A paper company ships notepads in rectangular boxes that have dimensions measuring 9 inches long, 9 inches wide, and 10 inches tall. Show work. Complete sentences.
V = LWH The volume of a rectangular prism / cube is equal to the length times the width times the height.
a. What is the volume of the box?

b. Each notepad is in the shape of a cube with an edge length of 3 inches. What is the volume of each notepad?

c. What is the maximum number of notepads that will fit in 1 closed box
i will give brainliest :)

Answer:

100

Step-by-step explanation:

well you can put 5 students in each class guaranteed 5 times over so it would make sense because 5 for each class 9th-12th 5 times over again and again will eventually give you the answer of 100 5•20

If we take 5 students are in each class.

Then let minimum number of students be x

ATQ

1/20()x = 5

x = 5 × 20

x = 100

Answer: 100 people

Must click thanks and mark brainliest

Answer:

m = 12.5

Step-by-step explanation:

x = - 3

(3m - x) 2= 81

(3m - (-3)) 2= 81

(3m + 3) 2= 81

6m + 6  = 81

      - 6     - 6

6m = 75

[tex]\frac{6m}{6}[/tex] = [tex]\frac{75}{6}[/tex]

m = 12.5

hope this helps! if you have an questions, pls let me know!

Answer:

B. x = -3 and x = 4

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

f(x) = x² - x - 12

Step 2: Solve for x

Answer:

Hi!

Step-by-step explanation:

1234567890987654211234567890......

Step-by-step explanation:

12345678890098764321

Answer:

a) The rocket travels 200 meters horizontally.

b) The height of the rocket mid-flight is of 1000 meters.

Step-by-step explanation:

Height of the rocket:

The height of the rocket, in meters, after an horizontal distance of x, is given by:

[tex]y = 0.1x(200 - x)[/tex]

a) How far does the rocket travel horizontally?

This is x when [tex]y = 0[/tex]. So

[tex]0.1x(200 - x) = 0[/tex]

Then

[tex]0.1x = 0[/tex]

[tex]x = 0[/tex]

And

[tex]200 - x = 0[/tex]

[tex]x = 200[/tex]

So

The rocket travels 200 meters horizontally.

b How high does the rocket reach mid-flight?

This it the height y when x = 0, so:

[tex]y = 20*100 - 0.1*100^2 = 1000[/tex]

The height of the rocket mid-flight is of 1000 meters.

The order of rotational symmetry for the figure will be 2. The correct option is A.

A shape exhibits rotational symmetry when it retains its appearance following a little amount of rotation by a partial turn. The number of different orientations in which an object appears exactly the same for each rotation is known as the degree of rotational symmetry.

The number of full rotations a shape may undergo while maintaining its appearance is its order of rotational symmetry. The triangle never seems the same after being rotated a complete 360 degrees, with the exception of when it is returned to its original starting position.

Therefore, the order of rotational symmetry for the figure will be 2. The correct option is A.

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Answer:

1.572

Step-by-step explanation:

For a standard normal distribution,

P(z > c) = 0.058

To obtain C ; we find the Zscore corresponding to the proportion given, which is to the right of the distribution ;

Using technology or table,

Zscore equivalent to P(Z > c) = 0.058 is 1.572

Hence, c = 1.572

Answer:

There are 21 people in the line (including Kollam himself).

Answer:

2.3

Step-by-step explanation:

.5 - .3 = .2

.8 - .5 = .3

1.2 - .8 = .4

1.7 - 1.2 = .5

We should add .6 next

1.7+.6 = 2.3

Answer:

A. x = 1/2

General Formulas and Concepts:

Pre-Algebra

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

4x² + 3 = 4x + 2

Step 2: Solve for x

Answer:

B

Step-by-step explanation:

Use pythagorean theorem

4^2+5^2=AC^2, AC= 6.4

7^2+9^2=CB^2, CB=11.4

9514 1404 393

Answer:

  a. Definition of bisector.

Step-by-step explanation:

Line l is a line through the midpoint M. We can conclude it is a bisector, because, by definition, a bisector is a line through the midpoint.

The conclusion is justified by the definition of a bisector.

Answer:

1

step by step explanation

hope this helps :)

Answer:

[tex]s=6\sqrt{3}[/tex]

Step-by-step explanation:

In any 30-60-90 triangles, the sides are in ratio [tex]x:x\sqrt{3}:2x[/tex], where [tex]x[/tex] is the side opposite to the 30 degree angle and [tex]2x[/tex] is the hypotenuse of the triangle.

In the given diagram, the hypotenuse is marked as 12 miles. Therefore, the side opposite to the 30 degree angle must be [tex]12 \div 2=6[/tex] miles. The final leg, [tex]s[/tex], must then represent the [tex]x\sqrt{3}[/tex] part of our ratio, hence [tex]\implies \boxed{6\sqrt{3}}[/tex]

The range is virtually the answer to the question,

"In which interval can find all y-values of the function".

So you look at the y-axis and see that your function begins with [tex]y=-5[/tex] (including -5 because of the dot on the graph) and ends at including [tex]y=-1[/tex].

So the interval notation is,

[tex]y\in[-5,-1][/tex]

But you are asked to specify the set notation of the interval, to do so first rewrite the interval using inequality operators, say we find some y in between (and including) -5 and -1,

[tex]-5\leq y\leq-1[/tex]

To specify that this is a set use curly bracelets and a bar,

[tex]\{y\mid-5\leq y\leq-1\}[/tex].

The y before bar is a step function and everything followed after the vertical bar is the range of the step function.

Hope this helps.

Using it's concept, it is found that the range of f(x) is given by:

{y|-5 <= -y <= -1}

The range of a function is the set that contains all possible output values. In a graph, it is given by the values of y, that is, the values of the vertical axis.

In the function described by this graph, the vertical axis assumes values between -1 and -5, inclusive, hence the range is given by:

{y|-5 <= -y <= -1}

More can be learned about the range of a function at https://brainly.com/question/24374080

Answer:

d. The average exam scores for each group.

Step-by-step explanation:

The dependent variable, also called the measured or predicted variable is the variable which is being tested or measured in an experiment. It is the variable with which an experiment is being conducted. The outcome of the dependent variable however, relies on another variable called the independent variable.changes in the independent variable affects the outcome of the dependent variable. In the scenario above, the dependent variable is the average exam scores obtained which depends on how the amount of lavender sprayed brings an effect. Ounces of lavender sprayed is the independent variable.

Answer:

44/3

Step-by-step explanation:

V=L*W*H

WH=22/3

V=2*(22/3)

Answer:

Compound interest is $7,037,339.2

Step-by-step explanation:

[tex]{ \boxed{ \bf{A=P(1+ \frac{r}{100} ) {}^{n} }}}[/tex]

substitute:

[tex]{ \sf{ = 50000(1 + \frac{6.4}{100}) {}^{10} }} \\ \\ = { \sf{50000(1.64) {}^{10} }} \\ \\ { = \sf{7037339.2}}[/tex]

Answer:

0.1008 = 10.08% probability of thunderstorms on both memorial day and independence day.

Step-by-step explanation:

Probability of independent events:

If two events are independent, the probability of both happening is the multiplication of the probabilities of each happening, that is:

[tex]P(A \cap B) = P(A)P(B)[/tex]

In this question:

Event A: Thunderstorm on memorial day.

Event B: Thunderstorm on memorial day

The probability of a thunderstorm on memorial day 0.72

This means that [tex]P(A) = 0.72[/tex]

The probability of a thunderstorm on independance day is 0.14.

This means that [tex]P(B) = 0.14[/tex]

What is the probability of thunderstorms on both memorial day and independence day?

[tex]P(A \cap B) = P(A)P(B) = 0.72*0.14 = 0.1008[/tex]

0.1008 = 10.08% probability of thunderstorms on both memorial day and independence day.

Probabilities are used to determine the chances of events

The probability of thunderstorm on both days is 0.1008

Represent the event that there is thunderstorm on Memorial Day with A, and the event that there is thunderstorm on Independence Day with B

So, we have:

P(A) = 0.72

P(B) = 0.14

The probability of thunderstorm on both days is then calculated as;

P(Both) = P(A) * P(B) - P(A or B)

Given that the events are independent, the equation becomes

P(Both) = P(A) * P(B)

So, we have:

P(Both) = 0.72 * 0.14

Multiply

P(Both) = 0.1008

Hence, the probability of thunderstorm on both days is 0.1008

Read more about probabilities at:

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Answer:

P( yellow) =  8/23

P( blue or green) =  9/23

P(orange) = 0

Step-by-step explanation:

6 red, 5 green, 4 blue, and 8 yellow M&M's = 23  total

P( yellow) = yellow / total = 8/23

P( blue or green) = (blue+green) / total = (5+4)/23 = 9/23

P(orange) = orange/ total = 0/23

Answer:

there are 23 m&m's.

Step-by-step explanation:

Probability of getting red is 6/23

Probability of getting  green is 5/23

Probability of getting blue is  4/23

Probability of getting yellow is 8/23

Orange = red + yellow = 6+8/23

Probability of getting Orange = 14/23

Answer:

July 4th, 1776.

Step-by-step explanation:

By issuing the Declaration of Independence, adopted by the Continental Congress on July 4, 1776, the 13 American colonies severed their political connections to Great Britain. The Declaration summarized the colonists' motivations for seeking independence.

Answer:

91

Step-by-step explanation:

269 / 3 = about 90

Peter score = 90

others could be 90,81

+1 to peter

=91

Answer:

Hi! I'll provide the answers in the explanation.

Step-by-step explanation:

a) The table is in the attachment.

b) The percentage is 40%. Looking at the table, we can see that the total of teachers who voted is 30. You'll be able to find the percentage if you divide 30/75, since 75 is the total people who took the survey.

c) The percentage is 40%. For this situation, we have to divide the total of the people who voted for NO by the teachers who voted NO. So it'll be 20/50, which is 0.4. We can simplify that and the solution is 40%.

d) It represents the students who took the survey voted NO for a later start.

Hope this helps! :D

Answer:

5. Use the following information to answer the questions.

A survey asked 75 people if they wanted a later school day start time.

45 people were students, and the rest were teachers.

50 people voted yes for the later start.

30 students voted yes for the later start.

a) Use this information to complete the frequency table. (5 points: 1 point for each cell that was not given above)

Vote YES for later start

Vote NO for later start

Total

Students

30

15

45

Teachers

20

10

30

Total

50

25

75

b) Use the completed table from Part a. What percentage of the people surveyed were teachers? (2 points)

40%

c) Use the completed table from Part a. What percentage of the people surveyed were teachers who wanted a later start time? (2 points)

40%

d) What does the number in the bolded cell represent? (1 point)

The number of students that said no to a later start.

Step-by-step explanation:

A p E x

Answer:

B Trevor isn't correct because -2i must also be a root

Step-by-step explanation:

A Trevor is correct.

B Trevor is not correct because –2i must also be a root.

C Trevor is not correct there cannot be an odd number of roots.

D Trevor is not correct because there cannot be both rational and complex roots.

statements^^^^^^

The statement that f(x) must be a polynomial with degree 3 is not necessarily true based on the given roots.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

Since one of the roots is complex (2i), it follows that the coefficients of f(x) must be complex as well, and therefore f(x) must be a polynomial with complex coefficients.

However, it is possible for f(x) to have a higher degree than 3.

For example,

The polynomial (x + 7)(x - 2i)(x + 2i)(x - 7) has degree 4 and has the given roots of -7, 2i, and 7. Therefore, f(x) could be a polynomial with degree 4 or higher.

Thus,

The statement that f(x) must be a polynomial with degree 3 is not necessarily true based on the given roots.

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Answer:

a) 0.125 = 12.5% probability that it’s not raining and there is heavy traffic and I am not late.

b) 0.2292 = 22.92% probability that I am late.

c) 0.5454 = 54.54% probability that it rained that day.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

Question a:

2/3 probability of not raining.

If not raining, 1/4 probability of heavy traffic.

1 - 0.25 = 0.75 = 3/4 probability of not late.

So

[tex]p = \frac{2}{3} \times \frac{1}{4} \times \frac{3}{4} = \frac{2}{16} = 0.125[/tex]

0.125 = 12.5% probability that it’s not raining and there is heavy traffic and I am not late.

b. What is the probability that I am late?

0.5 of (1/3)*(1/2) = 1/6(rainy and heavy traffic).

0.25 of (1/3)*(1/2) = 1/6(rainy and no traffic).

1/8 = 0.125 of (2/3)*(3/4) = 1/2(not rainy and no traffic).

0.25 of (2/3)*(1/4) = 1/6(not rainy and traffic). So

[tex]P(A) = 0.5\frac{1}{6} + 0.25\frac{1}{6} + 0.125\frac{3}{6} + 0.25\frac{1}{6} = \frac{0.5 + 0.25 + 3*0.125 + 0.25}{6} = 0.2292[/tex]

0.2292 = 22.92% probability that I am late.

c. Given that I arrived late at work, what is the probability that it rained that day?

Event A: Late

Event B: Rained

0.2292 = 22.92% probability that I am late.

This means that [tex]P(A) = 0.2292[/tex]

Probability of late and rain:

0.5 of 1/6(rain and heavy traffic).

0.25 of 1/6(rain and no traffic). So

[tex]P(A \cap B) = 0.5\frac{1}{6} + 0.25\frac{1}{6} = \frac{0.5 + 0.25}{6} = \frac{0.75}{6} = 0.125[/tex]

Probability:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.125}{0.2292} = 0.5454[/tex]

0.5454 = 54.54% probability that it rained that day.

Answer:

the the 3rd one Is the one

Answer:

2x + 30° = 40°

4x + 30° = 50°

Step-by-step explanation:

2x + 30° and 4x + 30° are complementary angles.

Complementary angles sum up to give 90°.

Therefore,

2x + 30° + 4x + 30° = 90°

Add like terms

6x + 60 = 90

6x = 90 - 60

6x = 30

6x/6 = 30/6

x = 5

✔️2x + 30°

Plug in the value of x

2(5) + 30

10 + 30

= 40°

✔️4x + 30°

4(5) + 30°

20 + 30

= 50°

Answer:

The 95% confidence interval for the true difference between the mean amounts of time spent exercising each week by people who work out in the morning and those who work out in the afternoon or evening at the three health centers is (0.5, 0.9).

Step-by-step explanation:

Before building the confidence intervals, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

In the morning:

Sample of 57, mean of 5.2, standard deviation of 0.6, so:

[tex]\mu_1 = 5.2[/tex]

[tex]s_1 = \frac{0.6}{\sqrt{57}} = 0.0795[/tex]

In the afternoon/evening:

Sample of 70, mean of 4.5, standard deviation of 0.4, so:

[tex]\mu_2 = 4.5[/tex]

[tex]s_2 = \frac{0.2}{\sqrt{70}} = 0.0239[/tex]

Distribution of the difference:

[tex]\mu = \mu_1 - \mu_2 = 5.2 - 4.5 = 0.7[/tex]

[tex]s = \sqrt{s_1^2+s_2^2} = \sqrt{0.0795^2 + 0.0239^2} = 0.083[/tex]

Confidence interval:

The confidence interval is:

[tex]\mu \pm zs[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

The lower bound of the interval is:

[tex]\mu - zs = 0.7 - 1.96*0.083 = 0.5[/tex]

The upper bound of the interval is:

[tex]\mu + zs = 0.7 + 1.96*0.083 = 0.9[/tex]

The 95% confidence interval for the true difference between the mean amounts of time spent exercising each week by people who work out in the morning and those who work out in the afternoon or evening at the three health centers is (0.5, 0.9).