An audio compact disk (CD) has a playing time of 55 minutes. When the music starts, the CD is
rotating at an angular speed of 480 revolutions per minute (rpm) and during the playback the
rotation slows down. The average angular acceleration of the CD is a = -4.0 rev/min . Find the
angular speed at which the CD is rotating at the end of the music. Express your answer both in
rev/min and also in rad/s.

Select one:
27.2 rad/s
220 rad/s
120 rad/s
260 rad/s
22 rad/s

An Audio Compact Disk (CD) Has A Playing Time Of 55 Minutes. When The Music Starts, The CD Isrotating

Answers

Answer 1

Answer:

See below

Explanation:

-4 rev / min^2 * 55 min =  - 220 rev/ min

480 - 220 = 260 rev/min at end

2pi radians /rev * 260 rev/min  = 1633.6 Radians/min

Answer 2

At the end of the music, the angular speed of the C.D. would be (d) 260 rev/minute and 1633.6 rad/minute

To calculate angular speed following information is given in the question:

The angular speed (ω) of the C.D. at starting = 480 revolutions/minuteThe playing time (t) of the C.D. is = 55 minutesThe angular acceleration (α) of the C.D. = -4 rev/[tex]min^{-2}[/tex] Angular speed of the C.D. at the end of the music will be = α*tAngular speed of the C.D. at the end of the music will be = 4 rev/[tex]min^{-2}[/tex] *55 min = -220 rev/minAt the end of the music angular speed = 480-220 rev/min = 260 rev/minValue of angular speed in rad/sec = 2π radians/rev*260 rev/min = 1633.6 Radians/min

Hence, option (d) is correct which states that the angular speed is 260 rev/min and 1633.6 radians/min.

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Related Questions

Microphones are used to convert sound vibrations to electrical signals. In one kind of microphone, sound waves move a coil of wire up and down in a magnetic field, as shown in (Figure 1). The coil shown has a diameter of 1.4 cm and has 100 turns; the 0.010 T magnetic field points radially out from the north pole to the south.

If the microphone's emf at some instant is 10 mV , what is the speed of the coil?

Answers

The speed of coil of the microphone is 0.227 m/s

What is a Microphones?

A microphone is a device used to transmit sound energy through electrical energy. it makes use of magnetic fields whose strength is measures in Tesla

Given data

D = 1.4cm = 0.014m

N = 100

B = 0.010T

emf = 10mV

speed = dx / dt = ?

solution

emf = N dΦ / dt

Φ = BA

A =  2 pi R x

R = D / 2 = 0.014 / 2 = 0.007

emf = N d ( B 2 pi R x ) / dt

emf = N B 2 pi R dx / dt

and dx / dt = speed

speed = emf / N B 2 pi R

speed = 10 * 10 ^ -3 / ( 100 * 0.010 * 2 * 3.142 * 0.007)

speed = 10 * 10 ^ -3 / ( 0.043988 )

speed = 0.227 m/s

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ε = vLB

v - velocity = ?

ε - emf = 10mV = 0.01V

B - magnetic field = 0.010 T

L - length of wire = find

Find L

N - turns of wire = 100

d = diameter = 1.4 cm = 0.014 m

L = circumference of 1 turn of wire * # of turns of wire

L = 2πr * N

L = πdN

L = π * 0.014 m * 100

L = 1.4π m

Return to main equation

ε = vLB

[tex]v = \frac{\epsilon}{LB}[/tex]

[tex]v = \frac{0.01}{(1.4\pi)*(0.010)}[/tex]

v = 0.227 m/s

1. A person walks 20 meters toward the east and then walks 30 meters toward the west. What is the total distance covered? What is the displacement? with explaination
2. What is the average speed of a car that travels 2000 meters in 5 minutes in meters/second? with explaination

Answers

Answer:

1.) 30 m is the total distance covered 10m is the displacement you

2.)24,000m/h (24km/h or 6.67m/s) Average speed is calculated by dividing the total distance that something has traveled by the total amount of time it took it to travel that distance

Explanation:

Which statement about the observed results of the double-slit experiment is true?

O Waves that are out of phase constructively interfere to create bright bands.

O Waves that are in phase destructively interfere to create bright bands.

O Waves that are in phase constructively interfere to create bright bands.

O Waves that are out of phase constructively interfere to create bright bands.

Answers

Waves that are in phase constructively interfere to create bright bands was observed in the double-slit experiment.

What is Interference?

This is defined as the phenomenon which occurs when two waves meet while traveling along the same medium.

A wave when in phase undergoes constructive interference while out of phase undergoes destructive interference which is why option C was chosen as the most appropriate choice.

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An object with a mass of 70.5 kg is placed on a 2-meter strand of metal (with a 2-millimeter radius) hanging from the ceiling. It stretches 1 millimeter. What is this strand made of?

Answers

Based on the value of the Young's modulus, the strand of the metal is made of copper.

Young's modulus of the metal

The Young's modulus of the metal is calculated as follows;

E = stress/strain

Stress of the metal

The stress of the metal is calculated as follows;

σ = F/A = mg/A

where;

A is area of the metal

A = πr²

A = π( 2 x 10⁻³)²

A = 1.257 x 10⁻⁵ m²

σ = (70.5 x 9.8) / (1.257 x 10⁻⁵)

σ = 5.5 x 10⁷ N/m²

Strain of the metal

The strain is calculated as follows;

strain = x/L

where;

x is extension

L is original length

strain = (1 x 10⁻³ m) / 2 m

strain = 5 x 10⁻⁴

Young's modulus of the metal

E = stress/strain

E = (5.5 x 10⁷ ) / (5 x 10⁻⁴)

E = 1.1 x 10¹¹ N/m²

E = 110 Gpa

The Young's modulus of copper metal is 110 Gpa

Thus, based on the value of the Young's modulus, the strand of the metal is made of copper.

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Year

Carbon Dioxide (CO2) in Atmosphere (ppm*)

2010



2011



Copyright © Enginuity Inc.

Copyright © Enginuity Inc.




Global Temperature Change – Student Guide




2012



2013



2014



2015



2016



2017

Answers

Answer:

Theres a diagram missing for Q

Explanation:

What is all this?

Could you add a question so I can answer it :)

A dragster's top acceleration is 60 m/s.
If it accelerates for 3 seconds from the
starting line, how fast will it be going?

Answers

Answer:

very fast

Explanation:

The maximum kinetic energy of electrons ejected from a sheet of uranium exposed to 250 nm ultraviolet light is 1.33 EV.

What is the work function of the uranium metal? (Planck's constant (h) is 6.626 × 10-34 J∙s, c is 3.0 × 108 m/s, 1 eV = 1.6 × 10-19 J)

Answers

Answer: The maximum kinetic energy KEe of ejected electrons (photoelectrons) is given by KEe = hf − BE, where hf is the photon energy and BE is the binding energy (or work function) of the electron to the particular material.

Explanation:

The work function of the uranium metal will be given by the value 7.9*10^-19

What is work function?

The work function of a particle is defined as the product of the planks constant to the frequency of the particle.

[tex]\phi=h\times f[/tex]

Now the frequency will be given as

[tex]f=\dfrac{c}{\lambda}[/tex]

So the formula will become

[tex]\phi=\dfrac{hc}{\lambda}[/tex]

h=6.626 × 10-34 J∙s

c=3.0 × 108 m/s

[tex]\lambda[/tex] = 250 nm 250* 10^-9

[tex]\phi=\dfrac{6.626\times 10^{-26}\times3\times 10^{8}}{250\times 10^{-9}}[/tex]

[tex]\phi=7.9\times 10^{-19}[/tex]

Hence the work function of the uranium metal will be given by the value 7.9*10^-19

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is this right lol i think it is but im not so sure XD

Answers

[tex]\bold{Heya!}[/tex]

Yup. your answer is correct!

→ EXPLANATION :-

1. just put the numbers in order [tex]^1^6^, ^1^8^,^2^3^,^2^4^,^2^9^,^3^0[/tex]

2. Cross off high/low pairs, we left with the numbers :-

        [tex]23,24.[/tex]

3. Add the leftover numbers.

        [tex]23 \: + 24 = 47.[/tex]

Divide the sum of 2.

        [tex]\frac{47}{2} = 23.5[/tex]

Hopefully This Helps ! ~

#LearnWithBrainly

[tex]\underline{Answer :}[/tex]

Jaceysan ~

Answer:

GIVE HIM BRAINLEST

Loosing weight without diet require moving to the top of a mountain explain using weight and gravitational force

Answers

Answer:

You would weigh very slightly more at sea level than at the top of a mountain, not enough for you to notice, but a measurable amount. Weight, which really means gravitational force, is proportional to the product of the masses of two objects acting on each other, in this case the giant earth and the minuscule you.

Explanation:

An electron of mass 9.11 x 10 -31 kg moves with a speed of 0.8725 c. What is its momentum?

Answers

Explanation:

momentum = mass × velocity

mass = 9.11 × 10^-31

velocity = 0.8725 multiplied by c ( which is the speed of light )

therefore velocity = 0.8725 × 3 × 10^8 = 2.6175 × 10^8 m/s

[tex]m = 9.11 \times 10 {}^{ - 31} \times 2.6175 \times 10 {}^{8} [/tex]

[tex]m = 9.11 \times 2.6175 \times 10 {}^{ - 31 + 8} [/tex]

[tex]m = 23.85 \times 10 {}^{ - 23} kgms {}^{ - 1} [/tex]

if this helped pls give brainliest

.
Which of the following is not true about the lymphatic system?
it drains white blood cells away from tissue
it brings nutrients to the tissue
it builds muscle cells
it fights infection

Answers

Answer:

it builds muscle cells

Explanation:

took test

Can someone help with this

Answers

Hi there!

A.

We can use the work-energy theorem to solve.

Initially, both blocks have gravitational potential energy, which is then converted to kinetic energy.

Recall:
[tex]U = mgh \\[/tex]

U = Potential Energy (J)
m = mass (kg)
g = acceleration due to gravity (m/s²)

h = height (m)

And at the end, block 2 has both kinetic and potential energy. Kinetic is defined as:
[tex]KE = \frac{1}{2}mv^2[/tex]

v = velocity (m/s)

We can do a summation of initial and final forces.

Initial:
[tex]E_i = m_2g\frac{h}{2} + m_1gh[/tex]

Final:
[tex]E_f = \frac{1}{2}m_2 v^2 + m_2g\frac{3h}{2} + \frac{1}{2}m_1 v^2[/tex]

Set the two equal (no energy loss in this situation) and solve for velocity.

[tex]m_2g\frac{h}{2} + m_1gh = \frac{1}{2}m_2 v^2 + m_2g\frac{3h}{2} + \frac{1}{2}m_1 v^2\\\\m_2g\frac{h}{2} + m_1gh - m_2g\frac{3h}{2} = \frac{1}{2}m_2 v^2 + \frac{1}{2}m_1 v^2\\\\v^2 = \frac{gh(\frac{m_2}{2} + m_1 - \frac{3m_2}{2})}{\frac{1}{2}m_2 + \frac{1}{2}m_1}\\\\v = \sqrt{\frac{gh(\frac{m_2}{2} + m_1 - \frac{3m_2}{2})}{\frac{1}{2}m_2 + \frac{1}{2}m_1}}\\\\v = \boxed{3.704 \frac{m}{s}}[/tex]

**This can be solved in a simpler way using a summation of forces.

B.

Now, we can do a summation of forces to solve. First, we must solve for the acceleration of the system now that we have found the velocity. Use the kinematic equation:
[tex]v_f^2 = v_i^2 + 2ad[/tex]

Initial velocity is 0 m/s, so:
[tex]v_f^2 = 2ad\\\\a = \frac{v_f^2}{2d} = \frac{(3.704^2)}{2(2.10)} = 3.267 \frac{m}{s^2}[/tex]

Now, we can use a summation of forces for any block. We can do block 1:
[tex]\Sigma F = m_1g - T[/tex]

Using Newton's Second Law:
[tex]m_1a = m_1g - T\\\\T = m_1g - m_1a \\T = m_1 (g - a) = 4.10(9.8 - 3.267) = \boxed{26.828 N}[/tex]

Seamus made an electromagnet from an iron nail, a piece of copper wire with three coils spread out across the nail, and a AAA-
sized battery. His magnet attracts only one paper clip, and he wants to boost the power of his magnet to attract at least four paper
clips. What two things can Seamus do to accomplish his goal?
A)
B
Seamus can add batteries to decrease the voltage, and he can decrease the
space between the wire coils.
Seamus can add batteries to increase the voltage, and he can increase the
space between the wire coils,
Seamus can add batteries to increase the voltage, and he can decrease the
space between the wire coils.
Seamus can add batteries to decrease the voltage, and he can increase the
space between the wire coils
D

Answers

Seamus can add batteries to increase the voltage, and he can decrease the space between the wire coils to accomplish this goal.

What is Attraction?

This is defined as any type of force that causes objects to come together and is possessed by objects such as a magnet.

In order to increase the power of the magnet it is best to increase the voltage and decrease the space of the coils so as to ensure it attracts at least four paper clips which makes option C the most appropriate choice.

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What is the centripetal acceleration of 30 kg child standing 5 meters from the center of a
rotating carousel? The carousel is rotating at a linear velocity of 20 m/s.

Answers

Answer:

80m/s2

Explanation:

m=30kg. r = 5meter v = 20m/s2 a= ? centripetal acceleration = v*v/r

20*20/5=80m/s2

centripetal acceleration=80 m/s2

Spring
The pulling force acting on an object is 350.0 N. It also is being affected by a 50.0 N
kinetic friction force. As a result, its acceleration is 3.0 m/s?, what is its mass?
A. 67 kg
B. 83 kg
C. 100 kg
D. 600 kg
E. 0.0 kg
If the gravitational force of the Farth nulling you"down" in th

Answers

Answer:

100 kg

Explanation:

Net force = 350 - 50 = 300 N

F= ma

300 N  = m * 3 m/s^2

100 kg = mass

The measured value of mass M in an experiment is M = 0.743 ± 0.005kg. The error in 2M is
Select one:
dM
3dM
2.5 dM
2dM​

Answers

Given the measured value of mass M in the experiment the error in 2M is  ; dM

Given data :

Measured value of mass M = ( 0.743 ± 0.005 ) kg

The error in 2M in the measured value

The error in 2M in the measured value M = 0.743 ± 0.005 kg is dM while the error in M² will be 2dM

Hence we can conclude that the measured value of mass M in the experiment the error in 2M is  ; dM.

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If a→=3i^-2j^-k^ and b→=i^+4j^+k^, find a unit vector n^ normal to the plane containing a→ and b→ such that a→, b→ and n^, in this order, form a right-handed system.​

Answers

The unit vector normal to the plane is ; n = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]

Given data :

The unit vectors

a→=3i^-2j^-k^  and  b→=i^+4j^+k^

Determine the unit vector normal to the plane

The unit vector normal to the plane is calculated as

n = [tex]\frac{a*b}{|b*b|}[/tex]  ---- ( 1 )

where ; a→ * b→ =  2i - 4j + 14k  and  |b * b| = [tex]\sqrt{216}[/tex]  

back to equation ( 1 )

n = ( 2i - 4j + 14k ) / [tex]\sqrt{216}[/tex]

  = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]

Hence we can conclude that The unit vector normal to the plane is ; n = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]

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If a snowboarder’s initial speed is 4 m/s and comes to rest when making it to the upper level. With a slightly greater initial speed of 5 m/s, the snowboarder is moving to the right on the upper level. His final speed in this case is 3 m/s. Suppose this situation is repeated on planet Epsilon, where gravity is less than gravity on earth.

A. Would the height of the hill on Epsilon cause a reduction in speed from 4 m/s to 0 greater than, less than, or equal to the height of the corresponding hill on earth? Explain.

B. Consider the hill on Epsilon discussed in part A. If the initial speed at the bottom of the hill is 5 m/s, will the final speed at the top of the hill be greater than, less than, or equal to 3 m/s? Explain.

Answers

(a) At a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

(b) If the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

Conservation of mechanical energy

The effect of height  and gravity on speed on the given planet Epislon is determined by applying the principle of conservation of mechanical energy as shown below;

ΔK.E = ΔP.E

¹/₂m(v²- u²) = mg(hi - hf)

¹/₂(v²- u²) = g(0 - hf)

v² - u² = -2ghf

v² = u² - 2ghf

where;

v is the final velocity at upper levelu is the initial velocityhf is final heightg is acceleration due to gravity

when u² = 2gh, then v² = 0,

when gravity reduces, u² > 2gh, and v² > 0

Thus, at a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

Final speed

v² = u² - 2ghf

where;

u is the initial speed = 5 m/sg is acceleration due to gravity and its less than 9.8 m/s²v is final speedhf is equal height

Since g on Epislon is less than 9.8 m/s² of Earth;

5² - 2ghf > 3 m/s

Thus, if the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

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a cup of coffee has a mass of .297 kg if you place this cup of coffee on a desk and let it sit there undisturbed how much force is the desk exerting on it

Answers

The force of the table upon the cup is 2.9106 N

The desk is exerting a normal force of approximately 2.913 Newtons on the cup of coffee, which is also equal to 2.913 N in magnitude.

The force that the desk exerts on the cup of coffee is known as the normal force. This force counteracts the weight of the coffee cup due to gravity. The normal force is equal in magnitude and opposite in direction to the force exerted by the cup's weight.

The weight of an object is given by the equation:

Weight = mass × acceleration due to gravity

Where:

Mass = 0.297 kg (mass of the coffee cup)

Acceleration due to gravity (on the surface of the Earth) ≈ 9.81 m/s²

Weight = 0.297 kg × 9.81 m/s² ≈ 2.913 kg m/s² (Newtons)

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list down the general of the office of guardian and tutor​

Answers

Answer:

legal guardians, the four types: personal guardians, financial guardians, conservators, and pet “guardians”

what are the four things that affect the resistance of a wire? A. length, diameter, material, and temperature B. weight, diameter, material, and temperature C. length, height, material, temperature D. length, weight, material, and temperature

Answers

Answer:

A. length, diameter, material, temperature

If a lever was a meter long and the fulcrum was placed at 50mm, what would the mechanical advantage be?

Please show work if possible

Answers

Answer:

The mechanical advantage would depend on where the load force and the balancing force were placed on the stick

MA = (50 - F) / (L - 50)

Supoose the balancing force was placed at zero and the load at 75 cm

then MA = (50 - 0) / (75 - 50) = 50 / 25 = 2

or the balancing force was applied at 10 cm and the load force was applied at 60 cm then

MA =  (50 - 10) / (60 - 50) = 40 / 10 = 4

6. A spring is originally 1.5 m long. It is stretched so that it is 1.8 m long. The spring constant is 50 N/m.
Find the potential energy stored in the spring.

Answers

Answer:

PE = 1/2 K X^2

K = 50 N/m

X = .3 m

PE = 1/2 * 50 * .3^2 = 2.25 Joules

Match the missions with their objectives.
NEAR
Lunar Prospector
Deep Impact
SETI
mapping the Moon's surface composition,
looking for possible deposits of polar ice,
and examining the Moon's resources,
structure, and origins
first space probe to orbit and perform
an in-depth Investigation of an asteroid
searching for extraterrestrial life in the universe
probing beneath the surface of a comet to
obtain clues about its internal composition
and structure

Answers

Matching the missions with their objectives

NEAR -------> First space probe to orbit and perform an in-depth Investigation of an asteroid. Lunar prospector ----- > mapping the Moon's surface composition,looking for possible deposits of polar ice,and examining the Moon's resources,structure, and origins.Deep Impact -------> probing beneath the surface of a comet to obtain clues about its internal composition and structureSETI -----> searching for extraterrestrial life in the universe

The Mission Overview

The NEAR ( Near Earth Asteroid Rendezvous ) is a mission whose objective is to study origin and nature of objects near the earth such as asteroids and comets.

Lunar prospector was a mission designed to perform an orbit investigation of the moon.

The deep impact mission created by NASA was to probe beneath the comet and discover the structure and composition. The deep impact projected lasted for 9 years in space.

Hence we can conclude that the missions and their objectives are as listed above.

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1) How many joules of heat are required to raise the temperature of 550 g of water from
12.7 °C to 28.8°C ? Specific heat of liquid water is 4.184 J/g °C.

Answers

Answer:

Explanation:

You can use [tex]Q = mc\Delta T=(550)(4.184)(28.8-12.7)=37049.32[/tex] joule.

The two basic properties of all matter are ______ and ______.
options for first blank
a. length B. volume
options for second blank
a. density B. mass

Answers

Answer:

volume , mass

Explanation:

the 3 basic properties of a matter is volume, mass and shape.

1. Discuss the two ways by which volcanoes are formed.

2. Does the theory of plate tectonics answer the question on why volcanoes erupt? Support your answer.

3. What are mantle plumes and where are they usually found?

4. What are the gases released by volcanoes in smaller amounts?

5. Extinct volcanoes may be classified as inactive volcanoes but this doest not mean they will not erupt again. Explain this statement.​

Answers

Answer:

1.Divergent boundaries (crust moves apart, magma fills in) Convergent boundaries (magma fills when one plate goes beneath another) Hot spots (a large magma plume rises from mantle)

2.Some mountains are made of solid rock, like the Rocky Mountains or the Swiss Alps. But, some mountains are actually volcanoes.

3.an area under the rocky outer layer of Earth, called the crust, where magma is hotter than surrounding magma.

4.hydrogen sulfide, carbon monoxide, hydrogen chloride, hydrogen fluoride, and other minor gas species.

5.Extinct volcanoes are not expected to erupt in the future. Inside an active volcano is a chamber in which molten rock, called magma, collects. Pressure builds up inside the magma chamber, causing the magma to move through channels in the rock and escape onto the planet's surface.

Explanation:

hope its help:)

Consider the two-slit interference experiment. Electromagnetic radiation passes through the two slits that are a distance of 0.0170 nm apart. A fourth-order bright fringe forms at an angle of 8.0 degrees relative to the incident beam. What is the wavelength of the light? (1 point)

O 581 nm

O 420 nm

O 789 nm

O 591 nm

Answers

Answer:

The answer is 581

Explanation:

I just took the Quick Check and got it right.

A atom in its ground state contains 18 electrons. how many of these electrons are in orbital l=0 values?​

Answers

Orbital one has one electron

The Empire State Building is about 381m high. If you threw a baseball downward at 25 m/s from the top of the building how fast would it be traveling just before it landed?

Answers

Answer:

Explanation:

You can use that [tex]v = v_{o}+gt[/tex] or [tex]v^{2}=v_{o}^{2}+2gh=(25)^{2}+(2)(10)(381)=8245 \rightarrow v \approx 90.8[/tex] m/s.

Other Questions
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