The magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.
What is force?The force is an action of push or pull which makes a body to move or stop.
Given is the weight of tourist W = 805 N and L is the length of the bridge.
Let the reaction force at both the ends of the bridge is R1 and R2.
Taking the moments about point A,
R1 x 0 - W x L/4 +R2 x L =0
R2 = W/4
R2 = 805 /4
R2 = 201.25 N
Thus, the magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.
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Consider an object of mass 2kg at rest on a ramp with βs=0.5 and βk=0.4.
If the ramp angle is 60 degrees, how far can the object travel in the first 1 seconds?
The distance traveled by the object in the first 1 second is determined as 0.98 m.
Distance traveled by the objectThe distance traveled by the object is calculated as follows;
F - μkmgcosθ = ma
0 - μkmgcosθ = ma
- μkgcosθ = a
-(0.4)(9.8)cos60 = a
- 1.96 m/s² = a
s = ut + ¹/₂at²
s = 0(1) + ¹/₂(-1.96)(1)²
s = -0.98 m
|s| = 0.98 m
Thus, the distance traveled by the object in the first 1 second is determined as 0.98 m.
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When the ultrasound beam strikes the surface at or nearly at right angles, the fraction of sound energy that is reflected (R) at the interface between two materials of acoustic impedance Z1 and Z2, respectively, is given by:
Explanation:
the expression of x= -4t+2t^2 where x is displecement?If an object is moving with a constant velocity of 700 cm/s and starts at an initial position of 20 cm at t=0, what will be the position at t= 0.9 s?
Which of the following can refer to the form of exercise that uses free weights, weight machines, resistance bands, or the weight of the body to put stress on the muscles? A. Strength training B. Weight training C. Resistance training D. All of the above
Answer:
option C...
resistance training is the correct answer
What controls how fast an object falls?
Answer:
gravity
Explanation:
as the earth rotates on an axis, it causes an effect known as centripetal acceleration with is an acceleration that pulls objects towards the center of the object. in planets, we call this Gravity
Answer:
See below
Explanation:
The initial downward velocity, the acceleration of gravity and air friction all play a part
Dodgems A has a mass of 120 kg, is initially moving to the right at a speed of 10 m/s. It collides with Dodgems B, which has a mass of 160 kg, moving to the right at a speed of 7 m/s. After collision, Dodgems A continues to move to the right but with a speed of 5 m/s. What is the speed of Dodgems B after collision?
Answer:
10.75 m/s
Explanation:
let velocity of Dodgems b be y
law of conservation of momentum
120 x 10 + 160 x 7=120x5+ 160 x y
1200+1120 = 600 + 160 x y
160y = 1720
y = 10.75 m/s
A helium balloon has a pressure of 40 psi at 20°C. What will the pressure be at 40°C? Assume constant volume and mass.
Answer:
P V = N R T ideal gas equation
P2 / P1 = T2 / T1 where the other variables are constant
P2 = (T2 / T1) * P1 = (313 / 293) * 40 psi = 42.7 psi
An increase in voltage results in
If the current is held constant, an increase in voltage will result in an increase in resistance.
hope it helps...!!!
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Explanation:
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A student repeats a reaction several times to test the effects of various
changes on the reaction rate. The data table shows the results. How does
increasing the temperature of the system change thereaction rate?
A. Increasing the temperature decreases the reaction rate.
B. Increasing the temperature increases the reaction rate.
C. More information is needed to determine what happens to the reaction rate.
D. Increasing the temperature has no effect on the reaction rate.
Answer:
The correct answer is - C. Increasing the concentration increases the reaction rate.
Explanation:
Answer:
B. Increasing the temperature increases the reaction rate.
Explanation:
The reaction time column displays how long the reaction ran for. If a reaction rate was fast then time taken for reaction to run would be slow right?
Therefore, original condition had reaction time of 10 second, but increaseing temperature lowered the time to 5 second, which must mean that reaction rate increased.
A body with an initial velocity of 4m/s accelerates uniformly at the rate of 1.2 m/s² over a distance of 20 m. Calculate: (i) the final velocity of the body.(ii) the time in which the body covers that distance. (iii) the average velocity of the body during the journey
v² = u² + 2as
v² = 4² + 2 × 1.2 × 20
v² = 16 + 2 × 12/10 × 20
v² = 16 + 48
v² = 64
v = 8 ms - 1
So,the final velocity is 8 m/sii)
V = u + at
8 = 4 + 1.2 × t
8 - 4 = 1.2t
4 = 12/10 t
4 × 10 /12 = t
3.33 = t
So,the time is 3.33 secondsiii)Average velocity = Displacement/Time
20/3.33
6.006 ms - 1
So,the average velocity is 6.006 m/sWhich of the following is a characteristic of a balanced force?
1) equal in size opposite in direction
2) causes a change in the direction of an object
3) causes a change in the motion of an object
An object moving at 15 m/s slows uniformly at a rate of 2.0 m/s each second for 5.0 s. What is its final speed?
What does the term conservation mean?
A. The process of changing used materials into new products
B. The process of removing pollution from a natural resource
C. Consistent overuse of renewable resources
D. The protection and careful use of natural resources
==============================
[tex] \large \sf \underline{Question:}[/tex]
What does the term conservation mean?==============================
[tex] \large \sf \underline{Answer:}[/tex]
[tex] \qquad \qquad \huge \bold{Option \: D}[/tex]
==============================
[tex] \large \sf \underline{Explanation:}[/tex]
From the term or word itself "Conservation" or in other words conserve, it directly means the protection and careful use of natural resources.==============================
,a circular loop carrying a current of 40A produce a field of 3*10^8 T at the center what should be the current in the straight conductor so that it produce the same field at a distance equal to the radius if the loop ?
Hi there!
We can begin by deriving the magnetic field strength for a circular loop at its center.
Using Biot-Savart's Law:
[tex]dB = \frac{\mu_0}{4\pi }\frac{idl \times \^r}{r^2}[/tex]
μ₀ = Permeability of free space (Tm/A)
dl = Differential length element
r = radius (m)
We can rather use 'ds' to represent a differential arc length since we are finding the magnetic field for a circular loop.
We must begin by dealing with the cross-product. Luckily, this derivation is simple since the radius vector is ALWAYS perpendicular to the path of integration along the loop's circumference. (ONLY if we are finding the field for the direct center.) Thus, since sin(90) = 1, we can get rid of the cross-product.
Therefore:
[tex]dB = \frac{\mu_0}{4\pi }\frac{ids}{r^2}[/tex]
Now, we can integrate with respect to ds.
[tex]= \frac{\mu_0}{4\pi }\int\limits^{2\pi r}_0 {\frac{i}{r^2}} \, ds\\\\ = \frac{\mu_0}{4\pi }{\frac{i * 2\pi r}{r^2}} \, ds[/tex]
Simplify:
[tex]B = \frac{\mu_0 i_{circle}}{2r}\\[/tex]
Now, for a straight conductor (assuming of infinite length), we know the magnetic field strength equation to be:
[tex]B = \frac{\mu_0 i_{rod}}{2\pi r}[/tex]
Set the two equal.
[tex]\frac{\mu_0 i_{circle}}{2r}= \frac{\mu_0 i_{rod}}{2\pi r}[/tex]
Cancel out '2', μ₀, and 'r':
[tex]i_{circle}}= \frac{ i_{rod}}{\pi }[/tex]
Plug in the given values and solve.
[tex]40\pi = i_{rod}\\\\i_{rod} = \boxed{125.663 A}[/tex]
Anujan and Piragavy are pulling on either side of a box with ropes. Anujan rope pulls with a force of 35 N [35° N of W], while Piragavy pulls with a force of 11 N [41° S of E]. There is a frictional force of 6 N [s] opposing the motion. Calculate the following: The Fnet and the acceleration of the object.
The net force on the block is 20.678 N. Force is defined as the product of mass and acceleration. Its unit is Newton.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
Anujan rope pulls with a force of 35 N [35° N of W]. The force is resolved in x and y direction as;
[tex]\rm F_{1x}= 35 cos 35^0 \\\\ F_{1y}=35 sin 35^0[/tex]
Piragavy pulls with a force of 11 N [41° S of E]. The force is resolved in x and y direction as;
[tex]\rm F_{2x}= 11 cos 41^0 \\\\ F_{2y}=11 sin 41^0[/tex]
The net force on the block is;
[tex]\rm F_{net}=F_{1x}-F_{2x}\\\\\ F_{net}=35 \ cos 35^0- 11 \cos 41^0 \\\\ F_{net}=20.678 \ N[/tex]
Hence,the net force on the block is 20.678 N.
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A metallic axle with a diameter of 20mm has to be fitted into a wheel which has a circular hole at its center with diameter of 18.5mm
The coefficient of linear expansion of the metal at the given length is determined as 3.75 x 10⁻⁴/⁰C.
Coefficient of linear expansion of the metalThe coeffcient of linear expansion of the metal is calculated as follows;
ΔL = αLΔT
α = ΔL/LΔT
Where;
α is the coefficient of linear expansionΔL is change in length = 20 mm - 18.5 mm = 1.5 mmΔT is change in temperature = 0 - (-200) = 200°CL is the original length = 20 mmα = (1.5)/(20 x 200)
α = 3.75 x 10⁻⁴/⁰C
The complete question is below:
A metallic axle with a diameter of 20mm has to be fitted into a wheel which has a circular hole at its center with diameter of 18.5mm. To fit the axle into the hole, the axle is dipped into liquid nitrogen at a temperature of -200°C. Calculate the coefficient of linear expansion of the metal.
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A simple pendulum has length of 820mm. Calculate the frequency (g = 9.8 ms -2)
Answer:
[tex]\huge\boxed{\sf f=0.55 \ Hz}[/tex]
Explanation:
Given Data:
Length = l = 820 mm = 0.82 m
Acceleration due to gravity = g = 9.8 ms⁻²
Required:
Frequency = f = ?
Formula:
[tex]\displaystyle f =\frac{1}{2 \pi} \sqrt{\frac{g}{l} }[/tex]
Solution:
[tex]\displaystyle f =\frac{1}{2 \pi} \sqrt{\frac{g}{l} } \\\\Put\ the\ givens\\\\f=\frac{1}{2 \pi} \sqrt{\frac{9.8}{0.82} }\\\\ f = 0.159 \times \sqrt{11.95} \\\\f=0.159 \times 3.457\\\\f=0.55 \ Hz\\\\\rule[225]{225}{2}[/tex]
Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10^-6 C, q2 = +2.50 x 10^-6 C, and q3 = -2.50 x 10^-6 C. Particles q1 and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m. What is the net force on q2
When q₂ is place between q₁ and q₃, the net force on q₂ is 0.486N.
What is the electrostatic force?The electrostatic force of attraction or repulsion is proportional to the product of magnitude of charges and inversely proportional to the square of distance between them.
Force on q₂ due to q₁
F₁₂ = kq₁q₂ / r₁₂²
Substitute the values provided , we get
F₁₂ = 9 x 10⁹ x 5 x 10⁻⁶ x 2.5 x 10⁻⁶ / (0.5)²
F₁₂ = 0.414 N
Force on q₂ due to q₃ placed at distance 0.25m
F₂₃ =kq₂q₃ / r₂₃²
Substitute the values, we get
F₂₃ = 9 x 10⁹ x 2.5 x 10⁻⁶ x 2.5 x 10⁻⁶ / (0.25)²
F₂₃ = 0.9N
The net force F =F₂₃ -F₁₂
F =0.9 - 0.414 = 0.486 N
Thus, the net force of q₂ is 0.486 N.
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Answer:
0.45
Explanation:
trust me
a 90 N force is applied to a 65 kg mass. the mass will accelerate at
F=m.a
a = F/m
a = 90/65
a = 1.385 m/s²
Answer:
solution
here,
Explanation:
weight = 90N
mass=65kg
acceleration due to gravity (g)=??
Now,
w=m×g
90=65×g
90/65=g
:g=1.38m/s^2
If an amount of heat Q is needed to increase the temperature of a solid metal sphere of diameter D from 4°C to 7°C, the amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C is
Answer:
Q = c M ΔT where c is the heat capacity and M the mass present
Q2 / Q1 = M2 / M1 since the other factors are the same
M = ρ V where ρ is the density
M = ρ Π (d / 2)^2 where d is the diameter of the sphere
M2 / M1 = (2 D/2)^2 / (D/2)^2 = 4
It will take 4Q heat to heat the second sphere
How does the force of gravity relate to size?
Answer:
Gravitational force is an attraction between masses. The greater the size of the masses, the greater the size of the gravitational force (also called the gravity force). The gravitational force weakens rapidly with increasing distance between masses
A reversible reaction is in
_______ when forward and reverse
directions of the reaction occur at the same rate so there is no overall change in the
amounts of reactants and products.
Answer:
Equilibrium
Explanation:
Equilibrium is a special situation or stage of a reactionAt equilibrium the concentrations of reactants and products are equalThe rate of change of forward and backward reaction is also same• Kelley and Raul are moving a 95 kg desk to the right. If the coefficient of friction between the desk and the floor is 0.29, what is the force of friction that will oppose the motion of the desk?
f = μk.N (N = m.g)
f = 0.29 x 95 x 10
f = 275.5 N
Explain the mechanism of hearing
Explanation:
The pinna collects the sound waves and conducts them to the auditory canal. Sound waves struck at the ear drum and set it into vibration. Eustachian tube equalizes the pressure on either side of the ear drum and thus allows it to vibrate freely. Ear drum transmits the vibrations to ear ossicles.
by observing ___ we can determine what kind of atoms or molecules are present and their relative abundance
The kind of atoms or molecules are present and their relative abundance can be determined by observing wavelengths.
What is wavelength?Wavelength is the distance between adjacent crest or trough of the wave.
The light travels in the form of wave and particle. It behaves like both. Light ray consist energy of the photons. The kind of atoms or molecules present behave like particle and they have particular wavelength.
Thus, by observing wavelength , we can determine the kind of atoms or molecules are present and their relative abundance.
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the diagram aeroplane banking to make a horizontal turn .The aeroplane is travelling at a speed of 75ms-1 and the radius of the turning circle is 800m
The centripetal acceleration of the aeroplane is determined as 7.03 m/s².
Centripetal acceleration of the aeroplaneThe centripetal acceleration of the aeroplane is calculated as follows;
ac = v²/r
where;'
v is the speed of the aeroplaner is the radius of the pathac = (75²)/(800)
ac = 7.03 m/s²
Thus, the centripetal acceleration of the aeroplane is determined as 7.03 m/s².
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3. A female minke whale has a core body temperature of 35°C and a core/blubber interface temperature of 29°C, with an average blubber thickness of 4.0 cm and thermal conductivity of 0.25 W/mK. At what rate is energy lost from the whale's core by conduction from the core/blubber interface through the blubber to the skin? Assume a skin temperature of 12°C and a total body area of 22 m².
The rate at which energy is lost from the whale's core from the core/blubber interface through the blubber to the skin is 3,162.5 W.
Rate of conduction of core/blubber interfaceThe rate of conduction of core/blubber interface is calculated as follows;
[tex]\frac{Q}{t} = \frac{kA\Delta T}{d}[/tex]
where;
k is thermal conductivity = 0.25 W/mkA is the total body area = 22 m²d is thickness of blubber = 4 cm = 0.04 mΔT is change in temperature[tex]\frac{Q}{t} = \frac{kA\Delta T}{d} = \frac{kA}{d} (\Delta Ta \ +\Delta Tb)\\\\\frac{Q}{t} = \frac{kA}{d} ((T_1- T_2 \ +\ T_2-T_3)\\\\\frac{Q}{t} = \frac{0.25 \times 22}{0.04} ( 35 - 29 \ + \ 29 - 12)\\\\\frac{Q}{t} = 137.5( 6 + 17)\\\\\frac{Q}{t} = 3,162.5 \ W[/tex]
Thus, the rate at which energy is lost from the whale's core from the core/blubber interface through the blubber to the skin is 3,162.5 W.
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if earth struck by a small asteroid how will the hours of daylight and night change?
Answer:
Nothing
Explanation:
We get struck by small asteroids. imperciptable changes in our degree of tilt and rate of rate of rotation
Some aliens traveling in a group know that their spaceship launchpad is 25 miles from the gas station where they are right now. How many kilometers is that distance?
The distance between the aliens traveling in group and their launchpad in kilometers is 40.23km.
How many kilometers is that distance?Given that data in the question;
Distance d = 25 milesDistance in kilometers = ?Note that;
1 miles = 1.609 kilometers
Now, the distance in kilometers will be;
distance = 25 miles
distance = ( 25 × 1.609 )kilometers
distance = 40.23km
Therefore, the distance between the aliens traveling in group and their launchpad in kilometers is 40.23km.
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