Answer:
A rainbow requires water droplets to be floating in the air. That's why we see them right after it rains. The Sun must be behind you and the clouds cleared away from the Sun for the rainbow to appears.
How is temperature related to the physical change of a substance
Answer:
Temperature is a measure of the kinetic energy of particles in a substance. As temperature increases, the atoms or molecules in a substance gain energy. As temperature decreases, the particles lose energy. A change in the energy of particles causes a change in their arrangement. A change in the arrangement of particles can lead to a physical change.
Explanation:
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how would a rock respond to stresses applied at depth?
The rock will compress as the stress applied increases with depth and it will break when it cannot withstand the stress.
The pressure or stress on the rock is defined as force per unit area of the rock which equally increases with depth. This can be expressed as follows;
[tex]P= \frac{F}{A}\\\\P = \rho gh[/tex]
where;
P is the pressure applied to the blockA is the area of the rock h is the depth in which the rock is subjected to g is acceleration due to gravityThus, we can conclude that the stress on the rock will increase with increase in depth. The rock will compress as the stress applied increases with depth and it will break when it cannot withstand the stress.
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__________ invented the analytical engine, a machine that did calculations.
Answer:
Charles Babbage
Explanation:
Analytical Engine, generally considered the first computer, designed and partly built by the English inventor Charles Babbage in the 19th century (he worked on it until his death in 1871).
Explain why adding ice to a drink can cause water droplets (condensation) to appear on the outside of the glass?
Answer:
it just condensed you know it isn't a big deal whatever happens does change anything
a car in tally at rest pics up and velocity of 72 km/h ^−1over a distance of 25m the acceleration of car is
Answer:
16 m/s^2
You find out the time first which is 1.25s
Below is a diagram of a weight on a spring. When the weight is pulled down and then released, the spring compresses and expands. Each position indicates a different point in time.
Which of the following statements is true?
a
In all four positions, mechanical energy is 0 J.
b
The elastic potential energy of the spring at Position 2 is converted to kinetic energy.
c
The chemical potential energy of the spring is greatest at Position 4.
d
In all four positions, the gravitational potential energy of the spring is the same.
Answer:
B.
Explanation:
The elastic potential energy of the spriy at position 2 is converted to kinetic energy.
The elastic potential energy of the spring at Position 2 is converted to kinetic energy. Option (B) is correct.
What is potential energy?The energy held within an object is known as potential energy. There are several different types of potential energy, including gravitational potential energy, elastic potential energy, and electric potential energy.
Here, the energy that an object possesses as a result of its position in relation to other objects is referred to as its gravitational potential energy.
Elastic potential energy is the energy that an object possesses as a result of the stresses that exist inside its body.
At Position 2, the elastic potential energy of the spring is converted to kinetic energy.
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what can be done not to let anyone of the country be hungry and clothless discuss in groups and present your findings in the class
...get food to people in need when they need it...
a spring vibrates 120 times in 2 mins find its frequency and time period
2 minutes is 120 seconds, so if you were finding vibrations per minute, it would be 60 times a minute.
15. A boy on board a cruise ship drops a 30.0 gram marble into the ocean. If the resistive force proportionality
constant is 0.50 kg/s, what is the terminal speed of the marble in m/s?
a. 0.06
b. 0.294
c.0.588
d. 60.0
e. 588.0
In star wars, john williams used the __________ concept of romantic opera in which a character is assigned a short melody. so, famous characters like darth vader, princess leia, and han solo all have their own melody.
In Star Wars, John Williams used the Leitmotif concept of romantic opera in which a character is assigned a short melody.
It is used for famous characters like Darth Vader, Princess Leia, and Han Solo all have their melody.
Leitmotif is generally described as a recurring theme shown or appears over musical or literary composition.
Leitmotif is more common in operas and symphonic poems. It is attributed to a specific person, idea, or situation.
Hence, in this case, it is concluded that in the movie Star Wars, John Williams used the Leitmotif concept of romantic opera.
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which contains the particles that are vibrating fastest?
Answer:
Boiling water
Explanation:
Why is the oort cloud important for understanding the formation of the solar system?
The Oort cloud is the proximate source of observed nearly parabolic, so-called 'new' comets entering the planetary region, and is also the presumed source of the long-period comet flux and the majority of Halley-type comets (HTCs).
The oort cloud is important for understanding the formation of the solar system.
What is oort cloud?It is believed to be an important source of comets that can provide valuable information about the conditions and processes that were present in the early solar system.
Here,
The Oort Cloud is important for understanding the formation of the solar system because it is believed to be a reservoir of icy bodies that formed early in the solar system's history. These icy bodies, which include comets, are thought to have played a key role in the early evolution of the solar system by delivering water and other volatile materials to the inner solar system, including the early Earth.
By studying the composition and properties of comets from the Oort Cloud, scientists can gain insights into the formation and evolution of the solar system and learn more about the conditions that were present in the early solar system.
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A spacecraft orbiting a planet at an altitude of 120 km releases a satellite that falls towards the surface. The planet has a mass of 5.2 x 10^23 kg and a radius of 2800 km. What is the acceleration of the satellite?
Answer:
Consider a satellite with mass Msat orbiting a central body with a mass of mass MCentral. The central body could be a planet, the sun or some other large mass capable of causing sufficient acceleration on a less massive nearby object. If the satellite moves in circular motion, then the net centripetal force acting upon this orbiting satellite is given by the relationship
Fnet = ( Msat • v2 ) / R
Explanation:
The acceleration of the satellite released from a spacecraft orbiting a planet at an altitude of 120 km and the planet has a mass of 5.2 x 10^23 kg and a radius of 2800 km is 4.426 * [tex]10^6[/tex] [tex]m/s^2[/tex].
What is acceleration?
The term "acceleration" refers to the rate and direction at which velocity varies over time. Acceleration is the change in direction or speed of an object or points moving ahead. The frequent change in direction causes motion on a circle to rise even when the speed remains constant.
For all other motions, these effects increase the acceleration. A vector quantity, acceleration, is something that has both a magnitude and a direction. Velocity is a vector quantity as well.
Given:
The altitude of the spacecraft, h = 120 km,
The mass of the planet, m = [tex]5.2 * 10^{23}[/tex] kg,
The radius of the planet, r = 2800 km.
Calculate the acceleration by the formula given below,
A = [tex]G* m /r^2[/tex]
Here, A is the acceleration, G is the gravitational constant,
Substitute the values,
A = 6.674 * [tex]10^{-11}[/tex] *5.2 * [tex]10^{23}[/tex] / [tex]2800^2[/tex]
A = 4.426 * [tex]10^6[/tex] [tex]m/s^2[/tex]
Therefore, the acceleration of the satellite is 4.426 * [tex]10^6[/tex] [tex]m/s^2[/tex]
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in each of five scenarios, a 1 kg mass is attached to the end of a massless stick by a massless string. each stick is motionless. rank the torques acting on each stick due to the tension in the attached string. take the axis of rotation in each case to be the end of the stick opposite the string.
Answer:
C=A>B>E>D
Explanation:
to analyze the characteristics and performance of the brakes on a 1500 kg car, researchers collected the data shown in the table above. it shows the car’s speed when the brakes are first applied and the corresponding braking distance required to stop the car. the magnitude of the average braking force on the car is most nearly:
He magnitude of the average braking force is 12,000 N.
The braking force can be calculated using the following formula:
Braking Force = (0.5 x mass of the car x squared velocity) / distanceNow, let's use this formula to find the Braking force in each case based on the information of the chart:
F = (0.5 x 1,500 x 100) / 6.1 = 12,295F = (0.5 x 1,500 x 400) / 23.9 = 12,550F = (0.5 x 1,500 x 900) / 53.5 = 12,616Now, let's add the results and divide the result into three to find the average:
12,295 + 12,550 + 12,616 = 37,461/ 3 = 12,487From these, the option that is the most similar is C 12,000 N
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In your own words, explain why elements
such as gold and silver are so rare to be
found in our Universe or within the Earth?
A boy throws a tennis ball of mass 3kg at a wall with velocity of 40m/s.If it bounces back with 35m/s in an impact that lasted for 0.01s the change in its linear momentum and the force exerted on the tennis by the wall are
Answer:
The change in the linear momentum is 225 kg.m/s and the force exerted on the tennis ball is 22,500 N.
Explanation:
What is linear momentum?Linear momentum is the measure of a body's motion. Every object that has mass and moves at any velocity has linear momentum. Here are some examples of everyday life: falling balls, launching rockets, driving a car etc.
Now let's attack the problem.
First, we got to write the data down:
[tex]\bullet \quad m=3\,kg\\\\\bullet \quad v_o=40\,m/s\\\\\bullet \quad v=35\,m/s\\\\\bullet \quad \Delta t =0.01\,s[/tex]
We can write the change in linear momentum of the tennis ball as follows:
[tex]\Delta p = p-p_o[/tex]
The ball's momentum is equal to its mass times its velocity. Hence:
[tex]\Delta p= m\cdot v-m\cdot v_o[/tex]
Let's set the reference system as positive to left (see picture attached). For that purpose, when the ball bounces back its velocity changes sign.
Now, we are able to plug in the data:
[tex]\Delta p = 3\cdot 35 - 3\cdot(-40)\\\\\\\Delta p = 105+120\\\\\\\therefore \boxed{\Delta p =225\,kg\cdot m/s}[/tex]
To calculate the exerted force, we must apply the impulse theorem, which states that impulse equals the change in linear momentum of an object. We get:
[tex]\mathbb{I}=\Delta p[/tex]
Hence,
[tex]F \cdot \Delta t=\Delta p\\\\\\F\cdot 0.01=225\\\\\\F=\dfrac{225}{0.01}\\\\\\\therefore \boxed{F=22,\!500\,N}[/tex]
Conclusion: the change in linear momentum is 225 kg . m/s and the exerted force is 22,500 N.
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una fila di ballerini lunga complessivamente 2,3 m sta avvicinandosi perpendicolarmente a uno specchio. Se il primo ballerino, essendo miope, percepisce i contorni in modo nitido degli oggetti lontani al massimo 6 m, a quale distanza dallo specchio comincerà a vedere chiaramente l'ultimo ballerino della fila?
Answer:
A Benjamin Franklin
B George Washington
C Abraham Lincoln
D John Adams
what is occurring when a light wave goes through a pane of glass in a window?
Answer:
transmission: the passing of a wave through an object
Explanation:
Friction force affects the work done by the applied force.
T OR F
Answer:
TRUE.
Explanation:
YES IT EFFECTS.
IT MAY HELP YOU.
Answer:
True
Explanation:
true because if you where to push a ball on a beach the friction with the sand would make it harder to push then being on concrete.
Two rocks are at the top of a building. Rock 1 is dropped from rest while Rock 2 is thrown horizontally at a velocity of 5 m/s.What is the horizontal acceleration of Rock 2
The horizontal acceleration of the rock 2 is zero.
The given parameters;
initial velocity of Rock 1 = 0
initial horizontal velocity of Rock 2 = 5 m/s
An object falling under the influence of gravity experiences acceleration due to gravity which is always directed vertically downwards.
An object moving horizontally is not affected by gravity and thus will experience no acceleration in the horizontal direction.
Thus, we can conclude that the horizontal acceleration of the rock 2 is zero.
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who invented the first telescope
Answer:
Hans Lipperhey
....................................
A cheetah running initially at a velocity of 20 m/s accelerates
uniformly at 3.0 m/s. The velocity of the cheetah will be
m/s after 4.0 seconds.
Answer: I think it’s 32 m/s
Explanation: Vi=20 m/s
Vf=?
a=3.0 m/s^2
t= 4s
Vf= Vi + at
Vf= 20 m/s + (3 m/s^2)(4s)
Vf= 20 m/s + 12m/s
Vf= 32m/s
If A cheetah running initially at a velocity of 20 m/s accelerates
uniformly at 3.0 m/s2. The velocity of the cheetah after 4.0 seconds will be 32 m/s.
To find the velocity of the cheetah after some time we can use the formula:
v = u + at
where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Given:
Initial velocity (u) = 20 m/s
Acceleration (a) = 3.0 m/s²
Time (t) = 4.0 seconds
now we can put values in eq.
v = 20 m/s + (3.0 m/s²) * 4.0 s
v = 20 m/s + 12 m/s
v = 32 m/s
so the answer is 32 m/s.
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The graph below represents the relationship between velocity and time of travel for a toy car moving in a straight line.the shaded area under the line represents the toy cars
Answer:
Displacement
Explanation:
The definition of speed and the graphical analysis allows to find the result for the question of the meaning of the area under the curve is:
The area corresponds to the displacement of the body.
Velocity is defined as the variation of position with respect to time.
[tex]v = \frac{dx}{dt}[/tex]
Where v is the velocity, x the displacement and t the time.
If we make a graph of speed versus time, see attached, where we have a diagram of the process.
The expression of the velocity for the case of zero acceleration is
[tex]v = \frac{\Delta x}{\Delta t }[/tex]
Δx = v Δt
They indicate that the shaded section is under the curve, therefore it is
Area = Δv Δt
When comparing the two expressions they are equivalent, therefore the area is equal to the distance traveled.
In conclusion, using the definition of velocity and graphical analysis we can find the result for the question of the meaning of the area under the curve is:
The area corresponds to the displacement of the body.
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Physics - Vectors-- Could you help me please?
Answer:
please share the question
Explanation:
please someone should help me and solve this is under Hooke's law
[tex]F=k(l_1-l_2)[/tex]
[tex]10=5k[/tex]
[tex]k=2[/tex]
[tex]15=2*(30-l_2)[/tex]
[tex]15=60-2l_2[/tex]
[tex]2l_2=45[/tex]
[tex]l_2=22,5cm[/tex]
which of the following is a selectively permeable membrane?
a) nulcer membrane
b) plasma membrane
c) cell wall
d)none of these
Answer:
B
Explanation:
The plasma membrane is a selectively premeable membrane that chooses what goes in and out of the cell. The cell wall is for support and the nuclear membrane decides what goes in and out of the nucleus
Answer:
Plasma membrane
Explanation:
The plasma membrane consists of a lipid bilayer that is semipermeable.The plasma membrane regulates the transport of materials entering and exiting the cell.So, it is selectively permeable membrane.
Why does the force between the locomotive and the first car always have to be larger
than the force between the first car and the second?
Answer:
Because the locomotive does most of the pulling
An airplane during departure has a constant acceleration of 3 m / s².
a. What is the speed that the plane reaches in 4 s?
b. If the plane passes at a flight point of
at a speed of 20 m / s, what is the speed 8 s later?
Constant acceleration of plane = 3m/s²
a) Speed of the plane after 4s
Acceleration = speed/time
3m/s² = speed/4s
S = 12m/s
The speed of the plane after 4s is 12m/s.
b) Flight point will be termed as the point the plane got initial speed, u, 20m/s
Find speed after 8s, v
a = 3m/s²
from,
a = v - u
t
3 = v - 20
8
24 = v - 20
v = 44m/s
After 8s the plane would've 44m/s speed.
A car accelerated from rest in 3.07s. During this time, the car went 46m forward. What was its acceleration?
_______m/s/s
