A moving car hits the breaks and starts to slow down. The car was moving 35 m/s when hitting the breaks and slows at a rate of 7 m/s/s. What is the final velocity of the car after 4 seconds?

Answers

Answer 1

7 miles per second.

It would take 5 seconds to stop because 35 divided by 7 = 5.

It would slow 28 miles in 4 seconds because 7 x 4 = 28.

35 - 28 = 7.


Related Questions

The magnitude of acceleration due to gravity is

Select one:
a. 9.8 m/s

b. 8.9 m/s?

c. 4.6 m/s?

d. 9.8 m/s2

Answers

Answer:

The magnitude of acceleration is 9.8 m/s

Explanation:

Its not always in m/s^2 but in m/s due to the unit of distance and time

Can any1 tell if my answer is right

Answers

Answer:

The correct answer would be C. 5.0kg

Explanation:

The mass of an object never changes unless parts of the object are taken away. In other words, although the gravitational force is different on the moon then on the earth the mass of the object would remain the same.

effect of looping the loop​

Answers

Answer:

What does this mean? please provide more explanation when asking for help

the motion of a particle along a straight line is represented by the position versus time graph above. at which of the labeled points on the graph is the magnitude of the acceleration of the particle greatest?

Answers

Point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

On the graph, A is the point where magnitude of the acceleration of the particle is greatest as compared to other positions on the graph because the height of point A is the largest as compared to other points of the graph.

The graph shows at which point acceleration of an object is higher and lower so we can conclude that point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

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A car travels 120 miles in 12 hours. What is
the car's speed?

Select one:
O a. 10 m/s

b. 10 mph

c. 1200 mph

O d. 0.1 m/s

Answers

Answer:

I hope it will help you...

#CARRYONLERANING

Calculate the Work done if the force is 2000 Newtons
and the distance is 5 km.

Answers

Answer:

10 million joules or 10,000 KJ

Explanation:

Work= Force x Displacement

convert 5km into meters -5km=5000m

W= 2000N x 5000m

w=10,000,000 Joules

or 10,000KJ

Write a paragraph explaining how a pressurized garden sprayer works. Make sure todescribe what happens to the air pressure insidethe sprayer as it is pumped by hand.

Answers

The principle of operation of a pressurized garden sprayer is as follows;

A pressurized garden sprayer is a chamber which is filled with a liquid which can be a lubricant, paint or chemical, then filled with compressed air to allow the liquid to be sprayed at high pressure.

As it is pumped by hand, the compressed air with which it is filled serves the primary purpose of allowing the liquid to be sprayed at high pressure - an important requirement for performance characteristics of the sprayer.

Flammable liquids must not be used with such equipment.

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Which car will experience a greater KE, a car traveling at 16 m/s or a half as massive car traveling at 32 m/s

Answers

Answer:

The car that is hald as massive

Explanation:

We can use the eqation for kinetic energy to solve this problem

KE = 1/2mv^2 (where m is mass and v is velocity/speed)

Lets give the original car a mass of 100kg and use the equation

KE = 1/2(100kg)(16m/s)^2 = 12800J

and now lets find kinetic energy of the half as massive car

KE2 = 1/2(50kg)(32m/s)^2 = 25600J

From this, we find that the hald as massive car will experience a greater kinetic energy while travling at double the velocity

A stone is thrown horizontally from the top of an inclined plane (angle of inclination θ). How would I find the initial speed of the stone if it hit the plane a distance L down the slope from the point of launch?

Answers

Answer:

S = V t     where S is the horizontal distance traveled

1/2 g t^2 = H       where H is the vertical distance traveled

t^2 = 2 H / g

V^2 = S^2 / t^2 = S^2 g / (2 H) combining equations

tan theta = H / S

V^2 = S g / (2 tan theta)

Using S = L cos theta

V^2 = L g cos theta / (2 tan theta)

Giving V in terms of L and theta

Read this statement: Biotechnology uses primary clarifiers for biological nutrient removal.

Which part of the statement is not true?

Biological nutrients are found in wastewater.
Primary clarifiers remove biological nutrients.
Biological nutrients are part of biotechnology processes.
Biological nutrient removal is part of wastewater management.

Answers

Primary clarifiers removing biological nutrients is not true. Primary clarifiers

involves the use of processes such as sedimentation in order to remove

particles floating or other inorganic solids from the waste water.

Biological nutrients such as nitrogen and  phosphorus are found in waste

water and removal of these important nutrients for other uses is a part of

waste water management.

The secondary clarifiers are the ones responsible for the removal of

biological nutrients in the waste water through biofiltration etc.

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use these terms in to show they are related, radiant energy, solar collector, active solar heating system

Answers

Answer:

The term "solar collector" commonly refers to a device for solar hot water heating, but may refer to large power generating installations such as solar parabolic troughs and solar towers or non water heating devices such as solar air heaters. radiant energy is the energy of electromagnetic and gravitational radiation.Active solar heating systems use solar energy to heat a fluid;either liquid or air; and then transfer the solar heat directly to the interior space or to a storage system for later use. If the solar system cannot provide adequate space heating, an auxiliary or back-up system provides the additional heat.

a car collides with a wall. compare the forces exerted by the car on the wall and the wall on the car​

Answers

Answer:

Newton’s third law states that for every action there is an equal and opposite reaction. Based on this you can say that the car crashing into the wall would put force into the wall. However, because the wall didn’t move it gives an equal force back to the car, probably causing it to crumple.

Explanation:

Mass multiplied by acceleration produces force.

The acceleration is (v - 0)/t in this situation, where t seems to be the time it takes automobile A to come to a stop. According to Newton's third law of motion, the automobile produces this turning force of the wall, however the wall, which really is static and indestructible, forces an equal force back on the car.

According to Newton's third law, each action has an equal and opposite response. On this basis, you may deduce that a car driving into a wall would exert force on the wall. However, since the wall did not move, the automobile receives an equivalent force, causing it to collapse.

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write down 4 situations where magnets are used in our daily life​

Answers

Answer:

Magnets are used to make a tight seal on the doors to refrigerators and freezers

They power speakers in stereos, earphones, and televisions

Magnets are used to store data in computer's

magnets are used in the compass

a flashlight operates with a current of 3.0 a and a power of 4.5 W. what is the voltage of the flashlights battery?

Answers

Answer:

V=1.5V

Explanation:

p=I×V

4.5=3×V

[tex]v = \frac{4.5}{3} [/tex]

[tex]v = \frac{3}{2} [/tex]

v=1.5

Using techniques similar to the aluminum foil lab, how could you do an experiment to determine the volume of the filled soda bottle? What factors might limit the accuracy of your experiment?

Answers

Answer:

applications of density measurements. The densities of brass and aluminum will be calculated from mass and volume measurements.

Explanation:

A(n) 1700 kg car is moving along a level road at 21 m/s. The driver accelerates, and in the next 10 s the engine provides 22000 J of additional energy. If 3666.67 J of this energy must be used to overcome friction, what is the final speed of the car

Answers

The final speed of the car at the given conditions is 30.1 m/s.

The given parameters:

Mass of the car, m = 1700 kgVelocity of the car, v = 21 m/sTime of motion, t = 10 sAdditional energy provided by the engine, E₁ = 22,000 JEnergy used in overcoming friction, E₂ = 3,666.67 J

The change in the energy applied to the car is calculated as;

[tex]\Delta E = E_1 - E_2\\\\\Delta E = 22,000 \ J \ - \ 3,666.67 \ J\\\\\Delta E = 18,333.33 \ J[/tex]

The final speed of the car is calculated as follows;

[tex]\Delta E = \frac{1}{2} m(v_f^2 - v_0^2)\\\\v_f^2 - v_0^2 = \frac{2\Delta E}{m} \\\\v_f^2 = \frac{2\Delta E}{m} + v_0^2\\\\v_f = \sqrt{ \frac{2\Delta E}{m} + v_0^2} \\\\v_f = \sqrt{ \frac{2\times 18,333.4}{1700} + (21)^2} \\\\v_f = 30.1 \ m/s[/tex]

Thus, the final speed of the car at the given conditions is 30.1 m/s.

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Convert: 12 km/hr =
m/s

Answers

[tex]12~ \text{km} ~ \text{h}^{-1} = \dfrac{12 \times 1000}{3600} ~~ \text{m s}^{-1} = 3.33 ~~ \text{m s}^{-1}[/tex]

Answer:

3 1/3 or 3.3333....

Explanation:

You multiply the kilometres by 1,000 because there are 1,000 metres in a kilometre. Then you divide by 60 because there are 60 minutes per hour, and then again by 60 because 60 seconds per minute.

12,000 / 60 = 200

200 / 60 = 3.333

This is not meant to be a long, mathematically-intensive problem. If you find yourself going down that road, you might want to rethink your approach.

Answers

Answer:

rethink your approach to what?

Explanation:

a 1.0 kg ball falls from rest a distance of 15 m. what was its change in potential energy?

Answers

Answer:

147 J

Explanation:

PE = mgh

PE = (1.0)(9.8)(15)

PE = 147 joules

Your friend has a rubber band stretched between two fingers. When you pluck the rubber band, it vibrates and makes sound. What would you have to do to make the sound a higher pitch?

To make a higher pitch, stretch the rubber band more.


To make a higher pitch, pluck the rubber band less hard.


To make a higher pitch, stretch the rubber band less.


To make a higher pitch, pluck the rubber band harder.

Answers

Answer:

I think it is   To make a higher pitch, stretch the rubber band more

Explanation:

I'm not too sure. Sry if u got it wrong

Answer:

To make a higher pitch ,pluck the rubber band more

What important role does each play in an exercise regiment?

Answers

Answer: There are five principles of fitness out of which two are overload principle and rest and recovery principle. Overload principle is one of the most important principle which tell that to gain and improve the fitness one should do the hard work.  

Slowly and gradually the intensity and time of exercise are increased so that our body can adapt to the hard work. Overload principle plays an important role in improving the skills and improving performance during exercise and sports.

Rest and recovery principle is important to relax the body and release the stress that happens due to intense training like in case of weight lifting one day rest should be taken to repair and rebuild the muscles. This allows the body to encounter the fatigue and improve performance.

Explanation:

Explain why the formation of sand is a physical change.

Answers

In chemical changes new substances are formed and the process is often difficult to reverse. During chemical changes particles do change with atoms or ions regrouping.Bonds between atoms break and new ones
form and energy is either given out or
taken in. Some chemical changes are
initiated by mixing

Answer:

The formation of sand is a physical change because some of the physical properties of the rocks change, but their identities do not. The particles of rock are rearranged as their sizes and shapes change, but their identities and total mass remain the same.

A car that's initially traveling at 10 m/s acceleration uniformly for 4 seconds at a rate of 2 m/s?in a straight line. How far does the car travel during this time?

Answers

Answer:

Explanation:

The answer is -2m/s²

PLZZZ HELPPP ASAP
I really need help as soon as possible

Answers

Answer:

Friction

Explanation:

As the toy cars rolls away, more friction is created. The more friction there is, the more friction on surface rubs against another which creates friction which in-term slows it down. Hope this helps.

please help me please please, i will brainliest the right answer

Answers

help with whatttt? there’s nothing

. What material does sound move quicker through?
Water
Air
Steel

Answers

Answer:

steel

Explanation:

the close molecules in solids allows sound to travel at a faster speed

Sound will move quicker through Steel than in water and air.

Sound: This can be defined as an audible form of energy, that is radiated outward from a source.

⇒ Generally,

Sound wave travels fastest in solid,  more than in liquid or gas. This is because the molecules of solid are more closely together.

⇒ From the question above,

Water is a liquid materialAir is a gaseous materialSteel is a solid material

Therefore, sound will move quicker through Steel than in water and air.

Hence: sound will move quicker through Steel than in water and air.

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Need
Help answering the questions

Answers

Ummm, can’t really answer the questions if we can’t see them. You need to post more than the photos of the files my man

What’s 5.1 cm in Newton’s?

Answers

0.051 newton meter.

Over a period of 2.50 seconds, a speedboat accelerates uniformly from 18.5 m/s to 46.5 m/s. What is the acceleration of the speedboat relative to the shore?

Answers

The answer is : 11.2 m/s2

According to the question, the acceleration of the speedboat relative to the shore is found to be 11.2 [tex]m/sec^2.[/tex]

What is Acceleration?

Acceleration may be characterized as the rate of change of the velocity of an object with respect to time. It is a vector quantity, as it defined both magnitude and direction. This allows you to measure how fast velocity changes in meters per second squared (m/s^2).

According to the question,

The initial velocity of the boat = 18.5 m/s.

The final velocity of the boat = 46.5 m/s.

Difference in velocity = Final velocity - Initial velocity = 46.5-18.5 = 28 m/s.

The formula for calculating the acceleration of the boat is as follows:

a = Difference in velocity/time taken.

           = 28/2.50 = 11.2 [tex]m/sec^2[/tex].

Therefore,  the acceleration of the speedboat relative to the shore is found to be 11.2 [tex]m/sec^2.[/tex]

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How much force is necessary to stretch a spring 0.5 m when the spring constant is 190 N/m?

Answers

Answer:

95 N

Explanation:

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