Among 320 randomly selected airline travelers, the mean number of hours spent travelling per year is 24 hours and the standard deviation is 2. 9. What is the margin of error, assuming a 90% confidence level? Round your answer to the nearest tenth.

Answers

Answer 1

The margin of error of the random selection is 0.29

The given parameters are:

[tex]n = 320[/tex] --- the sample size

[tex]\sigma = 2.9[/tex] --- the standard deviation

[tex]\bar x = 24[/tex] --- the mean

[tex]\alpha = 90\%[/tex] --- the confidence level.

The margin of error (E) is calculated as follows:

[tex]E = z \times \sqrt{\frac{\sigma^2}{n}}[/tex]

So, we have:

[tex]E = z \times \sqrt{\frac{3.2^2}{320}}[/tex]

[tex]E = z \times \sqrt{\frac{10.24}{320}}[/tex]

The z-value for 90% confidence level is 1.645.

Substitute 1.645 for z

[tex]E = 1.645 \times \sqrt{\frac{10.24}{320}}[/tex]

[tex]E = 1.645 \times \sqrt{0.032}[/tex]

Take square roots

[tex]E = 1.645 \times 0.1789[/tex]

Multiply

[tex]E = 0.2943[/tex]

Approximate

[tex]E = 0.29[/tex]

Hence, the margin of error is 0.29

Read more about margin of error at:

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Proof:-

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Answer:

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Write and solve a system of THREE inequalities that models the situation below.
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Answer:

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Given:

3x - 2

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Please show your work...No spam.. Thank you.​

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Answer:

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: If 10 less than 5 times a number is two more than 3 times the number, then the number is ​

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Answer:

x = 1

Step-by-step explanation:

If 10 less than 5 times a number is two more than 3 times the number, then the number is ​

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---------------

check

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d

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they intersect but aren't perpendicular.

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