Enter the values needed to find the
length AB. (Simplify your answer.)
A(-3a, b)
F
В(3a, b)
AB = ([?])2
✓([?])2 + (0)2
Distance Formula: d = x)2 + (92-y)
C-a Sb)
Enter
Answer:
The missing value is 6a
Step-by-step explanation:
Given:
[tex]\displaystyle \large{A(-3a,b)}\\\displaystyle \large{B(3a,b)}[/tex]
Find:
Missing Value
Distance Formula:
[tex]\displaystyle \large{\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}[/tex]
Determine:
[tex]\displaystyle \large{(x_2,y_2)=(3a,b)}\\\displaystyle \large{(x_1,y_1)=(-3a,b)}[/tex]
Input given information above in the formula:
[tex]\displaystyle \large{AB=\sqrt{(3a-(-3a))^2+(b-b)^2}}\\\displaystyle \large{AB=\sqrt{(3a+3a)^2+(0)^2}}\\\displaystyle \large{AB=\sqrt{(6a)^2}}\\\displaystyle \large{AB=6a}[/tex]
The length is 6a but since we want to find the value in the square root then the answer is still 6a
Which of the following is in vertex form of quadratic?
The vertex form of quadratic equation is f(x) = -5(x-1)^2 + 6
A quadratic equation is written in its vertex form in order to easily determine the maximum or minimum point on the curve.
The standard vertex form of an equation is given as:
a(x-b)^2 + k
From the given option, we can see that the only eqeuation writen in this form is f(x) = -5(x-1)^2 + 6
Hence the vertex form of quadratic equation is f(x) = -5(x-1)^2 + 6
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Cos2A + cosec4A = cot A-cot 4A
Answer:
no solution
Step-by-step explanation:
A graphing calculator shows the left-side expression is never equal to the right-side expression for any real-number value of A.
The equation is not an identity, and has no solution.
__
Additional comment
By subtracting the right-side expression from the left-side expression, we get an equation of the form f(A)=0. Any solutions will be x-intercepts of the graph. The graph for this equation never comes close to crossing the x-axis.
which equation is equivalent to 3(2x - 5) = 4 (x + 3) ?
Step-by-step explanation:
3(2x - 5) = 4(x+3)
Distribute. Multiply 3 by 2x so the product keeps the variable, multiply 3 by 5 and keep the subtraction symbol. Multiply 4 by x so it would be 4x, multiply 4 by 3
(6x-5=4x+12) Answer
The sum of three numbers is 10. The sum of twice the first number, 4 times the second number, and 5 times the third number is 33. The difference between 6 times the first number and the second number is 28. Find the three numbers.
Answer:
5 2 3Step-by-step explanation:
The given relations allow us to write three equations in the three unknown values. We can let x, y, z represent the three numbers, in order.
__
x +y +z = 10 . . . . . . . the sum of the three numbers is 10
2x +4y +5z = 33 . . . . . designated sum is 33
6x -y = 28 . . . . . . . . 6 times the first is 28 more than the second
__
There are many ways to solve a system of equations like this. Perhaps one of the easiest is to enter the equations as an augmented matrix in your calculator, and let it do the work. (Some calculators will solve the equations directly.)
The three numbers are 5, 2, and 3.
_____
Additional comment
The third equation lets you write an expression for y in terms of x:
y = 6x -28
Substituting this into the first two equations, we get ...
x +(6x -28) +z = 10 ⇒ 7x +z = 38
2x +4(6x -28) +5z = 33 ⇒ 26x +5z = 145
Subtracting the second from 5 times the first of these equations gives ...
5(7x +z) -(26x +5z) = 5(38) -(145)
9x = 45 . . . . . the y-variable is eliminated
x = 5
Use equations from above to find z and y.
z = 38 -7x = 3
y = 6(5) -28 = 2
Statistics 1
You are buying uniforms for young male military recruits. You know the mean chest size and the standard deviation of the chest size. About what proportion of the chest sizes of the recruits would you expect to be within one standard deviation of the mean chest size? Choose the best answer below
A. 50%, if the mean chest size is Normally distributed
B. 2/3
C. 50%, if the chest sizes are Normally distributed
D. 68%, if the chest sizes are Normally distributed
E. 95%
Solve the equation.
y + 6 = –3y + 26
y = –8
y = –5
y = 5
y = 8
Answer:
y = 5
Step-by-step explanation:
y + 6 = –3y + 26
y + 3y + 6 = 26
4y + 6 = 26
4y = 26 - 6
4y = 20
y = 5
I hope this helps!
Tickets for a carnival cost $8 for children and $12 for adults. The carnival sold a total of 233 tickets and collected $2,156. How many children’s tickets were sold?
A.
180
B.
160
C.
73
D.
108
You spin the spinner once.
2,3,4,5,6,7
What is P(6)?
Write your answer as a fraction or whole number.
Helps pls i did 120 questions
Answer:
1/6
Step-by-step explanation:
it is like a cube just with slightly different numbers on each side. but the probabilty structure is still the same.
we have 6 different possible outcomes, all with the same basic probabilty (as every field on the spinner is seemingly of the same size as the others).
and we desire one of these possible outcomes (6).
so the probabilty to get 6 is still 1/6 (1 desired over 6 possible outcomes).
[tex]$a+a r+a r^{2}+\ldots \infty=15$$a^{2}+(a r)^{2}+\left(a r^{2}\right)^{2}+\ldots \infty=150$. Find $a r^{3}+a r^{4}+a r^{6}+\ldots \infty$[/tex]
Options:
[tex](a) $\frac{1}{2}$\\(b) $\frac{2}{5}$[/tex]
Let
[tex]S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n[/tex]
where we assume |r| < 1. Multiplying on both sides by r gives
[tex]r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}[/tex]
and subtracting this from [tex]S_n[/tex] gives
[tex](1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}[/tex]
As n → ∞, the exponential term will converge to 0, and the partial sums [tex]S_n[/tex] will converge to
[tex]\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}[/tex]
Now, we're given
[tex]a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a[/tex]
[tex]a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}[/tex]
We must have |r| < 1 since both sums converge, so
[tex]\dfrac{15}a = \dfrac1{1-r}[/tex]
[tex]\dfrac{150}{a^2} = \dfrac1{1-r^2}[/tex]
Solving for r by substitution, we have
[tex]\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)[/tex]
[tex]\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}[/tex]
Recalling the difference of squares identity, we have
[tex]\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}[/tex]
We've already confirmed r ≠ 1, so we can simplify this to
[tex]\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15[/tex]
It follows that
[tex]\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12[/tex]
and so the sum we want is
[tex]ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}[/tex]
which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?
A regular octagon with side length = 5.3 meters. What is the total area of the shape? Round to two
decimal places at the end of your calculation.
Answer:
97.31 [tex]m^2[/tex]
Step-by-step explanation:
The area of the octagon is:
[tex]\frac{8 * 5.3 * 2.65\sqrt{3} }{2}[/tex] ~97.31 m^2
14 m
F. 2,352 m
G. 1,476 m
H. 392 m
I. 261.3 m
7 m
24 m
25 m
Answer:
choice for your help today 12 m is not answering me, sorry I think 25m
Find the hourly wage for a person with an income of $60376, who works 57 hours a week for 44 weeks.
Answer:
$24.07
Step-by-step explanation:
57×44=2508 hrs
60376÷2508=$24.07 per hr
Help help math math math math
Answer:
C. -3/7
Step-by-step explanation:
Irrational numbers: cannot be written as a fraction
Rational numbers: can be written as a fraction
The only option that contains a fraction, is C
Hope this helps!
Option C
Solution:Rational numbers can be expressed as a fraction in the form [tex]\displaystyle\frac{p}{q}[/tex], where p is the numerator and q is the denominator.Now, which numbers can and cannot be expressed as a fraction?First of all, can we express [tex]\sqrt{12}[/tex] as a fraction? No, it's a surd.Can we express [tex]\pi[/tex] as a fraction? No. Remember, pi is irrational. It has an infinite number of digits after the decimal point (same with √12)Can we express [tex]-\displaystyle\frac{3}{7}[/tex] as a fraction? Sure. What's more, it's already a fraction.Can we express √7 as a fraction? No. It's also irrational, like √12 and π.Hope it helps.
Do comment if you have any query.
I need help finding the surface area of this shape
Answer:
1030 [tex]yd^{2}[/tex]
Step-by-step explanation:
split it into 2 different rectangular prisms
first one is 27 yd by 8 yd by 9 yd
second is 10yd by 8 yd by 12 yd
Answer:
1494 [yd²].
Step-by-step explanation:
1) the required area can be calculated as (see the attached picture):
A=A1+A2+A3+A4+A5+A6+2*A7;
2) finally,
A=9*8+17*8+8*12+10*8+(12+9)*8+27*8+2*(27*9+12*10);
A=1494 [yd²].
Note, the suggested solution is not the shortest one.
Guys please help me!!!
Answer:
p = 2
q = -1
k = -1
Step-by-step explanation:
Cosine functions always start above or below 0. So, the one that starts at (0, 1) is f(x) = (p)cosx + q. Sine functions always start at 0. So, the one that starts at (0, 0) is g(x) = (k)sinx.
Using the help image attached, we know that:
p and k = amplitude (top to midline)
Negative when cosx/sinx starts at the bottomq = vertical shift (movement of midline)
For f(x) = (p)cosx + q:
p = 2
q = -1
For g(x) = (k)sinx:
k = -1
Hope this helps!
A pianist plans to play 5 pieces at a recital from her repertoire of 27 pieces. How many different recital programs are possible?
The different recital programs that are possible is 80,730 ways
Combination and permutationPermutation has to do with arrangement while combination has to do with the selection.
According to the question, a pianist plans to play 5 pieces at a recital from her repertoire of 27 pieces, this shows that he can select the 5 pieces in any form.
The number of ways this can be done is given as:
[tex]27C_5=\frac{27!}{(27-5)!5!}\\ 27C_5=80,730[/tex]
Hence the different recital programs that are possible is 80,730 ways
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find the range of the data.
133,117,152,127,168,146,174
133, 117, 152, 127, 168, 146, 174.
to find:range.
solution:first arrange the numbers in order, which gives you:
= 117, 127, 133, 146, 152, 168, 174
then subtract the lowest number from the highest, which gives you:
174 - 117
= 57
range= 57.
Solve:
x + 1/x = 4 1/4
Ans: 4,1/4
Answer:
x = 4, 1/4
solving steps
[tex]\sf \rightarrow x + \dfrac{1}{x}=4\dfrac{1}{4}[/tex]
make the denominators same
[tex]\sf \rightarrow \dfrac{x(x)}{x} + \dfrac{1}{x}=4\dfrac{1}{4}[/tex]
simplify the following
[tex]\sf \rightarrow \dfrac{x^2}{x} + \dfrac{1}{x}=\dfrac{17}{4}[/tex]
join both fractions together
[tex]\sf \rightarrow \dfrac{x^2+1}{x}=\dfrac{17}{4}[/tex]
cross multiply
[tex]\sf \rightarrow 4(x^2+1)=17(x)[/tex]
simplify
[tex]\sf \rightarrow 4x^2-17(x)+4=0[/tex]
completing square
[tex]\sf \rightarrow 4x^2-16(x)-x+4=0[/tex]
factor
[tex]\sf \rightarrow 4x(x-4)-1(x-4)=0[/tex]
group the variables
[tex]\sf \rightarrow (4x-1)(x-4)=0[/tex]
simplify
[tex]\sf \rightarrow (x-4)=0, \ (4x-1) =0[/tex]
final answer
[tex]\sf \rightarrow x=4, \ x =\dfrac{1}{4}[/tex]
Answer:
[tex]\boxed{x = \dfrac{1}{4}}[/tex] and [tex]\boxed{x = 4}[/tex]
Step-by-step explanation:
Given equation:
[tex]x + \dfrac{1}{x} = 4\dfrac{1}{4}[/tex]
Step-1: Convert the mixed fraction on the R.H.S into improper fraction
[tex]x + \dfrac{1}{x} = 4\dfrac{1}{4}[/tex]
[tex]x + \dfrac{1}{x} = \dfrac{4 \times4 + 1}{4}[/tex]
[tex]x + \dfrac{1}{x} = \dfrac{16 + 1}{4}[/tex]
[tex]x + \dfrac{1}{x} = \dfrac{17}{4}[/tex]
Step-2: Make common denominators on the L.H.S:
[tex]x + \dfrac{1}{x} = \dfrac{17}{4}[/tex]
[tex]\dfrac{x^{2} }{x} + \dfrac{1}{x} = \dfrac{17}{4}[/tex]
Step-3: Combine the denominators on the L.H.S
[tex]\dfrac{x^{2} }{x} + \dfrac{1}{x} = \dfrac{17}{4}[/tex]
[tex]\dfrac{x^{2} +1}{x} = \dfrac{17}{4}[/tex]
Step-4: Use cross multiplication
[tex]\dfrac{x^{2} +1}{x} = \dfrac{17}{4}[/tex]
[tex]x^{2} +1} = \dfrac{17x}{4}[/tex]
[tex]4(x^{2} +1}) = {17x}[/tex]
Step-5: Simplify the distributive property
[tex]4(x^{2} +1}) = {17x}[/tex]
[tex]4x^{2} +4} = {17x}[/tex]
[tex]-17x + 4x^{2} +4} = 0[/tex]
Step-6: Change "-17x" to "-16x - x" as it is equivalent
[tex]-17x + 4x^{2} +4} = 0[/tex]
[tex](-16x - x) + 4x^{2} +4} = 0[/tex]
Step-7: Factor the common terms
[tex](-16x - x) + 4x^{2} +4} = 0[/tex]
[tex]-16x - x + 4x^{2} +4} = 0[/tex]
[tex]4x(-4 + x) - 1(x - 4) = 0[/tex]
Step-8: Group the terms
[tex]4x(-4 + x) - 1(x - 4) = 0[/tex]
[tex](x - 4)(4x - 1) = 0[/tex]
Step-9i: Use cross multiplication for (x - 4)
[tex](x - 4)(4x - 1) = 0[/tex]
[tex]x - 4 = \dfrac{0}{4x - 1 } = 0[/tex]
Step-9ii: Use cross multiplication for (4x - 1)
[tex](x - 4)(4x - 1) = 0[/tex]
[tex]4x - 1 = \dfrac{0}{x - 4} = 0[/tex]
Thus [tex]x - 4 = 0[/tex] and [tex]4x - 1 = 0[/tex].
Step-10: Simplify both equations
[tex]4x - 1 = 0[/tex] [tex]x - 4 = 0[/tex]
[tex]4x = 0 + 1[/tex] [tex]x = 0 + 4[/tex]
[tex]4x = 1[/tex] [tex]\boxed{x = 4}[/tex]
[tex]\boxed{x = \dfrac{1}{4}}[/tex]
Part 2 of 2 Points: 0 of 1 Save Some states now allow online gambling. As a marketing manager for a casino, you need to determine the percentage of adults in those states who gamble online. How many adult must you survey in order to be 95% confident that your estimate Is In error by no more than two percentage points? Complete parts (a) and (b) below. a. Assume that nothing is known about the percentage of adults who gamble online. n = 2401 (Round up to the nearest Integer) b. Assume that 18% of all adults gamble online, n = (Round up to the nearest Integer.)
The sample size for part (a) is 2401, and the sample size for part (b) is 1417 if the margin of error is no more than two percentage points and use a confidence level of 95%
What is the margin of error(MOE)?It is defined as an error that gives an idea about the percentage of errors that exist in the real statistical data.
The formula for finding the MOE:
[tex]\rm MOE= Z{score}\times \frac{s}{\sqrt{n} }[/tex]
Where Z_{score} is the z score at the confidence interval
s is the standard deviation
n is the number of samples.
We have:
MOE = 2% = 0.02 and
α = 1-0.95 = 0.05
Let's assume the value of p = 0.5, and q = 0.5
From the table:
Z_(0.05/2) = Z_(0.025) = 1.96
[tex]\rm n = 0.5\times0.5\frac{1.96^2}{0.02^2}[/tex]
n = 2401
For part (b):
p = 18% = 0.18, and q = 0.82
[tex]\rm n = 0.18\times0.82\frac{1.96^2}{0.02^2}[/tex]
n = 1417.5 = 1417
Thus, the sample size for part (a) is 2401, and the sample size for part (b) is 1417 if the margin of error is no more than two percentage points and use a confidence level of 95%
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A, B, C, D are points on a line.
AB = 1
BC = 2
CD = 4
Find the length of segment AD. Consider all possibilities.
So far, I've only gotten 7, 5, and 1. But I know there is one left. Can you guys help?
The points A, B, C and D are collinear points
The length of the segment AD is 7 units
How to determine the length AD?The given parameters are:
AB = 1
BC = 2
CD = 4
Because the points are on the same line, then the following is the possible equation
AD = AB + BC + CD
Substitute known values
AD = 1 + 2 + 4
Evaluate the sum
AD = 7
Hence, the length of the segment AD is 7 units
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Evaluate 2x(8+4)-7
Please do some working out
Answer:
24x-7
Step-by-step explanation:
First, we distribute the 2x.
2x * 8 = 16x
2x * 4 = 8x
16x+8x-7
24x-7
This is the final result / your answer :
24x-7
Answer:
24x-7
Step-by-step explanation:
1. Add 8 and 4, this leaves us with 2x(12)-7
2. Multiply 12 and 2. This leaves us with 24x-7
Simplify the expression: 4(− + 7) < 40 *
a > −11.75
b < −11.75
c < −3
d > −3
Answer:x=70
Step-by-step explanation:
STEP
1
:
40
Simplify ——
x
Equation at the end of step
1
:
4 40
— - —— = 0
7 x
STEP
2
:
4
Simplify —
7
Equation at the end of step
2
:
4 40
— - —— = 0
7 x
STEP
3
:
Calculating the Least Common Multiple :
3.1 Find the Least Common Multiple
The left denominator is : 7
The right denominator is : x
Number of times each prime factor
appears in the factorization of:
Prime
Factor Left
Denominator Right
Denominator L.C.M = Max
{Left,Right}
7 1 0 1
Product of all
Prime Factors 7 1 7
Number of times each Algebraic Factor
appears in the factorization of:
Algebraic
Factor Left
Denominator Right
Denominator L.C.M = Max
{Left,Right}
x 0 1 1
Least Common Multiple:
7x
Calculating Multipliers :
3.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = x
Right_M = L.C.M / R_Deno = 7
Making Equivalent Fractions :
3.3 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. 4 • x
—————————————————— = —————
L.C.M 7x
R. Mult. • R. Num. 40 • 7
—————————————————— = ——————
L.C.M 7x
Adding fractions that have a common denominator :
3.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
4 • x - (40 • 7) 4x - 280
———————————————— = ————————
7x 7x
STEP
4
:
Pulling out like terms :
4.1 Pull out like factors :
4x - 280 = 4 • (x - 70)
Equation at the end of step
4
:
4 • (x - 70)
———————————— = 0
7x
STEP
5
:
When a fraction equals zero :
5.1 When a fraction equals zero ...
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
4•(x-70)
———————— • 7x = 0 • 7x
7x
Now, on the left hand side, the 7x cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape :
4 • (x-70) = 0
Equations which are never true:
5.2 Solve : 4 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation:
5.3 Solve : x-70 = 0
Add 70 to both sides of the equation :
x = 70
One solution was found :
x = 70
help me pleaseeeeeeee
Answer:
x = 25
Step-by-step explanation:
This is just algebra involved with geometry!
Your objective is to solve for x.
The line dividing the 2x-5 and x+20 is the bisector
A bisector means the two angles have to be equal!
Your objective is to solve for x.
The line dividing the 2x-5 and x+20 is the bisector
A bisector means the two angles have to be equal!
2x-5=x+20 should be the equation!
Subtract x from both sides
x-5=20
Now add 5 to both sides
x=20+5
x=25
Now you need to plug the answers in!
50-5 for 2x-5
25+20 for x+20
45+45 = 90
I don't really know about the 125 but if that was excluded then this is it ^^^
The value of x is,
⇒ x = 33.3°
What is mean by Angle?An angle is a combination of two rays (half-lines) with a common endpoint. The latter is known as the vertex of the angle and the rays as the sides, sometimes as the legs and sometimes the arms of the angle.
Given that;
The value of total angle is, 125°
Hence, By definition of angles we get;
⇒ (2x - 5) + (x + 20) = 125°
⇒ 3x + 15 = 125°
⇒ 3x = 125 - 15
⇒ 3x = 110
⇒ x = 33.3°
Thus, The value of x is,
⇒ x = 33.3°
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d. Henrietta Hardworker normally earns $8.50 per hour in a given 40-hour work-
week. If she works overtime, she earns time and a half pay per hour. During the
month of October, she worked 40 hours, 50 hours, 45 hours, and 42 hours for the
four weeks. How much did she earn fotal for October?
Answer:
1432.25
Step-by-step explanation:
8.50 x 40 = 340
340 x 4 = 1360
half of 8.50 is 4.25
4.25 x 10 = 42.5
4.25 x 5 = 21.25
4.25 x 2 = 8.5
add
1360 + 42.5 + 21.25 + 8.5 = 1432.25
i hope i did my math right, good luck mate
Select the best answer for the question.
15. If the following fractions were converted to decimals, which one would result in
O A.314
O B.5111
O C.317
OD. 1/9
Upon asking I got the rest of the information needed to answer this question.
-> Which one becomes a repeating decimal?
Your answer is D. 1/9.
1/9 = 0.111111111111111111111111111111111 ... or 0.1 repeating. It can be written with a line over the 1 asyou can see in the attached.
This means that D is the answer to your question.
What is the axis of symmetry for the function f(x)=7−4x+x2?
Answer:
The axis of symmetry is x=2
Step-by-step explanation:
How many ways can you place the letters in the word "PASTURE" into groups of four letters without repetition?
Using the permutation formula, it is found that there are 840 ways to place the letters.
The order in which the letters are placed is important, as PAST is a different arrangement that PTAS, for example, hence the permutation formula is used.
What is the permutation formula?The number of possible permutations of x elements from a set of n elements is given by:
[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]
In this problem, 4 letters are taken from a set of 7, hence:
[tex]P_{7,4} = \frac{7!}{3!} = 840[/tex]
There are 840 ways to place the letters.
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Answer:35
Step-by-step explanation:
15/2 + 13/8+ 14/4+ 2/1+52/8+36/4=
Answer:
30.125
the answer is 30.125 so that is the answer of this question
The distance between 2 cities is 7200 miles. How long will it take a plan that flies 600 miles/h to travel between the 2 cities?
