A tow truck applies a force of 2600 N on a 2100 Kg car for a period of 9 seconds. What is the magnitude of the change in the car’s momentum?
Answer:
P = 23400 [kg*m/s]
Explanation:
Momentum is defined as the product of force by the time of force duration. It can be determined by means of the following equation.
[tex]P=F*t[/tex]
where:
P = momentum [kg*m/s]
F = force = 2600 [N]
t = time = 9 [s]
Now replacing:
[tex]P=2600*9\\P=23400 [kg*m/s][/tex]
What is the pharmacy technician’s role in medication therapy management?
Two forces whose resultant is 100newton are perpendicular to each other. If one of them makes an angle of 60newton with the resultant. Calculate it magnitude
Answer:
100 N
Explanation:
Given that,
Two forces whose resultant is 100newton are perpendicular to each other.
If one of them makes an angle of 60newton with the resultant.
[tex]F_1=100\times \sin60=86.60\ N[/tex]
and
[tex]F_2=100\times \cos60=50\ N[/tex]
The magnitude of force,
[tex]F=\sqrt{F_1^2+F_2^2} \\\\F=\sqrt{86.6^2+50^2} \\\\F=99.99\ N[/tex]
or
F = 100 N
So, the magnitude of force is 100 N.
Calculate the momentum of a 1,500 kg car traveling at 6 m/s.
A military airplane sometimes needs to refuel in mid-air, and another plane flies above it to add the fuel. If a plane with a mass of 7,800 kg is traveling with a velocity of 30 m/s and refuels by adding an additional 800 kg of jet fuel, what will its new velocity be? (Hint: This is a multi-step problem).
Answer:
See the answers below.
Explanation:
Momentum is defined as the product of mass by velocity, in this way we have the following equation.
[tex]P=m*v[/tex]
where:
P = momemtum [kg*m/s]
m = mass = 1500 [kg]
v = velocity = 6 [m/s]
[tex]P = 1500*6\\P=9000 [kg*m/s][/tex]
Now we have to calculate the momentum of the plane when it travels at 30 [m/s].
[tex]P_{airplane}=m_{plane}*v_{plane}\\P_{airplane}=7800*30\\P_{airplane}=234000[kg*m/s][/tex]
Now this same momentum must be conserved, in such a way that the mass is increased but the velocity must decrease for the momentum to be conserved.
[tex]P=m_{new}*v_{new}\\234000=(7800+800)*v_{new}\\234000=8600*v_{new}\\v_{new}=27.2[m/s][/tex]
Answer:
1. 9000 kg-m/s
2. 27.2 m/s
In downtown Chicago, the east-west blocks are 400 ft long while the north-south blocks are 280 ft long. Because of the many one-way streets, it can be challenging to get around. Veronica starts at the corner of Dearborn and Ohio Streets. She drives four blocks north to Superior, two blocks east to Wabash, then a block south to get to her destination at Wabash and Huron.
Required:
What is the straight-line distance from her starting point?
Answer:
The answer is "1160 ft".
Explanation:
Using the Pythagoras theorem:
[tex]\to a= 280 \times 3= 840\\\\\to b= 400 \times 2= 800\\\\[/tex]
[tex]\bold{\to y^2= a^2+b^2}\\\\[/tex]
[tex]=840^2 +800^2\\\\= 705600+640000\\\\=1345600\\\\=1160 \ ft\\[/tex]
[tex]\to y=1160 \ ft[/tex]
Which is an example of current electricity?
A sample of 0.500 kg of ice is held at a temperature of 0°C. How much energy
must be added to completely turn the ice into liquid water? (The latent heat of
vaporization for water is 2260 kJ/kg; the latent heat of fusion for water is 333
kJ/kg.)
A. 1130 kJ
B. 666 kJ
C. 167 kJ
D. 4520 kJ
Answer:
C. 167 kJ
Explanation:
The minimum amount of heat require to complete turn the ice into liquid water is equal to the latent heat of the ice, that is, the amount of heat needed by the ice to turn into water. This amount is calculated by:
[tex]Q = m\cdot h_{f}[/tex] (1)
Where:
[tex]m[/tex] - Mass of ice, measured in kilograms.
[tex]h_{f}[/tex] - Latent heat of fusion, measured in kilojoules per kilogram.
[tex]Q[/tex] - Latent heat, measured in kilojoules.
If we know that [tex]m = 0.500\,kg[/tex] and [tex]h_{f} = 333\,\frac{kJ}{kg}[/tex], the latent heat of ice is:
[tex]Q = (0.500\,kg)\cdot \left(333\,\frac{kJ}{kg} \right)[/tex]
[tex]Q = 166.5\,kJ[/tex]
Therefore, the correct answer is C.
What's the effect of mass and speed on kinetic energy
Answer:
The relationship between Kinetic energy, mass and speed indicates that kinetic energy and mass are proportional. This proportionality implies that if the mass is doubled, its kinetic energy is doubled too. More generally, if two objects move with the same speed the most massive one has the higher kinetic energy
Explanation:
A spring with a rest length of 0.7 m has a spring constant of 70 N/m. It is stretched and now has a length of 2.5 m. What is the potential energy stored in the spring?
____ J
Answer:
113.4 J
Explanation:
Elastic Potential Energy
Is the energy stored in an elastic material like a spring of constant k, in which case the energy is proportional to the square of the change of length Δx and the constant k.
[tex]\displaystyle PE = \frac{1}{2}k(\Delta x)^2[/tex]
The spring has a natural length of 0.7 m and a spring constant of k=70 N/m. When the spring is stretched to a length of 2.5 m, the change of length is
Δx = 2.5 m - 0.7 m = 1.8 m
The energy stored in the spring is:
[tex]\displaystyle PE = \frac{1}{2}70(1.8)^2[/tex]
PE = 113.4 J
An endangered species is a species that has died out and no individuals are left. True or false
Answer:
the answer is false... ....
Answer:
False
Explanation:
A species that has died our ans has no individual's left would be considered extict.
what is mechanics physics
A 0.5 kg apple falls from a tree. When the apple is 1.5 meters above the ground it has a velocity of 2.4 m/s. What is the apple's total mechanical energy
Answer:
8.7975 Joules
Explanation:
Step one:
Given data
mass m= 0.5kg
height h= 1.5m
velocity v= 2.4m/s
The potential energy PE= mgh
The kinetic energy KE= 1/2mv^2
Step two
PE=0.5*9.81*1.5
PE=7.3575 Joules
KE= 1/2*0.5*2.4^2
KE=0.5*0.5*5.76
KE=1.44 Joules
The total mechanical energy is
PE+KE
=7.3575+1.44
=8.7975 Joules
A 2 kg toy car moves at a speed of 5 m/s.? If a child applies a 3 N force for 2 m in the same direction the car is already moving, how much work isdone on the car?
Answer:
its A
Explanation:
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Calculate the magnitude of the linear momentum for the following cases. (a) a proton with mass 1.67 10-27 kg, moving with a speed of 4.85 106 m/s
Answer:
8.0995×10^-21 kgms^-1Explanation:
Mass of proton :
[tex]m_P=1.67\times 10^-^2^7\:kg\\[/tex]
Speed of Proton:
[tex]v_P=4.85\times 10^6[/tex]
Linear Momentum of a particle having mass (m) and velocity (v) :
[tex]-> p =m->v\:\:\: (1)[/tex]
Magnitude of momentum :
[tex]p=mv\:\:\: (2)[/tex]
Frome equation (2), magnitude of linear momentum of the proton :
[tex]p_P=m_P\:v_P\\\\p_P=1.67\times 10^-^2^7 \:kg\times4.85\times 10^6\:ms^-^1\\\\p_P= 8.0995\times 10^-^2^1\:kgms^-^1[/tex]
The range is the horizontal distance from the cannon when the pumpkin hits the ground. This distance is given by the product of the horizontal velocity (which is constant) and the amount of time the pumpkin is in the air (which is determined by the vertical component of the initial velocity, as you just discovered). Set the initial speed to 14 m/s, and fire the pumpkin several times while varying the angle between the cannon and the horizontal. For which angle is the range a maximum (with the initial speed held constant)
Answer:
x(max) = 20 m
Explanation:
In projectile shoot e have:
V₀y = V₀*sin θ
V₀ₓ = V₀*cos θ
V₀ initial speed
θ shotting angle
Vₓ = V₀ₓ = V₀*cos θ during the trajectory
Vy = V₀y - g*t
And when Vy = 0 h is maximun and the time to reach y maximum is half of the overall time.
According to that
Vy = 0 V₀y = g*t t = V₀y/g
t = 14* sinθ / 9,8
t = 1,43 *sinθ s
And overall time is T = 2* 1,43*sinθ
t = 2,86*sinθ
x = V₀ₓ * t s
x = 14*cosθ * 2,86* sinθ
x = 40 * cosθ * sinθ
Lets take two very well know sin cos pairs
for ∡ 30 ∡ 45 ∡60
and 30 and 60 are complementary angles for boths
cosθ * sinθ is the same ( 1/2)*(√3/2)
cosθ * sinθ = 0,433 and
x = 40* 0,433
x = 17,32 m
For ∡ 45 boths sin45 and cos45 are equal √2/2
In this case
x = 40*(√2/2)*(√2/2)
x = 40* 2/4
x = 20 m
And that is the maximum range
x(max) = 20 m
If the evaporator outlet temperature on an r410A system is 50f and the evaporator superheat is 10f, what is the evaporating pressure of the refrigerant in the system
Answer:
So, the evaporating pressure of the R410A = 118 psig
Explanation:
Solution:
For R410A system:
Data Given:
Evaporator Outlet Temperature = 50°F
Evaporator Superheat = 10°F
Required:
Evaporating Pressure in the system = ?
For this, first of all, we need to calculate inlet temperature on R410A system from the given value of outlet temperature.
Evaporator inlet temperature is the difference of outlet temperature and evaporator superheat.
Evaporator inlet temperature = Outlet Temperature - Evaporator Superheat
Evaporator inlet Temperature = 50°F - 10°F
Evaporator inlet Temperature = 40°F
Now, as we have the inlet temperature and the R410A system. We can consult the pressure temperature chart or PT chart, which I have attached and highlighted the value of evaporating pressure for 40°F inlet temperature.
So, the evaporating pressure of the R410A = 118 psig
PLEASE HELP THIS IS TIMED!
a constant force is causing a sled to accelerate at 4 m/s^2. If the mass is suddenly cut in half what will the new acceleration be
Answer quick please thank
The energy lost during transformation is always in the form of:
chemical
heat
sunlight
mechanical
Answer:
heat
answer already there but yea just for da points
You are assigned the design of a cylindrical, pressurized water tank for a future colony on Mars, where the acceleration due to gravity is 3.71 meters per second per second. The pressure at the surface of the water will be 150 KPa , and the depth of the water will be 14.4 m . The pressure of the air in the building outside the tank will be 88.0 KPa .
Find the net downward force on the tank's flat bottom, of area 2.15 m2 , exerted by the water and air inside the tank and the air outside the tank.
Answer: F = 6262.2 kN
Explanation: Pressure is defined as force per area. But pressure varies according to the depth of a fluid: in air, it decreases the higher the altitude, while in water, it increases the deeper you go.
So, at the bottom of the tank, besides the pressure of air inside the tank and air outside the tank, there is pressure of water due to its depth.
Pressure due to the depth is calculated as
[tex]P=h.\rho.g[/tex]
h is the depth in m
ρ is density of the fluid, in this case is water, so ρ = 997 kg/m³
g is acceleration due to gravity, which, in this case, is 3.71 m/s²
Then, pressure at the bottom of the tank due to variation in depth is
[tex]P=14.4(997)(3.71)[/tex]
P = 53263.73 Pa or 53.26 kPa
Assuming positive referential is downward, all pressures at the bottom point down, so total or resultant pressure is:
[tex]P_{r}=P_{1}+P_{2}+P_{3}[/tex]
[tex]P_{r}=150+88+53.26[/tex]
[tex]P_{r}=[/tex] 291.26 kPa
At last, pressure is force per area:
[tex]P=\frac{F}{A}[/tex]
[tex]F=P.A[/tex]
[tex]F_{r}=P_{r}.A[/tex]
[tex]F_{r}=291.26.10^{3}(2.15)[/tex]
[tex]F_{r}=[/tex] 626209 N or 626.2 kN
At the cylindrical tank's flat bottom, net force has magnitude 626.2 kN.
Which ray diagram demonstrates the phenomenon of absorption?
tum
Answer:
hjbyvtf ghbj
Explanation:
uhgbnm,likjh
You move a 25 N object 5 meters. If it takes 8 s how much power did you do?
Answer:
15.625 watts
Explanation:
Recall that power is defined as the worked performed per unit of time:
Power = Work / time
The work done is Force * distance, so in our case the work is:
Work = 25 M * 5 m = 125 J
Then the power will be:
Power = 125 J / 8 sec = 15.625 watts
The classic Millikan oil drop experiment was the first to obtain an accurate measurement of the charge on an electron. In it, oil drops were suspended against the gravitational force by a vertical electric field. Given the oil drop to be 1.00 um in radius and have a density of 920 kg/m^3.
a. Find the weight of the drop.
b. If the drop has a single excess electron, find the electric field strength needed to balance its weight.
Answer:
a) [tex]W=3.78\cdot 10^{-14}\: N[/tex]
b) [tex]E=2.36\cdot 10^{5} N/C[/tex]
Explanation:
a) The weight is just the mass of the drop times the acceleration of gravity.
[tex]W=mg[/tex]
Or in terms of density.
[tex]W=\rho Vg[/tex] (1)
If we consider the volume of a drop as spherical, we can find the volume (R=1 μm = 0.000001 m).
[tex]V=\frac{4}{3}\pi R^{3}[/tex]
[tex]V=\frac{4}{3}\pi (10^{-6})^{3}[/tex]
[tex]V=\frac{4}{3}\pi 10^{-18}[/tex]
[tex]V=4.19\cdot 10^{-18}\: m^{3}[/tex]
Then, using equation (1), the weight will be:
[tex]W=920\cdot 4.19\cdot 10^{-18}\cdot 9.81[/tex]
[tex]W=3.78\cdot 10^{-14}\: N[/tex]
b) To balance the weight, the electric field times the charge must be the same value in the opposite direction, which means:
[tex]W-qE=0[/tex]
[tex]E=\frac{W}{q_{electron}}[/tex]
[tex]E=\frac{3.78\cdot 10^{-14}}{1.60\cdot 10^{-19}}[/tex]
[tex]E=2.36\cdot 10^{5} N/C[/tex]
I hope it helps you!
6. Balsa wood with an average density of 130 kg/m3 is floating in pure water. What percentage of the wood is submerged
Answer:
The percentage of the submerged wood is 13%.
Explanation:
Given;
density of the Balsa wood, [tex]\rho _{wood}[/tex] = 130 kg/m³
density of pure water, [tex]\rho_{water}[/tex] = 1000 kg/m³
The percentage of the submerged wood is calculated as;
[tex]Percentage \ of \ submerged \ wood = \frac{130 \ kg/m^3}{1000 \ kg/m^3} \ \times \ 100 \% \\\\Percentage \ of \ submerged \ wood = 13 \ \%[/tex]
Therefore, the percentage of the submerged wood is 13%.
a projectile is shot horizontally from the edge of a cliff, 230m above the ground. the projectile lands 300m from base of the cliff
Answer:
The time taken by the projectile to hit the ground is 6.85 sec.
Explanation:
Given that,
Vertical height of cliff = 230 m
Distance = 300 m
Suppose, determine the time taken by the projectile to hit the ground.
We need to calculate the time
Using second equation of motion
[tex]s=ut+\dfrac{1}{2}gt^2[/tex]
Where, s = vertical height of cliff
u = initial vertical velocity
g = acceleration due to gravity
Put the value in the equation
[tex]230=0+\dfrac{1}{2}\times9.8\times t^2[/tex]
[tex]t=\sqrt{\dfrac{230\times2}{9.8}}[/tex]
[tex]t=6.85 sec[/tex]
Hence, The time taken by the projectile to hit the ground is 6.85 sec.
Egg A is dropped from a height of 1m onto the floor. Egg B is dropped from a height of 1m into a bucket of water. Which statement
correctly describes why Egg B does not break?
Answer:
maybe it's because a bucket of water has more density than egg B
Answer:
Egg B experiences less force over a shorter time
Explanation:
A 4.5-kW resistance heater in a water heater runs for 3 hours to raise the water temperature to the desired level. Determine the amount of electric energy used in both kWh and kJ.
Answer:
The electrical energy is 13.5 kWh or 48600 kJ
Explanation:
Given that,
The power of the resistance heater, P = 4.5 kW
The water heater runs for 3 hours to raise the water temperature to the desired level.
We need to find the amount of electric energy used in both kWh and kJ.
Energy = Power × time
E = 4.5 kW × 3 h
= 13.5 kWh
Since,
1 kWh = 3600 kJ
13.5 kWh = 48600 kJ
Hence, the required electrical energy is 13.5 kWh or 48600 kJ
A 1570 kg car skidding due north on a level frictionless icy road at 156 km/h collides with a 2245.1 kg car skidding due east at 120 km/h in such a way that the two cars stick together. At what angle (−180◦ ≤ θ ≤ +180◦ ) East of North do the two coupled cars skid off at?
Answer:
θ = 47.75º East of North.
Explanation:
Assuming no external forces acting during the collision, total momentum must be conserved.Since momentum is a vector, if we project it along E-W and N-S axes, the momentum components along these axes must be conserved too.So, for the N-S axis, we can write the following equation:[tex]p_{Northo} = p_{Northf} (1)[/tex]
Since the car moving due east has no speed component along the N-S axis, the initial momentum along this axis is simply:[tex]p_{Northo} = m_{1} * v_{1o} (2)[/tex]
where m₁ = 1570 kg, v₁₀ = 156 km/h
In order to work with the same units, we need to convert the speed in km/h to m/s, as follows:[tex]v_{1o} = 156 km/h *\frac{1000m}{1 km}*\frac{1h}{3600s} = 43.3 m/s (3)[/tex]
Replacing by the values in the left side of (1), we get:[tex]p_{Northo} = m_{1} * v_{1o} = 1570 kg* 43.3 m/s = 67981 kg*m/s (4)[/tex]
Since the collision is inelastic, both cars stick together, so we can write the right side of (1) as follows:[tex]p_{Northf} = (m_{1} + m_{2})* v_{fNorth} = 3815.1 kg* v_{fNorth} (5)[/tex]
From (4) and (5) , we can solve for VfNorth:[tex]V_{fNorth} = \frac{67981kg*m/s}{3815.1kg} = 17.8 m/s (6)[/tex]
We can repeat exactly the same process for the E-W axis:[tex]p_{Easto} = p_{Eastf} (7)[/tex]
Since the car moving due north has no speed component along the E-W axis, the initial momentum along this axis is simply:[tex]p_{Easto} = m_{2} * v_{2o} (8)[/tex]
As we did with v₁₀, we need to convert v₂₀ from km/h to m/s, as follows:[tex]v_{2o} = 120 km/h *\frac{1000m}{1 km}*\frac{1h}{3600s} = 33.3 m/s (9)[/tex]
Replacing by the values in the left side of (7), we get:[tex]p_{Easto} = m_{2} * v_{2o} = 2245.1 kg* 33.3 m/s = 74762 kg*m/s (10)[/tex]
Since the collision is inelastic, both cars stick together, so we can write the right side of (7) as follows:[tex]p_{Eastf} = (m_{1} + m_{2})* v_{fEast} = 3815.1 kg* v_{fEast} (11)[/tex]
From (10) and (11) , we can solve for VfEast:[tex]V_{fEast} = \frac{74762 kg*m/s}{3815.1kg} = 19.6 m/s (12)[/tex]
In order to find the angle East of North of the velocity vector, as we know the values of the horizontal and vertical components, we need just to apply a little bit of trigonometry, as follows:[tex]tg \theta = \frac{V_{fEast}}{V_{fNorth} } = \frac{19.6}{17.8} = 1.1 (13)[/tex]
The angle θ, East of North, is simply tg⁻¹ (1.1):θ = tg⁻¹ (1.1) = 47.75º E of N.
The scientific method is a process that scientists use to understand the physical world. Place the four basic steps of the scientific method in the correct order, from start to finish.
a. Observation of physical world.
b. Create hypothesis about observation.
c. Test conscquences of hypothesis
d. Report outcome
e. Adjust results to agree with popular opinion
Answer:
a,b,c,e,d
Explanation:
The typical approach by the scientists use to understand the physical world includes the following steps:
Identifying a Problem
Researching the Information
Stating a Hypothesis (Possible Solution)
Testing the Hypothesis
Gather Data
Analysis of the Data
Stating a Conclusion
Publishing the Result
Therefore, according to the question the correct order would be:
a. Observation of physical world.
b. Create hypothesis about observation.
c. Test consequences of hypothesis
e. Adjust results to agree with popular opinion
d. Report outcome
hii Happy New year can you all please answer this
Answer:
truuuuuuuuuuuuueeeeeeeee
