A school staff meeting had 30 teachers in attendance, 60% of whom were first-year teachers. How many first-year teachers were in the meeting?

Answer:

Yo mean correct way??

yo can divide minute by 60 to convert minute into hour

For example

To convert 10 minute into hour. then we should divide 10 by 60. 10/60

Answer:

In any conversion you have to establish  ratios (or rates) for the different units being converted.

The process will be performed by a series of multiplications that will cancel out the "unwanted" units.

multiplication by one (1) does not change the value in an equation.

you have to multiply by a "series of ones" that take into account the units being converted..

for example  

1 minute/60 seconds   or  1 inch = 2.54 cm   or  1 day = 24 hours

in your problem you have minutes... lets say you have 100 minutes

100 minutes * 1 hour             minutes cancel and you have  100/60 = 1 [tex]\frac{2}{3}[/tex] hrs

                       60 minutes

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

Option c points at (-2,0) (-1, 0.5) and (1,1)

Step-by-step explanation:

DC=CF

We know

[tex]\boxed{\sf L=\dfrac{\theta}{180}\times πr}[/tex]

[tex]\\ \large\sf\longmapsto L=\dfrac{90}{180}\times \dfrac{22}{7}\times 10[/tex]

[tex]\\ \large\sf\longmapsto L=\dfrac{1}{2}\times \dfrac{220}{7}[/tex]

[tex]\\ \large\sf\longmapsto L=\dfrac{110}{7}[/tex]

[tex]\\ \large\sf\longmapsto L=15.5[/tex]

Now

[tex]\\ \large\sf\longmapsto CF=L+r-DE[/tex]

[tex]\\ \large\sf\longmapsto CF=15.7+10-16[/tex]

[tex]\\ \large\sf\longmapsto CF=25.7-16[/tex]

[tex]\\ \large\sf\longmapsto CF=9.7cm[/tex]

[tex]\large\sf\red{⟼L=18090×722×10}[/tex]

[tex]\begin{gathered}\\ \large\sf\red{ ⟼ L=\dfrac{1}{2}\times \dfrac{220}{7}}\end{gathered}[/tex]

[tex]\begin{gathered}{ \large\sf\red{⟼ L=\dfrac{110}{7}}\end{gathered}[/tex]

⟼ L=15.5

Now

⟼ CF=L+r−DE

⟼ CF=15.7+10−16

⟼ CF=25.7−16

Seena’s mother is 4 times as old as Seena. After 5 years her mother will be 3 times as old as she will be then .Find their present ages.

✧ Let us assume :

Seena's age be x

Her mother's age be 4x

✧ After 5 years :

Seena's age = x + 5

Her mother's age = 4x + 5

✧ Ratio of age after 5 years :

Seena's mother = 3

Seena's ratio = 1

Hence, the equation is :

[tex] \looparrowright\frak{ \frac{4x + 5}{x + 5} = \frac{3}{1} }[/tex]

By cross multiplying we get

[tex] \looparrowright \frak{3(x + 5) = 4x + 5}[/tex]

[tex] \looparrowright \frak{3x + 15 = 4x + 5}[/tex]

[tex] \looparrowright \frak{x = 10}[/tex]

Hence, the ages are

Seena's age = x = 10 yrs

Her mother's age = 4x = 4 × 10 = 40 years

∴ Seena's age is 10 and her mother's is 40 respectively

I am not understanding the language

Answer:

its Vietnamese

Step-by-step explanation:

I just dont understand what that type of math is? sorry ):

Answer:

165 ver una pelicula de terror, 137.5 (138) ver una novela, y 247 ver una pelicula de ciencia ficcion.

Step-by-step explanation:

0.3 x 550 = 165

0.25 x 550 = 137.5 --> 138

165 + 138 = 303

550 - 303 = 247

Answer:

B or (-2/3)

Step-by-step explanation:

Perpendicuar lines have negative inverse slopes SO

3/2 ---> -2/3

Answer:

C - exponential growth

Step-by-step explanation:

Answer:

The answer should be C

Step-by-step explanation:

Answer:

101

10+6+16+6*5

I hope it's correct

Answer:

Jawaharlal Nehru was the first

Answer:

Jawaharlal Nehru is the first prime minister of India

Answer:

540 is the answer

Step-by-step explanation:

hope u liked!

Answer:

10t + D = 40

Step-by-step explanation:

y = mx + b is the equation of a line in slope intercept form. We'll be using this equation since the slope, or distance traveled, is steady (linear). In this case, the slope is 10 since Sarah's pace is 10 km/hr. m is the slope, so m = 10.

y = 10x + b. However, she needs to run 40 km. So we're going to substitute 40 in for y.

40 = 10x + b. Now, we need to use t instead of x since that's what's been asked of us. (The slope represents the distance traveled over time, so t fits.)

10t + b = 40

b needs to become D, the distance in kilometers.

So now we have 10t + D = 40

Answer:

D(t)= 40-10t

Step-by-step explanation:

#KmNn

false                                               dsddsfsdfsfdfdsfdsdfsdfsdsfdfsfdsdfsdfsdfsfdsfd

Answer:

14.4

Step-by-step explanation:

since the longest side is 24,find the shortest side

√20^2-12^2

√400-144

√256

=16

which means the other shortest side is 24-16

which is 8

then you have to use the 12 and 8 to find the unknown side

√12^2+8^2

144+64

√208

14.4

I hope this helps

Answer:

A=2

B=4

C=6

D=5

E=7

F=8

G=3

H=1

Step-by-step explanation:

explanation is in the picture!

The only 2-digit number that is lesser than 50 and the sum of its digits remain unaffected despite being multiplied by a number < 1 would be '18.'

To prove, we will look at some situations:

If we add up the two digits of 18. We get,

[tex]1 + 8 = 9[/tex]

And we multiply 18 by 2 which is greater than 1. We get,

[tex]18[/tex] × [tex]2 = 36[/tex]

The sum remains the same i.e. [tex]3 + 6 = 9[/tex]

Similarly,

If 18 is multiplied to 3(greater than 1), the sum of the two digits comprising the number still remains the same;

[tex]18[/tex] × [tex]3 = 54[/tex]

where (5 + 4 = 9)

Once more,

Even if 18 is multiplied to 4 or 5(greater than 1), the sum of its digits will still be 9.

 [tex]18[/tex] × [tex]4 = 72[/tex]

[tex](7 + 2 = 9)[/tex]

[tex]18[/tex] × [tex]5 = 90[/tex]

[tex](9 + 0 = 9)[/tex]

Thus, 18 is the answer.

Learn more about 'numbers' here: brainly.com/question/1624562

Answer:

C) -1.255

Step-by-step explanation:

We are tasked to solve for the residual value given that when x equals 29, y will be equals to 27.255. But, when it is tested, y actual value is 26. The formula in solving residual is shown below:

Residual value = Observed value - predicted value

Residual value =  26 - 27.255

Residual values = -1.255

The answer is -1.255 for residual value.

Answer:

68 degrees 90+22=112 180 subtract 112 = 68

Answer:

Step-by-step explanation:

To solve this, we are going to make an age table:

                       Age Now                 Age 10 years ago

Tanya

Elliot

Filling the in the Age Now column comes from the first sentence. If Elliot is 2 times Tanya's age and we don't know Tanya's age, then Tanya's age is x and Elliot's age is 2x:

            Age Now                Age 10 years ago

Tanya         x

Elliot         2x

Filling in the Age 10 years ago column simply requires that we take their ages in the Age Now column and subtract 10 from each age:

         Age Now                Age 10 years ago

Tanya     x                              x - 10

Elliot      2x                           2x - 10

Since the question is How old is Elliot now based on the fact that 10 years ago....blah, blah, blah, we are using the ages in the 10 years ago column to write our equation. It says:

10 years ago, Elliot was 4 times as old as Tanya. Translated into mathspeak:

2x - 10 = 4(x - 10) and

2x - 10 = 4x - 40 and

-2x = -30 so

x = 15. That means that Elliot is 30 and Tanya is 15

Answer:

The sample size needed is of 10,484.

Step-by-step explanation:

We have to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.98}{2} = 0.01[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a p-value of [tex]1 - 0.01 = 0.99[/tex], so Z = 2.327.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

The weekly earnings of students in one age group are normally distributed with a standard deviation of 88 dollars.

This means that [tex]\sigma = 88[/tex]

Find the sample size needed to assure with 98 percent confidence that the sample mean will not differ from the population mean by more than 2 dollars.

This is n for which M = 2. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]2 = 2.327\frac{88}{\sqrt{n}}[/tex]

[tex]2\sqrt{n} = 2.327*88[/tex]

[tex]\sqrt{n} = \frac{2.327*88}{2}[/tex]

[tex](\sqrt{n})^2 = (\frac{2.327*88}{2})^2[/tex]

[tex]n = 10483.3[/tex]

Rounding up:

The sample size needed is of 10,484.

Answer:

x=10

Step-by-step explanation:

Step 1: Multiply 4 with X and 3. You'll get 4x+12=x+42

Step 2: Keep the variable on one side and the number on the other side. you would subtract X and subtract 12. You'll get 3x=30

Step 3: Divide by the 3 on both sides and you'll get x=10

Given:

[tex] \\ ⇢ \tt \: 4(x + 3) = x + 42 \\ [/tex]

Solution:

[tex] \\ ⇢ \tt \: 4(x + 3) = x + 42 \\ \\ \\ \tt⇢ 4x + 12 = x + 42 \: \: \\ \\ \\ \tt \: ⇢4x - x = 42 - 12 \: \\ \\ \\ \tt \: ⇢3x = 30 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \tt \: ⇢x = \frac{30}{3} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \tt \: \pink{ \pmb{ \mathfrak{⇢x = 10}}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ [/tex]

Verification:

[tex] \\ ⇢ \tt \: 4(10+ 3) = 10+ 42 \\ \\ \\ \tt⇢ 40 + 12 = 10 + 42 \: \: \\ \\ \\ \tt \: ⇢52 = 52 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \: ⇢ \purple{ \pmb{ \bold{L.H.S = R.H.S}}}\\ \\ \\ [/tex]

Answer:

C.

[tex]{ \tt{f(x) = \frac{12}{x} - 18}} \: and \: { \tt{g(x) = \frac{12}{x + 18} }}[/tex]

Step-by-step explanation:

[tex]{ \tt{f(x) = \frac{12}{x} - 18}}[/tex]

Let inverse be m:

[tex]{ \tt{m = \frac{12}{x} - 18 }} \\ { \tt{x(m + 18) = 12}} \\ { \tt{x = \frac{12}{m + 18} }} \\ \\ { \boxed{ \sf{f {}^{ - 1} (x) = g(x) = \frac{12}{x + 18} }}}[/tex]

Answer:

answer of this qn is 15in^2

===========================================================

Work Shown:

(whole length)*(external part) = (whole length)*(external part)

(EG)*(FG) = (SG)*(HG)

(2x+4)*(4) = (x+5)*(5)

8x+16 = 5x+25

8x-5x = 25-16

3x = 9

x = 9/3

x = 3

Use this x value to find EF

EF = 2x

EF = 2*3

EF = 6

For more information, search out "secant secant formula". It's not a typo that I wrote "secant" twice.

Answer:

For number 5, it is D

For number 6, it is A

Step-by-step explanation:

For number 5, we have the dimensions options here.

We first need to check to see if all the choices give the perimeter of 34, as sometimes there are trick answers.

We know the 34 is the perimeter because we are looking for area, so we add the two given numbers and double it to find the perimeter since we have the length and width.

*(Formula for perimeter is 2(L + W)  )

(I already checked them all, and they all give to be 34 so they are all safe.)

Then we find the areas of each.

*(Formula for area is L * W   {the " * " symbol represents multiplication.)

We multiply 12 by 5 to get 60.

We multiply 13 by 4 to get 52.

We multiply 10 by 7 to get 70.

We multiply 9 by 8 to get 72.

Since we are looking for the greatest area, we look for the greatest number, which is the 72.

Therefore the 9 by 8 option, or D is correct.

For number 6, we are looking for the minimum perimeter and we have the area, so we set the same thing up except modified slightly.

We first check if all the areas are 64 to look for a trick answer.

We multiply 8 by 8 to get 64.

We multiply 1 by 64 to get 64.

We multiply 6 by 6 to get 36. (WHAT?!!?!! omg me big brain lolza. {nah jk})

We multiply 32 by 2 to get 64.

So we know the 6 by 6 option or C is wrong.

Then we look for the perimeters of the dimension solutions.

(This will skip C so it will go A, B, and then D, since we know C is incorrect and is unrelated now.)

2 ( 8 + 8 ) =  32

2 ( 1 + 64 ) =  130

2 ( 32 + 2 ) =  68.

Since we are looking for the smallest perimeter, it is the smallest answer this time.

So it must be A, since 32 is the smallest.

Hope this helps!

Answer:

Arthur should select the Mount Joy Pool when there are less than 10 people at the party

Step-by-step explanation:

The initial fee to rent the Woodbridge Pool = $50

The additional fee per person after renting = $5

The initial fee to rent at Mount Joy Pool = 0 (no initial fee)

The fee per person at Mount Joy Pool = $10

The equation of a straight line is y = m·x + c

Ley y  represent the total cost of renting the pool, x, represent the number of persons in the pool, m represent the fee per person and c represent the initial charges, we get;

The total cost of renting Woodbridge Pool, y = 5·x + 50

The total cost of renting the Joy Pool, y = 10·x

Equating both values of y gives;

5·x + 50 = 10·x

∴ 5·x = 50

x = 50/5 = 10

x = 10

From the above equations, the cost of renting the pool is lower for the Joy Pool when there are less than 10 persons at the pool

It will cost the same amount to rent the pool when the number of persons in the pool are 10 persons and the cost of renting the Mount Joy Pool  will be more than the cost of renting the Woodbridge Pool, when there are more than 10 persons

Therefore, Arthur should select the Mount Joy Pool when there are less than 10 people at the party.