\, r}[/tex].
In other words, when the radius of the circle is [tex]r[/tex], the coefficient of friction between the tire and the ground is [tex]\mu_{k}[/tex], and the gravitational field strength is [tex]g[/tex], the maximum speed of the vehicle would be [tex]\sqrt{\mu_{k}\, g \, r}[/tex].
In this question, it is given that [tex]r = 40.0\; {\rm m}[/tex] whereas [tex]\mu_{k} = 0.60[/tex]. Assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex], the maximum speed of this vehicle would be:
[tex]\begin{aligned}v_\text{max} &= \sqrt{\mu_{k}\, g\, r} \\ &= \sqrt{0.60 \times 9.81\; {\rm m\cdot s^{-2}} \times 40.0\; {\rm m}} \\ &\approx 15\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
What are the properties of mars
Answer:
Explanation:
Its surface is rocky, with canyons, volcanoes, dry lake beds and craters all over it. Red dust covers most of its surface. Mars has clouds and wind just like Earth
8. What force is needed to accelerate an elevator upward at a rate of 2m's if the mass of the
elevator is 2,350kg
Answer:
F = M a
F = 2350 kg * 2 m/s^2 = 4700 Newtons
That is in addition to the force of
F = 2350 * 9.8 m/s^2 = 23,030 N needed for a stopped elevator
When a person sees something, what carries the message from the eyes to the brain?
Answer:
nerves
Explanation:
The optic nerve is the nerve in each eye that carries the signal from your eye to your brain.
The acceleration due to gravity on earth is 6 times that on the moon. An object weighs 10 kg on Earth. What is the mass on the moon?
Answer:
The object obeys the equation
F = M a on both the earth and the moon (mass does not depend on location)
The problem is a little misleading because if an object has a mass of
10 kg then its weight is 10 kg * 9.8 m/s^2 = 98 Newtons
That means that weight is not expressed in Kg but rather in Newtons
Newton's Law is true on the moon as it is on the earth and F = M a
An object that weighed 10 N on earth would weigh 10 / 6 = 1.67 N on the moon
One must take care in describing a force in units of Newtons not in Kg
The half-life of radium-226 is 1,600 years and the half-life of carbon-14 is 5,730 years. in one to two sentences, mathematically prove that the decay constant for radium-226 is larger than the decay constant for carbon-14.
please and thank you :)
Explanation:
-226 of 1600
-14 of 5730
-226×16÷100= -36.16
-14×57.3÷100= -802.2
The decay constant for radium-226 is larger than the decay constant for carbon-14.
What is decay constant?Decay constant of radioactive substance is its probability of decay per unit time.
Decay constant for radium-226 is [tex]1.4*10^{-11} /sec[/tex] and for carbon-14 is [tex]3.8*10^{-12} /sec[/tex].
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