An airplane is traveling at 250 m/s in level flight. If the airplane is to make a change in direction, it must travel is a horizontal curved path. To fly in the curved path, the pilot banks the airplane at an angle such that the lift has a horizontal component that provides the horizontal centripetal acceleration to move in a horizontal circular path. If the airplane is banked at an angle of 15.0 degrees, then the radius of curvature of the curved path of the airplane is

Answer:

Explanation:

Given

initial velocity u = 0m/s

final velocity v = 18m/s

To get the time it takes the bird to make this trip, we will use the equation of motion

v = u+gt

g is the acceleration due to gravity = 9.81m/s²

t is the time

Substitute into the formula:

[tex]18 = 0+(9.81)t\\18 = 9.81t\\9.81t = 18\\t = \frac{18}{9.81}\\ t = 1.84secs[/tex]

Hence it took the bird 1.84seconds to make this trip

Answer:

.

Explanation:

Analysing the question:

We are given:

mass of object (m) = 0.03 kg

height of object (h) = 2.94 m

acceleration due to gravity (a) = 10 m/s²

initial velocity (u) = 0 m/s [the object fell, we are NOT given any initial velocity]

final velocity (v) = v m/s

Solving for Final velocity:

from the third equation of motion:

v² - u² = 2ah

replacing the variables

(v)² - (0)² = 2(10)(2.94)

v² = 58.8

v = 7.67 m/s

Answer:

C. Wanda's waist circumference indicates that she is not at risk, but her BMI indicates that she underweight. She should develop a plan to move her BMI into the normal range.

Explanation:

edge 2020 Brainliest would be appreciated

Answer:

Wanda's waist circumference indicates that she is not at risk, but her BMI indicates that she underweight. She should develop a plan to move her BMI into the normal range.

Explanation:

I just did the Cumulative Exam Review

Earth's rotation is crucial to understanding the Coriolis effect. The Equator is where Earth rotates more quickly than the poles. There at Equator, Earth is larger.

Equatorial areas therefore move at a speed of around 1,600 km/h (1,000 mph) in a 24-hour period to complete a revolution. Earth rotates slowly towards to the poles, at 0.00008 km/h (0.00005 mi/h).

Low-pressure systems called cyclones draw air towards their "eye" or central region. Fluids representing high-pressure systems in the Northern Hemisphere pass low-pressure regions to the right.

Air masses are deflected when they're drawn inside cyclones from across all sides, giving the appearance that a hurricane is rotating clockwise. Trade winds refer to these air masses' recurrent circulation patterns.

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Answer:

50

Explanation:

Answer:

90 km

Explanation:

45 km per hr

2 hrs

45 x 2 = 90

90 km/2 hrs

Hope this helps!

Answer:

The father will walk 6 more meters and the son will walk 12 meters

Explanation:

Uniform Speed and Acceleration

This is a problem where two objects have different types of motion. The father walks at a constant speed and later, his son starts a constant acceleration motion in pursuit of him.

Let's start with the father, whose speed is v=1 m/s during t=6 seconds. He travels a distance:

[tex]x=vt=1*6=6\ m[/tex]

Now the son, starting from rest (vo=0) accelerates at a=2/3 m/s^2. His speed will increase and eventually, he will catch up with his father. Let's suppose it happens at a time t1.

The distance traveled by the son is given by:

[tex]\displaystyle xs=v_o.t_1+\frac{a.t_1^2}{2}[/tex]

Since vo=0:

[tex]\displaystyle xs=\frac{a.t_1^2}{2}[/tex]

The father will continue with constant speed and travels a distance of:

[tex]xf=v.t_1[/tex]

For them to catch up, the distance of the son must be 6 m more than the distance of the father, because of the leading distance he has already taken. Thus:

[tex]xs=xf+6[/tex]

Substituting the equations of each man:

[tex]\displaystyle \frac{a.t_1^2}{2}=v.t_1+6[/tex]

We know a=2/3, v=1:

[tex]\displaystyle \frac{2}{3}\cdot\frac{t_1^2}{2}=t_1+6[/tex]

Simplifying:

[tex]\displaystyle \frac{t_1^2}{3}=t_1+6[/tex]

Multiply by 3:

[tex]t_1^2=3t_1+18[/tex]

Rearranging:

[tex]t_1^2-3t_1-18=0[/tex]

Factoring:

[tex](t_1-6)(t_1+3)=0[/tex]

Solving:

[tex]t_1=6 , t_1=-3[/tex]

Since time cannot be negative, the only valid solution is

[tex]t_1=6\ s[/tex]

The distance traveled by the son in 6 seconds is:

[tex]\displaystyle xs=\frac{2/3\cdot 6^2}{2}[/tex]

[tex]xs=12\ m[/tex]

Note the father will travel

[tex]xf=1*6=6\ m[/tex]

This 6 m plus the 6 m he was ahead of the son, make them meet while walking at 6 seconds.

Answer: The father will walk 6 more meters and the son will walk 12 meters

Acceleration is the change in the velocity of the object with time. Acceleration is the same for both objects so both objects will reach the ground at the same time.

Given that both the object dropped at the same time. So the gravitational acceleration of both the objects will be the same which is nearly 10 m/s.

The force at object 1 is given below.

[tex]F_1 = m_1\times g = m_1\times a_1[/tex]

Where m1 is the mass of object 1 and a1 is the acceleration of object 1.

[tex]F _1 = 1\times 10 = 10 \;\rm N[/tex]

The acceleration of object 1 is calculated as below.

[tex]a_1 = \dfrac{F_1}{m_1}[/tex]

[tex]a_1=\dfrac{10}{1} = 10 \;\rm m/s^2[/tex]

The force at object 2 is given below.

[tex]F_2 = m_2\times g = m_2\times a_2[/tex]

Where m2 is the mass of object 2 and a2 is the acceleration of object 2.

[tex]F_2 = 2\times 10 =20 \;\rm N[/tex]

The acceleration of object 2 is calculated as below.

[tex]a_2 = \dfrac{F_2}{m_2}[/tex]

[tex]a_2=\dfrac{20}{2} = 10 \;\rm m/s^2[/tex]

Hence we can conclude that the acceleration of both the objects is the same at every point so they will reach the ground at the same time.

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Answer:

124m/s

Explanation:

v=u+at

v=119+(0.5×10)

v=119+5

v=124m/s

Answer:A

Explanation:

Absolute method

Answer:

absolute method

Explanation:

trust

Answer:

12 cm

Explanation:

From what I got with my answer (8.192 cm) I went ahead and rounded it to the closest answer which is 12 cm. Hopefully im correct but if not, I apologize in advance.

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\ [/tex]

From the question we have

[tex]volume = \frac{20.2}{19.3} \\ = 1.04663212...[/tex]

We have the final answer as

Hope this helps you

Answer:

The answer of this question is windmill

Answer: 18.9 m

Explanation:

i did the kinematic equation & found the answer.

Answer:

The answer is 4, the west.

Answer:

The west

Explanation:

hopes this helps you and your questions

Answer:

1.5 hr

16.7

Explanation:

Zero apparent weight means there's no normal force.

Sum the forces in the centripetal direction.

∑F = ma

mg = mv²/r

v = √(gr)

v = √(7.4×10⁶ m × 10 m/s²)

v = 8602 m/s

The circumference of the equator is:

C = 2πr

C = 2π (7.4×10⁶ m)

C = 4.65×10⁷ m

So the period is:

T = C / v

T = (4.65×10⁷ m) / (8602 m/s)

T = 5405 s

T = 1.5 hr

The initial speed is:

v = C / T

v = (4.65×10⁷ m) / (25 h × 3600 s/h)

v = 517 m/s

The speed increases by a factor of:

8602 m/s / 517 m/s

16.7

The new period of the planet at the given radius is 1.5 h.

The speed of the planet increased by a factor of 16.7.

The given parameters;

The speed of the planet at the given radius is calculated as follows;

[tex]mg = \frac{mv^2}{r} \\\\gr = v^2\\\\v= \sqrt{rg} \\\\v = \sqrt{7.4 \times 10^6 \times 10} \\\\v = 8602.3 \ m/s[/tex]

The new period of the planet is calculated as follows;

[tex]T = \frac{2\pi R}{v} \\\\T = \frac{2 \pi \times 7.4 \times 10^6}{8602.3} \\\\T =5,405.72 s \\\\T = \frac{5405.72}{3600} = 1.5 \ hr[/tex]

The initial speed of the planet is calculated as follows;

[tex]v_i = \frac{2\pi R}{T} \\\\v_i = \frac{2\pi \times 7.4\times 10^6}{25 \times 3600} \\\\v_i =516.68 \ m/s[/tex]

The increase in the speed of the planet is calculated as;

[tex]= \frac{v}{v_i} \\\\= \frac{8602.3}{516.68} \\\\= 16.7[/tex]

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Answer:

60 kg

Explanation:

An astronaut weighs 588 N on the earth

He also weighs 98 N on the moon

Therefore the the mass of the astronaut on the moon can be calculated as follows

= 588/98

= 6 × 10

= 60 kg

Hence the mass of the astronaut on the moon is 60 kg

The mass of the astronaut on the moon will be equal to 60 kg whereas the gravitational acceleration on the moon is 1.63 [tex]\rm m/s^2[/tex].

Given information:

An astronaut weighing 588 N on the earth notices that he weighs only 98 N on the moon.

The mass of any object in the whole universe doesn't change but the gravitational force or weight can change. This is because the gravitational acceleration can change.

The mass of the object in the earth or anywhere will be,

[tex]w=mg\\588=m\times 9.8\\m=60\rm \; kg[/tex]

So, the astronaut has 60 kg mass which is constant.

The gravitational acceleration on the moon will be,

[tex]98=60a\\a=1.63\rm\; m/s^2[/tex]

Therefore, the mass of the astronaut on the moon will be equal to 60 kg whereas the gravitational acceleration on the moon is 1.63 [tex]\rm m/s^2[/tex].

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Answer:

t=0.14s

Explanation:

Answer:

Electromagnetic waves transfer energy through vibrations of electric and in magnetic fields. For sound waves the energy is transferred through the vibration of air particles or particles of a solid. Waves also carry energy, the amount of energy they carry depends on their frequency and their amplitude. The more energy and the higher frequency amplitude, the more energy waves are ^‿^

Answer:

i think radian degree thank you

Explanation:

cuz right the degree angle i responsible more

Answer:

Its radian degree

Explanation:

Because the length of an arc of a unit circle is equal to measurement in radians of angle.

So it is the biggest unit of plane angle

Complete Question

The diagram for this question is shown on the first uploaded image

Explain why the interconnection is not valid.

i A valid interconnection would require the 3 A and 4 A sources to supply different currents in the same direction, which they do not.

ii  A valid interconnection would require the 3 A and 4 A sources to supply different currents in opposite directions, which they do not.

iii  A valid interconnection would require the 3 A and 4 A sources to supply the same current in opposite directions, which they do not.

iv A valid interconnection would require the 3 A and 4 A sources to supply the same current in the same direction, which they do not

Answer:

The correct option is  iv

Explanation:

Looking at the diagram we see that the current source are connected in series, generally the current flowing through two source that are connected in series is suppose to be the same but in this case it is not so

i.e [tex]4A  \ne 3 A[/tex] hence Kirchhoff's law is broken or not followed in this circuit which means the interconnection is not valid  

also another reason why the interconnection is not valid is because the current are flowing in the different directions  

Answer:

The diameter of a hydrogen atom based on scientific notation is 1.06 x 10^-10 m

The diameter of a hydrogen atom is 0.000000000106 m. This is number can best be expressed in scientific notation as 1.06 x 10⁻¹⁰ m. Hence, option (C) is correct.

Scientific notation is a means to express values that are either too big or too little to be conveniently stated in decimal form (typically would result in a long string of digits). It is also known as standard form in the UK and scientific form, standard index form, and standard form.

Scientists, mathematicians, and engineers frequently utilize this base ten notation because it can make some mathematical operations simpler. It is typically referred to as "SCI" display mode on scientific calculators.

As there has 9 zeros after the decimal, this number can best be expressed in scientific notation as 1.06 x 10⁻¹⁰ m.

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Answer:

F = 3600 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of force must be equal to the product of mass by acceleration.

ΣF = m*a

where:

F = force [N]

m = mass = 2000 [kg]

a = acceleration = 1.8 [m/s^2]

Now replacing:

F = 2000*1.8

F = 3600 [N]

Answer:

Yes. Yes, you can.

Explanation:

Combinations of increased pressure and decreased temperature force gases into containers that we use every day. You might have compressed air in a spray bottle or feel the carbon dioxide rush out of a can of soda. Those are both examples of gas forced into a smaller space at a greater pressure.

Hope this helps :)