A system of equations has no solution. If y = 8x + 7 is one of the equations, which could be the other equation?

2y = 16x +14
y = 8x – 7
y = –8x + 7
2y = −16x − 14

Answers

Answer 1

Step-by-step explanation:

the answer is 2y=16x+14

Answer 2

The equations that could be the other equation are y = 8x - 7 and y = -8x + 7.

If the system of equations has no solution, then the other equation must not have the same slope-intercept form as the first equation.

The slope-intercept form of the equation y = 8x + 7 is y = mx + b, where m is the slope and b is the y-intercept. Thus, the slope of the first equation is 8 and the y-intercept is 7.

Now let's check each of the given equations to see which one could be the other equation.

2y = 16x + 14

Rewriting this equation in slope-intercept form, we get y = 8x + 7, which is the same as the first equation. Therefore, this equation cannot be the other equation.

y = 8x – 7

This equation has the same slope as the first equation but a different y-intercept. Therefore, it represents a different line and could be the other equation.

y = –8x + 7

This equation has a slope that is the negative of the slope of the first equation, so it represents a different line. Therefore, it could be the other equation.

2y = −16x − 14

Rewriting this equation in slope-intercept form, we get y = -8x - 7, which has the same slope as the first equation but a different y-intercept. Therefore, it represents a different line and could be the other equation.

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answers

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Answer:

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