A caterpillar crawls 20 feet in 5 minutes. What is the caterpillars crawling speed?
Equation needed:

Answer:

The distance of the object from the concave mirror determines if it is a virtual or real image

Explanation:

Concave mirrors form both real and virtual images. When the concave mirror is placed very close to the object, a virtual and magnified image is obtained and if we increase the distance between the object and the mirror, the size of the image reduces and real images are formed.

Answer:The choke coil works because it can act as an inductor. When the current pass through will change as AC currents creates a magnetic field in the coil that works against that current. This is known as inductance and blocks most of the AC current from passing through.

Explanation:

Given :

Charge on glass bead, Q = 8 nC .

To Find :

The magnitude of the electric field 2.0 m from the center of the bead.

Solution :

Electric field at position r is given by :

[tex]E = \dfrac{kQ}{r^2}\\\\E = \dfrac{9\times 10^9\times 8\times 10^{-9}}{2^2}\\\\E = 18\ N/C[/tex]

Therefore, the magnitude of the electric field 2.0 m from the center of the bead is 18 N/C .

Complete question is;

A 5 × 10^(5) kg subway train is brought to a stop from a speed of 0.5 m/s in 0.4 m by a large spring bumper at the end of its track. what is the force constant k of the spring

Answer:

781250 N/m

Explanation:

From conservation of energy, potential energy is equal to kinetic energy.

Thus;

½mv² = ½kx²

where;

m = mass of train

v = velocity of train

k = force constant of spring

x = the distance the train went while being stopped

We are given;

Mass; m = 5 × 10^(5) kg

Velocity; v = 0.5 m/s

Distance; x = 0.4 m

Thus, from ½mv² = ½kx²

Divide both sides by ½ to get;

mv² = kx²

k = mv²/x²

k = [(5 × 10^(5)) × 0.5²]/0.4²

k = 781250 N/m

This question is incomplete, the complete question is;

1.80 kg monkey wrench is pivoted 0.250 m from its center of mass and allowed to swing as a physical pendulum. the period for small angle oscillations is 0.940 s.

a) what is the moment of inertia of the wrench about an axis through the pivot?

b) If the wrench is initially displaced 0.400 rad from its equilibrium position, what is the angular speed of the wrench as it passes through the equilibrium position

Answer:

a) the moment of inertia of the wrench about an axis through the pivot is 0.0987 Kg.m²

b) the angular speed of the wrench as it passes through the equilibrium position is 2.6559 rad/s

Explanation:

Given that

mass m = 1.80 kg

L or d = 0.250 m

period T = 0.940 sec

g = 9.8

a)

we take a look at the expression for the moment of inertia

I = T²mgL / 4π²

we substitute

I = ((0.940)² × 1.80 × 9.8 × 0.250) / 4 × π²

I = 3.896676 / 4 × π²

I = 0.0987 Kg.m²

Therefore the moment of inertia of the wrench about an axis through the pivot is 0.0987 Kg.m²

b)

If the wrench is initially displaced 0.400 rad from its equilibrium position,

the angular speed of the wrench as it passes through the equilibrium position = ?

Using conservation of energy;

mg × d × ( 1 - cos∅) = 1/2×I×w²

we substitute

1.80 × 9.8 × 0.250 × ( 1 - cos(0.400 rad)) =  1/2 × 0.0987  × w²

4.41 × ( 1 - 0.921060994 ) = 0.04935 × w²

0.000441 = 0.04935w²

w² = 0.3481 / 0.04935

w² = 7.0536

w = √7.0536

w = 2.6559 rad/s

Therefore, the angular speed of the wrench as it passes through the equilibrium position is 2.6559 rad/s

I suppose you mean to say that the wall is frictionless in the first scenario? Also, I assume the block is to held in place. Construct a free body diagram for the block. There are 3 (in part A) or 4 (in part B) forces acting on it.

• its weight w, pulling it downward

• the normal force (magnitude n), pushing outward from the wall to the left

• the push as described, with magnitude p

• static friction (mag. f ), opposing the upward net force and thus pointing downward.

The static friction force has a magnitude proportional to that of the normal force. If the coefficient of static friction is µ, then

f = µ n

so if the wall is frictionless with µ = 0, then f = 0 and does not need to be considered.

(A) If µ = 0, then by Newton's second law we have

• net vertical force:

∑ F = p sin(50°) - w = 0

and we don't need to consider the net horizontal force to determine p from here. We get

p = w / sin(50°) = (4 kg) (9.8 m/s²) / sin(50°) ≈ 51 N

(B) If µ = 0.25, then Newton's second law gives

• net vertical force:

∑ F = p sin(50°) - w - f = 0

p sin(50°) - f = (4 kg) (9.8 m/s²)

p sin(50°) - f = 39.2 N

• net horizontal force:

∑ F = p cos(50°) - n = 0

p cos(50°) - f /0.25 = 0

[since f = 0.25 n]

p cos(50°) - 4f = 0

Multiply the first equation by -4, then add it to the second equation to eliminate f and solve for p :

-4(p sin(50°) - f ) + (p cos(50°) - 4f ) = -4 (39.2 N) + 0

p (cos(50°) - 4 sin(50°)) = -156.8 N

p = (156.8 N) / (4 sin(50°) - cos(50°)) ≈ 65 N

Answer:

the answer is A because

from tate 4 dozen is 48 and from joe the sixth multiple of eight is 48

Answer:

average

Explanation:

Answer:

Alpha radiation is a kinda massive type of radiation, this would mean that alpha radiation is weakly penetrating. Because of this:

a) When we have particles of smoke in the path of the alpha radiation, the smoke will "stop" a big part of the radiation, and when the detector stops detecting the radiation, it will let the alarm go off.

b) The radiation of alpha particles can be harmful, yes, but the smoke detector is shielded (Again, alpha radiation is weakly penetrating, then shielding the smoke detector is an easy task), this means that the radiation can not get out of the smoke detector, then it is not a problem for the people living near it.

Answer:

a strange world that has baffled scientists ever since it was discovered in 1930. It is not the large gas giant that one might expect to find in the outer reaches of the solar system.

Explanation:

Explanation

Answer:

C option is right.

Explanation:

According to columb's law

F ∝ 1/r²

so as r means distance between charges decrease force F increase and vice versa.

Answer:

Periodic Motion :–

This is a type of motion where the object repeats its motion after a fixed interval of time.

Examples: pendulum of a clock, motion of child on a swing etc.

Answer:

Periodic motion is a type of motion that is being performed. You can take a rocking chair, bouncing ball, and a swing as an example of periodic motion.

Periodic motion is just another word for the motion because it describes any type of object performing movements even an object vibrating is another great example of periodic motion. If you want to talk about the motion of the universe take Earth and the moon orbiting around the sun it is an object performing.

Hope this helped :)

Answer:

40m to the East

Explanation:

Displacement is the distance moved in a specific direction. When writing the displacement value of a moving body, the direction must be put in the description.

Displacement takes into account the start and finish position of a body.

                                                 100m

Start         --------------------------------------------------------------  →

                                                               60m

                                       Final ←----------------------------------

Displacement  = 100m  - 60m  = 40m

 Therefore, the displacement is 40m due east

Explanation:

Since Pressure = Force / Area,

We have 550N / (0.003m²) = 180k Pa. (2s.f.)

Answer:

The new gravitational force will be of 4.5 units

Explanation:

Recall that the formula for the gravitational force between two objects of masses m1 and m2 separated by a distance d is given by:

[tex]F_g=G\,\frac{m1*m2}{d^2}[/tex]

in our case, we are told that such gives 72 units of force:

[tex]F_g=G\,\frac{m1*m2}{d^2} =72[/tex]

Then we change the distance between the objects to 4 times the original (4 * d), such will produce a new gravitational force Fg':

[tex]F_g'=G\,\frac{m1*m2}{(4*d)^2} =G\,\frac{m1*m2}{16*d^2} = \frac{1}{16} *G\,\frac{m1*m2}{d^2}=\frac{1}{16} *\,72=4.5[/tex]

Therefore the new gravitational force would be of 4.5 units

Answer:

Work = 250 Joules.

Explanation:

Given the following data;

Potential difference, V = 25V

Charge, C = 10 Coulombs

To find the work required;

Work = Charge * potential difference

Substituting into the equation, we have

Work = 10*25

Work = 250 Joules.

Therefore, the amount of work required to move the charge from A to B is 250 Joules.

Answer:

Ca = 2

Cl = 2

O = 6

Explanation:

Element given from the question above include = 2CaClO₃

NOTE: The 2 in front of CaClO₃ is affecting Ca, Cl and O.

Thus, the number of each atom of element present in 2CaClO₃ can be obtained as follow:

Ca = 1 × 2 = 2

Cl = 1 × 2 = 2

O = 3 × 2 = 6

Thus,

Ca = 2

Cl = 2

O = 6

Answer:

Yes

Explanation:

Answer:70 watts

Explanation: I took the test and got it correct

Answer:

Explanation:

The best terms that represent vector quantity are magnitude and direction. Magnitude and direction are both qualities in vector quantity. The basic measurement of vector quantity is the meter all others would best be described as scalars. So to best describe vector quantity use the meter uni

Answer: it will take 1000 guitar players for sound intensity level to be 100 dB

Explanation:

Given that;

noise level of a single player = 70 dB

Intensity of one guitar will be;

SL= 10 × log(I/I₀)

where I₀ is hum threshold intensity = 10⁻¹² W/m²

I is intensity of sound produced by 1 guitar

SL is intensity level of one guitar

so we substitute

70 = 10 × log(I/10⁻¹²)

70/10 = log (I/10⁻¹²)

I = 10⁻¹² × 10⁷

I = 10⁻⁵ W/m²  

now Suppose n guitars produce sound intensity of 100 dB, then intensity of n guitars (In) will be;

100 = 10 × log(In/10⁻¹²)

log(In/10⁻¹²)  = 100/10

In = 10⁻¹² × 10¹⁰ =  10⁻² Wm²

we know that Now intensity of 1 guitar I = 10⁻⁵ W/m²

so Intensity of n guitars will be;

n × I = In

n = In / I

we substitute

n = 10⁻² Wm² /  10⁻⁵ W/m²

n = 1000

Therefore, it will take 1000 guitar players for sound intensity level to be 100 dB

Answer:

b

Explanation:

doing same amount of work while increase in amount of heat released

Answer:

90 m

Explanation:

For ball A::

The equation of a ball moving upwards is given by the formula:

s = ut - (1/2)gt²

where u is the initial velocity, t is the time covered, g is the acceleration due to gravity = 10 m/s² and s is the distance travelled.

Given that:

u = 10 m/s, t = 3 sec, g = 10 m/s², hence:

s = (10 * 3) - (1/2) * 10 * 3²

s = 30 - 45

s = -15 m

The negative sign means the object travels in the opposite direction. Hence s = 15 m

For ball B::

The equation of a ball falling downwards is given by the formula:

s = ut + (1/2)gt²

Given that:

u = 10 m/s, t = 3 sec, g = 10 m/s², hence:

s = (10 * 3) + (1/2) * 10 * 3²

s = 30 + 45

s = 75 m

Hence the separation between the two balls after 3 sec of projection = 15 m + 75 m = 90 m

Answer:

f = 0.0833 Hz

Explanation:

Frequency is defined as the no. of cycles per unit time. The frequency of water waves can be given by the following formula:

[tex]Frequency\ of\ waves = f = \frac{No.\ of\ Waves}{time}\\[/tex]

here,

No. of Waves = No. of times seagull moves up and down = 5

Time = 1 minute = 60 sec

Therefore, using these values in the formula, we get:

[tex]f = \frac{5}{60\ sec}[/tex]

f = 0.0833 Hz

Answer:

d = 8.06 (units)

Explanation:

In this problem, we are given two points with X & y coordinates. therefore we must use the Pythagorean theorem with the respective coordinates of each point to determine the required distance.

[tex]A = (-6, 1)\\B = (2, 2)[/tex]

Now using the Pythagorean theorem.

[tex]d=\sqrt{(x_{1}-x_{0})^{2} +(y_{1}-y_{o})^{2} }\\d=\sqrt{(2-(-6))^{2} +(2-1)^{2} }\\d=\sqrt{64+1} \\d=8.06[/tex]

Explanation:

Q is the charge, 9×10^9×3×10^4 is the magnitude ,d = 5 cm therefore q=3×10^4÷5^2=2.7×10^14÷25=1.08×10^13 c

Answer:

Apllo?

Explanation:

Answer:

A medium in which speed of light is more is known as optically rarer medium and a medium in which speed of light is less is said to be optically denser medium. For example in air and water, air is raer and water is a denser medium.

Explanation:

Answer:Rarer medium is less dense

Explanation:

Rarer medium is less dense than dense medium because rarer medium doesn't have a very high amount of particles packing it together. It's easier to see through a rarer medium, so you're able to get a clearer picture of what's on the other side of it. Denser medium is, simply put, more dense.

Answer:

a) v = 32.8 m/s

b) v= 15.4 m/s

Explanation:

a)

        [tex]v = v_{o} + a*t (1)[/tex]

        where v₀ is the initial velocity and a is the acceleration, being t the

       time elapsed.

       [tex]v = 23.6 m/s + (1.30 m/s2 * 7.10 s) = 32. 8 m/s (2)[/tex]

b)  

       [tex]v = 23.6 m/s + ((-1.15 m/s2) * 7.10 s)) = 15. 4 m/s (3)[/tex]