a cup of coffee has a mass of .297 kg if you place this cup of coffee on a desk and let it sit there undisturbed how much force is the desk exerting on it

Answers

Answer 1
The force of the table upon the cup is 2.9106 N
Answer 2

The desk is exerting a normal force of approximately 2.913 Newtons on the cup of coffee, which is also equal to 2.913 N in magnitude.

The force that the desk exerts on the cup of coffee is known as the normal force. This force counteracts the weight of the coffee cup due to gravity. The normal force is equal in magnitude and opposite in direction to the force exerted by the cup's weight.

The weight of an object is given by the equation:

Weight = mass × acceleration due to gravity

Where:

Mass = 0.297 kg (mass of the coffee cup)

Acceleration due to gravity (on the surface of the Earth) ≈ 9.81 m/s²

Weight = 0.297 kg × 9.81 m/s² ≈ 2.913 kg m/s² (Newtons)

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Related Questions

is this right lol i think it is but im not so sure XD

Answers

[tex]\bold{Heya!}[/tex]

Yup. your answer is correct!

→ EXPLANATION :-

1. just put the numbers in order [tex]^1^6^, ^1^8^,^2^3^,^2^4^,^2^9^,^3^0[/tex]

2. Cross off high/low pairs, we left with the numbers :-

        [tex]23,24.[/tex]

3. Add the leftover numbers.

        [tex]23 \: + 24 = 47.[/tex]

Divide the sum of 2.

        [tex]\frac{47}{2} = 23.5[/tex]

Hopefully This Helps ! ~

#LearnWithBrainly

[tex]\underline{Answer :}[/tex]

Jaceysan ~

Answer:

GIVE HIM BRAINLEST

6. When can you say that an object is accelerating?
A. when the speed remains the same
B. When the speed is changing
C. when the instantaneous velocity is the same
D. When there is a uniform motion

give explanation ​

Answers

Answer:

When the speed is changing is the correct answer

Explanation:

Because acceleration is rate of change of velocity

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE

Microphones are used to convert sound vibrations to electrical signals. In one kind of microphone, sound waves move a coil of wire up and down in a magnetic field, as shown in (Figure 1). The coil shown has a diameter of 1.4 cm and has 100 turns; the 0.010 T magnetic field points radially out from the north pole to the south.

If the microphone's emf at some instant is 10 mV , what is the speed of the coil?

Answers

The speed of coil of the microphone is 0.227 m/s

What is a Microphones?

A microphone is a device used to transmit sound energy through electrical energy. it makes use of magnetic fields whose strength is measures in Tesla

Given data

D = 1.4cm = 0.014m

N = 100

B = 0.010T

emf = 10mV

speed = dx / dt = ?

solution

emf = N dΦ / dt

Φ = BA

A =  2 pi R x

R = D / 2 = 0.014 / 2 = 0.007

emf = N d ( B 2 pi R x ) / dt

emf = N B 2 pi R dx / dt

and dx / dt = speed

speed = emf / N B 2 pi R

speed = 10 * 10 ^ -3 / ( 100 * 0.010 * 2 * 3.142 * 0.007)

speed = 10 * 10 ^ -3 / ( 0.043988 )

speed = 0.227 m/s

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ε = vLB

v - velocity = ?

ε - emf = 10mV = 0.01V

B - magnetic field = 0.010 T

L - length of wire = find

Find L

N - turns of wire = 100

d = diameter = 1.4 cm = 0.014 m

L = circumference of 1 turn of wire * # of turns of wire

L = 2πr * N

L = πdN

L = π * 0.014 m * 100

L = 1.4π m

Return to main equation

ε = vLB

[tex]v = \frac{\epsilon}{LB}[/tex]

[tex]v = \frac{0.01}{(1.4\pi)*(0.010)}[/tex]

v = 0.227 m/s

the dimensions of a cuboidal block are 2.5 m * 2m * 1.2m its weight 900 n what is the minimum presseure exerted by the block on the surface of its support.?​

Answers

Answer:

your answer is here 180

Explanation:

900/2.5 * 2 = 180

Answer:

The answer is 180 Pa.

Explanation:

Given;

Here, weight = thrust = 900 N,

dimensions are 2.5 m × 2 m × 1.2 m

To Find;Pressure exerted by the block on the surface of its support.Formula;Pressure = Thrust ÷ Area

We know that, Pressure is inversely proportional to area. For the minimum pressure the area must be more.

So, if the block is resting with 2.5 m × 2 m surface on the support, the pressure will be minimum.

Pressure = 900 N ÷ 2.5 × 2.0 m² = 180 Pa

Thus, The pressure exerted by the block on the support is 180 Pa.

Which statement about the observed results of the double-slit experiment is true?

O Waves that are out of phase constructively interfere to create bright bands.

O Waves that are in phase destructively interfere to create bright bands.

O Waves that are in phase constructively interfere to create bright bands.

O Waves that are out of phase constructively interfere to create bright bands.

Answers

Waves that are in phase constructively interfere to create bright bands was observed in the double-slit experiment.

What is Interference?

This is defined as the phenomenon which occurs when two waves meet while traveling along the same medium.

A wave when in phase undergoes constructive interference while out of phase undergoes destructive interference which is why option C was chosen as the most appropriate choice.

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The measured value of mass M in an experiment is M = 0.743 ± 0.005kg. The error in 2M is
Select one:
dM
3dM
2.5 dM
2dM​

Answers

Given the measured value of mass M in the experiment the error in 2M is  ; dM

Given data :

Measured value of mass M = ( 0.743 ± 0.005 ) kg

The error in 2M in the measured value

The error in 2M in the measured value M = 0.743 ± 0.005 kg is dM while the error in M² will be 2dM

Hence we can conclude that the measured value of mass M in the experiment the error in 2M is  ; dM.

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An object with a mass of 70.5 kg is placed on a 2-meter strand of metal (with a 2-millimeter radius) hanging from the ceiling. It stretches 1 millimeter. What is this strand made of?

Answers

Based on the value of the Young's modulus, the strand of the metal is made of copper.

Young's modulus of the metal

The Young's modulus of the metal is calculated as follows;

E = stress/strain

Stress of the metal

The stress of the metal is calculated as follows;

σ = F/A = mg/A

where;

A is area of the metal

A = πr²

A = π( 2 x 10⁻³)²

A = 1.257 x 10⁻⁵ m²

σ = (70.5 x 9.8) / (1.257 x 10⁻⁵)

σ = 5.5 x 10⁷ N/m²

Strain of the metal

The strain is calculated as follows;

strain = x/L

where;

x is extension

L is original length

strain = (1 x 10⁻³ m) / 2 m

strain = 5 x 10⁻⁴

Young's modulus of the metal

E = stress/strain

E = (5.5 x 10⁷ ) / (5 x 10⁻⁴)

E = 1.1 x 10¹¹ N/m²

E = 110 Gpa

The Young's modulus of copper metal is 110 Gpa

Thus, based on the value of the Young's modulus, the strand of the metal is made of copper.

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[tex]Question: $x_{1}=\frac{5}{2}[\sin (2 \pi t)+\cos (2 \pi t)], x_{2}=5\left[\sin \left(2 \pi t+\frac{\pi}{4}\right)\right]$[/tex]
Find the ratio of the amplitude of the given motion?
Options:
[tex](a) $\sqrt{2}: 1$\\(b) $2: 1$\\(c) $1: \sqrt{2}$\\(d) $1: 2$[/tex]

Answers

Condense x₁ to get

sin(2πt) + cos(2πt) = √2 • (sin(2πt) + cos(2πt))/√2

… = √2 (cos(2πt) cos(π/4) + sin(2πt) sin(π/4))

… = √2 cos(2πt - π/4)

So the amplitude of x₁ is (5/2) • √2 = 5/√2, while the amplitude of x₂ is 5. The ratio between them is then 5/√2 : 5, or equivalently 1/√2 : 1 or 1 : √2.

The sound intensity at a distance of 19 m from a noisy generator is measured to be 0.24 W/m2. What is the sound intensity at a distance of 27 m from the generator

Answers

Answer:

0.1111 W/m²

Explanation:

If all other parameters are constant, sound intensity is inversely proportional to the square of the distance of the sound. That is,

I ∝ (1/r²)

I = k/r²

Since k can be the constant of proportionality. k = Ir²

We can write this relation as

I₁ × r₁² = I₂ × r₂²

I₁ = 0.25 W/m²

r₁ = 16 m

I₂ = ?

r₂ = 24 m

0.25 × 16² = I₂ × 24²

I₂ = (0.25 × 16²)/24²

I₂ = 0.1111 W/m²

.
Which of the following is not true about the lymphatic system?
it drains white blood cells away from tissue
it brings nutrients to the tissue
it builds muscle cells
it fights infection

Answers

Answer:

it builds muscle cells

Explanation:

took test

1) How many joules of heat are required to raise the temperature of 550 g of water from
12.7 °C to 28.8°C ? Specific heat of liquid water is 4.184 J/g °C.

Answers

Answer:

Explanation:

You can use [tex]Q = mc\Delta T=(550)(4.184)(28.8-12.7)=37049.32[/tex] joule.

The two basic properties of all matter are ______ and ______.
options for first blank
a. length B. volume
options for second blank
a. density B. mass

Answers

Answer:

volume , mass

Explanation:

the 3 basic properties of a matter is volume, mass and shape.

Which statement about the interference behavior of electromagnetic radiation seen in the double-slit test experiment is true? (1 point)

O Waves that make up the radiation collide with each other so that they add together or cancel each other out.

O Particles that make up the radiation collide with each other so that they add together or cancel each other out.

O Particles that make up the radiation collide with each other and scatter randomly.

O Waves that make up the radiation do not interact with each other.

Answers

Waves that make up the radiation collide with each other so that they add together or cancel each other out.

What is Interference?

This is the phenomenon which occurs when two waves meet while traveling along the same medium.

In the double-slit test experiment, bright and dark fringes was observed which was caused by the superposition of overlapping light waves originating from the two slits which is why option A was chosen as the most appropriate choice.

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1. A person walks 20 meters toward the east and then walks 30 meters toward the west. What is the total distance covered? What is the displacement? with explaination
2. What is the average speed of a car that travels 2000 meters in 5 minutes in meters/second? with explaination

Answers

Answer:

1.) 30 m is the total distance covered 10m is the displacement you

2.)24,000m/h (24km/h or 6.67m/s) Average speed is calculated by dividing the total distance that something has traveled by the total amount of time it took it to travel that distance

Explanation:

If a snowboarder’s initial speed is 4 m/s and comes to rest when making it to the upper level. With a slightly greater initial speed of 5 m/s, the snowboarder is moving to the right on the upper level. His final speed in this case is 3 m/s. Suppose this situation is repeated on planet Epsilon, where gravity is less than gravity on earth.

A. Would the height of the hill on Epsilon cause a reduction in speed from 4 m/s to 0 greater than, less than, or equal to the height of the corresponding hill on earth? Explain.

B. Consider the hill on Epsilon discussed in part A. If the initial speed at the bottom of the hill is 5 m/s, will the final speed at the top of the hill be greater than, less than, or equal to 3 m/s? Explain.

Answers

(a) At a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

(b) If the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

Conservation of mechanical energy

The effect of height  and gravity on speed on the given planet Epislon is determined by applying the principle of conservation of mechanical energy as shown below;

ΔK.E = ΔP.E

¹/₂m(v²- u²) = mg(hi - hf)

¹/₂(v²- u²) = g(0 - hf)

v² - u² = -2ghf

v² = u² - 2ghf

where;

v is the final velocity at upper levelu is the initial velocityhf is final heightg is acceleration due to gravity

when u² = 2gh, then v² = 0,

when gravity reduces, u² > 2gh, and v² > 0

Thus, at a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

Final speed

v² = u² - 2ghf

where;

u is the initial speed = 5 m/sg is acceleration due to gravity and its less than 9.8 m/s²v is final speedhf is equal height

Since g on Epislon is less than 9.8 m/s² of Earth;

5² - 2ghf > 3 m/s

Thus, if the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

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If a→=3i^-2j^-k^ and b→=i^+4j^+k^, find a unit vector n^ normal to the plane containing a→ and b→ such that a→, b→ and n^, in this order, form a right-handed system.​

Answers

The unit vector normal to the plane is ; n = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]

Given data :

The unit vectors

a→=3i^-2j^-k^  and  b→=i^+4j^+k^

Determine the unit vector normal to the plane

The unit vector normal to the plane is calculated as

n = [tex]\frac{a*b}{|b*b|}[/tex]  ---- ( 1 )

where ; a→ * b→ =  2i - 4j + 14k  and  |b * b| = [tex]\sqrt{216}[/tex]  

back to equation ( 1 )

n = ( 2i - 4j + 14k ) / [tex]\sqrt{216}[/tex]

  = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]

Hence we can conclude that The unit vector normal to the plane is ; n = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]

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What is the cycle of a breaststroke?

Answers

Answer:

Breaststroke can be divided up into 4 distinct phases, which consists of the out sweep, in sweep, breathing phase, and lunge, extension, or recovery phase.

Explanation:

pa follow po

6. A spring is originally 1.5 m long. It is stretched so that it is 1.8 m long. The spring constant is 50 N/m.
Find the potential energy stored in the spring.

Answers

Answer:

PE = 1/2 K X^2

K = 50 N/m

X = .3 m

PE = 1/2 * 50 * .3^2 = 2.25 Joules

Spring
The pulling force acting on an object is 350.0 N. It also is being affected by a 50.0 N
kinetic friction force. As a result, its acceleration is 3.0 m/s?, what is its mass?
A. 67 kg
B. 83 kg
C. 100 kg
D. 600 kg
E. 0.0 kg
If the gravitational force of the Farth nulling you"down" in th

Answers

Answer:

100 kg

Explanation:

Net force = 350 - 50 = 300 N

F= ma

300 N  = m * 3 m/s^2

100 kg = mass

A 3 Hz wave has a wavelength of 0.4 m. Calculate the speed of the wave (in m/s).

Answers

The speed of the wave with the given frequency and wavelength is 1.2m/s.

Given the data in the question;

Wavelength of the wave; [tex]\lambda = 0.4m[/tex]Frequency; [tex]f = 3Hz = 3s^{-1}[/tex]Speed of the wave; [tex]v = \ ?[/tex]

Wavelength

Wavelength is  the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.

It is expressed as;

[tex]\lambda = \frac{v}{f}[/tex]

Where v is velocity/speed and f is frequency.

Now, we can easily get the speed of the wave by substituting our given values into the expression above.

[tex]\lambda = \frac{v}{f} \\\\0.4m = \frac{v}{3s^{-1}}\\ \\v = 0.4m * 3s^{-1}\\\\v = 1.2ms^{-1}\\\\v = 1.2m/s[/tex]

Therefore, the speed of the wave with the given frequency and wavelength is 1.2m/s.

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The Empire State Building is about 381m high. If you threw a baseball downward at 25 m/s from the top of the building how fast would it be traveling just before it landed?

Answers

Answer:

Explanation:

You can use that [tex]v = v_{o}+gt[/tex] or [tex]v^{2}=v_{o}^{2}+2gh=(25)^{2}+(2)(10)(381)=8245 \rightarrow v \approx 90.8[/tex] m/s.

Loosing weight without diet require moving to the top of a mountain explain using weight and gravitational force

Answers

Answer:

You would weigh very slightly more at sea level than at the top of a mountain, not enough for you to notice, but a measurable amount. Weight, which really means gravitational force, is proportional to the product of the masses of two objects acting on each other, in this case the giant earth and the minuscule you.

Explanation:

A DJ is setting up their equipment and measures the sound level near a speaker to be 55.65dB. They decide to add two more speakers next to the first. What would they measure the new sound level to be?

Answers

For a DJ is setting up their equipment and measures the sound level near a speaker to be 55.65dB, the new sound level is mathematically given as

L=50.470dB

What would they measure the new sound level to be?

Generally, the equation for the sound level  is mathematically given as

l=10logl/io

Therefore

logl/io=5.57

Hence

I=3.715*10^−8

In conclusion

L'=10log(3*3.715*10^−8)/10^{-12}

L=50.470dB

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Match the missions with their objectives.
NEAR
Lunar Prospector
Deep Impact
SETI
mapping the Moon's surface composition,
looking for possible deposits of polar ice,
and examining the Moon's resources,
structure, and origins
first space probe to orbit and perform
an in-depth Investigation of an asteroid
searching for extraterrestrial life in the universe
probing beneath the surface of a comet to
obtain clues about its internal composition
and structure

Answers

Matching the missions with their objectives

NEAR -------> First space probe to orbit and perform an in-depth Investigation of an asteroid. Lunar prospector ----- > mapping the Moon's surface composition,looking for possible deposits of polar ice,and examining the Moon's resources,structure, and origins.Deep Impact -------> probing beneath the surface of a comet to obtain clues about its internal composition and structureSETI -----> searching for extraterrestrial life in the universe

The Mission Overview

The NEAR ( Near Earth Asteroid Rendezvous ) is a mission whose objective is to study origin and nature of objects near the earth such as asteroids and comets.

Lunar prospector was a mission designed to perform an orbit investigation of the moon.

The deep impact mission created by NASA was to probe beneath the comet and discover the structure and composition. The deep impact projected lasted for 9 years in space.

Hence we can conclude that the missions and their objectives are as listed above.

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What is the centripetal acceleration of 30 kg child standing 5 meters from the center of a
rotating carousel? The carousel is rotating at a linear velocity of 20 m/s.

Answers

Answer:

80m/s2

Explanation:

m=30kg. r = 5meter v = 20m/s2 a= ? centripetal acceleration = v*v/r

20*20/5=80m/s2

centripetal acceleration=80 m/s2

Consider the two-slit interference experiment. Electromagnetic radiation passes through the two slits that are a distance of 0.0170 nm apart. A fourth-order bright fringe forms at an angle of 8.0 degrees relative to the incident beam. What is the wavelength of the light? (1 point)

O 581 nm

O 420 nm

O 789 nm

O 591 nm

Answers

Answer:

The answer is 581

Explanation:

I just took the Quick Check and got it right.

For the statements based on whether they are described as outcomes of results from thermal energy being added or removed particles move faster particles move slower temperature increases temperature decreases kinetic energy increases kinetic energy decreases thermal energy added thermal energy removed

Answers

For thermal energy added: particles move faster, temperature increases, kinetic energy increases.
Thermal energy removed: particles move slower, temperature decreases, kinetic energy decreases

list down the general of the office of guardian and tutor​

Answers

Answer:

legal guardians, the four types: personal guardians, financial guardians, conservators, and pet “guardians”

Year

Carbon Dioxide (CO2) in Atmosphere (ppm*)

2010



2011



Copyright © Enginuity Inc.

Copyright © Enginuity Inc.




Global Temperature Change – Student Guide




2012



2013



2014



2015



2016



2017

Answers

Answer:

Theres a diagram missing for Q

Explanation:

What is all this?

Could you add a question so I can answer it :)

Can someone help with this

Answers

Hi there!

A.

We can use the work-energy theorem to solve.

Initially, both blocks have gravitational potential energy, which is then converted to kinetic energy.

Recall:
[tex]U = mgh \\[/tex]

U = Potential Energy (J)
m = mass (kg)
g = acceleration due to gravity (m/s²)

h = height (m)

And at the end, block 2 has both kinetic and potential energy. Kinetic is defined as:
[tex]KE = \frac{1}{2}mv^2[/tex]

v = velocity (m/s)

We can do a summation of initial and final forces.

Initial:
[tex]E_i = m_2g\frac{h}{2} + m_1gh[/tex]

Final:
[tex]E_f = \frac{1}{2}m_2 v^2 + m_2g\frac{3h}{2} + \frac{1}{2}m_1 v^2[/tex]

Set the two equal (no energy loss in this situation) and solve for velocity.

[tex]m_2g\frac{h}{2} + m_1gh = \frac{1}{2}m_2 v^2 + m_2g\frac{3h}{2} + \frac{1}{2}m_1 v^2\\\\m_2g\frac{h}{2} + m_1gh - m_2g\frac{3h}{2} = \frac{1}{2}m_2 v^2 + \frac{1}{2}m_1 v^2\\\\v^2 = \frac{gh(\frac{m_2}{2} + m_1 - \frac{3m_2}{2})}{\frac{1}{2}m_2 + \frac{1}{2}m_1}\\\\v = \sqrt{\frac{gh(\frac{m_2}{2} + m_1 - \frac{3m_2}{2})}{\frac{1}{2}m_2 + \frac{1}{2}m_1}}\\\\v = \boxed{3.704 \frac{m}{s}}[/tex]

**This can be solved in a simpler way using a summation of forces.

B.

Now, we can do a summation of forces to solve. First, we must solve for the acceleration of the system now that we have found the velocity. Use the kinematic equation:
[tex]v_f^2 = v_i^2 + 2ad[/tex]

Initial velocity is 0 m/s, so:
[tex]v_f^2 = 2ad\\\\a = \frac{v_f^2}{2d} = \frac{(3.704^2)}{2(2.10)} = 3.267 \frac{m}{s^2}[/tex]

Now, we can use a summation of forces for any block. We can do block 1:
[tex]\Sigma F = m_1g - T[/tex]

Using Newton's Second Law:
[tex]m_1a = m_1g - T\\\\T = m_1g - m_1a \\T = m_1 (g - a) = 4.10(9.8 - 3.267) = \boxed{26.828 N}[/tex]

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