An architectural drawing lists the scale as 1/4" = 1'. If a bedroom measures 212" by 334" on the drawing, how large is the bedroom?

The exponential equation is given by y = 700(2)ˣ

An exponential function is given by:

y = abˣ

where y, x are variables, a is the initial value of y and b is the multiplier.

Let y represent the population of fish after x hours.

Given that he starts with 700 fishes, hence

a = 700

The population of the fish doubles every year, hence:

b = 2

The exponential equation becomes:

y = 700(2)ˣ

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Answer:

4

Step-by-step explanation:

Equation:-

2(5-3)

=> 2(2)

=> 4

[tex]-5x -16 = 8x -1\\\\\implies 8x +5x = -16 +1 \\\\\implies 13x = -15\\\\\implies x = -\dfrac{15}{13}[/tex]

Hey there!

(3)(4)(-3.5)

= 12(-3.5)

= -42

Therefore, your answer SHOULD be: -42

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Using the probability concept, it is found that there is a [tex]\frac{7}{20}[/tex] probability that the three segments chosen could form a triangle.

A probability is the number of desired outcomes divided by the number of total outcomes.

Combination formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

Total outcomes:

3 segments from a set of 6 lengths, hence:

[tex]C_{6,3} = \frac{6!}{3!3!} = 20[/tex]

Desired outcomes:

Then:

[tex]p = \frac{D}{T} = \frac{7}{20}[/tex]

[tex]\frac{7}{20}[/tex] probability that the three segments chosen could form a triangle.

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Answer:

Answer below

Step-by-step explanation:

Time can not be negative from any perspective. Hence, the correct answer is 10.16 seconds.

The equation of the path of a rocket is given that is  y= x^2 + 153x + 98

We need to determine the time that the rocket will hit the ground.

Now, if the rocket hits the ground after the launching then the overall displacement at the time of hitting the ground will be zero.

Therefore, the value of y is 0.

Thus,  -16x^2 +153x + 98 = 0

Now, the formula for finding the roots of the quadratic equation  

 ax^2 +bx +c = 0 is given as:

 [tex]x^{1} =\frac{-b+\sqrt{b^2 -4ac} }{2a}[/tex]

[tex]x^2 = \frac{-b -\sqrt{b^2 -4ac} }{2a}[/tex]

Comparing the expression with the standard form of the equation.

a = -16b = 153 and c = 98

By applying the formula there are two values are come that is,

x^1 = -0.602555

x^2 = 10.1651  

Time can not be negative from any perspective.

Hence, the correct answer is 10.16 seconds.

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(Hope this helps can I pls have brainlist (crown)☺️)

Answer:

B. m+4

Step-by-step explanation:

You are just writing the same equation but backwards so that the numbers still stay the same as well as the answer.

Answer: A

Step-by-step explanation:

Answer: 2

Step-by-step explanation:

Answer:

F= ma

m = F/a

m = 50/2

m = 25

Answer equal 25

Answer:

C

Step-by-step explanation:

standard form is ax + by = c, which is true for the third option.

Answer:

The expression is unclear so:

If the denominator is [tex]\sqrt{x}-1[/tex] then your set of existence is given by

[tex]\left \{ {{x\ge0} \atop {x\ne1}} \right.[/tex]

since you want the quantity inside both square roots to be positive (and it happens for both to be simply [tex]x\ge0[/tex] and you don't want a zero at the denominator so you have to rule out 1.

If the square root includes the whole denominator [tex]\sqrt{x-1}[/tex] the condition becomes [tex]\left \{ {{x\ge0} \atop {x>1}} \right.[/tex]

where you don't include the extreme in the second condition since, again, you don't want to divide by 0. The answer in this case is simply [tex]x>1[/tex] since values between 0 and 1 will give a negative root which is not a real number.

Step-by-step explanation:

a cube has 6faces.

side = 60/6 = 10cm

volume = 1000cm³.

hope this helps you.

Answer:

-1/3 or 1/-3 (it doesn't matter which one you pick because its still the same)

Step-by-step explanation:

You find slope by doing rise over run. Its left to right so you start on the left dot and go down one. This makes it -1 because you're going down, not up. You move 3 to the right which makes it positive. Once you do this itll lead you right the the 2nd point. 1 down= -1

                                       3 right=   3  

                                                -1/3

The amount by which the length and width of a shed can be increased to

more than double the area, depends on the initial dimensions.

Reasons:

The given parameters of the shed are;

The length of the shed = 12 m

Width of the shed = 5 m

The amount by which the length and the width are increased = The same amount

The new area after the increase in the length and width of the shed = More than double the initial area

Required:

The amount of increase in the length.

Solution:

Let the amount by which the length and width are increased = x

We have;

Initial area of the shed = 12 m × 5 m = 60 m²

The new area = (12 + x) × (5 + x) > 2 × 60

By multiplication, we get;

(12 + x) × (5 + x) = x² + 17·x + 60 > 2 × 60 = 120

x² + 17·x + 60 - 120 > 120 - 120 = 0

x² + 17·x - 60 > 0

By factorization, we get;

(x + 20)·(x - 3) > 0

x > -20, or x > 3

The increase (positive) amount of the solution is x > 3

Therefore, the amount by which both the length and the width can be increased to more than double the area is x > 3 meters

Learn more about the area of a rectangle here:

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Answer:

A-B = 6x^2-7x-6

Step-by-step explanation:

A = 5x^2-4x-11

B = x^2+3x-5

A-B = (5x^2-4x-11) - (-x^2+3x-5) = 5x^2-4x-11+x^2-3x+5 = 6x^2-7x-6

Answer: $106.00

Step-by-step explanation:

Answer:

$100

Step-by-step explanation:

12x5=60

+40= $100

Answer:

$100

Step-by-step explanation:

This is easy

12x5=60

+40=$100

Answer:

C

Step-by-step explanation:

Answer:

Ig 200 miles

Step-by-step explanation:

I am guessing

Answer:

14x 2 +9

Step-by-step explanation:

Answer:

61 m²

Step-by-step explanation:

Find the area of the whole rectangle and subtract the part that is cut off

Area =  [tex]11 *8 - 9 *(8-5)[/tex]

        = [tex]88 - 9*3[/tex]

        = [tex]88 - 27[/tex]

        = [tex]61[/tex]

Units = m * m or m²

61 m²

-Chetan K

Answer:

[tex]x=\frac{3b}{2} +\frac{5a}{2}[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

5(x - a) = 3(x + b)

5x - 5a = 3x + 3b

      2x = 5a + 3b

        x = 2.5a + 1.5b

Answer:

LCD = 30

Step-by-step explanation:

[tex]\frac{5}{6}[/tex] x - [tex]\frac{1}{10}[/tex] x = [tex]\frac{2}{15}[/tex]

Multiply through by 30 ( the LCM of 6, 10, 15 ) to clear the fractions

25x - 3x = 4

22x = 4 ( divide both sides by 22 )

x = [tex]\frac{4}{22}[/tex] = [tex]\frac{2}{11}[/tex]

Answer:

5

Step-by-step explanation:

[tex] \frac{5}{6} x - \frac{1}{10} x = \frac{2}{15} \\ \frac{50x - 6x}{60} = \frac{2}{15} (criss \: cross) \\ \frac{44x}{60} = \frac{2}{15 } \\ \frac{11x}{15} = \frac{2}{15} (simplify) \\ 165x = 30(criss \: cross) \\ x = \frac{30}{165} = \frac{6}{33} = \frac{2}{11} \\ x = \frac{2}{11} [/tex]

Answer:

[tex]\frac{d\theta}{dt}=-\frac{2}{5}[/tex] at [tex]x=12[/tex]

Step-by-step explanation:

[tex]\frac{dx}{dt}=2[/tex]

[tex]\frac{d\theta}{dt}=?[/tex]

[tex]x=12[/tex]

[tex]cos(\theta)=\frac{adjacent}{hypotenuse}[/tex]

[tex]cos(\theta)=\frac{x}{13}[/tex]

[tex]\frac{d}{dt}cos(\theta)=\frac{d}{dt}\frac{x}{13}[/tex]

[tex]-sin(\theta)\frac{d\theta}{dt}=\frac{1}{13}\frac{dx}{dt}[/tex]

[tex]-sin(\theta)\frac{d\theta}{dt}=\frac{1}{13}(2)[/tex]

[tex]-sin(\theta)\frac{d\theta}{dt}=\frac{2}{13}[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-13sin(\theta)}[/tex]

[tex]cos(\theta)=\frac{x}{13}[/tex]

[tex]cos(\theta)=\frac{12}{13}[/tex]

[tex]\theta=cos^{-1}(\frac{12}{13})[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-13sin(\theta)}[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-13sin(cos^{-1}(\frac{12}{13}))}[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-13(\frac{5}{13})}[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-5}[/tex]

[tex]\frac{d\theta}{dt}=-\frac{2}{5}[/tex]

The value of θ is given by the inverse sine function, from which the rate of

change of θ with respect to x can be derived.

Reasons:

[tex]\displaystyle \frac{dx}{dt} = \mathbf{2 \ units \ per \ second}[/tex]

[tex]\displaystyle cos(\theta) = \frac{x}{13}[/tex]

[tex]\displaystyle \theta = arccos \left(\frac{x}{13}\right)[/tex]

[tex]\displaystyle \frac{d}{dx} \theta = \frac{d\left(arccos \left(\frac{x}{13}\right)\right)}{dx} = \mathbf{\frac{\sqrt{169-x^2} }{x^2-169}}[/tex]

Using chain rule of differentiation, we have;

[tex]\displaystyle \frac{d\theta}{dt} = \mathbf{ \frac{d\theta}{dx} \times \frac{dx}{dt}}[/tex]

Therefore;

[tex]\displaystyle \frac{d\theta}{dt} =\frac{\sqrt{169-x^2} }{x^2-169}\times \frac{dx}{dt} = \mathbf{\frac{\sqrt{169-x^2} }{x^2-169}\times 2}[/tex]

When x = 12, we get;

[tex]\displaystyle \frac{d\theta}{dt} =\frac{\sqrt{169-12^2} }{12^2-169}\times 2 = -\frac{2}{5} = -0.4[/tex]

The rate of change of the angle, θ, with time at the instant when x = 12 is -0.4 rad/s

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Answer:

The answer is 90.

Step-by-step explanation:

90 is in the middle

Answer:

d

Step-by-step explanation:

cause i said so

Answer:

First, let's look at some polynomials of even degree (specifically, quadratics in the first row of pictures, and quartics in the second row) with positive and negative leading coefficients:❤