Answers
Hi there!
We can use the angular equivalent of the following kinematic equation:
[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta[/tex]
ωf = final angular velocity (1.9 rad/s)
ωi = initial angular velocity (11.3 rad/s)
α = angular acceleration (? rad/s²)
θ = angular displacement (17.95 rad)
We can rearrange the equation to solve for angular acceleration.
[tex]\omega_f^2 - \omega_i^2 = 2\alpha \theta\\\\\alpha = \frac{\omega_f^2 - \omega_i^2}{2\theta}[/tex]
Plug in the given values and solve.
[tex]\alpha = \frac{1.9^2 - 11.3^2}{2(17.95)} = \boxed{3.456 \frac{rad}{s}}[/tex]
Related Questions
A 0.5 kg turntable with a radius of 15 cm is rotating 78 times per minute.
A. What is the angular momentum of the turntable?
B. A 100 gram bar which is as long as the diameter of the turntable is dropped on the
turntable such that the bar is rotating about its center. What is the new angular velocity of the turntable-bar system?
C. In order to stop the turntable and bar in just one rotation, how much force must be applied to the edge of the turntable (assuming the force is applied perpendicular to the radius)?
Answers
Answer:
c
Explanation:
A ball is thrown directly upwards at 25 ms and the same time another ball is released from height of loom. At what height and time will the balls meets?
Answers
Answer:
Explanation:
When the balls meets, the time should be the same, let say t.
For the first ball (released from a loom):
[tex]\bar{h}=\frac{1}{2}gt^{2}[/tex] (Free fall motion) ([tex]\bar{h}[/tex] = the distance travelled by the first ball, measured from the loom)
So, we can find that [tex]\bar{h}=\frac{1}{2}(10t^{2})=5t^{2}[/tex]
For the second ball (which is thrown directly upwards):
[tex]y=v_{o}t-\frac{1}{2}gt^{2} = 25t-5t^{2}[/tex]
Because the height of the loom is h :
[tex]h=\bar{h}+y[/tex]
[tex]h=25t[/tex]
So, the time when two balls meets is : [tex]t=\frac{h}{5}[/tex] (In this question, the height of the loom h is not declared). When the height of the loom is known, you can calculate the time and the value of [tex]\bar{h}[/tex] or y
Vector approach in solving forces in 3d
Answers
Answer:
[tex] \red{ \rule{1pt}{500000pt}}[/tex] [tex] \red{ \rule{1pt}{500000pt}}[/tex]
Explanation:
What do radio waves, microwaves, light, and X-rays have in common
Answers
Answer:
They are all electromagnetic waves, electric and magnetic fields that oscillate together, perpendicular to each other
Kinetic is calculated using ___
Answers
Answer:
Ek= 1/2*m*v^2
Explanation:
kinetic energy= 1/2* mass * square velocity
An aircraft starts at rest and is accelerated for 9.2 seconds, at which time the aircraft launches. If the distance traveled from the starting point to the launch point was 428.8 m, what was the launch velocity of the aircraft in m/s? Assume the acceleration is constant. (Hint: multi-step problem).
Answers
Explanation:
Since the acceleration is constant, we use the big four equations.
[tex]x = x _{i} + vt[/tex]
[tex]x = \frac{1}{2} a {t}^{2} + v _{i}t + x _{i}[/tex]
[tex]v {}^{2} = (v _{i}) {}^{2} + 2a(x - x _{i})[/tex]
[tex] \frac{1}{2} (v + v _{i})t = x - x _{i}[/tex]
Next. identity the variables.
We know
t=9.2
change in position or (x- x_i) is 428.8
Initial Velocity is 0.
We need to solve for the final velocity, so we use the fourth equation.
[tex] \frac{1}{2} (v - v _{i})t = x - x _{i}[/tex]
Subsitue
[tex] \frac{1}{2} (v - 0)(9.2) = 428.8[/tex]
[tex] \frac{1}{2} (v)9.2 = 428.8[/tex]
[tex]v = 93.22 \frac{m}{s} [/tex]
The Earth's history is shaped by different geological processes over a wide range of space and time.
For example, in the late 1900s, a crater was discovered near the town of Wetumpka, Alabama. Scientists found shocked quartz in the core samples collected from the crater. Shocked quartz occurs as a result of intense metamorphism (change in the structure of rocks).
Which of the following geological processes is most likely responsible for the formation of the crater?
A. erosion by water
B. tectonic plate movement
C. volcanic eruption
D. meteor impact
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meteor impact this ecological processes is most likely responsible for the formation of the crater. Hence option D is correct.
What is meteor impact ?A collision between celestial objects that has quantifiable effects is called an impact event. The most frequent impact events involve asteroids, comets, or meteoroids and have little impact. However, impact events have been shown to occur often in planetary systems and have physical repercussions. However, many surface impacts are reduced by atmospheres through atmospheric entry when massive objects strike terrestrial planets like the Earth. Nonetheless, there may be major physical and biospheric effects. The majority of the solid objects in the Solar System are covered with impact craters and structures, which provide the best empirical evidence for their frequency and size. Since the birth of the Solar System, impact events appear to have had a substantial impact on how the Solar System has changed. Significant impact events have impacted Earth's history and have been linked
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A Rich has been hooked and is puilling on the line as shown in the figure below.
RO
18
If the pole makes an angle of 25° with the horizontal, the distance between the point where the line is attached to the pole and the anglers hand is L. 2.45 m, and the fish
pulls on the line such that the tension in the line is T-166 Nat an angle 35.0 below the horizontal, determine the magnitude (in N.m) of the torque exerted by the fish
about an axis perpendicular to the page and passing through the angler's hand.
Nm
Answers
For the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand is mathematically given as
Z = 360.33Nm
What is the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand?
Generally, the equation for the Torque is mathematically given as
Z = force x perpendicular distance
Z = Tcos30° x L
Z = 166(0.886) x 2.45
Z = 360.33Nm
In conclusion s the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand
Z = 360.33Nm
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an airplane whose speed is 60 m/s is flying at an altitude of 500 m over the ocean toward a stationary sinking ship. at what horizontal distance from the ship should the crew of the airplane drop a pump into the water next to the ship
Answers
For an airplane whose speed is 60 m/s is flying at an altitude of 500 m over the ocean toward a stationary sinking ship, the horizontal distance is mathematically given as
x=606m
What horizontal distance from the ship should the crew of the airplane drop a pump into the water next to the ship?Generally, the equation for the y axis distance is mathematically given as
y=vt+0.5gt^2
Therefore
500=0t+1.2(9.8)t^2
t=10.1s
In conclusion, the horizontal distance
x=vt
x=60*10.1
x=606m
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List three methods of energy transport in nature and explain how the energy is being transferred in each of those methods. Which two are means by which energy is transported inside the Sun?
This question is for my college astronomy class!
Answers
First normal transportation is the light energy of sun is transmitted to our earth .
Next for transportation inside sun they are
Fusion and fissionFusion means when two hydrogen atoms reacts to form helium nucleus .
Fission means when one nucleus is broken into two or more nucleus
Explanation:
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I will give brainlisted for the correct answer!
Answers
what are the two most important traits between a whale and a shark?
Answers
Answer:
Both are aquatic animals and are hunters
Explanation:
A Cadillac Escalade has a mass of 2,569.6 kg, if it accelerates at 4.65 m/s^2 what is the net force of the car?
Answers
Answer:
11948.64 Newtons
Explanation:
__________________ 1. Adobe Photoshop is the current market leader for commercial bitmap and image. __________________ 2. The image is the space provided for your picture. __________________ 3. The drawing tools allow you to modify the image with different tools and achieve the desired effect of your image. __________________ 4. In Photoshop, images are pixel-based. __________________ 5. Create a new layer by clicking on the Create New Layer icon. A new layer will be created below the active layer.
Answers
Answer:
Cheswick and apples cheessticks
A stone of mass 5g is projected with a rubber catapult. if the catapult is stretched through a distance of 7cm by an average force of 70 North, calculate the instantaneous velocity of the stone when released
Answers
Explanation:
solution: mass m = 5g = 0.005kg; extension e = 7cm = 0.07m; force f = 70 N; velocity = ?; using: work done in elastic material w = 1/2 fe = 1/2 ke2 = 1/2 mv2 - the kinetic energy of the moving stone. 1/2 fe =...
if a copper coin with a volume of exactly 50 cubic cm is dropped into the volume of water 4cubic cm,how much water will be overflown (water is half way of the can)
Answers
Answer:
50 cubic cm
Explanation:
As the water displaces 50 cubic centimeters the amount of water that must leave the container for it to be able to be dropped into it is also 50 cubic as the water which was in its place must have gone somewhere.
Which has more momentum, a 5000 kg truck moving at 20 km per hour or a 1000 kg truck moving at 50 km per hour?
Answers
Answer:
First truck has greater momnetum
Explanation:
momentum = m * v
truck a 5000 * 20 = 10 0000
truck b 1000 * 50 = 5 0000
The power in an electrical current is given by the equation
Answers
Answer:
P = VI
Explanation:
the power is equal to the current × voltage
Answer:
P = V • I
Explanation:
Power = Voltage • Current
1. Zahra oscillates a swing and makes 100 complete cycles in 20 seconds. Find: a. Period (
Answers
Answer:
Explanation:
Period is : [tex]T=\frac{t}{n}=\frac{20}{100}=0.2[/tex] s
A baseball is thrown a distance of 60 meters. What is it’s speed if it takes 1.5 seconds to cover the distance
Answers
Answer:
V = S / d = 60 m / 1.5 sec = 40 m/s
Note 40 m/s = 40 * 3.28 = 131 ft/sec
131 ft/sec = 131 ft/sec / (88 ft/sec / 60 mph) = 89 mi/hr
What should you do with electrical cells and batteries that no longer work
Answers
Answer:
Yes, single-use batteries are now made of common metals deemed non-hazardous by the federal government and can be disposed of in your regular trash in all states except California, where it is illegal to throw away all types of batteries.
A kitten sits in a lightweight basket near the edge
Answers
Answer:
So where's the problem now?
A kitten is just sitting
What is the difference between magnitude of displacement and magnitude of velocity
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(b) Magnitude of average velocity over an interval of time, and the average speed over the same interval. [Average speed of a particle over an interval of time is defined as the total path length divided by the time interval].
2. How long would it take a car to reach 50 m/s if they accelerated at a constant rate of 5.44
m/s?? Assume the car begins at rest.
Answers
9.19 seconds (2dp)
Given:
v = 50m/s
u = 0 m/s
a = 5.44 m/s
t = ?
Substitute values into the equation v = u + at
v = u + at
50 = 0 + 5.44 x t
t = 50/5.44
t = 9.19 seconds
Time is in seconds as the velocity and acceleration are in metres per second instead of kilometres per hour
Which graphs show the correct relationship between kinetic energy and mass?
ОА
у
kinetic energy
mass
ОВ.
yt
kinetic energy
X
mass
rights reserved.
Answers
Option "C" is your answer!
The kinetic energy of the object depends on its mass and velocity
The graph of the straight line shown in option C is the correct representation of the relationship between mass and KE of the object.
What is kinetic energy?
The kinetic energy of an object is the energy that an object or a particle has by reason of its motion. Kinetic energy is a property of a moving object or particle and depends not only on its motion but also on its mass.
The kinetic energy of an object is given by the expression.
[tex]KE = \frac{1}{2} {mv}^{2} [/tex]
Where KE is the kinetic energy, m is the mass and v is the velocity of the object.
The above expression of the kinetic energy shows that it is directly proportional to the mass of the object.
KE x m
If we show this relation of mass and KE on a graph, then it would be a straight line showing the direct proportionality between mass and KE of the object.
Hence we can conclude that the graph of the straight line shown in option C is the correct representation of the relationship between mass and KE of the object.
Definition law of moments
Answers
When an object is balanced (in equilibrium) the sum of the clockwise moments is equal to the sum of the anticlockwise moments.
By what percent is the torque of a motor decreased if its permanent magnets lose 6.5 % of their strength
Answers
If the period of oscillation of a simple pendulum is 4s, find its length. If the velocity of the bob
at the mean position is 40cms−1
, find its amplitude. (take gravity = 9.81ms−2
Answers
Answer:
Explanation:
Because we assume the pendulum is a "mathematical pendulum" (neglecting the moment of inertia of the bob), we can find:
[tex]T=2\pi\sqrt{\frac{L}{g}} \rightarrow 4=2\pi\sqrt{\frac{L}{9.81}} \rightarrow \frac{4}{\pi^{2}}=\frac{L}{9.81} \rightarrow L \approx 3.97 m[/tex]
By using the [tex]y=A\sin(\omega t) \rightarrow v = \frac{dy}{dt}=\omega A \cos\omega t = \omega\sqrt{A^{2}-y^{2}}[/tex]
The mean position is the position when y = 0, so:
[tex]\omega = \frac{2\pi}{T}=\frac{2\pi}{4}=0.5\pi[/tex] rad/s
and [tex]v = \omega A \rightarrow A=\frac{40}{0.5\pi}=\frac{80}{\pi}[/tex] in centimeters (cm).
Calculate the speed of sound in a string that has a tension of 100 N and a linear mass density of 0.0001 kg/m
Answers
Two pendula are shown in the figure. Each consists of a solid ball with uniform density and has a mass M. They are each suspended from the ceiling with massless rod as shown in the figure. The ball on the left pendulum is very small. The ball of the right pendulum has radius 1/2 L.
Find the period T of the right pendulum for small displacements in s.
Answers
The period (T) of the right pendulum for small displacements in s is equal to 1.49 seconds.
How to calculate the period (T).Mathematically, the time taken by this pendulum to undergo a small displacement is given by this formula:
[tex]T=2\pi \sqrt{\frac{L}{g} }[/tex]
Where:
L is the length.g is the acceleration due to gravity.Scientific data:
Acceleration due to gravity (g) = 9.8 m/s².
Assuming a randomized variable for the length of the rope to be 1.2 meter. Also, we know that the right pendulum has a radius of 1/2L.
1/2L = L/2
L/2 = 1.1/2
L/2 = 0.55 meter.
Substituting the parameters into the formula, we have;
[tex]T=2\times 3.142 \sqrt{\frac{0.55}{9.8} }\\\\T=6.284 \times \sqrt{0.0561} \\\\T=6.284 \times 0.2369[/tex]
T = 1.49 seconds.
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