a plane flies from Addis Ababa to Gamble is 400km. in 2 hrs, then straight back to Gamma is 200km. in 1hrs what is the average speed, average velocity, total distance and total displacement​

Answers

Answer 1

Answer:

a) Average speed = 200 Km/hr

b) Average velocity = 0 m/s

c) Total distance = 800 Km

d) Total displacement = 0 Km

Explanation:

a) Let the speed of the plane from Addis Ababa to Gamble be represented by [tex]S_{1}[/tex], and from Gamble to Addis Ababa by [tex]S_{2}[/tex].

Average speed = [tex]\frac{S_{1} + S_{2} }{2}[/tex]

[tex]S_{1}[/tex] = [tex]\frac{distance}{time}[/tex] = [tex]\frac{400}{2}[/tex]

        = 200 Km/hr

[tex]S_{2}[/tex] = [tex]\frac{distance}{time}[/tex] = [tex]\frac{200}{1}[/tex]

       = 200 Km/hr

Average speed = [tex]\frac{200 + 200}{2}[/tex]

        = 200 Km/hr

b) Velocity = [tex]\frac{displacement}{time}[/tex]

Average velocity = [tex]\frac{total displacement}{total time taken}[/tex]

Since the plane flies from Addis Ababa to Gamble, then back to Addis Ababa, its total displacement is zero.

So that,

Average velocity = 0 m/s

c) Total distance = 400 Km + 400 Km

                           = 800 Km

d) Total displacement = 400 Km + (-400 Km)

                           = 0 Km


Related Questions

Suppose that a single guitar player makes noise at 70 dB. If two guitar players play at the same time, the noise level will be approximately 73 dB. How many guitar players will it take for the sound intensity level to be 100 dB

Answers

Answer: it will take 1000 guitar players for sound intensity level to be 100 dB

Explanation:

Given that;

noise level of a single player = 70 dB

Intensity of one guitar will be;

SL= 10 × log(I/I₀)

where I₀ is hum threshold intensity = 10⁻¹² W/m²

I is intensity of sound produced by 1 guitar

SL is intensity level of one guitar

so we substitute

70 = 10 × log(I/10⁻¹²)

70/10 = log (I/10⁻¹²)

I = 10⁻¹² × 10⁷

I = 10⁻⁵ W/m²  

now Suppose n guitars produce sound intensity of 100 dB, then intensity of n guitars (In) will be;

100 = 10 × log(In/10⁻¹²)

log(In/10⁻¹²)  = 100/10

In = 10⁻¹² × 10¹⁰ =  10⁻² Wm²

we know that Now intensity of 1 guitar I = 10⁻⁵ W/m²

so Intensity of n guitars will be;

n × I = In

n = In / I

we substitute

n = 10⁻² Wm² /  10⁻⁵ W/m²

n = 1000

Therefore, it will take 1000 guitar players for sound intensity level to be 100 dB

 

What is periodic motion?​

Answers

Answer:

Periodic Motion :–

This is a type of motion where the object repeats its motion after a fixed interval of time.

Examples: pendulum of a clock, motion of child on a swing etc.

Answer:

Periodic motion is a type of motion that is being performed. You can take a rocking chair, bouncing ball, and a swing as an example of periodic motion.

Periodic motion is just another word for the motion because it describes any type of object performing movements even an object vibrating is another great example of periodic motion. If you want to talk about the motion of the universe take Earth and the moon orbiting around the sun it is an object performing.

Hope this helped :)

Need help ASAPPPPP plssssss giving big points

Answers

Answer:

average

Explanation:

A 3.50-g bullet has a muzzle velocity of 250 m/s when fired by a rifle with a weight of 25.0 N. (a) Determine the recoil speed of the rifle. m/s (b) If a marksman with a weight of 650 N holds the rifle firmly against his shoulder, determine the recoil speed of the shooter and rifle.

Answers

Answer:

(a) 0.343 m/s

(b) 0.012 m/s

Explanation:

(a) From the question above,

MV = mv............................... Equation 1

Where M = mass of the rifle, V = recoiling speed of the rifle, m = mass of the bullet, v = velocity of the bullet.

make V the subject of the equation

V = mv/M........................... Equation 2

Given: m = 3.5 g = 0.0035 kg, v = 250 m/s, M = 25 N = 25/9.8 = 2.55 kg.

Substitute into equation 2

V = (0.0035×250)/2.55

V = 0.343 m/s.

(b) Similarly,

(M'+M)V' = mv....................... Equation 3

Where M' = mass of the marksman, V' = recoiling speed of the shooter and rifle

make V' the subject of the equation

V' = mv/(M'+M)................... Equation 4

Given: m = 3.5 g = 0.0035 kg, v = 250 m/s, M = 25 N = 25/9.8 = 2.55 kg, M' = 650 N = 650/9.8 = 66.33 N

Substitute into equation 4

V' = (0.0035×250)/(66.33+2.55)

V' = 0.8125/68.88

V' = 0.012 m/s

The recoil velocity can be obtained using the principle of conservation of linear momentum.

Using the principle of conservation of linear momentum;

momentum before collision = momentum after collision

Mass of the bullet = 3.50-g or 0.0035 Kg

Mass of the rifle = 2.5 Kg

Where;

M1 = mass of rifle

M2 = mass of bullet

u1 =initial velocity of rife

u2 = initial velocity of the bullet

(2.5 × 0) + (0.0035 × 250) = (0.0035 × 0) + (2.5 × v)

0.875 = 2.5 v

v = 0.35 m/s

For the shooter and the rifle;

(67.5 × 0) + (0.0035 × 250) =  (0.0035 × 0) + (67.5 × v)

0.875 = 67.5 × v

v = 0.013 m/s

Learn more about momentum: https://brainly.com/question/904448

An object on the end of a spring with spring constant k moves in simple harmonic motion with amplitude A and frequency f. Which of the following is a possible expression for the kinetic energy of the object as a function of time t?

a. kA^2sin^(2πft)
b. 1/2kA^2cos^2(2πft)
c. 1/2kA sin(2πft)
d. kAcos(2πft)
e. 1/2kAsin(2πft)

Answers

The expression for the kinetic energy of the object as a function of time, t is [tex]K.E = \frac{1}{2} k A^2 \ cos^2 \ (2\pi ft)[/tex].

The general wave equation is given as;

[tex]x = A \ cso(\omega t)\\\\x = A \ cos(2 \pi ft)[/tex]

Apply the principle of conservation of energy, the kinetic energy of a particle in such motion is given as;

[tex]K.E = U_x\\\\K.E = \frac{1}{2} kx^2[/tex]

Substitute the value of x into the kinetic energy equation

[tex]K.E = \frac{1}{2} kx^2\\\\K.E = \frac{1}{2} k ( A \ cos (2\pi ft)^2\\\\K.E = \frac{1}{2} k A^2 \ cos^2 \ (2\pi ft)[/tex]

Thus, the expression for the kinetic energy of the object as a function of time, t is [tex]K.E = \frac{1}{2} k A^2 \ cos^2 \ (2\pi ft)[/tex].

Learn more here:https://brainly.com/question/13736293

The potential difference between points A and B in an electric

field is 25.0 volts. How much work is required to transfer 10.0

coulombs of charge from A to B?

Answers

Answer:

Work = 250 Joules.

Explanation:

Given the following data;

Potential difference, V = 25V

Charge, C = 10 Coulombs

To find the work required;

Work = Charge * potential difference

Substituting into the equation, we have

Work = 10*25

Work = 250 Joules.

Therefore, the amount of work required to move the charge from A to B is 250 Joules.

can i eat air? im hungry

Answers

Answer:

Yes

Explanation:

Which observation is the best evidence that some colors of visible light are
being absorbed in this photo?
A. The man's head is distorted under the water.
B. The top of the man's head appears disconnected.
C. The shape of the man's arm is clearly seen underwater.
D. The snorkel in the man's mouth appears yellow.

Answers

Answer:

D-The snorkel in the mans mouth appears yellow

Explanation:

Answer D is the only example related visible light being absorbed.

If the wrench is initially displaced 0.400 rad from its equilibrium position, what is the angular speed of the wrench as it passes through the equilibrium position

Answers

This question is incomplete, the complete question is;

1.80 kg monkey wrench is pivoted 0.250 m from its center of mass and allowed to swing as a physical pendulum. the period for small angle oscillations is 0.940 s.

a) what is the moment of inertia of the wrench about an axis through the pivot?

b) If the wrench is initially displaced 0.400 rad from its equilibrium position, what is the angular speed of the wrench as it passes through the equilibrium position

Answer:

a) the moment of inertia of the wrench about an axis through the pivot is 0.0987 Kg.m²

b) the angular speed of the wrench as it passes through the equilibrium position is 2.6559 rad/s

Explanation:

Given that

mass m = 1.80 kg

L or d = 0.250 m

period T = 0.940 sec

g = 9.8

a)

we take a look at the expression for the moment of inertia

I = T²mgL / 4π²

we substitute

I = ((0.940)² × 1.80 × 9.8 × 0.250) / 4 × π²

I = 3.896676 / 4 × π²

I = 0.0987 Kg.m²

Therefore the moment of inertia of the wrench about an axis through the pivot is 0.0987 Kg.m²

b)

If the wrench is initially displaced 0.400 rad from its equilibrium position,

the angular speed of the wrench as it passes through the equilibrium position = ?

Using conservation of energy;

mg × d × ( 1 - cos∅) = 1/2×I×w²

we substitute

1.80 × 9.8 × 0.250 × ( 1 - cos(0.400 rad)) =  1/2 × 0.0987  × w²

4.41 × ( 1 - 0.921060994 ) = 0.04935 × w²

0.000441 = 0.04935w²

w² = 0.3481 / 0.04935

w² = 7.0536

w = √7.0536

w = 2.6559 rad/s

Therefore, the angular speed of the wrench as it passes through the equilibrium position is 2.6559 rad/s

importance of choke coil?

Answers

Answer:The choke coil works because it can act as an inductor. When the current pass through will change as AC currents creates a magnetic field in the coil that works against that current. This is known as inductance and blocks most of the AC current from passing through.

Explanation:

I need help with science

Answers

Answer:

Ca = 2

Cl = 2

O = 6

Explanation:

Element given from the question above include = 2CaClO₃

NOTE: The 2 in front of CaClO₃ is affecting Ca, Cl and O.

Thus, the number of each atom of element present in 2CaClO₃ can be obtained as follow:

Ca = 1 × 2 = 2

Cl = 1 × 2 = 2

O = 3 × 2 = 6

Thus,

Ca = 2

Cl = 2

O = 6

The asteroid Icarus orbits the sun like other planets. Its period is about 410 days. What is its mean distance from the sun

Answers

Answer:

Mean distance = 1.61 x 10^8 km

Explanation:

Given the following data;

Orbital period for Icarus, T2 = 410 days

To find the mean distance of Icarus, we would use Kepler's third law of motion.

According to Kepler's third law of planetary motion, the square of any planetary body's orbital period (P) is directly proportional to the cube of its orbit's semi-major axis.

Mathematically, it is given by the formula;

[tex] (\frac {T_{1}}{T_{2}})^2 = (\frac {r_{1}}{r_{2}})^3 [/tex]

Where;

T1 & T2 is the orbital period of a planetary object.

r1 & r2 is the mean distance of a planetary object.

Also, we know that the orbital period for earth, T1 = 365 days

Mean distance of earth = 1.49x10^8 km

Substituting into the equation, we have;

[tex] (\frac {365}{410})^2 = (\frac {1.49x10^{8}}{r_{2}})^3 [/tex]

[tex] (\frac {365}{410}})^2 = (\frac {1.49x10^{8}}{r_{2}})^3 [/tex]

[tex] (0.8902)^2 = (\frac {1.49x10^{8}}{r_{2}})^3 [/tex]

[tex] (0.7925) = (\frac {1.49x10^{8}}{r_{2}})^3 [/tex]

Cross-multiplying, we have;

[tex] (r_{2})^3 = \frac {1.49x10^{8}}{0.7925} [/tex]

Taking the cube root of both sides;

[tex] r_{2} = 1.61 * 10^8 km[/tex]


When Coach Kwan notices that a player is getting tired, she takes out the tired player and substitutes a fresh player.
Which type of chemical reaction does this best model?

Answers

The answer is a




If you can’t get the correct answer, this is on edg


Answer:

is replacement

Explanation:

Which hormone is released by the pancreas to reduce blood glucose levels?
Glucagon
Insulin
Glycogen

Answers

Answer:

Insulin.

Explanation:

The most important hormone that the pancreas produces is insulin. Insulin is released by the 'beta cells' in the islets of Langerhans in response to food. Its role is to lower glucose levels in the bloodstream and promote the storage of glucose in fat, muscle, liver and other body tissues.

John is conducting an experiment that involves melting ice cubes. Which of the following is most important for John to collect reliable data?
A.The outcome needs to be controlled.

B.An unbiased observer must witness the experiment.

C.Technology needs to be used to determine the results.

D.Only one variable should be tested during the experiment.

Answers

Answer:

Hmmmm

Explanation:

Answer:

B

Explanation:

1. Each of four boys were given
some marbles.
have
day.
punc
exan
class
Joe: sixth multiple of eight
Khal: quarter of a gross
mar
Tate: 4 dozen
Tevin: one score plus a dozen
Which two boys r3eceived the same
number of marbles?
A. Joe and Tate
B. Joe and Khal
C. Tate and Tevin
D. Joe and Tevin​

Answers

Answer:

the answer is A because

from tate 4 dozen is 48 and from joe the sixth multiple of eight is 48

A small glass bead has been charged to 8.0 nC (nano-Coulombs). What is the magnitude of the electric field 2.0 m from the center of the bead

Answers

Given :

Charge on glass bead, Q = 8 nC .

To Find :

The magnitude of the electric field 2.0 m from the center of the bead.

Solution :

Electric field at position r is given by :

[tex]E = \dfrac{kQ}{r^2}\\\\E = \dfrac{9\times 10^9\times 8\times 10^{-9}}{2^2}\\\\E = 18\ N/C[/tex]

Therefore, the magnitude of the electric field 2.0 m from the center of the bead is 18 N/C .

When you mix two substances, the heat gained by one substance is equalto the heat lost by the other substance. Suppose you place 125 g of aluminum ina calorimeter with 1,000 g of water. The water changes temperature by 2 °C andthe aluminum changes temperature by â74.95 °C.

Required:
a. Water has a known specific heat capacity of 4.184 J/g °C. Usethe specific heat equation to find out how much heat energy the watergained (q).
b. Assume that the heat energy gained by the water is equal to the heat energy lost by the aluminum. Use the specific heat equation to solve for the specific heat of aluminum. (Hint: Because heat energy is lost, the value of q is negative.)

Answers

Answer:

A) 8,368 J

B) 0.893 J/gºC

Explanation:

A)

The heat gained by the water can be obtained solving the following equation:

       [tex]q_{g} = c_{w} * m * \Delta T (1)[/tex]

where cw = specific heat of water = 4.184 J/gºCm= mass of water = 1,000 gΔT = 2ºC Replacing these values in (1) we get:

       [tex]q_{g} = c_{w} * m * \Delta T = 4.184 J/gºC*1,000 g* 2ºC = 8,368 J (2)[/tex]

B)

Assuming that the heat energy gained by the water is equal to the one lost by the aluminum, we can use the same equation, taking into account that the energy is lost by the aluminum, so the sign is negative:  -8,368 J.Replacing by the mass of aluminum (125 g), and the change in temperature (-74.95ºC), in (1), we can solve for the specific heat of aluminum, as follows:

       [tex]q_{l} = c_{Al} * m_{Al} * \Delta T (3)[/tex]

⇒    [tex]-8,368 J = c_{Al}* 125 g * (-74.95ºC) (4)[/tex]

       [tex]c_{Al} = \frac{-8,368J}{125g*(-74.95ºC} = 0.893 J/gºC (5)[/tex]

Answer:

A: the heat gained is 8368 J (8.368 KJ)

B: 0.893 J/g°C

Explanation:

A:

q = ?

m = 1000 g

C = 4.184 J/g°C

△T = 2°C

q = mc△T

q = (1000g) (4.184 J/g °C) (2 °C)

q = 8368 J

B:

q = mc△T

---------------

△T    △T

c = q / m△T

c = - 8368 J / (125 g) (-74.95 °C)

c = 0.893 J/g°C

Does the mass of an object make it need more force to move, and to stop?

Answers

Answer:

Yea

Explanation:

Let's compare a brick to a small table, does it take more force and strength to push a car or a small table? A car, because it's heavier and has more mass.

Answer:

Heavier objects (objects with more mass) are more difficult to move and stop. Heavier objects (greater mass) resist change more than lighter objects. Example: Pushing a bicycle or a Cadillac, or stopping them once moving. The more massive the object (more inertia) the harder it is to start or stop.

Explanation:

☝️

Jane climbs the stairs to the first floor all by herself in a certain time. If the next time she rides the elevator to the first floor then which of the following statements is true?

The work done in both cases are different
the time taken in both cases is the same
the power in both cases is the same.
the work done in both cases is the same.

Answers

Answer:

the power in both cases is the same.

Explanation:

hope helps you

thanksss

look at the diagram below

Which statement is correct about Ray 1?

Answers

I believe it’s 1 aka A part of it is reflected as Ray 2

The student wants to collect data to determine the work done by the force due to gravity on the object as it falls. Which of the following lists contains the fewest number of measuring devices, in addition to the motion detector, that the student can use?
A - spring scale
B - spring scale and meterstick
C - stopwatch and meterstick
D - spring scale, meterstick, and stopwatch

Answers

Answer:

B - spring scale and meterstick

Explanation:

The work done by the force of gravity as the object falls is equal to the potential energy of the object.

We know that the gravitational potential energy(PE) of an object is obtained by;

PE =mgΔh

Where;

m = mass of the object

g = acceleration due to gravity

h= height of the object

The spring scale is needed to measure the mass of the object while the meterstick measures the Δh in meters.

Answer:

B

Explanation:

w= fd

f: spring scale

d: meterstick

Drop a comment if you have any questions! :)

When Pluto was classified as a planet it was known as a oddball planet why? Why is it less if an oddball now?

Answers

Answer:

a strange world that has baffled scientists ever since it was discovered in 1930. It is not the large gas giant that one might expect to find in the outer reaches of the solar system.

Explanation:

Explanation

58) Two balls, A and B are simultaneously projected from the top
of a building at 10 mis upwards & 20 m/s downwards respectively. Find
out the separation btwn them 3 sec after projection.

Answers

Answer:

90 m

Explanation:

For ball A::

The equation of a ball moving upwards is given by the formula:

s = ut - (1/2)gt²

where u is the initial velocity, t is the time covered, g is the acceleration due to gravity = 10 m/s² and s is the distance travelled.

Given that:

u = 10 m/s, t = 3 sec, g = 10 m/s², hence:

s = (10 * 3) - (1/2) * 10 * 3²

s = 30 - 45

s = -15 m

The negative sign means the object travels in the opposite direction. Hence s = 15 m

For ball B::

The equation of a ball falling downwards is given by the formula:

s = ut + (1/2)gt²

Given that:

u = 10 m/s, t = 3 sec, g = 10 m/s², hence:

s = (10 * 3) + (1/2) * 10 * 3²

s = 30 + 45

s = 75 m

Hence the separation between the two balls after 3 sec of projection = 15 m + 75 m = 90 m

which terms correctly represent a vector quantity and its respective unit

Answers

Answer:

Explanation:

The best terms that represent vector quantity are magnitude and direction. Magnitude and direction are both qualities in vector quantity. The basic measurement of vector quantity is the meter all others would best be described as scalars. So to best describe vector quantity use the meter uni

A man walks 10 km north, turns around and walks 5 km south. What displacement did the man walk?

A. 10km S
B. 5km N
C. 15km N
D. 5km S

Answers

Answer:

The total displacement is 5 km North (answer B)

Explanation:

Recall that displacement is defined by the vector formula:

Displacement = Final position - initial position

Which corresponds to a vector with its tail at the starting point, and the arrow at the final position. This gives a vector pointing North, and of length 5 km.

This agrees with answer labeled B.

According to Coulomb's Law, how does distance affect the electric force?
A. The electric force only acts on objects that are in contact with
each other.
B. Only in charging by induction can the electric force act at a
distance.
C. Electric force gets stronger as charges get closer together and
gets weaker as charges move farther apart.
D. The electric force is zero if the objects are more than several
centimeters apart.

Answers

Answer:

C option is right.

Explanation:

According to columb's law

F ∝ 1/r²

so as r means distance between charges decrease force F increase and vice versa.

C is the correct answer

What is my name?:

I am a god

I am a guardian of the sun

I am used to measure heat.

Answers

Answer:

Apllo?

Explanation:

Helios??? Apollo??? I really don’t know? Hi

Henry is researching the efficacy of a new drug for treating agoraphobia (fear of public places). His assistant, who is unaware of the study’s purpose, randomly assigns half of his 200 subjects a 30 day supply of the drug (Fearnot) and the other half a 30 day supply of a placebo (i.e., sugar pill). A month later the subjects are given a questionnaire to rate their fear of being in public. Henry finds that there is no difference between the two groups in their level of fear. How many subjects participated in this study?

Answers

Uvuvy u uh oh iyvuvu

A child pulls a wagon at a constant velocity of 4.0 m/s for 4.0 minutes along a level sidewalk. The child does this applying a 22 N force to the wagon handle, which is inclined at 35 ° to the sidewalk as shown below. How much work does the child do on the wagon ?
288 k J
8.7 kJ
17.3 kJ
2.3 kJ

Answers

Answer:

288kj

Explanation:

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