A company makes 3 types of cable. Cable A requires 3 black, 3 white, and 2 red wires. B requires 1 black, 2 white, and 1 red. C requires 2 black, 1 white, and 2 red. Make a 3 x 3 matrix showing the wire requirements. Assign the cable types to the rows and the wire types to the columns.
A) [2 1 2 1 2 1 2 1 3].
B) [3 3 2 1 2 1 2 1 1].
C) [3 1 2 3 2 1 2 1 2].
D) [2 1 3 1 2 1 2 1 2].

Answers

Answer 1

Answer:

The answer is (B) but with 2 as the last item in the matrix, instead of 1.

Step-by-step explanation:

The grand topic is MATRICES.

In Matrices, there are rules to follow when creating a matrix - which is a 'row by column' arrangement of objects or figures.

Rule 1: Identify your rows and columns.

What is a row? A row is a 'left to right' arrangement of items; also called a horizontal arrangement of items. What is a column? A column is an 'up to down' arrangement of items; also called a vertical arrangement of items.

Rule 2: Start your arrangement by rows.

Before reaching the instruction in the question, I already arranged the data for cables on the rows and the data for wire colors on the columns. You should follow this rule always; from the first information given in the question.

Rule 3: Nomenclature

This is the naming of a given matrix. In naming a matrix, consider the rows first before the columns. For example, a matrix with three rows and four columns with be called a 3 by 4 matrix and not a 4 by 3 matrix. In the case of this question, there is an equal number of rows and columns, so even if you counted the columns first, it wouldn't be noticed. Nevertheless, always count the rows first.

Having arranged the figures in a 3 by 3 matrix,

The full data on Cable A appears on the first row. The full data on Cable B appears on the second row. The full data on Cable C appears on the third row.

The full data on Black wires appears on the first column. The full data on White wires appears on the second column. The full data on Red wires appears on the third column.

So the answer is [tex]\left[\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right][/tex]

Kudos!


Related Questions

The Cinci Company issues $100,000, 10% bonds at 103 on October 1, 2020. The bonds are
dated January 1, 2020 and mature eight years from that date. Straight-line amortization is used.
Interest is paid annually each December 31. Compute the bond carrying value as of December
31, 2024.

Answers

According to the given values in the question:

The Amortization period is:

= [tex]8 \ years\times 12 \ months[/tex]

= [tex]96 \ months[/tex]

Number of months of Amortization is:

= [tex]3 \ months \ in \ 2020+(4 \ years\times 12 \ months)[/tex]

= [tex]3+48[/tex]

= [tex]51 \ months[/tex]

Now,

On bonds payable, the premium will be:

= [tex]Issue \ price - Face \ value[/tex]

= [tex](100000\times 103 \ percent)- 100000[/tex]

= [tex]103000-100000[/tex]

= [tex]3000[/tex] ($)

The Unamortized premium will be:

= [tex]Premium - Unamortized \ premium[/tex]

= [tex]3000-(3000\times \frac{51}{96} )[/tex]

= [tex]3000-1593.75[/tex]

= [tex]1406.25[/tex] ($)

hence,

The carrying value as of December  31, 2024 will be:

= [tex]100000+1406.25[/tex]

= [tex]101406.25[/tex] ($)

Learn more about the bond carrying value here:

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You take out a 60-day loan for $5000. At the end of the loan, you owe $73.97 in interest. What is the annual percentage rate? Round your answer to the nearest tenth of a percent.

Answers

The PERCENTAGE ANNUAL RATE is 9.0% to the nearest tenth using the SIMPLE INTEREST FORMULA

The question is related to a SIMPLE INTEREST problem:

Loan period = 60 days

using 365 days a year ;

converting to years , 60 days = (60 / 365) years

interest on loan = 73.97

principal = 5000

Using the formula:

interest = (principal * rate * time)

73.79 = (5000 * rate * (60/365)

Rate = 73.79/(5000 * (60/365)) =8.977%

rate = 9%

Therefore, PERCENTAGE ANNUAL RATE is 9.0%

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If there are
12 books in the rack, a person has to choose 5
out of them. In how many ways
can he choose books,if one
book is never selected?

Answers

Answer:

462 ways

Step-by-step explanation:

One book never selected means 12 - 1 = 11.

So to find the number of ways, 11C5 which equals to: 11!/(5!(11-5)!) = 462

Damaged items are marked down 25% to 40%. A newspaper coupon holder; to an additional 10% markdown of the new price due to the damage. What is the lowest price of a damaged item that was originally marked GHC100?
A GHC 35.60
B GH 5000
C. GHC 18.00
D. GHC 40.80
E GHC 23.40​

Answers

Markdown is the difference (at sale) between the price an item is placed at for retail sale, and the actual price the item is sold

The correct option is; B. GHC 50.00

The reason for choosing option B is as follows;

The known parameters

The percentage by which damaged items are marked down = 25% to 40%

The percentage markdown offered by the newspaper coupon = 10%

The original marked price of the item = GHC 100

Strategy:

Apply the damaged items and coupon markdown percentages to the original marked price of GHC100 sum the results to find the total markdown

Solution:

Markdown due to damage:

Given that the item is damaged, to have the lowest price, we apply the largest markdown of 40%;

40% is removed from the price to which the item marked down due to damage, as follows;

The markdown due to damage = 40/100 × GHC 100 = GHC 40

Markdown due to Coupon Holder:

The markdown the coupon holder is to get = 10% off the retail price

Given that the damage is not mentioned in the newspaper, we have;

∴ The markdown the coupon holder is to get = 10/100 × GHC 100 = GHC 10

Total markdown:

The total markdown is therefore equal to GHC 40 + GHC 10 = GHC 50

The Lowest Price of A Damaged Items marked GHC100:

The lowest price of the item = Original price - Maximum markdown

The lowest price of the item = GHC 100 - GHC 50 = GHC 50

Learn more about markdown and markup concepts here;

https://brainly.com/question/20705786

Find the missing side round your answer to the nearest tenth.

Answers

Answer:

x=74.3

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp /adj

tan 22 = 30/x

x tan 22 = 30

x = 30/ tan 22

x=74.25260

To the nearest tenth

x=74.3

find the two intersection points

(x+1)^2 +(y+2)^2 = 16

3x+ 4y = 1
Show your steps please

Answers

Answer:

Our two intersection points are:

[tex]\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)[/tex]

Step-by-step explanation:

We want to find where the two graphs given by the equations:

[tex]\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1[/tex]

Intersect.

When they intersect, their x- and y-values are equivalent. So, we can solve one equation for y and substitute it into the other and solve for x.

Since the linear equation is easier to solve, solve it for y:

[tex]\displaystyle y = -\frac{3}{4} x + \frac{1}{4}[/tex]

Substitute this into the first equation:

[tex]\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16[/tex]

Simplify:

[tex]\displaystyle (x+1)^2 + \left(-\frac{3}{4} x + \frac{9}{4}\right)^2 = 16[/tex]

Square. We can use the perfect square trinomial pattern:

[tex]\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16[/tex]

Multiply both sides by 16:

[tex](16x^2+32x+16)+(9x^2-54x+81) = 256[/tex]

Combine like terms:

[tex]25x^2+-22x+97=256[/tex]

Isolate the equation:

[tex]\displaystyle 25x^2 - 22x -159=0[/tex]

We can use the quadratic formula:

[tex]\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

In this case, a = 25, b = -22, and c = -159. Substitute:

[tex]\displaystyle x = \frac{-(-22)\pm\sqrt{(-22)^2-4(25)(-159)}}{2(25)}[/tex]

Evaluate:

[tex]\displaystyle \begin{aligned} x &= \frac{22\pm\sqrt{16384}}{50} \\ \\ &= \frac{22\pm 128}{50}\\ \\ &=\frac{11\pm 64}{25}\end{aligned}[/tex]

Hence, our two solutions are:

[tex]\displaystyle x_1 = \frac{11+64}{25} = 3\text{ and } x_2 = \frac{11-64}{25} =-\frac{53}{25}[/tex]

We have our two x-coordinates.

To find the y-coordinates, we can simply substitute it into the linear equation and evaluate. Thus:

[tex]\displaystyle y_1 = -\frac{3}{4}(3)+\frac{1}{4} = -2[/tex]

And:

[tex]\displaystyle y _2 = -\frac{3}{4}\left(-\frac{53}{25}\right) +\frac{1}{4} = \frac{46}{25}[/tex]

Thus, our two intersection points are:

[tex]\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)[/tex]


I need help answering this ASAP

Answers

Answer:

x greater than and equal to -7

Step-by-step explanation:

Parabola touches at -7 and is going straight towards all positive integers

Therefore the domain is all numbers greater than or equal to -7

Please help I need the answer ASAP!!

Answers

The hypotenuse will always be the longest side of the triangle. Option C is correct: AB > DC.

AB is the hypotenuse of triangle ABC. Therefore, it is greater than leg AC. AC is the hypotenuse of triangle ACD. If AC is less than AB, then DC must also be less than AB because DC is less than AC.

Hope this helps!

please please help its timed -H.M​

Answers

Answer:

1

General Formulas and Concepts:

Algebra I

Functions

Function Notation

Step-by-step explanation:

Step 1: Define

f(-2)

Step 2: Evaluate

f(-2) is x = -2 for function f(x).

According to the table, when x = -2, f(x) = 1.

∴ f(-2) = 1

Let A be an nxn matrix. Determine whether the statement below is true or false. Justify the answer. The determinant of a triangular matrix is the sum of the entries on the main diagonal Choose the correct answer below.
A. The statement is true. Cofactor expansion along the row (or column) with the most zeros of a triangular matrix produces a determinant equal to the son of the tries to the radar
B. The statement is true. The determinant of A is the following finite series. n det A= (-1)* laj, det A1 J = 1 In a triangular matrix, this series simplifies to the sum of the entries along the main diagonal.
C. The statement is false. The determinant of a matrix is the arithmetic mean of the entries along the main diagonal OD The statement is false. The determinant of a triangular matrix is the product of the entries along the main diagonal

Answers

I feel like it’s a because Once you are able to recognize the mathematical pattern of the basic sentence, it is time to move up to the next linguistic equation: the paragraph. I recently opened a new writing class by asking students how many sentences comprise a paragraph. The answers came with as much confidence as they were varied: 3 to 5, 4 to 6, 6 to 8. Students looked at one another with surprise as they waited for me to validate the answer they were taught, but the truth is simple. An effective paragraph must have at least 2 sentences: (1) an effective topic sentence that states the purpose of the paragraph, and (2) clear and specific evidence to support that purpose. The choice between a single sentence providing evidence or multiple sentences providing evidence depends entirely on the writer’s purpose and audience. When we complicate the simple math with preferences like 4, 6, or 8, we muddle the simplicity of basic linguistic structure. Equation #2: a topic sentence + evidence = a paragraph. confidence as they were varied: 3 to 5, 4 to 6, 6 to 8. Students looked at one another with surprise as they waited for me to validate the answer they were taught, but the truth is simple. An effective paragraph must have at least 2 sentences: (1) an effective topic sentence that states the purpose of the paragraph, and (2) clear and specific evidence to support that purpose. The choice between a single sentence providing evidence or multiple sentences providing evidence depends entirely on the writer’s purpose and audience. When we complicate the simple math with preferences like 4, 6, or 8, we muddle the simplicity of basic linguistic structure. Equation #2: a topic sentence + evidence = a paragraph.

Find the value of X. Round to the
nearest tenth.

Answers

Answer: 8.1

Step-by-step explanation:

4^2 + X^2 = 9^2

16 + X^2 = 81

X^2 = 81-16

X = sqrt 65 = 8.1

A student decides she wants to save money to buy a used car, which costs $2600.She comes upwith what she thinks is a very modest savings plan. She decides to save 2 cents the first day anddouble the amount she saves each day thereafter. On the second day she plans to save 4 cents, onthe third day, 8 cents, and so on.

(a)Write an expression that represents the amount savedon dayn;(b)Write an expression that represents the total amount savedby dayn (including day n);(c)Determine how long it will take her to save enough money to buy the car (The answermay surprise you!)

Answers

Answer: total cost to be saved is $2600. Her saving pattern is 2, 4, 8,…

a) The pattern of her saving is in geometric sequence. i.e. a=2, r=4/2=2 0r 8/4=2 ( a = First term, r = common ratio) so, expression for amount saved on day (n) = t(n) = ar^(n-1), where: a = first day of saving r = common ration n = number of day

b) Expression that represents the total amount saved by day (n) (including day n) = S = a(r^n-1)/r-1 where: S = sum of amount saved a = first day of saving r = common ration n = number of day

c) To buy the car, she needs at least $2600 which is equal 260000 cents.  S = a(r^n-1)/r-1 = 260000 = 2(2^n-1)/r-1 = 260000/2 = 2^n-1/2-1 = 130000 = 2n^-1 = 130000+1 = 2^n = 130001 = 2^n = n = ln(130001)/ln(2) = n = 16.988

So… for n to satisfy the least value of 130001 cents, n should be at least 17 Therefore it will take at least 17 days for her to save enough money to buy a car

Step-by-step explanation:

It will take her about 17 days to buy the car worth 260000 cents

If a student decides she wants to save money to buy a used car that cost $2600 (260,000 cents)

If she saves 2 cents the first day and doubles the amount thereafter, the sequence of savings will be:

2, 4, 8...

This sequence is geometric in nature

In order to determine how long it will take her to save 260,000, we will use the sum of a GP formula expressed as:

[tex]S_n = \frac{a(r^n-1)}{r-1}[/tex]

Given the folowing

a = 2

r = 4/2 = 8/4 = 2

Sn = 260,000

Substitute into the formula the given parameters

[tex]260000= \frac{2(2^n-1)}{2-1}\\260000/2=2^n-1\\130000 = 2^n - 1\\2^n = 130000 + 1\\2^n = 130001\\nlog 2=log130001\\n = \frac{log130001}{log2} \\n \approx 17[/tex]

This shows that it will take her about 17 days to buy the car worth 260000 cents

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The function g(x)=8(4*) is reflected across the x-axis to
create f(x).
What is the equation of f(x)?
O f(x)=8(4)
O f(x)=-8(4)*
14
9(x)
12
10
o f(x)=8(4)
o f(x)=-8()
do
OR
4
2
A
-3
-2
2
3
х
-10
-12
f(x)
14

Answers

9514 1404 393

Answer:

  (b)  f(x) = -8(4^x)

Step-by-step explanation:

Reflection across the x-axis multiplies the function by -1.

  f(x) = -g(x) = -8(4^x)

a coin is tossed succesively three times times . determine tje probabiliy of getting all three heads​

Answers

Answer:

Answer : 1/8.

Step-by-step explanation:

Hey there!

Please see the attached picture for your answer.

Hope it helps!

Please help asap! Easy question :)

Two fair dice are rolled. Determine the following probability:
P(​one number is a multiple of 4 and the other is a multiple of 6)

Answers

Answer:

P(​one number is a multiple of 4 and the other is a multiple of 6) = 1/18

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Total outcomes:

For the pair of dice:

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

So 36 total outcomes.

Desired outcomes:

One multiple of 4 and one multiple of 6.

2 possible outcomes: (4,6) or (6,4)

Probability:

2 outcomes out of 36, so:

[tex]p = \frac{2}{36} = \frac{1}{18}[/tex]

Then

P(​one number is a multiple of 4 and the other is a multiple of 6) = 1/18

A 6-pound container of detergent costs $4.38. what is the price per pound?

Answers

Answer:

.73 per pound

Step-by-step explanation:

Take the total cost and divide by the number of pounds

4.38/ 6

.73 per pound

y=4.5x+13.45 y=6x-4.55

Answers

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(

12

,

67.45

)

Equation Form:

x

=

12

,

y

=

67.45

g A gift shop sells 40 wind chimes per month at $110 each. The owners estimate that for each $11 increase in price, they will sell 2 fewer wind chimes per month. Find the price per wind chime that will maximize revenue.

Answers

Answer:

The price that maximizes the revenue is $165

Step-by-step explanation:

We can model the price as a function of sold units as a linear relationship.

Remember that a linear relationship is something like:

y = a*x + b

where a is the slope and b is the y-intercept.

We know that if the line passes through the points (x₁, y₁) and (x₂, y₂), then the slope can be written as:

a = (y₂ - y₁)/(x₂ - x₁)

For this line, we have the point (40, $110)

which means that to sell 40 units, the price must be $110

And we know that if the price increases by $11, then he will sell 2 units less.

Then we also have the point (38, $121)

So we know that our line passes through the points (40, $110) and  (38, $121)

Then the slope of the line is:

a = ($121 - $110)/(38 - 40) = $11/-2 = -$5.5

Then the equation of the line is:

p(x) = -$5.5*x + b

to find the value of b, we can use the point (40, $110)

This means that when x = 40, the price is $110

then:

p(40) = $110 = -$5.5*40 + b

            $110 = -$220 + b

       $110 + $220 = b

        $330 = b

Then the price equation is:

p(x) = -$5.5*x + $330

Now we want to find the maximum revenue.

The revenue for selling x items, each at the price p(x), is:

revenue = x*p(x)

replacing the p(x) by the equation we get:

revenue = x*(-$5.5*x + $330)

revenue = -$5.5*x^2 + $330*x

Now we want to find the x-value for the maximum revenue.

You can see that the revenue equation is a quadratic equation with a negative leading coefficient. This means that the maximum is at the vertex.

And remember that for a quadratic equation like:

y = a*x^2 + b*x + c

the x-value of the vertex is:

x = -b/2a

Then for our equation:

revenue = -$5.5*x^2 + $330*x

the x-vale of the vertex will be:

x = -$330/(2*-$5.5) = 30

x = 30

This means that the revenue is maximized when we sell 30 units.

And the price is p(x) evaluated in x = 30

p(30) = -$5.5*30 + $330 = $165

The price that maximizes the revenue is $165

(x + y, 2) = (13, 2x - y)​

Answers

Answer: (x, y) = (5,8)

Step-by-step explanation:

x + y = 13       2x - y = 2

y = -x + 13

2x - (-x + 13) = 2   3x =15

x=5

x=5       y = -x + 13

y = -(5) + 13 = 8

Help me please and thank you

Answers

Answer:

D) 0.89

Step-by-step explanation:

round 0.885 to 0.89

What is the order of rotational symmetry for the figure?
A. 3
B. 2
C. 4 or more
D. 1

Answers

9514 1404 393

Answer:

  C.  4 or more

Step-by-step explanation:

Rotating the figure in increments of 90° will give the same figure. There are 4 such rotations in a full turn. The order of rotational symmetry is 4.

HELP !
Find the measure it the given angle.​

Answers

Answer:

it's 90

Step-by-step explanation:

inscribed angle intercepts a semicircle is always 90

Answer:90
Because you have to find the radius and x by pi

Colin stacks 3 snowballs on top of each other to make a snowman. The snowballs are \dfrac7{10} \text{ meter} 10 7 ​ meterstart fraction, 7, divided by, 10, end fraction, start text, space, m, e, t, e, r, end text, \dfrac12 \text{ meter} 2 1 ​ meterstart fraction, 1, divided by, 2, end fraction, start text, space, m, e, t, e, r, end text, and 38 \text{ centimeters}38 centimeters38, start text, space, c, e, n, t, i, m, e, t, e, r, s, end text tall. What is the total height of the snowman in centimeters?

Answers

Answer:

[tex]Total = 158cm[/tex]

Step-by-step explanation:

Given

[tex]x: \dfrac7{10}m, \dfrac12m,38cm[/tex]

See comment

Required

The total height

This is calculated as:

[tex]Total = \sum x[/tex]

So, we have:

[tex]Total = \dfrac7{10}m+ \dfrac12m+38cm[/tex]

Express m as cm

[tex]Total = \dfrac7{10}cm * 100+ \dfrac12cm * 100+38cm[/tex]

[tex]Total = 70cm + 50cm + 38cm[/tex]

Take LCM

[tex]Total = 158cm[/tex]

Answer: ♔158 centimeters.☯ Trust me it is correct. ヾ(•ω•`)o

Trucks in a delivery fleet travel a mean of 120 miles per day with a standard deviation of 23 miles per day. The mileage per day is distributed normally. Find the probability that a truck drives less than 159 miles in a day. Round your answer to four decimal places.

Answers

Answer:

the probability that a truck drives less than 159 miles in a day = 0.9374

Step-by-step explanation:

Given;

mean of the truck's speed, (m) = 120 miles per day

standard deviation, d = 23 miles per day

If the mileage per day is normally distributed, we use the following conceptual method to determine the probability of less than 159 miles per day;

1 standard deviation above the mean = m + d, = 120 + 23 = 143

2 standard deviation above the mean = m + 2d, = 120 + 46 = 166

159 is below 2 standard deviation above the mean but greater than 1 standard deviation above the mean.

For normal districution, 1 standard deviation above the mean = 84 percentile

Also, 2 standard deviation above the mean = 98 percentile

143 --------> 84%

159 ---------> x

166 --------- 98%

[tex]\frac{159-143}{166-143} = \frac{x-84}{98-84} \\\\\frac{16}{23} = \frac{x-84}{14} \\\\23(x-84) = 224\\\\x-84 = 9.7391\\\\x = 93.7391\ \%[/tex]

Therefore, the probability that a truck drives less than 159 miles in a day = 0.9374

Calculate the break even sales dollars if the fixed expenses are $7,000 and the contribution ratio is 40%.

Answers

Answer:

Break even sales = $17,500 (Approx.)

Step-by-step explanation:

Given:

Fixed expenses = $7,000

Contribution ratio = 40%

Find:

Break even sales dollars

Computation:

Break even sales = Fixed expenses / Contribution ratio

Break even sales = 7,000 / 40%

Break even sales = 7,000 / 0.40

Break even sales = 17,500

Break even sales = $17,500 (Approx.)

Factor the trinomial. Write the answer in binomial fctor form.
2x^2– 13x + 11

Answers

9514 1404 393

Answer:

  (2x -11)(x -1)

Step-by-step explanation:

The middle term can be rewritten as a sum using the coefficients of the first and last terms. Then the expression can be factored by pairs of terms.

  2x^2 -13x +11 = 2x^2 -2x -11x +11 = 2x(x -1) -11(x -1)

  = (2x -11)(x -1)

a jet flew 2660 miles in 4.75 hours. what is the rate of speed in miles per hour? (the proportion would be 2660:4.75::x:1 set the proportion in fractional form and proceed to find x.)​

Answers

Set the proportion as shown:

2660/4.75 = x/1

Cross multiply:

4.75x = 2660

Divide both sides by 4.75

x = 560

Answer: 560 miles per hour

–20 ÷ 5 =

I need help

Answers

The answer is -4
-20 divided by 5 ^

find the equation of straight line passes through point (3,1) such that the intercept on y-axis exceeds that on the x- axis by 4.



Answers

Answer:

Step-by-step explanation:

Use the integral test to determine whether the series is convergent or divergent. [infinity] n = 2 n2 n3 + 1 Evaluate the following integral. [infinity] 2 x2 x3 + 1 dx

Answers

I think the given series is

[tex]\displaystyle\sum_{n=2}^\infty \frac{n^2}{n^3+1}[/tex]

You can use the integral test because the summand is clearly positive and decreasing. Then

[tex]\displaystyle\sum_{n=2}^\infty\frac{n^2}{n^3+1} > \int_2^\infty\frac{x^2}{x^3+1}\,\mathrm dx[/tex]

Substitute u = x ³ + 1 and du = 3x ² dx, so the integral becomes

[tex]\displaystyle \int_2^\infty\frac{x^2}{x^3+1}\,\mathrm dx = \frac13\int_9^\infty\frac{\mathrm du}u = \frac13\ln(u)\bigg|_{u=9}^{u\to\infty}[/tex]

As u approaches infinity, we have ln(u) also approaching infinity (whereas 1/3 ln(9) is finite), so the integral and hence the sum diverges.

Other Questions
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