A toddler is allowed to dress himself on Mondays, Wednesdays, and Fridays. For each of his shirt, pants, and shoes, he is equally likely to put it on correctly as incorrectly. Getting these articles of clothing on correctly are independent of each other. On the other days, the mother dresses the toddler with 100% accuracy. Given that the toddler is correctly dressed, what is the probability that today is Monday

Answers

Answer 1

Answer:

0.0286 = 2.86% probability that today is Monday.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Dressed correctly

Event B: Monday

Probability of being dressed correctly:

100% = 1 out of 4/7(mom dresses).

(0.5)^3 = 0.125 out of 3/7(toddler dresses himself). So

[tex]P(A) = 0.125\frac{3}{7} + \frac{4}{7} = \frac{0.125*3 + 4}{7} = \frac{4.375}{7} = 0.625[/tex]

Probability of being dressed correctly and being Monday:

The toddler dresses himself on Monday, so (0.5)^3 = 0.125 probability of him being dressed correctly, 1/7 probability of being Monday, so:

[tex]P(A \cap B) = 0.125\frac{1}{7} = 0.0179[/tex]

What is the probability that today is Monday?

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0179}{0.625} = 0.0286[/tex]

0.0286 = 2.86% probability that today is Monday.


Related Questions

The 3rd and 6th term of a geometric progression are 9/2 and 243/16 respectively find the first term, common ratio, seventh term​

Answers

Answer:

Hello,

Step-by-step explanation:

[tex]Let\ (u_n)\ the\ geometric\ progression.\\\\r\ is\ the\ common\ ratio.\\\\u_3=u_0*r^3\\u_6=u_0*r^6\\\\\dfrac{u_6}{u_3} =r^3=\dfrac{\frac{243}{16} }{\frac{9}{2} } =\dfrac{27}{8} =(\frac{3}{2} )^3\\\\\boxed{r=\dfrac{3}{2} }\\\\\\u_3=u_1*r^2 \Longrightarrow\ u_1=\dfrac{u_3}{r^2} =\dfrac{\frac{9}{2} }{(\frac{3}{2^2}) } =2\\\\\\u_7=u_6*\dfrac{3}{2} =\dfrac{729}{32}[/tex]

Look at images below. : ]

Answers

Answer:

1) A

B) 5.818 stops

Step-by-step explanation:

Number One is less than or equal to 21 because the person only has 21 dollars, so she can't spend more than 21.

B can be solved through the equation by first subtracting $5, and then dividing 2.75 by 16.

Dr. Kingston predicted that swearing can help reduce pain. In the study, each participant was asked to plunge a hand into icy water and keep it there as long as the pain would allow. In one condition, the participants repeatedly yelled their favorite curse words while their hands were in the water. In the other condition the participants repeated a neutral word. The table below presents the amount of time that participants kept their hand in the ice in each condition.

​​​​

Swear Words

Neutral Words

98

56

70

61

52

47

87

60

46

32

120

92

72

53

41

31



1. Calculate the mean for the Swear Words condition:_______________

Answers

Answer:

Step-by-step explanation:

First, we add them all up.

98+70+52+87+46+120+72+41 = 586

Now, we divide 586 by the number of things there are. 586 / 8 = 73.25.

The mean of the swear words condition is 73.25.

the answer should be 586/8=73.25

♥️♥️♥️♥️♥️♥️♥️♥️♥️ help me

Answers

9514 1404 393

Answer:

AC = 2.0 mm = 41.3 kg

Step-by-step explanation:

The sum of torques about the pivot point is zero when the system is in equilibrium. That means the total of clockwise torques is equal to the total of counterclockwise torques. For this purpose, torque can be modeled by the product of mass and its distance from the pivot. The uniform beam can be modeled as a point mass at its center.

__

a) Let E represent the location of the center of mass of the beam. So, AE = 1.5 m. Then the distance from C to E is AC-AE = AC -1.5 and the CCW torque due to the beam's mass is (16 kg)(AC -1.5 m).

The distance from B to C is 3 m - AC, so the CW torque due to the particle at B is (7 kg)(3 -AC m)

These are equal, so we have ...

  16(AC -1.5) = 7(3 -AC)

  16AC -24 = 21 -7AC . . . . . eliminate parentheses

  23AC = 45 . . . . . . . . . . . add 7AC+24

  AC = 45/23 ≈ 1.957 . . divide by the coefficient of AC

  AC ≈ 2.0 meters . . . . rounded to 1 dp

__

b) The torques in this scenario are ...

  M(0.7) = 16(0.8) +7(2.3) . . . . . . AD = 0.7 m, DE = 0.8 m, DB = 2.3 m

  M = 28.9/0.7 ≈ 41.286 . . . . simplify, divide by the coefficient of M

  M = 41.3 kg . . . . rounded to 1 dp

_____

Additional comment

Torque is actually the product of force and distance from the pivot. Here, the forces are all downward, and due to the acceleration of gravity. The gravitational constant multiplies each mass, so there is no harm in dividing the equation by that constant, leaving the sum of products of mass and distance.

Hello people can you please help me on this I've been stuck on it for like 30 minuets now

Answers

Answer:

Step 1:  Complete the first equation

0.01 is a hundredth, therefore if we have 1.86 then we have 186 hundredths.

Step 2:  Complete the second equation

1.86 / 2 = 0.93

0.01 is a hundredth, therefore if we have 0.93 then we have 93 hundredths.

Step 3:  Complete the third equation

1.86 / 2 = 0.93

Use the given information to find the number of degrees of​ freedom, the critical values χ2L and χ2R​, and the confidence interval estimate of σ. It is reasonable to assume that a simple random sample has been selected from a population with a normal distribution. Nicotine in menthol cigarettes 99​% ​confidence; n=23​, s=0.28 mg.
df = (Type a whole​ number.)
χ2L = ​(Round to three decimal places as​ needed.)
χ2R = ​(Round to three decimal places as​ needed.)
The confidence interval estimate of σ is __ mg < σ < __ mg. ​(Round to two decimal places as​ needed.)

Answers

Answer:

χ²R = 8.643

χ²L = 42.796

0.20 < σ < 0.45

Step-by-step explanation:

Given :

Sample size, n = 23

The degree of freedom, df = n - 1 = 23 - 1 = 22

At α - level = 99%

For χ²R ; 1 - (1 - 0.99)/2= 0.995 ; df = 22 ; χ²R = 8.643

For χ²L ; (1 - 0.99)/2 = 0.005 ; df = 22 ; χ²L = 42.796

The confidence interval of σ ;

s * √[(n-1)/χ²L] < σ < s * √[(n-1)/χ²R)]

0.28 * √(22/42.796) < σ < 0.28 * √(22/8.643)

0.2008 < σ < 0.4467

0.20 < σ < 0.45


rewrite -4<x<-1 using absolute value sign​

Answers

[tex] - | 4 | < x < - |1| [/tex]

dunno if that's the desired form tough, but it states the same definition

The given inequality rewritten using absolute value sign​ as |-4|<x<|-1|.

What are inequalities?

Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

The given inequality is -4<x<-1.

An absolute value inequality is an expression with absolute functions as well as inequality signs.

Here, using absolute value sign​ we get

|-4|<x<|-1|

Therefore, the given inequality rewritten using absolute value sign​ as |-4|<x<|-1|.

To learn more about the inequalities visit:

https://brainly.com/question/20383699.

#SPJ2

Use the graph of ƒ to find ƒ(2).
0.5
–8
–0.5
Does not exist

Answers

Answer:

Step-by-step explanation:

When you're looking to find things like f(2) and f(4) and f(-3000), etc. the number inside the parenthesis is an x value. Look to the graph, find that x value, and locate the y value that corresponds to it. f(2) = -8. f(-1) = 4. f(1) = -4. See?

Answer:

does not exist

Step-by-step explanation:

that what i put hope it helps

Match each sequence below to statement that BEST fits it.

Z. The sequence converges to zero;
I. The sequence diverges to infinity;
F. The sequence has a finite non-zero limit;
D. The sequence diverges.

_______ 1. ns in (1/n)
_______2. ln(ln(ln(n)))
_______3. (ln(n))/n
_______4. n!/n^1000

Answers

Answer: hello your question is poorly written attached below is the complete question

answer:

1 ) =  I (

2) = F

3) = Z

4) = D

Step-by-step explanation:

attached below is the required solution.

1 ) =  I ( The sequence diverges to infinity )

2) = F ( The sequence has a finite non-zero limit )

3) = Z ( The sequence converges to zero )

4) = D ( The sequence diverges )

Drag each equation to the correct location on the table.
Match the equations with the value of x that makes them true.
5x - 2x - 4 = 5
5x - (3x - 1) = 7
x + 2x + 3 = 9
2(2x - 3) = 6
4x - (2x + 1) = 3
5(x + 3) = 25
x = 2
X = 3

Answers

Answer:

The answer to your questions are given below.

Step-by-step explanation:

To answer the question given above, we shall determine the value of x in each equation. This can be obtained as follow:

5x - 2x - 4 = 5

3x - 4 = 5

Collect like terms

3x = 5 + 4

3x = 9

Divide both side by 3

x = 9/3

x = 3

5x - (3x - 1) = 7

Clear the bracket

5x - 3x + 1 = 7

2x + 1 = 7

Collect like terms

2x = 7 - 1

2x = 6

Divide both side by 2

x = 6/2

x = 3

x + 2x + 3 = 9

3x + 3 = 9

Collect like terms

3x = 9 - 3

3x = 6

Divide both side by 3

x = 6/3

x = 2

2(2x - 3) = 6

Clear the bracket

4x - 6 = 6

Collect like terms

4x = 6 + 6

4x = 12

Divide both side by 4

x = 12/4

x = 3

4x - (2x + 1) = 3

Clear the bracket

4x - 2x - 1 = 3

2x - 1 = 3

Collect like terms

2x = 3 + 1

2x = 4

Divide both side by 2

x = 4/2

x = 2

5(x + 3) = 25

Clear the bracket

5x + 15 = 25

Collect like terms

5x = 25 - 15

5x = 10

Divide both side by 5

x = 10/5

x = 2

SUMMARY:

x = 2

x + 2x + 3 = 9

4x - (2x + 1) = 3

5(x + 3) = 25

x = 3

5x - 2x - 4 = 5

5x - (3x - 1) = 7

2(2x - 3) = 6

Write A linear equation in standard form the passes through the points (4,-2) and (2,6)

Answers

Answer:

Step-by-step explanation:

4 x + y =

14

How much would $200 invested at 5% interest compounded monthly be
worth after 9 years?

Answers

9514 1404 393

Answer:

  $313.37

Step-by-step explanation:

The compound interest formula is used to find that value.

  A = P(1 +r/12)^(12t)

P compounded monthly at annual rate r for t years.

  A = $200(1 +0.05/12)^(12·9) ≈ $313.37

PLEASE HELP
Identify the first five terms of the sequence in which a, = 3n2 - 1.

Answers

Step-by-step explanation:

you cannot just put the actual numbers in and calculate ?

and you can't provide the correct problem statement, as it seems.

I assume you mean

an = 3n² - 1

a sequence starts with a1, so, n>=1

a1 = 3×1² - 1 = 3-1 = 2

a2 = 3×2² -1 = 3×4 - 1 = 12 - 1 = 11

a3 = 3×3² - 1 = 3×9 - 1 = 27 - 1 = 26

a4 = 3×4² - 1 = 3×16 - 1 = 48 - 1 = 47

a5 = 3×5² - 1 = 3×25 - 1 = 75 - 1 = 74

there, that is all there is to it. you really needed help with that ?

Use the slope-intercept form of the linear equation to write an equation of the line with given slope and y-intercept.
Slope: -6/5 y intercept (0,8)

Answers

Answer:

5y + 6x = 40

Step-by-step explanation:

hope it is well understood?

Slope intercept- y=mx+b
m is the slope
b is the y intercept (0,y)

y=-6/5x+8

The function sin 0 is reciprocal of cot 0.

True
False

Answers

Answer: False

Step-by-step explanation:

This is because sin 0 is equal to 0 but cot 0 is equal to undefined

There are 165 children taking swimming lessons at the pool. If 10 children will be assigned to each instructor, how many instructors are needed?

Answers

17 but one will have only 5 children

Answer:

17 instructors

Step-by-step explanation:

If each instructor will get 10 children, we have to divided the total number of children taking swimming lessons by the number of children assigned to each instructor (10):

165/10 = 16.5

Unfortunately, we can't have 16 and a half instructors. Since 5 children are remaining, we can round up 16.5 to 17 and get 17 instructors. This implies that 16 instructors will teach 10 children (160 in total) and 1 instructor will teach 5 children (5 in total). 160+5 = 165 total children.

At a large Midwestern university, a simple random sample of 100 entering freshmen in 1993 found that 20 of the sampled freshmen finished in the bottom third of their high school class. Admission standards at the university were tightened in 1995. In 1997, a simple random sample of 100 entering freshmen found that only 10 finished in the bottom third of their high school class. Let p 1 and p 2 be the proportions of all entering freshmen in 1993 and 1997, respectively, who graduated in the bottom third of their high school class. What is a 90% plus four confidence interval for p 1 – p 2?

Answers

Answer:

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

p1 -> 1993

20 out of 100, so:

[tex]p_1 = \frac{20}{100} = 0.2[/tex]

[tex]s_1 = \sqrt{\frac{0.2*0.8}{100}} = 0.04[/tex]

p2 -> 1997

10 out of 100, so:

[tex]p_2 = \frac{10}{100} = 0.1[/tex]

[tex]s_2 = \sqrt{\frac{0.1*0.9}{100}} = 0.03[/tex]

Distribution of p1 – p2:

[tex]p = p_1 - p_2 = 0.2 - 0.1 = 0.1[/tex]

[tex]s = \sqrt{s_1^2+s_2^2} = \sqrt{0.04^2 + 0.03^2} = 0.05[/tex]

Confidence interval:

[tex]p \pm zs[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

90% confidence level

So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].  

The lower bound of the interval is:

[tex]p - zs = 0.1 - 1.645*0.05 = 0.01775 [/tex]

The upper bound of the interval is:

[tex]p + zs = 0.1 + 1.645*0.05 = 0.18225 [/tex]

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

Find the missing segment in the image below

Answers

Answer:

x = 12

Step-by-step explanation:

Missing length of the segment is the altitude of the right triangle.

Based on the geometric mean theorem, we would have the following:

h = √(ab)

Where,

h = x

a = 16

b = 9

Plug in the values:

x = √(16*9)

x = √144

x = 12

I need help with this question

Answers

Answer:

7

This question is tying to introduce an idea that

eventually becomes a calculus question ....

(4^2 + 3(4)) - (0^2+3(0))

             4 - 0

28 - 0       = 7

   4

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

1. Approach

The average rate of change can simply be defined as the slope of a line that passes through any two points on a coordinate plane. In this situation, one is given a function, and one is asked to find the rate of change over an interval.

Given function: [tex]f(x)=x^2+3x[/tex]

Intervale, [tex][0, 4][/tex]

This can be done by evaluating the endpoints of the interval by substituting them into the function. Then writing the resulting the form of a point on the coordinate plane ([tex]x, y[/tex]). Finally, one can find the slope of the line that passes through the points by using the following slope formula,

[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Where ([tex]x_1,y_1[/tex]) and ([tex]x_2,y_2[/tex]) are coordinate points.

2. Find the points

With the function (f(x)), substitute the end points of the itnerval ( [0, 4] ) into the function to generate coordinate points,

[tex]f(x)=x^2+3x[/tex]

[ 0, 4 ]

[tex]f(0)=(0)^2+3(0)\\=0 + 0\\ =0[/tex]

Point: (0, 0)

[tex]f(4)=(4)^2+3(4)\\= 16 + 12\\ = 28[/tex]

Point: (4, 28)

3. Find the average rate of change,

Now substitute the points the formula to find the slope, then simplify to evaluate

[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

(0, 0), (4, 28)

Substitute,

[tex]\frac{y_2-y_1}{x_2-x_1}\\\\=\frac{28-0}{4-0}\\\\=\frac{28}{4}\\\\= 7[/tex]

The average rate of change is 7.

a-bcosc/c-bcosa=sinc/sina​

Answers

=ac-b(cosc-ccosa)

=sinc/sina

Can someone please help!!! Sec. 12.7 #78

Answers

Question please I can’t see 1
theres nothikg to see

What is the slope, m, and the y-intercept of the line that is graphed below?

On a coordinate plane, a line goes through points (negative 3, 0) and (0, 3).

Answers

Answer:

Slope: 1

Y-intercept: (0,3)

Step-by-step explanation:

The y intercept is when the slope reaches the y-axis line. In this case, it is given to us. Anything that is formed like this: (0, y) is the y-intercept.

Y intercept: (0, 3)

For slope, you can use the formula rise over run. [tex]\frac{Rise}{Run}[/tex]

From the picture, I have drawn the rise over run, which is [tex]\frac{3}{3}[/tex], which is also 1.

Slope: 1

Hope this helped.

Answer: 1

Step-by-step explanation: got it right on edge

Alejandro wants to adopt a puppy from an animal shelter. At the​ shelter, he finds eight puppies that he​ likes: a male and female puppy from each of the four breeds of and Labrador. The puppies are each so cute that Alejandro cannot make up his​ mind, so he decides to pick the dog randomly. Find the probability that Alejandro chooses a .

Answers

Answer:

Hence the required probability is, 3/4

Step-by-step explanation:  

At the shelter, he likes :  

a male coolie, a female coolie, a male boxer, a female boxer, a male beagle, a female beagle, a male Labrador, and a female Labrador.  

Let, A denote the event of selecting a male coolie and B denote the event of selecting a male Labrador.  

P(A) = 1/8 = P(B)  

Here the probability of selecting a puppy except A & B is,  

P(AUB)c = 1 - P(AUB) = 1 - { P(A) + P(B) } = 1 - 1/8 - 1/8 = 3/4

Find the sum of -3x^2-4x+3 2x^2+3

Answers

The answer is -x^2-4x+6

A computer is selling for $883 the finance value is $1077.26 under an 11% simple interest loan what is the length of the loan

Answers

Answer:

The length of the loan was 2 years.

Step-by-step explanation:

Given that a computer is selling for $ 883, and the finance value is $ 1077.26 under an 11% simple interest loan, to determine what is the length of the loan, the following calculation must be performed:

883 x 0.11 = 97.13

(1077.26 - 883) / 97.13 = X

194.26 / 97.13 = X

2 = X

Therefore, the length of the loan was 2 years.

What is the equation of exponential regression equation? Round all numbers you your answer to three decimal places

Answers

Given:

The given values are:

[tex]a=0.2094539899[/tex]

[tex]b=2.507467975[/tex]

[tex]r^2=0.9435996398[/tex]

[tex]r=0.9713905701[/tex]

To find:

The exponential regression equation for the given values (Rounded to three decimal places).

Solution:

The general form of exponential regression equation is:

[tex]y=a\cdot b^x[/tex]          ...(i)

Where, a is the initial value and b is the growth/decay factor.

We have,

[tex]a=0.2094539899[/tex]

[tex]b=2.507467975[/tex]

Round these numbers to three decimal places.

[tex]a\approx 0.209[/tex]

[tex]b\approx 2.507[/tex]

Substitute [tex]a=0.209, b=2.507[/tex] in (i) to find the exponential regression equation.

[tex]\hat{y}=0.209\cdot 2.507^x[/tex]

Therefore, the correct option is C.

You flip a coin that is not fair, the prbability of heads on each flip is 0.7. if the coin shows heads, you draw a marble from urn h with 1 blue and 4 red marbles. if the coin shows tails, you draw a marble from urn t with 3 blue and 1 red marble. Find the following probabilities:

a. The probability of choosing a red marble.
b. The probability of choosing a blue marble, given that the coin showed heads.
c. The probability that the coin showed tails, given that the marble was red.

Answers

Solution :

P(H) = 0.7  ;  P(T) = 0.3

If heads, then Urn H,  1 blue and 4 red marbles.

If tails, then Urn T ,  3 blue and 1 red marbles.

a).

P ( choosing a Red marble )

= P (H) x P( Red from Urn H) + P (T) x P( Red from Urn T)

[tex]$=0.7 \times \frac{4}{5} + 0.3 \times \frac{1}{4}$[/tex]

= 0.56 + 0.075

= 0.635

b).  If P (B, if coin showed heads)

If heads, then marble is picked from Urn H.

Therefore,

P (Blue) [tex]$=\frac{1}{5}$[/tex]

             = 0.2

c). P (Tails, if marble was red)

[tex]$=P (T/R) = \frac{P(R/T)}{P(R)} \ P(T)$[/tex]

Where P (R/T) = P ( red, if coin showed tails)

                        [tex]$=\frac{1}{4}$[/tex]

                        = 0.25 (As Urn T is chosen)

P (R) =  P (Red) = 0.635 (from part (a) )

P (T) = P (Tails) = 0.3

∴ [tex]$P(T/R) = \frac{0.25 \times 0.3}{0.635}$[/tex]

                = 0.118

                 

Find the circumference of the circle.
10.1 in
Hint: C = xxd
x= 3.14




A.15.857 in
B.31.714 in
C.63.428 in
D.13.24 in

Answers

Step-by-step explanation:

c=3.14×3.14×10.1

=99.58196

Step 3: Write the equation of the line that passes through the point (4,−1)
(
4
,

1
)
that is parallel to the line 2−3=9

Answers

Answer:

-

Step-by-step explanation:

-

The quadratic equation x^2 + 3x + 50 = 0 has roots r and s. Find a quadratic equation whose roots are r^2 and s^2.

Answers

Answer:

x^2 + 91x + 2500

-----------------------------------------------------------------------------

x^2 + 3x + 50

(x-r)(x-s)

-> x^2-(r+s)x+rs

rs = 50, r + s = -3

-> (rs)^2 = 2500

(r+s)^2 = 9

-> r^2 + 2rs + s^2 = 9

-> r^2 + 2(50) + s^2 = 9

-> r^2 + s^2 + 100 = 9

-> r^2 + s^2 = -91

(x-r^2)(x-s^2)

-> x^2-(r^2+s^2)x+(rs)^2

-> x^2 - (-91)x + 2500

x^2 + 91x + 2500

Other Questions
any four source of energy Which of the following best challenges the readers' critical thinking? A. Presence of foreign words B. Author's cultural and ethnic background C. Presence of ambiguity D. Presence of anachronisms Which graph represents an odd function? Hope made 3 different yo-yo's. She used 1 3/4 meters of string for the first yo-yo, 1 meter of string (4.23)(1.6) please multiple datafind the range between 14, 15, 16, 14,23,1315, 24, 12, 23, 14; 20, 17, 21, 22, 1031, 19, 20,17, 16, 15, 11, 12, 21, 20, 17, 18, 19, 23 What type of operating system is Linux? An outsourced operating system An open source operating system A closed source operating system A variable source operating system ayone amos right now gonna be answering : yungbreezyf2 Let be the density function for the shelf life of a brand of banana which lasts up to weeks. Time, , is measured in weeks and . Incorrect answer icon Your answer is incorrect. Find the mean shelf life of a banana using . Round your answer to one decimal place. Mean find length of missing sides just fill in the missing blanks I need the answer dont have to put the explanation what is two plus two Describe the five types of physical activity. Give an example of each. A four digit password is a number that begins with a 3. If digits can be repeated how many possible passwords are there? show and explain your work Imagine that you are operating a Chinese clothing retail chain and you wish to enter the Italian market in order to access the latest fashion designs and trends from Italy. To meet this goal, it is important to have strong control and coordination of your Italian operations and to be able to easily transfer tacit knowledge back to China. Based on this information what entry mode would you choose to enter Italy?a. Wholly owned subsidiary b. Exporting c. Franchising d. Strategic alliance e. Licensing Explain how the changes in the villi of a person with coeliac disease may cause the person to lose weight and have low amounts of vitamins and minerals in their body Hi ! How can you return the value of the class computeDiscountInfo to the variable savings in the main class ?Here is my code :import java.util.Scanner;public class RoomCost{public static void main (String [] args){double price;double discount;double savings;Scanner keyboard = new Scanner(System.in);System.out.print("Enter cutoff price for discount $>> ");price = keyboard.nextDouble(); System.out.print("Enter discount rate as a whole number >> "); discount = keyboard.nextDouble(); displayinfo(); //insert code to set the value returned from computeDiscountInfo method to savings); // savings = System.out.println("Special this week on any room over " + price);System.out.println("Discount of " + discount + " percent");System.out.println("That's a savings of at least $" + savings);} public static void displayinfo(){ System.out.println("We want your stay to be memorable.");System.out.println("We promise to make you as comfortable as possible."); } public static double computeDiscountInfo(double price, double discountRate){double savings;//(insert code to calculate savings as price multiplied by discount divided by 100);savings = (price * discountRate)/100;return savings;}} Andersen and Bem (1981) conducted a variation of the getting-acquainted telephone study by Snyder, Elizabeth Tanke, and Berscheid (1977). Andersen and Bem provided attractive and unattractive photos of men to women who interacted with men at the other end of a telephone. What would you expect happened when the women thought that the men with whom they were speaking were the men in the photos The temperature of a body falls from 30C to 20C in 5 minutes. The airtemperature is 13C. Find the temperature after a further 5 minutes. In the context of managing international transfers and assignments, repatriation occurs when a manager is: a. brought back home from a foreign assignment. b. expelled from the foreign country where he or she is sent on an assignment. c. deported from his home country to a foreign country. d. sent by his or her company on a second foreign assignment. In ABC, what is the measure of angle B?