An F test for the two coefficients of promotional expenditures and district potential is performed. The hypotheses are H0: 1 = 4 = 0 versus Ha: at least one of the j is not 0. The F statistic for this test is 1.482 with 2 and 21 degrees of freedom. What can we say about the P-value for this test?

Answers

Answer 1

Answer:

Pvalue > 0.10

Step-by-step explanation:

Given the hypothesis :

H0 : β1 = β4 = 0

H1 : Atleast one of βj is not 0

F statistic = 1.482 ;

Degree of freedom = 2 and 21 ;

DFnumerator = 2

DFdenominator = 21

Using the Pvalue calculator from Fstatistic ;

Pvalue(1.482, 2, 21) = 0.24999 = 0.25

Hence, Pvalue for the test is 0.25

Pvalue > 0.10

An F Test For The Two Coefficients Of Promotional Expenditures And District Potential Is Performed. The

Related Questions

Help once again thanks! !!!!!!!

Answers

Ok so
1. 52° because it’s the same as angle 5, which is opposite of 7 so it’s the same
2. Is Also 52° because it is the same as angle 7 which is 52°

The ratio of the volumes of two similar solid polyhedra is equal to the square root of the ratio between their edges. True or False? HELP QUICK PLSSSSS

Answers

Answer:

FALSE.The ratio of the volumes of two similar solid polyhedra is equal to the square of the ratio between their edges. This statement is false. A polyhedron is a shape that has no gaps between their edges or vertices.

Answer:

it's false

~~~~~~~~~~~

The surface areas of two similar solids are 16m2 and 100 m2. The volume of the larger one is 750m3. What is the volume of the smaller one?

Answers

Answer:

48 m^3

Step-by-step explanation:

If the scale factor of linear dimensions between two solids is k, then the scale factor for areas is k^2, and the scale factor of volumes is k^3.

Let's call the solid with 16 m^2 of area solid A, and the other one solid B.

The scale factor of areas from, A to B is (100 m^2)/(16 m^2) = 25/4

In other words, multiply the area of the solid A by 25/4 to get the area of solid B.

Let's check: 16 m^2 * 25/4 = 16 * 25/4 m^2 = 4 * 25 m^2 = 100 m^2

We do get 100 m^2 for solid B, so the area scale factor of 25/4 is correct.

The area scale factor is k^2, so we have:

k^2 = 25/4

We solve for k:

k = 5/2

Now we cube both sides to get k^3, the scale factor of volumes.

k^3 = 5^3/2^3

k^3 = 125/8

Let V = volume of smaller solid, solid A.

V * 125/8 = 750 m^3

V = 750 * 8/125 m^3

V = 48 m^3

15.8 Use multiple linear regression to fit x1 0 1 1 2 2 3 3 4 4 x2 0 1 2 1 2 1 2 1 2 y 15.1 17.9 12.7 25.6 20.5 35.1 29.7 45.4 40.2 Compute the coefficients, the standard error of the estimate, and the correlation coefficient.

Answers

Answer:

Kindly check explanation

Step-by-step explanation:

regression to fit

x1 0 1 1 2 2 3 3 4 4

x2 0 1 2 1 2 1 2 1 2

y 15.1 17.9 12.7 25.6 20.5 35.1 29.7 45.4 40.2

Using technology ;

The multiple linear regression fit for the data is :

y = 9.025x1 - 5.704x2 + 14.461

Where 9.025 and - 5.704 are the slope values of x1 and x2 respectively.

14.461 = intercept.

The Correlation Coefficient, R from the output is 0.998 ; this depicts a strong positive relationship  between the independent variables and dependent variable.

Evaluate the functions

Answers

Answer:

Step-by-step explanation:

Which statement best applies to the slope of the line below?

A.
the slope is negative
B.
the slope is zero
C.
the slope is positive
D.
the line has no slope

Answers

Answer:

D

Step-by-step explanation:

fro the diagram below there line has no slope

Answer: B) The slope is zero

============================================================

Explanation:

Any horizontal line will always have a slope of 0. This is because there is no change in y (aka the rise is 0).

So we could say something like

slope = rise/run = 0/1 = 0

The run can be anything we want, and we'd still get 0 every time.

------------

Another way to see this is to pick two points from this line. Whichever points are selected, they are plugged into the slope formula

m = (y2-y1)/(x2-x1)

You'll find that the y2-y1 expression turns into 0. Why? Because y1 and y2 are the same, so they subtract to 0. It doesn't matter what x2-x1 turns into.

If a point in quadrant IV is reflected in the y-axis, its image will lie in quadrant:
A. IV
B. II
C. I
D. III

Answers

Answer:

Option D is correct.

Step-by-step explanation:

A plane mirror shows that the image formed by it is of same size as that of object, same distance as that of object and same orientation and laterally inverted.

So, when a point is in IV quadrant and reflection is from Y axis, the image is in  III quadrant.  

Find y' for the following. ​

Answers

Answer:

[tex]\displaystyle y' = \frac{\sqrt{y} + y}{4\sqrt{x}y \Big( y^\Big{\frac{3}{2}} + \sqrt{y} + 2y \Big) + \sqrt{x} + x}[/tex]

General Formulas and Concepts:

Calculus

Differentiation

DerivativesDerivative Notation

Derivative Property [Multiplied Constant]:                                                           [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]

Derivative Property [Addition/Subtraction]:                                                         [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Basic Power Rule:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]:                                                                           [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]

Derivative Rule [Chain Rule]:                                                                                 [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Implicit Differentiation

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \frac{\sqrt{x} + 1}{\sqrt{y} + 1} = y^2[/tex]

Step 2: Differentiate

Implicit Differentiation:                                                                                 [tex]\displaystyle \frac{dy}{dx} \bigg[ \frac{\sqrt{x} + 1}{\sqrt{y} + 1} \bigg] = \frac{dy}{dx}[ y^2][/tex]Quotient Rule:                                                                                               [tex]\displaystyle \frac{(\sqrt{x} + 1)'(\sqrt{y} + 1) - (\sqrt{y} + 1)'(\sqrt{x} + 1)}{(\sqrt{y} + 1)^2} = \frac{dy}{dx}[ y^2][/tex]Rewrite:                                                                                                         [tex]\displaystyle \frac{(x^\Big{\frac{1}{2}} + 1)'(y^\Big{\frac{1}{2}} + 1) - (y^\Big{\frac{1}{2}} + 1)'(x^\Big{\frac{1}{2}} + 1)}{(y^\Big{\frac{1}{2}} + 1)^2} = \frac{dy}{dx}[ y^2][/tex]Basic Power Rule [Addition/Subtraction, Chain Rule]:                               [tex]\displaystyle \frac{\frac{1}{2}x^\Big{\frac{-1}{2}}(y^\Big{\frac{1}{2}} + 1) - \frac{1}{2}y^\Big{\frac{-1}{2}}y'(x^\Big{\frac{1}{2}} + 1)}{(y^\Big{\frac{1}{2}} + 1)^2} = 2yy'[/tex]Factor:                                                                                                           [tex]\displaystyle \frac{\frac{1}{2} \bigg[ x^\Big{\frac{-1}{2}}(y^\Big{\frac{1}{2}} + 1) - y^\Big{\frac{-1}{2}}y'(x^\Big{\frac{1}{2}} + 1) \bigg] }{(y^\Big{\frac{1}{2}} + 1)^2} = 2yy'[/tex]Rewrite:                                                                                                         [tex]\displaystyle \frac{x^\Big{\frac{-1}{2}}(y^\Big{\frac{1}{2}} + 1) - y^\Big{\frac{-1}{2}}y'(x^\Big{\frac{1}{2}} + 1)}{2(y^\Big{\frac{1}{2}} + 1)^2} = 2yy'[/tex]Rewrite:                                                                                                         [tex]\displaystyle x^\Big{\frac{-1}{2}}(y^\Big{\frac{1}{2}} + 1) - y^\Big{\frac{-1}{2}}y'(x^\Big{\frac{1}{2}} + 1)}= 4yy'(y^\Big{\frac{1}{2}} + 1)^2[/tex]Isolate y' terms:                                                                                             [tex]\displaystyle x^\Big{\frac{-1}{2}}(y^\Big{\frac{1}{2}} + 1) = 4yy'(y^\Big{\frac{1}{2}} + 1)^2 + y^\Big{\frac{-1}{2}}y'(x^\Big{\frac{1}{2}} + 1)}[/tex]Factor:                                                                                                           [tex]\displaystyle x^\Big{\frac{-1}{2}}(y^\Big{\frac{1}{2}} + 1) = y' \bigg[ 4y(y^\Big{\frac{1}{2}} + 1)^2 + y^\Big{\frac{-1}{2}}(x^\Big{\frac{1}{2}} + 1)} \bigg][/tex]Isolate y':                                                                                                       [tex]\displaystyle \frac{x^\Big{\frac{-1}{2}}(y^\Big{\frac{1}{2}} + 1)}{4y(y^\Big{\frac{1}{2}} + 1)^2 + y^\Big{\frac{-1}{2}}(x^\Big{\frac{1}{2}} + 1)} = y'[/tex]Rewrite/Simplify:                                                                                           [tex]\displaystyle y' = \frac{\sqrt{y} + y}{4\sqrt{x}y \Big( y^\Big{\frac{3}{2}} + \sqrt{y} + 2y \Big) + \sqrt{x} + x}[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Book: College Calculus 10e

Prove: Quadrilateral ABCD is a parallelogram.

m∠AEB = m∠CED

Answers

Answer:

m∠ AEB = m∠ CED ......... By Vertical Angles Theorem.

Step-by-step explanation:

Vertical Angles Theorem: Vertical angle theorem states that vertical angles, angles that are opposite each other and formed by two intersecting lines, are congruent. If two lines intersect each other, we have the two pair of vertical opposite angles. As shown in the figure. Here, ∠ 1 and ∠ 2 are vertical opposite angles, and also they are equal. ∠ 3 and ∠ 4 are also vertical opposite angles, and also they are equal. For, step 3. m∠ AEB = m∠ CED Therefore, the reason for this proof is Vertical Angles Theorem.

Use the given information to determine which of the following relationships
can be proved and why.
L= 20
ME ZP
ML = PO
A. ALMN - A OPQ, because of AAS.
B. ALMNE A OPQ, because of ASA.
C. We cannot prove any relationship based on these data.
D. ALMN=A OPQ, because of SAS,

Answers

Answer:

B. ∆LMN ≅ ∆OPQ because of ASA

Step-by-step explanation:

Two triangles are congruent if two angles and an included side of one triangle are congruent to two corresponding angles and a corresponding included side of the other.

From the information given, we have:

Two angles (<L and <M) in ∆LMN that are congruent to two corresponding angles (<O and <P) in ∆OPQ.

Also, included side in both triangles are congruent (ML ≅ PO).

Therefore, ∆LMN ≅ ∆OPQ by the ASA Theorem.

Please help explanation if possible

Answers

Answer:

Step-by-step explanation:

so d = 2r which means r = 5cm.

A = πr^2 = π(5)^2 = 25π =  (25)(3.14) = 78.5 cm^2.

So input 78.5

Answer:

see below

Step-by-step explanation:

so d = 2r which means r = 5cm.

A = πr^2 = π(5)^2 = 25π =  (25)(3.14) = 78.5 cm^2.

So input 78.5

HOPE IT HELPS YOU

1 poir
Question 1. Jessica has $1,625.00 to purchase a five-year Certificate of
Deposit (CD). In the chart, there are CD rates frombankrate.com. What
would the account ending balance be at Synchrony Bank if it is
compounded quarterly? *
Use the Compound Interest Formula to calculate the ending balance. A = P(1 + 5)nt
Nationwide
Bank
Nationwide
2.01%
No
Synchrony Bank
all synchrony
1.95%

Answers

9514 1404 393

Answer:

  $1790.99

Step-by-step explanation:

Given:

  $1625 is invested at an annual rate of 1.95% compounded quarterly for 5 years

Find:

  the ending balance

Solution:

The compound interest formula applies.

  FV = P(1 +r/n)^(nt) . . . Principal P at rate r for t years, compounded n per year

  FV = $1625(1 +0.0195/4)^(4·5) = $1625(1.004875^20) ≈ $1790.99

The account ending balance would be $1790.99.

Days before a presidential​ election, a nationwide random sample of registered voters was taken. Based on this random​ sample, it was reported that​ "52% of registered voters plan on voting for Robert Smith with a margin of error of ±​3%." The margin of error was based on a​ 95% confidence level. Fill in the blanks to obtain a correct interpretation of this confidence interval. We are​ ___________ confident that the​ ___________ of registered voters​ ___________ planning on voting for Robert Smith is between​ ___________ and​ ___________.

Answers

Answer:

We are 95% confident that the percentage of registered voters in the nation planning on voting for Robert Smith is between 49% and 55%.

Step-by-step explanation:

Given that :

Margin of Error = ±3%

Sample Proportion = 52%

Confidence level = 95%

The 95% confidence interval is :

Sample proportion ± margin of error

52% ± 3%

Lower boundary = 52% - 3% = 49%

Upper boundary = 52% + 3% = 55%

The interpretation is that at a given confidence level ; the popukation proportion based on the sample proportion and margin of error is in the confidence interval.

write your answer as an integer or as a decimal rounded to the nearest tenth

Answers

Answer:

VW ≈ 4.0

Step-by-step explanation:

Using the sine ratio in the right triangle

sin35° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{VW}{VX}[/tex] = [tex]\frac{VW}{7}[/tex] ( multiply both sides by 7 )

7 × sin35° = VW , then

VW ≈ 4.0 ( to the nearest tenth )

If there are g girls and b-boys in a room, write an expression for the total number of children in the room.

Answers

Answer:

g+b

number of girls+number of boys

if i am incorrect forgive me plz

The expression for the total number of children in a room is g+ b.

What is an expression?

Expressions in math are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.

What is addition?

Addition is the process of finding the total, or sum, by combining two or more numbers or variables.

According to the given question

We have

Number of girls = g

And, number of boys = b

Therefore, the expression for the total number of children in room is given by

Total number of children = g + b

Hence, the expression for the total number of children in a room is g+ b.

Learn more about expression and addition here:

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by selling a purse for rupees 250 Rajan loses one sixth of what cost should find the cost price of the first her loss percentage​

Answers

Answer:

300, 16.67%

Step-by-step explanation:

Let x be the cost price. x-(1/6)x=250. 5x/6=250. x=300. Losss percentage is 16.67%

A baseball is thrown into the air from the top of a 224-foot tall building. The baseball's approximate height over time can be represented by the quadratic equation
MO-167 +800+ 224, where t represents the time in seconds that the baseball has been in the air and represents the baseball's height in feet. When factored, this
equation is -16(-7)(t+ 2).
What is a reasonable time for it to take the baseball to land on the ground?
OA 2 seconds
ОВ
7 seconds
C. 5 seconds
D.
9 seconds

Answers

9514 1404 393

Answer:

  A.  7 seconds

Step-by-step explanation:

We assume your factored equation is something like ...

  h(t) = -16t(t -7)(t +2)

The time it takes the ball to reach the ground is the positive value of t that makes a factor zero:

  t -7 = 0   ⇒   t = 7

The ball will land on the ground in 7 seconds.

SOMEONE PLS HELP ME!!!

Answers

Answer:

No

Step-by-step explanation: Bye

Which equation is correct?
1
A. cos x =
sin a
1
B. tan x=
CSC 2
C. sec =
COS
1
D. cot 2 =
sec
SUBMIT


Answers

Yes it’s c) secx = 1/cosx
It’s a reciprocal identity

The requried secant function is the reciprocal of the cosine function, i.e., sec x = 1/cos x. Option C is correct.

What are trig ratios?

If you know the lengths of two sides of a right triangle, you can use trigonometric ratios to calculate the measures of one (or both) of the acute angles.

Here,
The correct equation is option C: sec x = 1/cos x.

This is because the secant function is the reciprocal of the cosine function, i.e., sec x = 1/cos x.

Option A is incorrect because the cosine and sine functions are not reciprocals of each other. Option B is incorrect because the tangent function is the reciprocal of the cotangent function, not the cosecant function. Option D is incorrect because the cotangent function is the reciprocal of the tangent function, not the secant function.

Learn more about trig ratios here:

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Find the length of AC

Answers

Answer:

377.19 (rounded off to 2dp)

Step-by-step explanation:

since its a right angled triangle, we can use tangent

tan(x) =opp/adj

tan(5) =33/AC

AC =33/tan(5)

which of the following is the formula in solving for the area of a circle?
A.A=2πr
B.A=πr²
C.A=πd
D.A=2πr²​

Answers

The area of circle is πr²

Answer:

πr²

Step-by-step explanation:

The answer is πr² where,

π = pi, 3.14...

r = radius

This is the most common way of solving for the area of the circle.

4 football is kicked with a speed of 18.0 m/s at an angle of 36.9to the horizontal. 8. How long is the football in the air? Neglect air resistance. A ) 1.1 s B C ) 2.2 D) 3.3 E) 4.0

Answers

9514 1404 393

Answer:

  C)  2.2 seconds

Step-by-step explanation:

The initial vertical speed of the football is ...

  v = (18.0 m/s)sin(36.9°) ≈ 10.807 m/s

Since the ball starts and ends at ground level, its speed when it hits the ground is the same as its launch speed. That is, the acceleration due to gravity causes the velocity to change from +v to -v. The time required to do that is ...

  t = 2v/g = 2(10.807 m/s)/(9.8 m/s^2) = 21.614/9.8 s ≈ 2.206 s

The football is in the air about 2.2 seconds.

Solve the following equation for n. Be sure to take into account whether a letter is capitalized or not.
t=n-r

Answers

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

[tex]n = t + r[/tex]

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Solving for 'n'...}}\\\\t = n - r\\----------\\\rightarrow t + r = n -r + r\\\\\rightarrow t+r = n\\\\\rightarrow \boxed{n=t+r}[/tex]

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

Which of the following is a quadratic function

Answers

A quadratic a function has a form of,

[tex]f(x)=ax^2+bx+c,a\neq0[/tex]

The first function has a term [tex]x^3[/tex] which doesn't fit the profile of a quadratic function. The highest exponent on x inside a quadratic function can be 2, but here we have 3 so this is not a quadratic function, but rather a cubic function.

The second function fits the form of a quadratic function perfectly.

The third function is a bit tricky. While technically the third function could be considered quadratic if the leading term would be something like [tex]0x^2[/tex] and we did't even see it written out because multiplying with 0. But when we specified the form of a quadratic function, we strictly said that the number before [tex]x^2[/tex] aka [tex]a[/tex] cannot equal to zero. So the last function is not a quadratic function but rather a linear function.

Hope this helps :)

Step-by-step explanation:

f(x) = 4x² + x - 3

[tex]f(x) = 4x {}^{2} + 3 - 2[/tex]

r3t40 is correct

A distribution of values is normal with a mean of 1986.1 and a standard deviation of 27.2.
Find the probability that a randomly selected value is greater than 1914.8.
P(X> 1914.8) =
Enter your answer as a number accurate to 4 decimal places. *Note: all z-scores must be rounded to
the nearest hundredth.

Answers

Answer:

I used the function normCdf(lower bound, upper bound, mean, standard deviation) on the graphing calculator to solve this.

Lower bound = 1914.8Upper bound = 999999Mean = 1986.1Standard deviation = 27.2

Input in these values and it will result in:

normCdf(1914.8,9999999,1986.1,27.2) = 0.995621

So the probability that the value is greater than 1914.8 is about 99.5621%

I'm not sure if this is correct 0_o

A local church holds an annual raffle to raise money for a new roof. They sell only 500 tickets at $50 each. This year's prizes include: $3,000 in cash, four $100 Amazon gift cards, and two $75 Visa gift cards. You buy one ticket. What is your mathematical expectation for this game

Answers

Answer:

The expectation for an event with outcomes:

{x₁, x₂, ..., xₙ}

Each one with probability:

{p₁, p₂, ..., pₙ}

Is:

Ev = x₁*p₁ + ... + xₙ*pₙ

There are 500 tickets sold.

1 of these, wins $3,000  (this is the event x₁)

4 of these, wins $100     (this is the event x₂)

2 of these, wins $75        (this is the event x₃)

The others do not have a prize.

So the probability of winning the $3000 is equal to the quotient between the number of tickets with that prize (1) and the total number of tickets (500)

p₁ = 1/500

Similarly, the probability of winning $100 will be:

p₂ = 4/500

And for the $75 prize:

p₃ = 2/500

Then the probability of not winning is:

p₄ = 493/500

Then the expected value for a single ticket is:

Ev = $0*493/500 + $75*2/500 + $100*4/500 + $3000*1/500

Ev = $7.1

If you take in account that you pay $50 for the ticket, the actual expectation should be:

E = $7.10 - $50 = -$42.90

Find r given: (4,-7) and (-2, r) with a slope of 8/3

Answers

Answer:

r = -23

Step-by-step explanation:

slope = (y1-y2)/(x1-x2)

(r--7)/(-2-4) = 8/3

(r+7)/-6 = 8/3

3(r+7)=8 x -6

3r + 21 = -48

3r = -69

r = -23

Use the graph to complete the statement. O is the origin.

T<2,1> ο r(90°,O) : (4,-1)

Answers

Answer:

(3,5)

Step-by-step explanation:

After transformation the point will be (3, 5).  

What is a rotation in a transformation ?

A rotational transformation can be done clockwise or anticlockwise to certain number of degrees. Rotational transformation does not alter the size and shape of the figure.

Rotating (4,-1) 90° anticlockwise centred at the origin yields the point (1, 4).

Then transforming the point (1, 4) two units to the right and 1 unit up results in the point (3, 5).

We can also rotate 90° clockwise that would result in some different point on this coordinate system.

Instead on a straight line we can also have some 2D figures like a triangle a rectangle etc.

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express the following in standard form (0.000000045)^4​

Answers

0.00000004 to the power of 4

Your answer would be 0

The point (3,-4) is on the terminal side of an angle 0. What is cos 0?
А. 3/4
В. -3/4
C. 3/5
D. -3/5 E. 3

Answers

9514 1404 393

Answer:

  C.  3/5

Step-by-step explanation:

The distance from the origin to the given point is ...

  d = √(3² +(-4)²) = √(9+16) = 5

The cosine of the angle is the ratio of the x-coordinate to this value:

  cos(θ) = x/d

  cos(θ) = 3/5

Other Questions
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