A company specializing in parachute assembly claims that its main parachute failure rate is at most 1%. You perform a hypothesis test to determine whether the company's claim is true or false. Your sample data resulted in enough evidence to go against the claim made by the company. It was later determined that the claim made by the company was actually incorrect. What kind of error, if any, was committed

Answers

Answer 1

Answer:

There was enough evidence to reject the null hypothesis, and in fact, the null hypothesis is false, which means that no error was committed.

Step-by-step explanation:

A company specializing in parachute assembly claims that its main parachute failure rate is at most 1%.

At the null hypothesis, we test if the proportion is of at most 1%, that is:

[tex]H_0: p \leq 0.01[/tex]

At the alternative hypothesis, we test if the proportion is of more than 1%, that is:

[tex]H_0: p > 0.01[/tex]

Type I and type II errors:

Type I: Rejection of a true null hypothesis. The null hypothesis is true, but from a sample, you get enough evidence to reject.

Type II: Non-rejection of a false null hypothesis. The null hypothesis is false, but from a sample, you do not get enough evidence to reject.

Your sample data resulted in enough evidence to go against the claim made by the company.

This means that there was enough evidence to reject the null hypothesis.

It was later determined that the claim made by the company was actually incorrect.

The null hypothesis was false.

What kind of error, if any, was committed?

There was enough evidence to reject the null hypothesis, and in fact, the null hypothesis is false, which means that no error was committed.


Related Questions

PLEASE HELPPPPPPPPPPPPP

Answers

Step-by-step explanation:

The following configurations are evaluated, as given or stated within the interrogate:

P(Q) = 0.6

P(R) = 0.9

When the variable constant of Q and R transition into independent events within the function notation, the product of the individual values, as equated to those particular independent variables, is required.

For example:

If P(Q) = 0.6 and P(R) = 0.9, and Q and R fuse, then find the product of 0.9 and 0.6 is obligated:

0.9 * 0.6 = 0.54

Thus, given the independent events, P(Q and R) is equivalent to 0.54.

ASK YOUR SIR BRO I DONT KNOW

write 6x10x10x10x10 with an expont

Answers

Answer:

6x10^4

Step-by-step explanation:

Which statement is correct?

Answers

Answer:

c is the answer why cause I did it

Anyone know how to do this

Answers

Answer:

30 cm

Step-by-step explanation:

Since the length of tangents drawn from a point are equal, the perimeter is 3+3+9+9+3+3=30

Answer:

30 centimeter

A ball is thrown upward with an initial velocity​ (v) of 13 meters per second. Suppose that the initial height​ (h) above the ground is 7 meters. At what time t will the ball hit the​ ground? The ball is on the ground when S=0. Use the equation S=−5t2+vt+h.

Answers

Answer:

the correct answer is, 4

х
0
1
2
3
4
y
12 36 108
Which exponential function is the equation for the values in the table?

Answers

Answer:

12*(3)^x

Step-by-step explanation:

Let the exponential function be y=a*b^x. Given y(0)=12, a=12. Next y(2)=36, b=3

Answer:

Your answer is f(x)=4(3)x

Step-by-step explanation:

Mark me brainliest :)

Which graph shows the quadratic function y = 3x2 + 12x + 10? (5 points)

The following graph is labeled A: A four quadrant graph with a parabola opening up, passing through the points negative 3, 1, negative 2, negative 2, and negative 1, 1 with the vertex at 2, negative 2. The following graph is labeled B: A four quadrant graph with a parabola opening up, passing through the points 1, 4, 2, 1, and 3, 4 with the vertex at 2, 1. The following graph is labeled C: A four quadrant graph with a parabola opening up, passing through the points negative 3, 5, negative 2, 2, and negative 1, 5 with the vertex at negative 2, 2. The following graph is labeled D: A four quadrant graph with a parabola opening up, passing through the points 1, 1, 2, negative 2, and 3, 1 with the vertex at 2, negative 2.

Answers

Answer:

The correct graph is A.

Answer:

A i got it right

Step-by-step explanation:

Which of the following represents the factorization of the trinomial below?
- 4x3 - 4x2 +24 x
O A. -4(x2-2)(x+3)
B. -4(x2 + 2)(x+3)
O C. -4x(x + 2)(x+3)
D. -4x(x - 2)(x+3)

Answers

Answer:

D. -4x(x - 2)(x+3)

Step-by-step explanation:

We are given the following trinomial:

[tex]-4x^3 - 4x^2 + 24x[/tex]

-4x is the common term, so:

[tex]-4x(\frac{-4x^3}{-4x} - \frac{4x^2}{-4x^3} + \frac{24x}{-4x}) = -4x(x^2+x-6)[/tex]

The second degree polynomial can also be factored, finding it's roots.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]

[tex]\Delta = b^{2} - 4ac[/tex]

x² + x - 6

Quadratic equation with [tex]a = 1, b = 1, c = -6[/tex]

So

[tex]\Delta = 1^{2} - 4(1)(-6) = 25[/tex]

[tex]x_{1} = \frac{-1 + \sqrt{25}}{2} = 2[/tex]

[tex]x_{2} = \frac{-1 - \sqrt{25}}{2} = -3[/tex]

So

[tex]x^2 + x - 6 = (x - 2)(x - (-3)) = (x - 2)(x + 3)[/tex]

The complete factorization is:

[tex]-4x(x^2+x-6) = -4x(x - 2)(x + 3)[/tex]

Thus the correct answer is given by option d.

Which function is graphed?
(Help please)

Answers

Answer:

the function that is graphed is y=½CSC(x)

Move the numbers to the lines to order them from least to greatest.
least
greatest
67.98
68.6
68.11
Please answer ASAP

Answers

Answer:

67.98,68.11, 68.6

Find the slope of the line

Slope=m=_______

Answers

slope intercept form is y=mx+b. the answer to this graph would be y=3/4x-3 because the y intercept is at -3 and you go up 3 and over to the right 4. 3/4 would be your slope

Answer:

[tex]\displaystyle m = \frac{3}{4}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Reading a coordinate planeCoordinates (x, y)Slope Formula: [tex]\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Step-by-step explanation:

Step 1: Define

Identify points from graph.

Point (4, 0)

Point (0, -3)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Substitute in points [Slope Formula]:                                                              [tex]\displaystyle m = \frac{-3 - 0}{0 - 4}[/tex]Simplify:                                                                                                             [tex]\displaystyle m = \frac{3}{4}[/tex]

Suppose a jar contains 7 red marbles and 28 blue marbles. If you reach in the jar and pull out 2 marbles at random at the same time, find the probability that both are red.​

Answers

Answer:

3/85

Step-by-step explanation:

that's the answer above

prove that.

lim Vx (Vx+ 1 - Vx) = 1/2 X>00 ​

Answers

Answer:

The idea is to transform the expression by multiplying [tex](\sqrt{x + 1} - \sqrt{x})[/tex] with its conjugate, [tex](\sqrt{x + 1} + \sqrt{x})[/tex].

Step-by-step explanation:

For any real number [tex]a[/tex] and [tex]b[/tex], [tex](a + b)\, (a - b) = a^{2} - b^{2}[/tex].

The factor [tex](\sqrt{x + 1} - \sqrt{x})[/tex] is irrational. However, when multiplied with its square root conjugate [tex](\sqrt{x + 1} + \sqrt{x})[/tex], the product would become rational:

[tex]\begin{aligned} & (\sqrt{x + 1} - \sqrt{x}) \, (\sqrt{x + 1} + \sqrt{x}) \\ &= (\sqrt{x + 1})^{2} -(\sqrt{x})^{2} \\ &= (x + 1) - (x) = 1\end{aligned}[/tex].

The idea is to multiply [tex]\sqrt{x}\, (\sqrt{x + 1} - \sqrt{x})[/tex] by [tex]\displaystyle \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}}[/tex] so as to make it easier to take the limit.

Since [tex]\displaystyle \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}} = 1[/tex], multiplying the expression by this fraction would not change the value of the original expression.

[tex]\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \lim\limits_{x \to \infty} \left[\sqrt{x} \, (\sqrt{x + 1} - \sqrt{x})\cdot \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}}\right] \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}\, ((x + 1) - x)}{\sqrt{x + 1} + \sqrt{x}} \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}}\end{aligned}[/tex].

The order of [tex]x[/tex] in both the numerator and the denominator are now both [tex](1/2)[/tex]. Hence, dividing both the numerator and the denominator by [tex]x^{(1/2)}[/tex] (same as [tex]\sqrt{x}[/tex]) would ensure that all but the constant terms would approach [tex]0[/tex] under this limit:

[tex]\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \cdots\\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}} \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x} / \sqrt{x}}{(\sqrt{x + 1} / \sqrt{x}) + (\sqrt{x} / \sqrt{x})} \\ &= \lim\limits_{x \to \infty}\frac{1}{\sqrt{(x / x) + (1 / x)} + 1} \\ &= \lim\limits_{x \to \infty} \frac{1}{\sqrt{1 + (1/x)} + 1}\end{aligned}[/tex].

By continuity:

[tex]\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \cdots\\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}} \\ &= \cdots \\ &= \lim\limits_{x \to \infty} \frac{1}{\sqrt{1 + (1/x)} + 1} \\ &= \frac{1}{\sqrt{1 + \lim\limits_{x \to \infty}(1/x)} + 1} \\ &= \frac{1}{1 + 1} \\ &= \frac{1}{2}\end{aligned}[/tex].

Answer:

Hello,

Step-by-step explanation:

[tex]\displaystyle \lim_{x \to \infty} \sqrt{x}*(\sqrt{x+1}-\sqrt{x} ) \\\\\\= \lim_{x \to \infty}\dfrac{ \sqrt{x}*(\sqrt{x+1}-\sqrt{x} )*(\sqrt{x+1}+\sqrt{x} )}{\sqrt{x+1} +\sqrt{x} } \\\\= \lim_{x \to \infty} \dfrac{\sqrt{x} *1}{\sqrt{x+1} +\sqrt{x} } \\\\\\= \lim_{x \to \infty} \dfrac{1} {\sqrt {\dfrac {x+1} {x} }+\sqrt{\dfrac{x}{x} } } \\\\\\=\dfrac{1} {\sqrt {1}+\sqrt{1} } \\\\\\=\dfrac{1} {2} \\[/tex]

using the unit circle what is the exact value of tanpi/6

Answers

Answer:

[tex] \frac{ \sqrt{3} }{3} [/tex]

Step-by-step explanation:

[tex]\frac{1}{3} \div \sqrt{3} [/tex]

given that the following two are geometric series are convergent: 1+x+x^2+x^3+...and 1-x+x^2-x^3+... determine the value(s) of x for which the sum of the two series is equal to 8​

Answers

Let S and T denote the two finite sums,

S = 1 + x + x ² + x ³ + … + x

T = 1 - x + x ² - x ³ + … + (-x) ᴺ

• If both S = 8 and T = 8 as N goes to infinity:

Then

xS = x + x ² + x ³ + x ⁴ + … + x ᴺ⁺¹

-xT = -x + x ² - x ³ + x ⁴ + … + (-x) ᴺ⁺¹

so that

S - xS = 1 - x ᴺ⁺¹   ==>   S = (1 - x ᴺ⁺¹)/(1 - x)

and similarly,

T = (1 - (-x) ᴺ⁺¹)/(1 + x)

For both sums, so long as |x| < 1, we have

lim [N → ∞] S = 1/(1 - x)

lim [N → ∞] T = 1/(1 + x)

Then if both sums converge to 8, this happens for

S : 1/(1 - x) = 8   ==>   x = 7/8

T : 1/(1 + x) = 8   ==>   x = -7/8

• If the sum S + T = 8 as N goes to infinity:

From the previous results, we have

1/(1 - x) + 1/(1 + x) = 8   ==>   x = ±√3/2

Solve for x.

5x - 3 = 12

A) X = 3
B) X = -3
C) X = -9/5
D) X = 9/5

Answers

Answer:

A. x = 3

Step-by-step explanation:

5x - 3 = 12

5x = 12 + 3

5x = 15

x = 15/5

= 3

Historically, the industries with the most complaints to the Better Business Bureau have been banks, cable and satellite television companies, collection agencies, cellular phone providers, and new car dealerships. The results for a sample of complaints are contained in the file BBB. Click on the datafile logo to reference the data. a. Construct a frequency distribution for the number of complaints by industry. Category Observed Frequency Bank Cable Car Cell Collection Total b. Using , conduct a hypothesis test to determine whether the probability of a complaint is the same for the five industries. The test-statistic is (to 3 decimals). -value (to 4 decimals) What is your conclusion

Answers

Answer:

χ² = 19

Pvalue = 0.0008 ( 4 decimal places)

WE reject the H0 and conclude that probability of complaint is not the same for the 5 industries

Step-by-step explanation:

H0 : probability of complaint is the same for the 5 industries.

H1: probability of complaint is not the same for the 5 industries.

Category ____ observed frequency

Bank _______ 26

Cable _______44

Car _________42

Cell _________60

Collection ____ 28

Total ________200

The test statistic ;

χ² = (O - E)² / E

O = Observed Frequency ; E = Expected Frequency

Expected Frequency, E = (1 / n) * total

n = number of industries = 5

Expected frequency, E = (1/5)*200 = 40

Expected frequency is the same for all, thus E for all 5 industries = 40

χ² = Σ(O - E)² / E;

χ² = (26-40)² / 40 + (44-40)² / 40 + (42-40)² / 40 + (60-40)² / 40 + (28-40)² / 40

χ² = 19

At α = 0.05 ; df = n-1 = 4 ; χ²critical = 0.000786

Since Pvalue < α ; WE reject the H0 and conclude that probability of complaint is not the same for the 5 industries.

A survey asked 50 students if they play an instrument and if they are in band.
1.25 students play an instrument.
2. 20 students are in band.
3. 30 students are not in band.
Which table shows these data correctly entered in a two-way frequency?

Answers

C, just look at the "Total" for each single information.

the values in the inner grid combine multiple informations.

The table shows these data correctly entered in a two-way frequency is table C.

What is Two way Frequency?

Two-way frequency tables show the potential connections between two sets of categorical data visually. The table's four (or more) inside cells contain the frequency (count) data, which is displayed above and to the left of the table's designated categories.

We have been the information 25 students play an instrument 20 are in a band 30 are not in a band.

So, the two way table is:

                                     Band            Not in Band       Total

Play instrument                20                   5                     25

Do not play instrument     0                     25                 25

Total                                  20                    30                50

So, Table C is Correct.

Learn more about two-way frequency here:

https://brainly.com/question/9033726

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Please help out explanation need it

Answers

Answer:

[tex] \sin(θ) = \frac{19}{41} \\ θ = 27.6 \\ θ = 28[/tex]

I need help completing this problem ASAP

Answers

Answer:

8 sqrt(5)

Step-by-step explanation:

sqrt(45) + sqrt(125)

Rewriting

sqrt(9*5) + sqrt( 25 *5)

we know sqrt(ab) = sqrt(a) sqrt(b)

sqrt(9) sqrt(5) + sqrt(25) sqrt(5)

3 sqrt(5)+5 sqrt(5)

Add like terms

8 sqrt(5)

Answer:

A.    [tex] 8\sqrt{5} [/tex]

Step-by-step explanation:

[tex] \sqrt{45} + \sqrt{125} = [/tex]

[tex] = \sqrt{9 \times 5} + \sqrt{25 \times 5} [/tex]

[tex] = 3\sqrt{5} + 5\sqrt{5} [/tex]

[tex] = 8\sqrt{5} [/tex]

Please Help with this

Answers

Answer:

csc = 6/5= 1.2

cot = √(11)/5= 0.6633

sin = 5÷6= 0.83333

Which of the following are exterior angles? Check all that apply.

Answers

Answer:

<5

Step-by-step explanation:

exterior angles + the corresponding interior angle of the triangle = 180º or a straight angle

the only exterior angle shown in the diagram is <5, which corresponds to the interior <2

hope this helps!

Answer:

<5

Step-by-step explanation:

everything else is matched up perfectly so it has to be <5

Find x. Round your answer to the nearest tenth of a degree.

Answers

Answer: x=52.6°

Step-by-step explanation:

To find the value of x, we have to use our SOHCAHTOA. We can eliminate sine and cosine because both uses hypotenuse, which is not labelled. Therefore, we use tangent.

[tex]tan(x)=\frac{17}{13}[/tex]

To find x, we want to use inverse tangent.

[tex]x=tan^{-1}(\frac{17}{13} )[/tex]      [plug into calculator]

[tex]x=52.6[/tex]

Now, we know that x=52.6°.

Find the missing side lengths leave your answer as a racials simplest form

Answers

Answer:

x = 20

y = 10

Answered by Gauthmat

Can someone please help with 25 , please put the way you got it. Please no links it’s serious

Answers

Answer:

X * 0.8 = $64

x = $80

Step-by-step explanation:

A math professor is wondering if students today are better or worse than in the past. He has given the same final to this year's class that he gave ten years ago. Compute mean, median, and mode for both classes and write a paragraph summarizing the differences.

This Year
35 45 65 75 87
80 69 71 53 90
99 95 70 82 73
93 67 61 57 74
72 77 71 81 83

Ten Years Ago
56 77 75 76 59
74 51 89 55 79
67 77 69 91 68
90 65 79 69 79
87 86 98 91 95

Answers

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following data:

This year :

35, 45, 53, 57, 61, 65, 67, 69, 70, 71, 71, 72, 73, 74, 75, 77, 80, 81, 82, 83, 87, 90, 93, 95, 99

Mean = ΣX / n = 1825 / 25 = 73

The mode = 71 ( most frequently occurring)

Median = 1/2(n+1)th term = 1/(26) = 13th term

Median = 73

10 years ago :

51, 55, 56, 59, 65, 67, 68, 69, 69, 74, 75, 76, 77, 77, 79, 79, 79, 86, 87, 89, 90, 91, 91, 95, 98

Mean = ΣX / n = 1902 / 25 = 76.08

The mode = 79 ( most frequently occurring)

Median = 1/2(n+1)th term = 1/(26) = 13th term

Median = 77

According to the computed statistics, we can conclude that, today is worse than the past as the average score which is almost similar to the median value is higher 10 years ago and the modal score is better 10 years ago as well.

A 2-column table has 2 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f (x) with entries 8, 2, 0.5, 0.125, 0.03125.
Use the table of values to write the exponential function.

Answers

Answer:

0.5

0.25

Step-by-step explanation:

The equation for the exponential function is f(x) = 0.5(0.25)ˣ after applying the concept of the function.

What is an exponential function?

It is defined as a function that rapidly increases and the value of the exponential function is always positive. It denotes with exponent y = aˣ

where a is a constant and a>1

It is given that:

A 2-column table has 2 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f (x) with entries 8, 2, 0.5, 0.125, and 0.03125.

x     f(x)

-2     8

-1      2

0      0.5

1       0.125

2       0.03125

Let the function is:

f(x) = a(b)ˣ

Plug x = 0 and f(x) = 0.5

0.5 = a

Plug x = -1 and f(x) = 2

2 = 0.5(1/b)

b = 0.5/2 = 0.25

f(x) = 0.5(0.25)ˣ

Thus, the equation for the exponential function is f(x) = 0.5(0.25)ˣ after applying the concept of the function.

Learn more about the exponential function here:

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If g(x)=x+1/x-2 and h(x) = 4 – x, what is the value of (9*h)(-3)?

Answers

9514 1404 393

Answer:

  (g·h)(-3) = 2.8

Step-by-step explanation:

Given:

  g(x) = (x +1)/(x -2)

  h(x) = 4 -x

Find:

  (g·h)(x) = g(x) × h(x)   for x = -3

Solution:

  g(-3) = (-3+1)/(-3-2) = -2/-5 = 2/5

  h(-3) = 4 -(-3) = 4 +3 = 7

Then the product is ...

  g(-3)·h(-3) = (2/5)(7) = 14/5 = 2.8

  (g·h)(-3) = 2.8

Find the measure of the missing angles.

Answers

Answer:

Step-by-step explanation:

14. In a garden 746496 apple trees are arranged in such a way that, there are as inany rows as there are in a row. How many rows are there in the garden ​

Answers

Answer:

864

Step-by-step explanation:

do the square root of the total number

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