A group of high school students were surveyed about their handedness and their favorite sport. The results are displayed below.



Which of the following statements is not true, according to the graph?

The left-handed group has a higher percentage of people who prefer baseball.
The right-handed group has a lower percentage of people who prefer basketball.
The percentage of people who prefer soccer has a lower percentage in the left-handed group.
The percentage of people who prefer football is approximately the same for the right- and left-handed groups.

Answer:

x = 12

Step-by-step explanation:

Δ ESR and Δ EGF are similar, then ratios of corresponding sides are equal, so

[tex]\frac{ES}{EG}[/tex] = [tex]\frac{ER}{EF}[/tex] , substitute values

[tex]\frac{45}{12x-3}[/tex] = [tex]\frac{55}{143}[/tex] ( cross- multiply )

55(12x - 3) = 6435 ( divide both sides by 55 )

12x - 3 = 117 ( add 3 to both sides )

12x = 120 ( divide both sides by 12 )

x = 10

Hi there!

[tex]\large\boxed{\frac{1}{18}}[/tex]

1/3x = 6

Begin by multiplying both sides by 3 to cancel the fraction:

1/x = 18

Take the reciprocal of both sides:

x = 1/18

Answer:

1/18

Step-by-step explanation:

I N E E D P O I N T S :O)

What do you personaly feel like is most dificult.

For me its rembering minus signs

Answer:

The expected number of items that will be classified into group 1 is 100.

Step-by-step explanation:

For each observation, there are only two possible outcomes. Either it will be classified into group 1, or it will not. The probability of an observation being classified into group 1 is independent of any other observation, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

400 observations

This means that [tex]n = 400[/tex]

Four mutually exclusive groups. The probability of a randomly selected item being classified into any of the four groups is equal.

This means that [tex]p = 0.25[/tex]

Then the expected number of items that will be classified into group 1 is

[tex]E(X) = np = 400*0.25 = 100[/tex]

100 is the answer.

Answer:

a) 0.0038 = 0.38% probability that the mean weight of the sample is less than 5.97 ounces.

b) Given a mean of 6.05 ounces, it is very unlikely that a sample mean of less than 5.97 ounces, which means that the true mean must be recalculated.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 6.05 ounces and a standard deviation of .18 ounces.

This means that [tex]\mu = 6.05, \sigma = 0.18[/tex]

Sample of 36:

This means that [tex]n = 36, s = \frac{0.18}{\sqrt{36}} = 0.03[/tex]

a. Find the probability that the mean weight of the sample is less than 5.97 ounces.

This is the p-value of z when X = 5.97. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{5.97 - 6.05}{0.03}[/tex]

[tex]Z = -2.67[/tex]

[tex]Z = -2.67[/tex] has a p-value of 0.0038.

0.0038 = 0.38% probability that the mean weight of the sample is less than 5.97 ounces.

b. Suppose your random sample of 36 cans of salmon produced a mean weight that is less than 5.97 ounces. Comment on the statement made by the manufacturer.

Given a mean of 6.05 ounces, it is very unlikely that a sample mean of less than 5.97 ounces, which means that the true mean must be recalculated.

Answer:

[tex][1, -4 ,5][/tex]

Step-by-step explanation:

In this question we are multiplying together two matrices. When we multiply a (1 x 3) matrix with a (3 x 3) matrix, we get a (1 x 3) matrix.

To compute each value, all you need to do is take the each value in each row in the first matrix, and multiply it by each value in each column of the second matrix and add up the result. So let's do that.

[tex]a = (2 * 1) + (1 * -1) + (0 * 0) = 2 - 1 + 0 = 1[/tex]

[tex]b = (2 * -1) + (1 * -2) + (0 * 1) = -2 -2 = -4[/tex]

[tex]c = (2 * 2) + (1 * 1) + (0 * 1) = 4 + 1 + 0 = 5[/tex]

Answer:

2

Step-by-step explanation:

33

Answer:

.......................

Answer:

[tex]B =102[/tex]

[tex]Y = 32[/tex]

Step-by-step explanation:

Solving (47):

To solve for B, we have:

[tex]B + 50 + 28 = 180[/tex] --- sum of angles in a triangle

This gives

[tex]B + 78 = 180[/tex]

Collect like terms

[tex]B =- 78 + 180[/tex]

[tex]B =102[/tex]

Solving (48):

To solve for Y, we have:

[tex]X + Y+ Z = 180[/tex] --- sum of angles in a triangle

This gives

[tex]Y = 180 - X - Z[/tex]

Where

[tex]W+ X=180[/tex] -- angle on a straight line

Solve for X

[tex]X=180 -W[/tex]

[tex]X=180 -100 = 80[/tex]

So, we have:

[tex]Y = 180 - X - Z[/tex]

[tex]Y = 180 - 80 - 68[/tex]

[tex]Y = 32[/tex]

Answer:

b(-2,-5)

Step-by-step explanation:

Step-by-step explanation:

xx is the Roman number of 20

Answer:

3 pants are $20.55

4 shirts are $47.9

Step-by-step explanation:

a pant is $6.85 × 3= $20.55

68.45 - 20.55 = $47.9

$47.9 ÷ 4 = $11.98 a shirt

Answer:

C

Step-by-step explanation:

Since the triangles are similar, the scale factor is 100/5=20. So L/15=20, L=300

9514 1404 393

Answer:

  C)  12 cm

Step-by-step explanation:

In a 30°-60°-90° triangle, the ratios of side lengths are ...

  1 : √3 : 2

This means the hypotenuse (AC) is 2/√3 times the length of the long side (AB).

  (10 cm)(2/√3) = 20/√3 cm ≈ 11.55 cm

Rounded to the nearest cm, the length of AC is 12 cm.

Answer:

a. These four vectors are dependent because there are columns of 3 by 4 matrix with one free variable.

b. If one is a multiple of other

c. c1v1 + c20 = 0 has nontrivial solution.

Step-by-step explanation:

Any set of 4 or more vectors must be linearly dependent. The non trivial combination of vector may produce zero as the set is linearly dependent. The vector v1 and v2 will be dependent if one is the multiple of the other.

Answer:

a) 0.1295

b) The 95% confidence interval for the population proportion of disks which are defective is (0.1071, 0.1519).

Step-by-step explanation:

Question a:

112 out of 865, so:

[tex]\pi = \frac{112}{865} = 0.1295[/tex]

Question b:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 865, \pi = 0.1295[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].  

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1295 - 1.96\sqrt{\frac{0.1295*0.8705}{865}} = 0.1071[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1295 + 1.96\sqrt{\frac{0.1295*0.8705}{865}} = 0.1519[/tex]

The 95% confidence interval for the population proportion of disks which are defective is (0.1071, 0.1519).

Answer:

75cedis

[tex]50 = 40\% \\ 60\%[/tex]

The amount of money Kofi earned today from mowing lawns is 30 cedis.

Percentage can be described as a fraction of a number multiplied by 100. Percentage is represented with this sign - %.

In order to determine the amount Kofi earned today, this formula would be used:

Percentage Kofi earned today x amount Kofi earned yesterday

60% x 50 cedis

0.6 x 50 cedis

= 30 cedis

To learn more about percentages, please check: https://brainly.com/question/92258?referrer=searchResults

9514 1404 393

Answer:

  6

Step-by-step explanation:

The number of distinct zeros in the product will be the union of the sets of zeros. Duplicated values are not distinct, so show in the union of sets only once.

  F = {-2, 3, 7}

  G = {-3, -1, 4, 7}

  F∪G = {-3, -2, -1, 3, 4, 7} . . . . . . a 6-element set

The product has 6 distinct zeros.

_____

As you may notice in the graph, the duplicated zero has a multiplicity of 2 in the product.

Answer:

Step-by-step explanation:

Answer:

Answer is D.

Step-by-step explanation:

Let the inverse be m:

[tex]{ \sf{m = \sqrt{x} - 8 }} \\ { \sf{m + 8 = \sqrt{x} }} \\ { \sf{x = {(m + 8)}^{2} }} \\ { \bf{f {}^{ - 1} (x) = {(x + 8)}^{2} }}[/tex]

Domain:

[tex]{ \sf{x \geqslant - 8}}[/tex]

The equation of the line is.

y = (3/8)*x - 1.5

A general linear relationship can be written as:

y = a*x + b

Where a is the slope, and b is the y-intercept.

If the line passes through the points (x₁, y₁) and (x₂, y₂), we can write the slope as:

a = ( y₂ - y₁)/(x₂- x₁)

We define the y-intercept and the x-intercept as the points where the graph intersects the y-axis or the x-axis correspondingly.

Here we know that the x-intercept is 4, or we can write this as (4, 0)

we also know that the y-intercept is -1.5, or we can write this as (0, -1.5)

So we know two points of the line, this means that we can find the slope of the line:

a = (-1.5 - 0)/(0 - 4) = (1.5)/(4) = (3/2)*(1/4) = 3/8

Then the line is:

y = (3/8)*x + b

And remember that b is the y-intercept, which we know is equal to -1.5, so we can just replace it:

Then the equation of the line is.

y = (3/8)*x - 1.5

If you want to learn more about this topic, you can read:

https://brainly.com/question/24329241

Công thức xác định tuổi thọ KL

Answer: y = 30x

Step-by-step explanation:

Because we are talking about over 8 hours. The question states that you get 30$ per hour for overtime hours. That means if you work over 8 hours your dollars per hour increases to 30. So because the amount of dollars increases to 30 you can infer that all you have to do is make the same equation as the 20 dollar's per hour equation. Except you put 30 making it y = 30x.

The question is somewhat poorly posed because the equation doesn't involve θ at all. I assume the author meant to use x.

sec(x) = csc(x)

By definition of secant and cosecant,

1/cos(x) = 1/sin(x)

Multiply both sides by sin(x) :

sin(x)/cos(x) = sin(x)/sin(x)

As long as sin(x) ≠ 0, this reduces to

sin(x)/cos(x) = 1

By definition of tangent,

tan(x) = 1

Solve for x :

x = arctan(1) + nπ

x = π/4 + nπ

(where n is any integer)

In the interval 0 ≤ x ≤ 2π, you get 2 solutions when n = 0 and n = 1 of

x = π/4   or   x = 5π/4

Answer:

See Below.

Step-by-step explanation:

We have the equation:

[tex]\displaystyle y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}[/tex]

And we want to show that:

[tex]\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}[/tex]

Instead of differentiating directly, we can first square both sides:

[tex]\displaystyle y^2 = 3e^{2x} -4x + 1[/tex]

We can find the first derivative through implicit differentiation:

[tex]\displaystyle 2y \frac{dy}{dx} = 6e^{2x} -4[/tex]

Hence:

[tex]\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}[/tex]

And we can find the second derivative by using the quotient rule:

[tex]\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}[/tex]

Substitute:

[tex]\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}[/tex]

Simplify:

[tex]\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}[/tex]

Combine fractions:

[tex]\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}[/tex]

Simplify:

[tex]\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}[/tex]

Simplify:

[tex]6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}[/tex]

Q.E.D.

Answer:

ytre

Step-by-step explanation:

Answer:

Option (D) x≥ 0 is absolutely correct

Step-by-step explanation:

The reason is that the square root function is defined for only non negative numbers.

Answer: x is greater than or equal to 0

Step-by-step explanation: