Question:
All of the following are advantages of using a pressure transducer rather than a vacuum gauge EXCEPT:
A. greater accuracy.
B. easier identification of the cylinder.
C. measuring higher pressures.
D. ability to see the levels graphically
Answer:
The correct answer is D) ability to see the levels graphically
Explanation:
The above question derives from the Rudiments of Automotive Technology.
The function of the pressure transducer is to enable the diagnostic who is testing the engine vacuum to detect the cylinder with a faulty vacuum.
The pressure transducer does allow its user to see the vacuum graphically NOT the levels.
Cheers.
What information should a professional Engineer keep private
Answer:
Work to develop software and related documents that respect the privacy of those who will be affected by that software.
Explanation:
In the Software Engineering Code of Ethics and Professional Practice, under Principle, which is section three (3) of the document, it is stated in clause 12 on what information should a professional Engineer keep private.
In it, it is stated that professionals engineers should keep private information relating to "Work to develop software and related documents that respect the privacy of those who will be affected by that software."
The pressure at a point in a pipeline is 80 kPa. Assuming standard atmospheric pressure, the absolute pressure in the pipeline is most nearly:
Answer:
[tex]P_{a}=181.324 kPa[/tex]
Explanation:
The pressure you measure on a pipeline is generally a gauge pressure, this is the difference between the pressure inside the pipe and the atmospheric pressure.
In order to find the absolute pressure, we need to add the pressure in the atmosphere to the measured pressure, so we get:
[tex]P_{a}=80kPa+101.325kPa[/tex]
the 101.325kPa is the equivalent to 1atm, so we get:
[tex]P_{a}=181.325kPa[/tex]
Technician A says to make sure all vehicle protection is removed prior to releasing the vehicle to the customer. Technician B says that prior to customer pick up of the repaired vehicle you should ensure that no damage to the vehicle has been sustained during repair. Who is correct?
Answer:
Technician B says that prior to customer pick up of the repaired vehicle you should ensure that no damage to the vehicle has been sustained during repair
Explanation:
After a vehicle has been repaired, the technician should check that no damage was placed on the vehicle during repair. For the customer it is important to check;
Repaired area appearance near and from a farThe paint {color, texture and spray}Test the car if it was a mechanical repairNeatness of the car after repairReport to technicians if you notice any problem.
Which of the following describes one of an employee's responsibilities under OSHA's rules?
Answer:
First off, employees must follow all OSHA safety and health standards AND all rules issued by their employers that are intended to comply with OSHA's health and safety standards and the OSH Act. Report all occupational injuries and illnesses. Report hazardous conditions. Cooperate during an OSHA inspection.
The statement that describes one of an employee's responsibilities under OSHA's rules is to report unsafe and unhealthful working conditions to appropriate officials. Thus, the correct option for this question is D.
What are the responsibilities of employees under OSHA?Congress created OSHA to assure safe and healthful conditions for working men and women by setting and enforcing standards and providing training, outreach, education, and compliance assistance. Under OSHA law, employers are responsible for providing a safe and healthful workplace for their workers.
Employees shall use safety equipment, personal protective equipment, and other devices and procedures provided or directed by the agency and necessary for their protection. Employees shall have the right to report unsafe and unhealthful working conditions to appropriate officials.
At first, employees must have to follow all sorts of OSHA safety and health standards. All rules and regulations are issued by their employers that are intended to comply with OSHA's health and safety standards and the OSH Act.
Therefore, the correct option for this question is D.
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List 3 specific things you can do with a drill press (not just cut holes in wood)
Answer:
tapping, horizontal dusting, slash drilling
Explanation:
The pacific ocean surrounded by extremely high earthquake and volcanic activity the Atlantic ocean by contrast has little activity of this nature based on the Maps what attributes of the Atlantic ocean make it likely for earthquakes to occur or volcanoes to form
Answer: There are no major convergent boundaries in the Atlantic, which is where these events are more likely to occur
Explanation:
Determining criteria and constraints is part of which steps in the engineering design phase? doing an analysis researching the problem brainstorming solutions defining the need
Answer:
defining the need
Explanation:
Of course, since the first stage of the engineering design phase involves defining the need of the design, it is at this stage that the researcher/engineer should determine the criteria and constraints.
This stage involves asking such questions as:
What restrictions or limitations exist that should be considered in the design?What design requirements do I need so the product can achieve the objective?The production of carbon dioxide makes it unwise and unsafe to operate a tractor or any motor vehicle inside enclosed spaces such as a barn.
True
False
Design a VHDL module
Inputs: din, clock, reset
Output dout
The first D-Flip-Flop (DFF) should have its D input connected to a module input and the last DFF should have its Q output connected to the module output. Include a clock and a reset to the module. The reset should asynchronously reset all four DFFs. Use a separate process for each DFF
Answer:
how we gonna do dat
Explanation:
Answer:https://www.chegg.com › questions-and-answers › four...
Question: Four Bit Shift Register Design a VHDL module Inputs: din, clock, reset Output dout The first D-Flip-Flop (DFF) should have its D input connected ...
1 answer
·
Top answer:
library IEEE; use IEEE.STD_LOGIC_1164.all; entity siso is port( din : in STD_LOGIC; clk : in STD_LOGIC; reset : in STD_LOGIC; dout : out STD_LOGIC ...
Explanation:
what do you need to craft netherite ingots come on man you should know this
4 netherite scrap and 4 gold
in a crafting table
CAN I GET ANSWERS PLEASE, I TRY THE FORMULA AND MY TEACHER HAS A FAMILY EMERGENCY SO HE CANT RESPOND BACK SO PLEASE HELP ME
Explanation:
I won't answer each of these, but will give you an explaination of how to solve for each.
You'll need to use Ohm's Law and Kirchhoff's Voltage Law.
Remember Ohm's Law as [tex]V = IR[/tex].
Kirchoff's Voltage Law says that the sum of voltages for a given circuit "loop" must equal zero. In the circuit shown, this means that the voltage provided by the battery (E_T) equals the voltage drop across each of the three resisters in the loop.
[tex]E_T = E_1 + E_2 + E_3[/tex]
A couple of other helpful notes:
These three resistors are in series which means that the current flowing through them is equal.
So it is easy to see that... [tex]V = IR \rightarrow E_1 = 4*2 = 8 V[/tex]
Solve for the voltage across E_2 and E_3. The sum of the three voltages equals the voltage of the battery (E_T).
In a certain chemical plant, a closed tank contains ethyl alcohol to a depth of 71 ft. Air at a pressure of 17 psi fills the gap at the top of the tank. Determine the pressure at a closed valve attached to the tank 10 ft above its bottom.
Answer:
the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi
Explanation:
Given that;
depth 1 = 71 ft
depth 2 = 10 ft
pressure p = 17 psi = 2448 lb/ft²
depth h = 71 ft - 10 ft = 61 ft
we know that;
p = P_air + yh
where y is the specific weight of ethyl alcohol ( 49.3 lb/ft³ )
so we substitute;
p = 2448 + ( 49.3 × 61 )
= 2448 + 3007.3
= 5455.3 lb/ft³
= 37.88 psi
Therefore, the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi
The characteristics of water flow over a dam spillway are to be measured in a geometrically similar small-scale laboratory model. The width of the prototype is 30 m and the width of the model is 2 m. If the flow in the prototype is 100 m3/s, the flow rate in the model for similitude is:
Answer:
[tex]Q_m \simeq 0.11 \ m^3/sec[/tex]
Explanation:
From the given information:
The width of the prototype [tex]L_p[/tex] = 30 m
The flow of the prototype [tex]Q_p[/tex] = 100 m/s
width of the model [tex]L_m[/tex] = 2 m
The flow rate of the model can be calculated by using the geometrical similarities of Froude's Number Fr
[tex](Fr)_m = (Fr)_p[/tex]
[tex]\implies ( \dfrac{v}{\sqrt{ gy} }) _m = ( \dfrac{v}{\sqrt{gy}}) _p[/tex]
[tex]V_r = \sqrt{L_r}--- (1)[/tex]
[tex]Q_r = V_r *A_r[/tex]
[tex]Q_r = \sqrt { L_r} *L_r^2[/tex]
[tex]Q_r = L_r^{2.5}[/tex]
∴
[tex](\dfrac{Q_m}{Q_p}) = (\dfrac{L_m}{L_p})^{2.5}[/tex]
[tex](\dfrac{Q_m}{100}) = (\dfrac{2}{30})^{2.5}[/tex]
[tex](\dfrac{Q_m}{100}) =0.001147550621[/tex]
[tex]Q_m \simeq 0.11 \ m^3/sec[/tex]
A force of 12 N is applied to a block moving west. Another force of 26 N is being applied in the opposite direction. The block weighs 7kg. What is the net force and the acceleration?
Answer:
[tex]F_{Net} = 14N[/tex]
[tex]a = 2m/s^2[/tex]
Explanation:
Given
[tex]Mass = 7kg[/tex]
[tex]F_{west} = 12N[/tex]
[tex]F_{opposite} = 26N[/tex]
Solving (a): The net force:
The force towards the west direction, will be regarded as negative while the opposite force will be regarded as positive.
So, the net force is:
[tex]F_{Net} = -F_{west} + F_{opposite}[/tex]
Substitute values for the given forces
[tex]F_{Net} = -12N + 26N[/tex]
[tex]F_{Net} = 14N[/tex]
The net force is 14 N
Solving (b): Acceleration
Net force is calculated as:
[tex]F_{Net} = Mass * Acceleration[/tex]
Substitute 7 kg for Mass and 14 N for Net force:
[tex]14N = 7kg* a[/tex]
Make a the subject:
[tex]a = \frac{14N}{7kg}[/tex]
[tex]a = 2N/kg[/tex]
[tex]a = 2m/s^2[/tex]
Hence, the acceleration is [tex]2m/s^2[/tex]
In some companies, workers who increase the quantity or quality of their work receive a. benefits. c. performance bonuses. b. pension plans. d. orientation. Please select the best answer from the choices provided A B C D
Answer:
performance bonuses
Explanation:
When a pungent odor is detected during a sealed system recovery and/or repair which of the following is most likely
Answer: A leak in the system
Explanation:
Which option identifies the tool best to use in the following scenario?
Theresa has just purchased a crib and needs to assemble it quickly. The crib came with instructions, but no tools, and she does not know what she needs. On all of the screws in her kit, there is a six-sided hole in the head.
an Allen wrench
a Phillips screwdriver
a flathead screwdriver
an adjustable crescent wrench
NEXT QUESTION
Answer:
an Allen wrench
Explanation:
it is hexagonal
how does a motion sensor work?
Answer:
A motion sensor uses one or multiple technologies to detect movement in an area. When a sensor detects motion, it sends a signal to your security systems control panel, which connects to your monitoring panel system. This alerts you and the monitoring center to a potential threat in your home.
Hope It Helps You................
g Asbestos is a fibrous silicate mineral with remarkably high tensile strength. But is no longer used because airborne asbestos particles can cause lung cancer. Grunerite, a type of asbestos, has a tensile strength of 3.5 × 10ଶ kg mmଶ ⁄ (meaning a strand of grunerite with a 1-mmଶ cross-sectional area can hold up to 3.5 × 10ଶ kg). The tensile strength of aluminum and Steel No. 5137 are 2.4 × 10ସ lb inଶ ⁄ and 5.0 × 10ସ lb inଶ ⁄ respectively. Calculate the cross section areas in mmଶ of wires of aluminum and of Steel No. 5137 that have the same tensile strength as a fiber of grunerite with a cross-sectional area of 1.0 μmଶ
Answer:
Aluminum cross sectional area = 1.99 * 10^-5 mm^2
Steel cross sectional area = 9.95* 10^-6 mm^2
Explanation:
Given data:
Tensile strength of Grunerite = 3.5 * 10^2 kg/mm^2 = 3.5 * 10^-4 kg/um^2
Tensile strength of Aluminum = 2.5 × 10^4 lb/in2 = 2.5 × 10^4 * 703.07 kg/m^2
Tensile strength of Steel number 5137 = 5.0 × 10^4 lb/in2 = 5.0 × 10^4*703.07 kg/m^2
Calculating the cross sectional area of the wires of aluminum and steel No5137
first we will determine the cross sectional area of the aluminum wire ( A ) by equating tensile strength of aluminum with the tensile strength
of Grunerite
(2.5 × 10^4 * 703.07) * A = 3.5 * 10^-4 kg
Hence ; A = 1.99 * 10^-5 mm^2
Next we calculate the cross sectional area of steel
5.0 × 10^4*703.07 kg/m^2 * A" = 3.5 * 10^-4 kg
Hence ; A" = 9.95* 10^-6 mm^2
Which option identifies the tool best to use in the following scenario?
Theresa has just purchased a crib and needs to assemble it quickly. The crib came with instructions, but no tools, and she does not know what she needs. On all of the screws in her kit, there is a six-sided hole in the head.
an Allen wrench
a Phillips screwdriver
a flathead screwdriver
an adjustable crescent wrench
Answer: an Allen wrench
Explanation:
Based on the information given in the question, the option that identifies the tool that will be the best to use in the following scenario is the Allen key.
The Allen key also refered to as the hex key is a simple tool that is used in driving both screws, bolts and also used in driving the screws that have hexagonal sockets that is, six sided hole in their heads.
University administrators have developed a Markov model to simulate graduation rates at their school. Students might drop out, repeat a year, or move on to the next year. Students have a 3% chance of repeating the year. First-years and sophomores have a 6% chance of dropping out. For juniors and seniors, the drop-out rate is 4%. Compute the probability that a student who starts as a 1st-year eventually graduates the university.
Solution :
The percentage of the students who have a chance of repeating their current year = 3%
The drop out students for the first year and the sophomores = 6%
Drop out rate of first year and the seniors = 4%
Now for the state space :
S = { first year(1), sophomores(2), juniors(3), seniors(4), graduates(G), Dropouts(D) }
Therefore
the first year students are indicated as '1'
Sophomores are indicated as '2'
Juniors are indicated as '3'
Seniors are indicated as '4
Graduates are indicated as 'G'
Dropouts are indicated as 'D'
The transition diagram is attached below.
The probability of the students who have the chance of repeating their current year = 3/100 = 0.03
Probability of first year dropouts and sophomores = 6/100 = 0.06
Probability of dropout rate of juniors and seniors = 4/100 = 0.04
Therefore, the probability matrix can be made as :
1 2 3 4 G D
[tex]\begin{matrix}1\\ 2\\ 3\\ 4\\ G\\ D\end{matrix}[/tex] [tex]\begin{bmatrix}0.03 & 0.91 & 0 & 0 & 0 & 0.06\\ 0& 0.03 & 0.91 & 0 & 0 & 0.06\\ 0& 0 & 0.03 & 0.93 & 0 & 0.04\\ 0& 0 & 0 & 0.03 & 0.93 & 0.04\\ 0& 0 & 0 & 0 & 1 & 0\\ 0& 0 & 0 & 0 & 0 & 1\end{bmatrix}[/tex]
Here, G represents 'graduates' and D represents 'Dropouts.'
What is a height gage?
What is true about gaging?
How often do frequently used instruments need calibration?
What is a machinist rule?
Acertain foundation will experience a bearing capacity failure when it is subjected to a downward load of 2200 kN. Using ASD with a factor of safety of 3, determine the maximum allowable loadthat will satisfy geotechnical ULS requirements.
Answer:
550kN
Explanation:
We are required to find the maximum allowable load that will satisfy geotechnical ULS requirements
P' = pu/FOS ---1
Pu = design load
FOS = factor of safety
We get the design of safety
Pu = 0.75p
= 0.75 x 2200
= 1650kN
Factor of safety = 3
Design load = 1650
P' = 1650/3
= 550kN
So we have the maximum allowable load to be 550kN
What is the normal balance side of an asset?
A compressor receives air at 290 K, 95 kPa and shaft work of 5.5 kW from a gasoline engine. It should deliver a mass flow rate of 0.01 kg/s air to a pipeline. Find the maximum possible exit pressure of the compressor.
Answer:
P2 = 3.9 MPa
Explanation:
Given that
T₁ = 290 K
P₁ = 95 KPa
Power P = 5.5 KW
mass flow rate = 0.01 kg/s
solution
with the help of table A5
here air specific heat and adiabatic exponent is
Cp = 1.004 kJ/kg K
and k = 1.4
so
work rate will be
W = m × Cp × (T2 - T1) ..........................1
here T2 = W ÷ ( m × Cp) + T1
so T2 = 5.5 ÷ ( 0.001 × 1.004 ) + 290
T2 = 838 k
so final pressure will be here
P2 = P1 × [tex](\frac{T2}{T1})^\frac{k}{k-1}[/tex] ..............2
P2 = 95 × [tex](\frac{838}{290})^\frac{1.4}{1.4-1}[/tex]
P2 = 3.9 MPa
Briefly describe the two types of visual acuity.
a. What color combinations are used for regulatory signs (e.g., speed limit signs) and general warning signs (e.g., advance railroad crossing signs)?
b. Why are these combinations used?
Answer:
8765432
Explanation:
8765433
There are the white inheritance regulatory signs are the color combinations of the regulatory signs indicate right- of-way. The general warning signs railroad crossing signs yellow. There was the used the color are the communication purposes.
What is railroad?
The term “railroad” refers to a defunct rail track. The railroad's track does not change and is permanent. In the seventeenth century, the railroad brought England into the world. Two parallel lines are permanently installed on the railroad track.
Regulatory signs are used to command speeds, such as maximum and minimum speed boundaries. The color was the used in the white background. The general warning signs in the railroads are the used in the sign's yellow color. There was the used this color are the communicated to the people.
As a result, the different color used of the communication purposes.
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Water flows through this orifice meter by gravity. The orifice diameter is 50 cm and water height difference is 10 m. If the contraction coefficient is 0.62 and velocity coefficient is 0.90, the flow rate through the orifice is most nearly:
Answer:
Q ≅ 1.53 m³/s
Explanation:
From the given information:
The flow rate of the orifice is:
[tex]v = c_v \sqrt{2gh}[/tex]
[tex]v = 0.90 \times \sqrt{2*9.81 * 10}[/tex]
where;
[tex]Q = c_d \times \sqrt{2gh} \times A[/tex]; &
[tex]c_d = c_c \times c_v[/tex]
∴
[tex]Q = c_c \times c_v \sqrt{2gh} \times \dfrac{\pi}{4}\times d^2[/tex]
[tex]Q = 0.90 \times 0.62 \sqrt{2*9.81*10} \times \dfrac{\pi}{4}\times 0.5^2[/tex]
[tex]Q = 0.558 \times 14.00714104 \times 0.1963495408[/tex]
Q ≅ 1.53 m³/s
Problem 3. The uniform beam is supported by two rods AB and CD that have cross-sectional areas of 10 mm2 and 15mm2, respectively. Determine the intensity w of the distributed load so that the average normal stress in each rod does not exceed 300 kPa.
Answer:
hello the diagram related to your question is missing attached below is the required diagram.
The value of AC = 6m
answer 2.25 N
Explanation:
From the diagram attached below
average intensity of loading = w/2
Total load due to linearly varying load = [tex]\frac{wL}{2}[/tex]
w = maximum intensity of load , L = span of varying load
since AC = 6m( L ) then
Total load due to linearly varying load = 3w ------ ( 1 )
attached below is the detailed solution of the given problem
Maych the unit of measurement to the vocabulary term
Explanation:
current- amperes
resistance- ohms
voltage- volts
electrical energy- kilowatt hours
electrical power- watts
hope it helps!
A sample of blue gray soilwas obtained from Paine Field in Everett, WA to determine its Atterberg Limits and classify itssoil type according to the Unified Soil Classification system.84% of the sample passed through the #200 sieve with 16% retained on the #4 sieve. For one of the PL determinations, the wet weight + dish = 11.53 grams and the dry weight + dish = 10.49 grams. The dish only weighed 4.15 grams. Compute the plastic limit. Three determinations of the liquid limit were made. For 17 blows, the water content was 49.8%; for 26 blows, the water content was 47.5%; and for 36 blows, the water content was 46.3%.
Required:
Evaluate the soil type, indicate the information on a plasticity chart,and give the Unified Soil Classification System (USCS) symboland the proper narrative description.
Solution :
1. PL [tex]$= \frac{11.53 - 10.49}{10.49 - 4.5} \times 100$[/tex]
= 17.36 %
2. Liquid limit at 25 number of blows,
[tex]$LL = \frac{(26-25)\times 49.8 + (25 - 2.17) \times 47.5}{26-17}$[/tex]
[tex]$= 47.75 $[/tex] %
Since 84 % of the passes the number 200 sieve the soil is immediately fine grained and MI, OI or CI because LL = 47.75 % > 35%
Therefore, the Plasticity index, PI [tex]$=47.75 - 17.36 = 30.39$[/tex] %
Equation of A-line [tex]$= 0.73 \times [47.75 - 20]$[/tex]
[tex]$=20.25 $[/tex] %
Thus the soil lies above the A-line, that is soil is medium compressible clay ---- CI
