A uniform, solid sphere of radius 2.50 cm and mass 4.75 kg starts with a purely translational speed of 3.00 m/s at the top of an inclined plane. The surface of the incline is 2.75 m long, and is tilted at an angle of 22.0∘ with respect to the horizontal. Assuming the sphere rolls without slipping down the incline, calculate the sphere's final translational speed v2 at the bottom of the ramp.

Answers

Answer 1

Answer:

The final translational seed at the bottom of the ramp is approximately 4.84 m/s

Explanation:

The given parameters are;

The radius of the sphere, R = 2.50 cm

The mass of the sphere, m = 4.75 kg

The translational speed at the top of the inclined plane, v = 3.00 m/s

The length of the inclined plane, l = 2.75 m

The angle at which the plane is tilted, θ = 22.0°

We have;

[tex]K_i[/tex] + [tex]U_i[/tex] = [tex]K_f[/tex] + [tex]U_f[/tex]

K = (1/2)×m×v²×(1 + I/(m·r²))

I = (2/5)·m·r²

K =  (1/2)×m×v²×(1 + 2/5) = 7/10 × m×v²

U = m·g·h

h = l×sin(θ)

h = 2.75×sin(22.0°)

∴ 7/10×4.75×3.00² + 4.75×9.81×2.75×sin(22.0°) = 7/10 × 4.75×[tex]v_f[/tex]² + 0

7/10×4.75×3.00² + 4.75×9.81×2.75×sin(22.0°) ≈ 77.93

∴ 77.93 ≈ 7/10 × 4.75×[tex]v_f[/tex]²

[tex]v_f[/tex]² = 77.93/(7/10 × 4.75)

[tex]v_f[/tex] ≈ √(77.93/(7/10 × 4.75)) ≈ 4.84

The final translational seed at the bottom of the ramp, [tex]v_f[/tex] ≈ 4.84 m/s.


Related Questions

How can you say gravitational force is a field force

Answers

Answer:

because gravity pulled us in the land if there is no gravitational force there will not be field force too

Explanation:

hope it's will help you

valancy of an atom is +2. what does it mean. ​

Answers

Answer: I hope you find it useful

Explanation: Group 2 elements have two valence electrons. The two valence electrons are easily lost in the formation of chemical bonds. Once the two electrons are lost, the atom then has a full outer shell and is therefore more stable.

so,  if an atom has valency 2 , then it means that the atom can combine with 2 other atoms .

You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to the right. The snow exerts a friction force of 30 N on the sled to the left. The mass of the sled is 50 kg.

Find the sun of the force on the self

Determine the acceleration of the sled

If the sled has an initial velocity 2m/s to the right, how fast will it be traveling after 5 seconds?

Answers

Answer:

Part 1

20 N

Part 2

0.4 m/s²

Part 3

4 m/s

Explanation:

The force which pulls the sled right = 50 N

The friction force exterted towards left by the snow = -30 N

The mass of the sled = 50 kg

Part 1

The sum of the forces on the sled, F = 50 N + (-30) N = 20 N

Part 2

The acceleration of the sled is given as follows;

F = m·a

Where;

m = The mass of the sled

a = The accelertion

a = F/m

∴ a = (20 N)/(50 kg) = 0.4 m/s²

The acceleration of the sled, a = 0.4 m/s²

Part 3

The initial velocity of the sled, u = 2 m/s

The kinematic equation of motion to determine the speed of the sled is v = u + a·t

The speed, v, of the sled after t = 5 seconds is therefore;

v = 2 m/s + 0.4 m/s² × 5 s = 4 m/s.

Two football players run towards each other along a straight path in Penrith Park in the clash between the Melbourne storms and the Penrith Panthers a month ago. Melbourne's Justin Olam who is about 95kg and ran towards Viliame Kikau at 3.75m/s. Viliame Kikau is 111kg and moves towards Justin Olam at 4.10m/s. They end up in a head-on collision and are stuck together.

A) What is their velocity immediately after the collision?

B) What are the initial and final kinetic energies of the system?​

Answers

Answer:

a) v = 0.4799 m / s,  b)  K₀ = 1600.92 J,    K_f = 5.46 J

Explanation:

a) How the two players collide this is a momentum conservation exercise. Let's define a system formed by the two players, so that the forces during the collision are internal and also the system is isolated, so the moment is conserved.

Initial instant. Before the crash

        p₀ = m v₁ + M v₂

where m = 95 kg and his velocity is v₁ = -3.75 m / s, the other player's data is M = 111 kg with velocity v₂ = 4.10 m / s, we have selected the direction of this player as positive

Final moment. After the crash

       p_f = (m + M) v

as the system is isolated, the moment is preserved

       p₀ = p_f

       m v₁ + M v₂ = (m + M) v

       v =[tex]\frac{m v_1 + M v_2}{m+M}[/tex]

let's calculate

        v = [tex]\frac{ -95 \ 3.75 \ + 111 \ 4.10}{95+111}[/tex]

        v = 0.4799 m / s

b) let's find the initial kinetic energy of the system

         K₀ = ½ m v1 ^ 2 + ½ M v2 ^ 2

         K₀ = ½ 95 3.75 ^ 2 + ½ 111 4.10 ^ 2

         K₀ = 1600.92 J

the final kinetic energy

         K_f = ½ (m + M) v ^ 2

         k_f = ½ (95 + 111) 0.4799 ^ 2

         K_f = 5.46 J

Numerical problems:
a. convert the following as instructed:
i) 340 cm into m
ii)86400 seconds into day​

Answers

Answer:

a=3.4m because of the m

b=1day because 86400=a day

state the term used to describe the turning force exerted by the man pushing down on a lever to lift one end of a heavy log​

Answers

A force called the effort force is applied at one point on the lever in order to move an object, known as the resistance force, located at some other point on the lever.

The way levers work is by multiplying the effort exerted by the user. Specifically, to lift and balance an object, the effort force the user applies multiplied by its distance to the fulcrum must equal the load force multiplied by its distance to the fulcrum. Consequently, the greater the distance between the effort force and the fulcrum, the heavier a load can be lifted with the same effort force.

The term used to describe the turning force exerted when pushing an object is effort.

What is effort?

The is the input force or force applied at one point of a lever in order to overcome a load.

The relationship between effort, load and mechanical advantage of a lever is given as;

M.A = L/E

where;

M.A is mechanical advantageL is the loadE is the applied force or effort

Thus, the term used to describe the turning force exerted when pushing an object is effort.

Learn more about effort here: https://brainly.com/question/24237657

The magnetic coils of a tokamak fusion reactor are in the shape of a toroid having an inner radius of 0.700 m and an outer radius of 1.30 m. The toroid has 900 turns of largediameter wire, each of which carries a current of 14.0 kA. Find the magnitude of the magnetic field inside the toroid along (a) the inner radius and (b) the outer radius.

Answers

Answer:

(a) 11.3 T

(b) 6.09 T

Explanation:

Current, I = 14 kA = 14000 A

number of turns, N = 900

inner radius, r = 0.7 m

outer radius, R = 1.3 m

The magnetic field due to a circular coil is given by

[tex]B = \frac{\mu o}{4\pi}\times \frac{2 N\pi I}{R}[/tex]

(a) The magnetic field due to the inner radius is

[tex]B = 10^{-7}\times \frac{2\times 900\times 3.14\times 14000}{0.7}\\\\B = 11.3 T[/tex]

(b) The magnetic field due to the outer radius is

[tex]B = 10^{-7}\times \frac{2\times 900\times 3.14\times 14000}{1.3}\\\\B = 6.09 T[/tex]

what is efficiency of a machine?

Answers

Mechanical efficiency is a measure of how well the machine converts the input work or energy into some useful output. It is calculated by dividing the output work by the input work. The ideal machine has mechanical efficiency equal to unity, while the real machine has mechanical efficiency less than unity

Answer:

Efficiency of a machine is defined as the ratio of output work to input work in a machine . It is expressed in percentage and denoted by

η ( eta).

which type of place is rich in biodiversity?​

Answers

Explanation:

hey

the answer is Brazil

hope it helps ✌

If a fan draws 220 watts on a 120- volt circuit what is the current being drawn?
22. amperes
O 5.2 amperes
O 1.8 ampmes
15. amperes

Answers

Explanation:

here's the answer to your question


State one effect of increase in heat for a temperature range of 50°C to 100°C
on Plastic

Answers

Answer:

why is fraction called a necessary evil

The heat for a temperature in plastic increases at the range of 50°C to 100°C then the plastic decreases its stiffness or flexural modulus.

It is given that the temperature is increased from 50°C to 100°C that means temperature is increasing.

It is required to state the effect of increase in heat on plastic.

What will be the effect of increase in heat for a temperature range of 50°C to 100°C on Plastic?

The plastic starts to lose its stiffness or we say that it converts into a softened material as long as we increase the temperature of the material.

So if we increase the temperature too much or exceed above the limit of temperature range then it will distort.

Also there are many qualities that can be affected by increasing the temperature like mechanical property, material fatigue or chemical phenomenon.

Therefore, the heat for a temperature range of 50°C to 100°C

Plastic increases then the plastic decreases its stiffness or flexural modulus.

Learn more about the range of temperature here:

https://brainly.com/question/11316625

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Difference between gravitational force and frictional​

Answers

Explanation:

gravitational force or gravity is the force of attraction between objects that have mass.

frictional force is the forec that opposes motion (movement) when two surface are in contact. (acts in the opposite direction of motion)

so to sum it up,

- gravtional force is the force of attraction between objects that have mass.

- objects on the earth have weight because of gravitational force between them and the earth.

frictional force

- oppose motion

- slow down and stop moving objects and;

- produce heat

hope it helps :)

Answer: the difference is that they are 2 completely separate things

find the expression for pressure exerted by fluid with proper description​

Answers

Answer:   Let us calculate the pressure exerted on the bottom by the weight of the fluid. That pressure is the weight of the fluid mg divided by the area A supporting it (the area of the bottom of the container): P=mgA P = m g A .

Explanation:

state the formula for period of sham in terms of acceleration and displacement ​

Answers

Answer:

Finding time period of SHM from equation of displacement

Explanation:

0

Say for example I've got the equation of a SHM as:

x=Acos(ωt+ϕ)

where A is the amplitude.

How do I find the time period of this motion?

I tried by finding the second order differential of the given equation.

a=d2xdt2=−Aω2cos(ωt+ϕ)

Comparing it with the general equation for acceleration a=−ω2x, we can find ω from here.

But that is where the problem is coming. It makes no sense if I write ω=ωA−−√.

What is the correct method to find the time period of the SHM? What am I missing?

There is a very simple mistake in your math. Notice A is part of x, it is factored so you'll get to ω=ω again. If you want to find a meaning to ωT=2π, consider the fact that cos (or sin) are periodic functions with period 2π. Hence, every time you have a time difference such that ω(t1−t2)=2π you are back at the same point. Hence the period is given by ωT=2π.

y’all know what to do… please help

Answers

Answer:

A. It increased gradually as the reaction progressed.

Answer: A it increased gradually

as the reaction progressed

If the half-life of a decaying isotope is 10 years, which statement is true after
10 years?

Answers

Answer:

no is the most expensive but u have

John walked a distance of 900 meters in 10 minutes what was his average speed in kilomerters per hour

Answers

Answer:

5.4

Explanation:

900/10=90 and 90(60)=5400 meters. 5400/100=5.4

Describe the term of inertia with the respect of motion

Answers

Answer:

Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.

Explanation:

Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point.

This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.

Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.

Newton's First Law of Motion is also known as Law of Inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.

The inertia of an object such as a truck is greatly dependent or influenced by its mass; the higher quantity of matter in a trailer, the greater will be its tendency to continuously remain at rest.

In conclusion, inertia is applicable to all physical objects.

The pressure at the ice point for a constant-volume gas thermometer is 4.81 x 10^4Pa.
While that at the steam point is 6.48 x 10^4 Pa.
What pressure would the thermometer indicate at 50°c?

Answers

Answer:

0 deg C = 4.81E4     pressure at 0 deg

100 deg C = 6.48E4     pressure at steam point

100 deg C - 50 deg C = (6.48 - 4.81) * 10^4 = 1.67E4 Pa

50 deg C = 50 / 100 * 1.67E4 + 4.81E4 = 5.65E4 Pa Just the halfway point between the two given pressures

Which court would you go to if you wanted to declare bankruptcy?
A.
Civil court
B.
U.S. Court of Appeals
C.
Supreme Court
D.
U.S. District Court

Answers

Answer:

A. Cilvil court.........

Civil court  would you go to if you wanted to declare bankruptcy. The correct option is A.

Thus, According to the United States Bankruptcy Code, bankruptcy proceedings are typically filed in a federal bankruptcy court.

The federal court system includes these courts, which deal with Chapter 7, Chapter 11, and Chapter 13 bankruptcy cases.

The additional alternatives (U.S. Court of Appeals, Supreme Court, and U.S. District Court) are not the main courts where bankruptcy cases are generally filed.

Thus, Civil court  would you go to if you wanted to declare bankruptcy. The correct option is A.

Learn more about Civil court, refer to the link:

https://brainly.com/question/29614273

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The distance a cart moves down a track (from rest) is proportional to the time squared. How far would a cart move down a track (from rest) in two seconds if it moves (from rest) a distance of 20 cm in one second?

A) 5 cm B) 10 cm C) 20 cm D) 40 cm E) 80 cm

Answers

A car move down a track a distance of 80 cm

Letter E  80 cm

Proportional

if the distance is proportional to the time square we can express such condition writing

d = k*t²        (1)

where d is the distance t is the time and k is the constant of proportionality.

Now we must considerer that if the cart moves a distance of 20 cm in one second then by substitution in equation (1)

20 = k * (t)²        ⇒     20 = k*1   then   k = 20

The proportionality constant is K = 20

To determine how far the cart move down in 2 seconds, again by substitution in equation (1) ( but now knowing k )

d = 20*(2)²

d = 20*4

d = 80 cm

a load of 800 newton is lifted by an effort of 200 Newton. if the load is placed at a distance of 10 cm from the fulcrum. what will be the effort distance ?​

Answers

Answer:

40 cm

Explanation:

We are given that

Load=800 N

Effort=200 N

Load  distance=10 cm

We have to find the effort distance.

We know that

[tex]load\times load\;distance=Effort\times effort\;distance[/tex]

Using the formula

[tex]800\times 10=200\times effort\;distance[/tex]

Effort distance=[tex]\frac{800\times 10}{200}[/tex]

Effort distance=[tex]\frac{8000}{200}[/tex]

Effort distance=40 cm

Hence,  the effort distance will be 40 cm.

An iron weight, suspended by a string, is motionless. The tension
in the string is 4.75 newtons. What is the mass of the iron
weight?

Answers

Answer:

Explanation:

If the mass hangs at the end of the string and the string can support the mass and doesn't break, and the mass hangs still, that means that the tension in the string is equal to the downward pull of the mass. However, we are given the tension in Newtons and the mass needs to be in kg. So we use the equation for weight:

w = mg where w, the weight, is the same as the tension in the string. Gravity is always 9.8 in the metric system:

4.75 = m(9.8) so

m = .48 kg

Answer:

Answer: A

0.485 Kg

Explanation:

the unit of force and pressure are called derived unit​

Answers

Answer:

yes

Explanation:

because they can be derived in the form of base units

explain how force and surface area affect the applied pressure.​

Answers

Answer:

force and surface area are two factors affecting pressure on solids

more the force you apply, more will be the pressure

pressure and force are directly proportional meaning if Force is greater, pressure will also be greater

more the surface area of the solid less will be the pressure

surface area and pressure are inversely proportional meaning if surface are is big, pressure will be less, surface area small, pressure will be greater

Answer and Explanation:

We have a basic equation: Pressure = Force/Area.

So for example:

Increase pressure - increase the force or reduce the area the force acts on.

Decrease pressure - decrease the force, or increase the area the force acts on

The force per unit area is pressure. The force on the object is spread over the surface area. The area where the force is applied is divided by the equation for pressure.

Cheers,

A person carries a box of 100 kg. What is the weight of the box? (g= 9.8 m/s2)​

Answers

Answer:

980 newton

Explanation:

100×9.8 = 980

at what angle should the circular road be banked so that a car running at 50 km per hour be safe to go round the circular from of 200m radius​

Answers

Answer:

Mark brainliest please

answer is 5.5 degrees

Explanation:

Given,

Speed of car (v) = 50km/hr = 50×1000/60×60 m/s

Radius of circle (r) = 200m

Banking angle (θ) =?

we know ,

tanθ = v^2/rg

or , tanθ = (50×1000/60×60)^2/200×10 = 0.0965

∴ θ = tan-1(0.0965) = 5.5°

For Gerald the Human Cannonball, the gunpowder transforms and gives Gerald what type of energy?

Answers

Explanation:

The explosives changes Gerald the Human Cannonball and provides him with chemical energy.

Sulfur and carbon serve as fuels, whereas saltpetre serves as an oxidant. Gunpowder has long been employed as a propellant in weapons, artillery, rocketry, and fireworks, as well as a blasting ingredient in quarrying, mine, and road construction.

Question 12 of 19 Lions can run at speeds up to approximately 80.0 km/h. A hungry 109 kg lion running northward at top speed attacks and holds onto a 36.0 kg Thomson's gazelle running eastward at 78.0 km/h. Find the final speed vf of the lion‑gazelle system just after the lion attacks.

Answers

Answer:

The final velocity of the lion-gazelle system is approximately 62.321 kilometers per hour.

Explanation:

Let suppose that both lion and the Thomson's gazelle collide each other inelastically, the use of the Principle of Linear Momentum Conservation suffices to describe the entire phenomenon:

[tex]m_{L}\cdot \vec v_{L} + m_{T}\cdot \vec v_{T} = (m_{L}+m_{T})\cdot \vec v[/tex] (1)

Where:

[tex]m_{L}[/tex] - Mass of the lion, in kilograms.

[tex]m_{T}[/tex] - Mass of the Thomson's gazelle, in kilograms.

[tex]\vec v_{L}[/tex] - Initial velocity of the lion, in meters per second.

[tex]\vec v_{T}[/tex] - Initial velocity of the Thomson's gazelle, in meters per second.

[tex]\vec v[/tex] - Final velocity of the lion-gazelle system, in meters per second.

Let suppose that both northward velocity and eastward velocity are positive.

If we know that [tex]m_{L} = 109\,kg[/tex], [tex]\vec v_{L} = (0, 22.222)\left[\frac{m}{s} \right][/tex], [tex]m_{T} = 36\,kg[/tex] and [tex]\vec v_{T} = (21.667, 0)\,\left[\frac{m}{s} \right][/tex], then the final velocity of the lion-gazelle system is:

[tex]109\cdot (0,22.222)+36\cdot (21.667,0) = 147\cdot (v_{x},v_{y})[/tex]

[tex](v_{x}, v_{y}) = (0, 16.478) + (5.306, 0) \,\left[\frac{m}{s} \right][/tex]

[tex](v_{x}, v_{y}) = (5.306, 16.478)\,\left[\frac{m}{s} \right][/tex]

[tex](v_{x}, v_{y}) = (19.102, 59.321)\,\left[\frac{km}{h} \right][/tex]

And the final speed of the lion-gazelle system is calculated by the Pythagorean Theorem:

[tex]v = \sqrt{19.102^{2}+59.321^{2}}\,\left[\frac{km}{h} \right][/tex]

[tex]v \approx 62.321\,\frac{km}{h}[/tex]

The final velocity of the lion-gazelle system is approximately 62.321 kilometers per hour.

can anyone please help me​

Answers

Answer:its most likely c

Explanation:

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