About what percentage of the data lies within 2 standard deviations of the mean in a normal distribution? 47. 5% 68% 95% 99. 7%.

Answer:

it is a 30 degree angle

Step-by-step explanation:

Answer:

The similarity statement is RTS and ACB. Other options are correct

.................................

Answer:

[tex]x^{\frac{3}{2} } p^{6}[/tex]

Step-by-step explanation:

Answer:

42

Step-by-step explanation:

5²+3(2)+5+6

25+6+5+6

31+11

42

Hope it helps

Answer:

x=180-125

=55

z=55

y=180-(55+55)

y=70

Answer:

1/4

Step-by-step explanation:

First, add up the marbles:

2 + 9 + 7  = 18

Multiply by 2 because you pick two:

18 × 2 = 36

Simplify:

9/36 = 3/12 = 1/4

Hope this helped.

Answer:

4^8

Step-by-step explanation:

If the second 4 is an exponent, as in (4^2)^4, then multiply the exponents.

(4^2)^4 = 4^(2 * 4) = 4^8

I'm assuming the integral is

[tex]\displaystyle \int \frac{\mathrm dx}{x+\sqrt{x^2-1}}[/tex]

Rationalize the denominator:

[tex]\dfrac1{x+\sqrt{x^2-1}} \times \dfrac{x-\sqrt{x^2-1}}{x-\sqrt{x^2-1}} = \dfrac{x-\sqrt{x^2-1}}{x^2-\left(\sqrt{x^2-1}\right)^2} = x-\sqrt{x^2-1}[/tex]

Then the integral is

[tex]\displaystyle \int\left(x-\sqrt{x^2-1}\right)\,\mathrm dx = \dfrac12x^2 - \int\sqrt{x^2-1}\,\mathrm dx[/tex]

For the remaining integral, substitute x = sec(t ) and dx = sec(t ) tan(t ) dt. Then over an appropriate domain, we have

[tex]\displaystyle\int\sqrt{x^2-1}\,\mathrm dx = \int\sec(t)\tan(t)\sqrt{\sec^2(t)-1}\,\mathrm dt = \int\sec(t)\tan^2(t)\,\mathrm dt[/tex]

Integrate by parts, taking

u = tan(t )   ==>   du = sec²(t ) dt

dv = sec(t ) tan(t ) dt   ==>   v = sec(t )

Then

[tex]\displaystyle\int\sec(t)\tan^2(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec^3(t)\,\mathrm dt[/tex]

Now for *this* remaining integral, integrate by parts again, taking

u = sec(t )   ==>   du = sec(t ) tan(t ) dt

dv = sec²(t ) dt   ==>   v = tan(t )

so that

[tex]\displaystyle\int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec(t)\tan^2(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec(t)(\sec^2(t)-1)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec^3(t)\,\mathrm dt + \int\sec(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \frac12\sec(t)\tan(t)+\frac12\int\sec(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C[/tex]

To summarize, if I denotes the original integral, we have

[tex]\displaystyle I = \frac12x^2 - \int\sqrt{x^2-1}\,\mathrm dx \\\\ I = \frac12x^2 - \int\sec(t)\tan^2(t)\,\mathrm dt \\\\ I = \frac12x^2 - \sec(t)\tan(t) + \int\sec^3(t)\,\mathrm dt \\\\ I = \frac12x^2 - \sec(t)\tan(t) + \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C \\\\ I = \frac12x^2 - \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C[/tex]

Putting everything back in terms of x, we have

sec(t ) = x

tan(t ) = √(x ² - 1)

so that

[tex]\displaystyle I = \boxed{\frac12x^2 - \frac12x\sqrt{x^2-1}+\frac12\ln\left|x+\sqrt{x^2-1}\right|+C}[/tex]

Answer:

a

Step-by-step explanation:

assuming theyre asking you to graph y = (x-2)(x+3)  -cant see the signs in your photo

the x-intercepts would be 2 and -3 , so option a!

Answer:

13. 10

14. 51

Step-by-step explanation:

Answer:

13. 10

14. 51

Step-by-step explanation:

Answer:

P(t) = 14300e^0.07t

Step-by-step explanation:

Let :

Population as a function of years, t = P(t) ;

Growth rate, r = 7%

Estimated population on year 2000 = Initial population = 14300

The given scenario can be modeled using an exponential function as the change in population is based in a certain percentage increase per period.

P(t) = Initial population*e^rt

P(t) = 14300*e^(0.07t)

P(t) = 14300e^0.07t

Where, t = number of years after year 2000.

The diagram is missing and so i have attached it.

Answer:

Next step is;

to keep the same compass width and draw an arc centered at H crossing the previous arc in the image.

Step-by-step explanation:

A perpendicular line is to be drawn to line GH through point A.

The steps are;

1. Identification of the two end points of the line which has been done.

2. Place one leg of the compass at point G and draw a small arc above the line GH. This has been done.

3. Without changing the span of the compass, place the same leg of the compass at point H and draw another small arc above the line GH to intersect the previously drawn small arc.

4. Make use of a straight object to connect the point of intersection of the two small arcs to the point A.

This line is the perpendicular line to GH.

In the figure attached, they have just finished point 2 I wrote above. Thus, the next step is point 3.

Answer:

to keep the same compass width and draw an arc centered at H crossing the previous arc in the image.

Step-by-step explanation:

Answer:

[tex]x = \frac{2 \sqrt{3} }{3} [/tex]

[tex]y = 1[/tex]

Step-by-step explanation:

30, 60, 90 triangle

Answer:

B. A linear, partial variation

Step-by-step explanation:

We know that speed = distance / time. From the table we have a linear function, and it's indirect, or partial.

Area of the triangle = 1/2 x base x height

Area of triangle = 1/2 x 6 x 8.3 = 24.9 square feet.

Area of rectangle = length x width

Area of rectangle = 33.2 x 12 = 398.4 square feet.

To find the number of triangles that can fit in the rectangle divide the area of the rectangle by the area of the triangle:

398.4 / 24.9 = 16

Answer: 16 triangles

Answer:

240

Step-by-step explanation:

The profit a company makes from producing x tabletops is modeled by the equation P(x) = 480x – 2x2. For what number of tabletops does the company make a profit of $0?

Answer:

240 Tabletops

Answer:

75%

Step-by-step explanation:

9 ÷ 12 = 0.75

0.75 x 100 = 75 = 75%

Answer:

3/4

Step-by-step explanation:

Experimental probability, is the probability determined according to the results of an "experiment" or a trial. In Carla's "experiment", she attempted 12 total shots and made 9 shots. The probability that she made a shot would be 9/12, or 3/4.

Answer:

the number A(t) of grams of salt in the tank at a time is A(t)=150-110e-t/50

Answer:

Stratified sampling

Step-by-step explanation:

Convenient: Sample drawn from a conveniently available pool.

Random: Basically, put all the options into a hat and drawn some of them.

Systematic: Every kth element is taken. For example, you want to survey something on the street, you interview every 5th person, for example.

Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.

Stratified: Also divides the population into groups. However, then only some elements of the group are surveyed.

In this question:

Divided by groups(according to age)

A certain amount of each group is sampled.

Thus, stratified sampling is used.

Answer:

a) log 2 (48 ×3 ×9 )

log 2 1296

10.3

b) log 4 24 - log 4 3/4 log 4 2

log 4 36

2.58

Answer:

hi friends good evening

Answer:

250°

There are 250°……………

Answer:

diameter of a circle

Step-by-step explanation:

Answer:

A diameter of a circle

Step-by-step explanation:

given the construction we have to choose the construction which uses the compass for only one step in addition to drawing circle itself . show a diameter of a circle only e uses one stay in addition to draw circle itself

Answer:

 R=.2,P=.25, G=.55

Step-by-step explanation:

Answer:

x= Hamburguesa

y=Papas

y=x+50

x+y=1300

x+(x+50)=1300

2x+50=1300

2x=1250

x=625

Calorias de Hamburguesa = 625

Calorias de Papas = 625+50 = 675

Answer:

false

Step-by-step explanation:

the relationship between lengths/dimensions and areas is that areas are created by multiplying 2 dimensions.

when you quadruple (×4) the dimensions, then the areas are growing with the square of the factor (×4×4 = ×16), because the factor goes twice into the multiplication : one time for every dimension involved.

so, quadrupling the dimensions would multiply the areas by 16.

Answer:

[tex]x^3y^{-7} = \frac{x^3}{y^7}[/tex]

Step-by-step explanation:

Given

[tex]x^3y^{-7}[/tex]

Required

The equivalent

We have:

[tex]x^3y^{-7}[/tex]

Apply the following rule of exponents

[tex]a^{-b} = \frac{1}{a^b}[/tex]

So, we have:

[tex]x^3y^{-7} = x^3 * \frac{1}{y^7}[/tex]

[tex]x^3y^{-7} = \frac{x^3}{y^7}[/tex]

Answer:

the 2nd one or B

Step-by-step explanation:

Answer:

Step-by-step explanation:

30