Answer:
Mass of bullet is m=0.01kg
Mass of the block is M=4kg
Coefficient=0.25,distance=20m
So, let the speed of the block just after the bullet embedded in it be V and v be the speed of bullet before striking the block,
By applying conservation of momentum,
mv=(m+M)V
V=
M+m
mv
Explanation:
please mark me as the brainliest answer and please follow me for more answers to your questions..
The initial velocity of the bullet is 382 m/s
The given parameters;
mass of the wood, m₁ = 0.6 kgheight of the port, h = 2mass of the bullet, m₂ = 10 g = 0.01 kghorizontal distance traveled by the bullet, x = 4 mApply the principle of conservation of mechanical energy;
The maximum potential energy of the bullet-wood system at the top of the port = maximum kinetic energy of the system at the base of the port.
[tex]K.E_{max} = P.E_{max}\\\\\frac{1}{2} mv_{max}^2 = mgh_{max}\\\\v^2_{max} = 2gh_{max}\\\\v_{max} = \sqrt{2gh_{max}} \\\\v_{max} = \sqrt{2\times 9.8\times 2} \\\\v_{max} = 6.26 \ m/s[/tex]
Apply the principle of conservation of linear momentum to determine the initial velocity of the bullet;
let the initial velocity of the bullet = u₂[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\0.6(0) + 0.01(u_2) = 6.26((0.6 + 0.01)\\\\0.01u_2 = 3.819\\\\u_2 = \frac{3.819}{0.01} \\\\u_2 = 381.9 \ \approx 382 \ m/s[/tex]
Thus, the initial velocity of the bullet is 382 m/s
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If a car travels 600m west in 25 seconds, what is its velocity?
Answer:
The answer is 24 m/sExplanation:
The velocity of the car can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex]v = \frac{600}{25} \\ [/tex]
We have the final answer as
24 m/sHope this helps you
What is the purpose of a free body diagram?
CO
to show the velocity of an object
to show the acceleration of an object
to show the forces acting on an object
to show the direction of motion vectors of an object
Answer:
i think the answer is c
Explanation:
zrrxtcyvjvugugyctcyvjv
A free body diagram consists of a diagrammatic representation of a single body or a subsystem of bodies isolated from its surroundings showing all the forces acting on it.
What is free body ?
"A body is said to be "free" when it is singled out from other bodies for the purposes of dynamic or static analysis." The object does not have to be "free" in the sense of being unforced, and it may or may not be in a state of equilibrium; rather, it is not fixed in place and is thus "free" to move in response to forces and torques it may experience.
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True or false- Normally, all objects are electrically positively charged
A sports car of mass 1.00x103 kg can accelerate from rest to 30.0 m/s in 7.00 s. What is the average forward force on the car?
Answer:
Explanation:
Before you can find the force, you need to find the acceleration.
Givens
vi = 0
vf = 30 m/s
t = 7 seconds
Formula
a = (vf - vi) / t
Solution
a = (30 - 0)/7
a = 4.28 m/s
Now you can look at the Force
F = m * a
F = 1.00*10^3 * 4.28
F = 4.28 * 10^3 N
Two point charges of magnitudes +5.00 μC, and +7.00 μC are placed along the x-axis at x = 0 cm and x = 100 cm, respectively. Where must a third charge be placed along the x-axis so that it does not experience any net force because of the other two charges? Two point charges of magnitudes +5.00 μC, and +7.00 μC are placed along the x-axis at x = 0 cm and x = 100 cm, respectively. Where must a third charge be placed along the x-axis so that it does not experience any net force because of the other two charges? 50 cm 45.8 cm 9.12 cm 91.2 cm 4.58 cm
Answer:
45.8 cm
Explanation:
To solve this, we will use the formula
5 / x² = 7/(1 - x)²
5 / x² = 7 / (1 - 2x + x²)
5 / 7 = x² / (1 - 2x + x²)
x = 0.5 * (√(35) - 5) meters
x = 0.5 * (5.916 - 5)
x = 0.5 * (0.916)
x = 0.458 or x = 45.8
The position where the third charge is placed along the x-axis so that it does not experience any net force because of the other two charges is 45.8 cm.
Given :
Two point charges of magnitudes +5.00 μC, and +7.00 μC are placed along the x-axis at x = 0 cm and x = 100 cm, respectively.
The following calculation can be used in order to determine the position where the third charge is placed along the x-axis so that it does not experience any net force because of the other two charges.
[tex]\rm \dfrac{5}{x^2}=\dfrac{7}{(1-x)^2}[/tex]
Simplify the above expression by cross multiplying.
[tex]5(x^2+1-2x)=7x^2[/tex]
[tex]\rm 5x^2 + 5 - 10x = 7x^2[/tex]
[tex]2x^2+2x-1=0[/tex]
Further, simplify the above expression in order to determine the value of x.
x = 0.458
x = 45.8 cm
Therefore, the correct option is b).
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the first outside orbit of Earth planet is
a Jupiter
b Mars
c Saturn
d uranus
Answer:
I believe it would be B, Mars.
Hope this helps!
The superhero Green Lantern steps from the top of a tall building. He falls freely from rest to the ground, falling half the total distance to the ground during the last 1.00 s of his fall (Fig. 2.30). What is the height h of the building?
SOLUTION GUIDE
IDENTIFY and SET UP
1. You’re told that Green Lantern falls freely from rest. What does this imply about his acceleration? About his initial velocity?
2. Choose the direction of the positive y -axis. It’s easiest to make the same choice we used for freely falling objects in Section 2.5.
3. You can divide Green Lantern’s fall into two parts: from the top of the building to the halfway point and from the halfway point to the ground. You know that the second part of the fall lasts 1.00 s. Decide what you would need to know about Green Lantern’s motion at the halfway point in order to solve for the target variable h. Then choose two equations, one for the first part of the fall and one for the second part, that you’ll use together to find an expression for h. (There are several pairs of equations that you could choose.)
EXECUTE
4. Use your two equations to solve for the height h. Heights are always positive numbers, so your answer should be positive.
Answer:
1) its initial velocity is zero, 2) the downward direction as positive
3) h = 25.66 m
Explanation:
This is a free fall exercise.
1) with falls, its initial velocity is zero and the acceleration is constant throughout the path and is equal to the acceleration due to gravity.
2) a widely used selection to estimate the downward direction as positive
3) We know that for the second part of the fall
y₀ -y = h/2 at t = 1 s
y = y₀ + v₁ t + ½ g t²
where v₁ is the initial velocity of this interval at the point y = h / 2
v₁ t = (y -y₀) - ½ g t²
v₁ = h / 2 - ½ g t²
v₁ = h/2 - g/2
now let's write the equation for the first interval
v₁² = v₀² + 2 g (y₁ - y₀)
in this interval v₀ = 0
v₁² = 2 g (y₁ -y₀)
v₁² = 2g h/2
we write our system of equations
v₁² = (h/2 - g/2)²
v₁² = (2g h / 2)
(h /2 - g/2)² = (2g h / 2)
h² / 4 - 2 g/2 h/2 + (g/2)² = g h
h² / 4 - g h/2 - g h + g²/4 = 0
h² - 3 g h + g² =0
h² - 29.4 h +96.04 = 0
we solve the quadratic equation
h = [29.4 ±√ (29.4² - 4 96.04)] / 2
h = [29.4 ± 21.91] / 2
h₁ = 25.66 m
h₂ = 3.75 m
As the system takes more than 1 S to fall, the correct answer for the height is h = 25.66 m
Answer 1)
This is a free fall exercise with falls, its initial velocity is zero and the acceleration is constant throughout the path and is equal to the acceleration due to gravity.
Answer B :
A widely used selection to estimate the downward direction as positive.
Answer 3:
We know that for the second part of the fall:
y₀ -y = h/2 at t = 1 s
y = y₀ + v₁ t + ½ g t²
where v₁ is the initial velocity of this interval at the point
y = h / 2
v₁ t = (y -y₀) - ½ g t²
v₁ = h / 2 - ½ g t²
v₁ = h/2 - g/2
Answer 4:
Now let's write the equation for the first interval
v₁² = v₀² + 2 g (y₁ - y₀)
in this interval v₀ = 0
v₁² = 2 g (y₁ -y₀)
v₁² = 2g h/2
we write our system of equations
v₁² = (h/2 - g/2)²
v₁² = (2g h / 2)
(h /2 - g/2)² = (2g h / 2)
h² / 4 - 2 g/2 h/2 + (g/2)² = g h
h² / 4 - g h/2 - g h + g²/4 = 0
h² - 3 g h + g² =0
h² - 29.4 h +96.04 = 0
we solve the quadratic equation
h = [29.4 ±√ (29.4² - 4 96.04)] / 2
h = [29.4 ± 21.91] / 2
h₁ = 25.66 m
h₂ = 3.75 m
As the height is h = 25.66 m.
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You drive 200 miles in 3 hours before stopping
for 30 minutes for lunch and gas. After lunch,
you travel 150 miles in an hour and a half. What
was your average speed for the trip?
Answer 55.5mph
explanation
Question 4
10 pts
Que
A ping pong ball is thrown straight up into the air and has an initial velocity of 20.5 m/s.
Determine the peak height to which the ping pong ball rises.
Time Runnir
Attempt due:
30 Minutes
O 21 m
O 1 m
O 43 m
O Om
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Submit Ouiz
Answer:
I have no clue what this means or what the answer is i am just trying to get my points up so i can ask questions
Explanation:
i am going to put something here so it looks like an explanation so yeah this has no meaning whatsoever i am very sorry that i am not able to give you the answer try looking the answer up im very very very very sorry :(
Which statements about the kinetic energy of a moving object are true?
Answer:
it a most depends on the moving objects mass
Answer:
Its amount depends on the moving object’s mass,
It can be transferred from one object or body to another, and Its amount depends on the moving object’s speed.
Explanation:
Explain why 15yr old need more calcium than adults
Answer:
When adolescents get enough calcium during the teen years, they can start out their adult lives with the strong bones and significantly reduce their risk for fractures as an adult. Inadequate calcium intake during adolescence and young adulthood puts individuals at risk for developing osteoporosis later in life.
Answer:
I hoped this helpful for youThank you ☺️☺️
Three point charges are positioned as follows: a positive charge +q is located on the x-axis at the point (b, 0), a negative charge -2q is located on the x-axis at the point (-2b, 0), and the third, a positive point charge +q/3 is located at the point (-2/3b, -1/3b). What is the symbolic expression for the electric field at the origin due to this system of point charges, in terms of k e, q and b and what is the magnitude of the electric field at the origin? To answer this question, please go through the following steps: To begin, carefully draw the three electric field vectors originating from the origin: the contribution to the net electric field from each of the three source charges. Consider: what information do you need to find the x and y-components of each of these three vectors?
Answer:
Ex = k q / b2 [- ¾] , Ey = k q / b2 3
Explanation:
For this exercise we calculate the electric field created by each load on a test charge located at the origin
Field created by load q = + q
E₁ = k q / r²
r = b-0
E₁ = k q / b²
in the negative direction of the x axis
Field created by load q = -2q
E₂ = k (2q) / (2b-0)₂
E₂ = K q / 2b₂
The field is in the negative direction of the x-axis
Field created by charge q = + q / 3
this charge creates a field that has components on the x and y axes
X axis
E3x = K (q / 3) / (2b / 3) 2
E3x = K q 3 / 4b²
as the charge is on the negative side of the x axis. The field goes to the bright side
Axis y
E3y = k (q / 3) / (b / 3) 2
E3y = k q / b²
directed up
therefore the electric field is the sum of the field created by each charge
X axis
Ex = -E1 + E2 + E3x
Ex = -k q / b2 - k q / 2b2 + k q 3 / 4b2
Ex = k q / b2 [-1 -1/2 + ¾]
Ex = k q / b2 [- ¾]
Axis y
Ey = k q / b2 3
1. Why is it important to use units in any graph?
2. Why does any graph need a title on it?
Answer:
so its easier to understand for the reader
Explanation:
2) Labelling. Graphs are used to present data. They must be clearly labelled if the reader is to understand them. By labelling we are referring to the text inside the graph itself, and not the title.
Calculate the dot product of D and E, where D=7i - 3j + 2k and E=4i + 5j - 3k.
please show working
Answer:
Since i dot i = 1 and j dot j = 1 and k dot k = 1 and the other terms are zero
(7 i - 3 j + 2 k) dot (4 i + 5 j - 3 k) = 28 - 15 -6 = 7
A racing car increases its speed from 10 m/s to 50 m/s over a distance of 60 m.
How long does this take?
A building's 10th floor (34.5 m high) is blazing with fire. A fire truck arrived at the scene and the fire
men shoots water from their hose. The water leaves the hose at the speed of 29 m/s, at an angle
of
63° and is held at 0.90 m from the ground. Will the water reach the fire? If so, how far from the
building should the hose be so the fire could be put out?
Answer:
Yes, the water will be reach the fire.
The hose should be at 34.7 m from the building
Explanation:
Given that,
Height of building's =34.5 m
Speed = 29 m/s
Angle = 63°
Distance from the ground = 0.90 m
We need to calculate the actual height
Using formula of height
[tex]H=\dfrac{u^2\sin^2\theta}{2g}[/tex]
Put the value into the formula
[tex]H=\dfrac{29^2\sin^2{63}}{2\times9.8}[/tex]
[tex]H=34.0\ m[/tex]
The height from the ground will be
[tex]H'=34+0.90[/tex]
[tex]H'=34.9\ m[/tex]
We can say that, the water gun attained the maximum height that is 0.4 m more than the 10th floor.
So, yes, the water will be reach the fire.
We need to calculate the range
Using formula of range
[tex]R=\dfrac{u^2\sin2\theta}{g}[/tex]
Put the value into the formula
[tex]R=\dfrac{29^2\times\sin(2\times63)}{9.8}[/tex]
[tex]R=69.4\ m[/tex]
The house should be at half of R.
[tex]\dfrac{R}{2}=\dfrac{69.4}{2}[/tex]
[tex]\dfrac{R}{2}=34.7\ m[/tex]
Hence, Yes, the water will be reach the fire.
The hose should be at 34.7 m from the building
when are two magnets attracted?
Answer:
when the negative and positive energy is connected
Explanation:
I the Lord am your God You shall have no other gods besides Me."
Which ancient river civilization would believe in this quote?
Answer:
Israelites
Explanation:
They only believed in one GOD
I WILL MARK YOU AS BRAINLIEST IF RIGHT
A car traveling north with a speed of 35 m/s slows down to a velocity of 10 m/s within 5 seconds. What is the car's deceleration?
Answer:
-5
Explanation:
10-35/5
-25/5
-5m/s^2it ask the deceleration this mean
vf<vi so it's negative it is the simplest way
From the concepts you have learned in this module, how are you going to assess
the Earth's condition to support life? Explain your answer.
1. Temperature
2. Water
3. Atmosphere
4. Energy
5. Nutrients
Answer:
Find the explanation below.
Explanation:
Earth is properly designed to support life. This is seen in the favorable temperature that supports life, the water cycle that recycles water for plant and animal life, the atmosphere, energy, and nutrients.
1. Temperature: The temperature which is regulated by the different weather conditions such as the rains, snows, dry seasons all help to maintain a stable condition for life.
2. Water: The water cycle through processes like evaporation, condensation, precipitation, helps to ensure that there is never a lack of water in the earth. The numerous water bodies like the seas, oceans, rivers, lakes, also provide a habitat for some living things. Water makes up 70% of the earth.
3. Atmosphere: The atmosphere is a mixture of gases in the right proportions that are necessary for life. Oxygen, Nitrogen, Carbon, etc are released and inhaled by man and other living things. They are also involved in so many biochemical reactions that help in metabolism and catabolism.
4. Energy: Energy generated from the sun and within the earth is stored in various forms and is always conserved. This energy is converted to different states such as the potential, chemical, kinetic, mechanical forms to get work done and to release heat.
5. Nutrients: Though cycles such as the carbon, nitrogen, oxygen, and phosphorous cycles, the earth maintains its stock of essential nutrients that help to sustain life.
An interdisciplinary approach encompassing climatology, oceanography, environmental science, and other fields of study is necessary to evaluate the Earth's capacity to support life.
Temperature: Monitoring and analyzing climate data from numerous sources, including weather stations, satellites, and ocean buoys, is necessary to determine the Earth's temperature. To understand how temperature patterns vary over time, scientists look at long-term trends, seasonal variations, and severe events. They forecast future temperature increases and their possible effects on life and ecosystems using global climate models.
Water: Monitoring freshwater availability, water quality, and water distribution throughout various regions are all part of the assessment of Earth's water resources. Studies of precipitation patterns, data on ice melting from polar regions, and measurements of water levels in lakes, rivers, and aquifers are all conducted by researchers. Testing for toxins, pollutants, and chemical compositions is part of evaluating water quality to make sure it adheres to acceptable standards for both ecological and human health.
Atmosphere: scientists measure and research a number of factors, such as greenhouse gases, air quality, and atmospheric pressure, in order to evaluate the Earth's atmosphere. Carbon dioxide (CO2), methane (CH4), and other greenhouse gases are measured at monitoring sites throughout the globe to better understand how they contribute to climate change. Pollutants like particle matter and ozone, which have an influence on both human health and ecosystems, are measured by air quality monitoring stations.
Energy: studying diverse energy sources and their effects on the environment and ecosystems is necessary to evaluate the amount of energy present on Earth. Scientists assess the usage of non-renewable energy sources like fossil fuels as well as renewable energy sources like solar, wind, hydro, and geothermal energy. To create sustainable energy plans that support life on Earth, they examine energy consumption trends, carbon emissions, and energy efficiency.
Nutrients: studying nutrient cycles and availability in soils, oceans, and terrestrial ecosystems is necessary for evaluating the availability of nutrients in the Earth's ecosystems. To determine the nutrient levels for agriculture and plant growth, researchers examine soil samples. In order to gauge the productivity and availability of nutrients for marine life, they also research marine ecosystems.
Hence, an interdisciplinary approach encompassing climatology, oceanography, environmental science, and other fields of study is necessary to evaluate the Earth's capacity to support life.
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Two dogs are running a race of 100m. The green dog runs the 100m in 10s. The
red dog runs the first half of the race in 3s and then turns around and runs back
to the starting line in 5s. Describe what the velocity time graph would look like of
the race.
Answer: What type of dog is green and red?
Explanation:
The answer pleaseeeeeee
A man runs 400.0m around the track,
then another 400.0m around the track again.
As the track is 400.Om long, the man is back
where he started!
a) calculate distance travelled
b) calculate mans displacement
Answer:
Distance = 800 m, Displacement = 0
Explanation:
It is given that,
A man runs 400 m around the track, then another 400 m around the track again.
(a) Distance travelled by an object is the sum of total path covered.
In this case, he has covered total path of 400 m + 400 m i.e. 800 m. It means he travelled a distance of 800 m.
(b) Displacement covered by an object is the shortest path covered by it. In this problem, he reaches the point from where he has started. It means that his displacement is equal to 0.
Which of the following is a characteristic of electromagnetic waves? (2 points)
Invisible fence for dogs. In this type of system, a wire is buried under the surface and a current at a given frequency passes through the wire. The dog wears a small unit made of a pickup coil and electronics that delivers a short high-voltage pulse to the dog through a couple of electrodes pressed against its skin. The pulse is not harmful, but it does provide a correction that encourages the dog to keep away. In an invisible fence, the wire carries a 10kHz sinusoidal current with an amplitude of 0.5 Amps. The dog carries a sensoron its collar made as a coil with 150 turns and 30 mm in diameter.If the detection level at the coil inside the collar is set at 200 μV RMS (i.e., the level at which the dog will receive a correction pulse), what is the furthest distance from the wire the dog will "feel" the presence of the fence?
Answer:
The distance is [tex] s = 2.3 \ m [/tex]
Explanation:
From the question we are told that
The frequency of the current is [tex]f = 10\ kHz = 10 *10^{3} \ Hz[/tex]
The magnitude of the current is [tex]I_o = 0.5\ Amps[/tex]
The number of turns is [tex]N = 150\ turns[/tex]
The diameter is [tex]d = 30 mm = 0.03 \ m[/tex]
The detection level is [tex]V_{rms} = 200 \mu V = 200 * 10^{-6} \ V[/tex]
Generally the radius is mathematically represented as
[tex]r = \frac{d}{2}[/tex]
=> [tex]r = \frac{0.03}{2}[/tex]
=> [tex]r 0.015 \ m [/tex]
Generally the magnetic field generated by the fence is mathematically represented as
[tex]B = \frac{\mu_o * N * I}{2 * \pi * s}[/tex]
Here s is the point where the do will feel the magnetic field
[tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2 [/tex]
So
[tex]B = \frac{ 4\pi * 10^{-7} * 150 * I}{2 * 3.142 * s}[/tex]
Generally the magnetic flux is mathematically represented as
[tex]\Phi = B * \pi * r^2[/tex]
=> [tex]\Phi = \frac{ 4\pi * 10^{-7} * 150 * I}{2 * 3.142 * s} * \pi * r^2[/tex]
=> [tex]\Phi = \frac{2.121 *10^{-8} * I }{s}[/tex]
Generally the induced emf is mathematically represented as
[tex]\epsilon =- \frac{d \Phi}{dt}[/tex]
=> [tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * \frac{d I}{dt}[/tex]
Generally the angular frequency is mathematically represented as
[tex]w = 2 \pi f[/tex]
=> [tex]w = 2 * 10*10^{3} \pi [/tex]
=> [tex]w = 20000 \pi [/tex]
So the current is mathematically represented as
[tex]I = I_o sin (wt)[/tex]
=> [tex]I = I_o sin ( 20000 \pi * t)[/tex]
So
[tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * \frac{d [ I_o sin ( 20000 \pi * t)]}{dt}[/tex]
[tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * I_o * 20000 \pi [ cos ( 20000 \pi * t) [/tex]
[tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * 0.5 * 20000 \pi [ cos ( 20000 \pi * t) [/tex]
[tex]\epsilon =- \frac{ 6.6*10^{-4} }{ s } [ cos ( 20000 \pi * t) [/tex]
Here the
[tex]\epsilon_{rms} = \frac{ \frac{ 6.6*10^{-4} }{ s }}{\sqrt{2} }[/tex]
=> [tex]\epsilon_{rms} = \frac{ 6.6*10^{-4} }{ s\sqrt{2} }[/tex]
But from the question we are told that [tex]V_{rms} = 200 \mu V = 200 * 10^{-6} \ V[/tex]
So
[tex]\frac{ 6.6*10^{-4} }{ s\sqrt{2} } = 200 * 10^{-6}[/tex]
=> [tex]6.6*10^{-4}= 2.8284 *10^{-4} * s[/tex]
=> [tex] s = 2.3 \ m [/tex]
Explain the
energy
transformation
processes in an
electromagnet.
Answer:
when the enrgy flow a electromagnet will exist
Explanation:
i dont reaaly understand by the word energy transformation but thats how elektromagnetic will form
A automotive test driver travels due north in a prototype hybrid vehicle at 30 mi/h
for 2 hours. She then reverses her direction and travels due south at 60 mi/h for 1 hour.
What is the average speed of the vehicle?
a) 40 mi/h
b) 50 mi/h
c) zero mi/h
d) 60 mi/h
e) 30 mi/h
Answer:
Option A. 40 mi/h
Explanation:
To obtain the average speed of the vehicle, we'll begin by calculating the distance travelled by the vehicle in each case. This is illustrated below:
Case 1:
Speed = 30 mi/h
Time = 2 h
Distance =...?
Speed = Distance /Time
30 = Distance /2
Cross multiply
Distance = 30 × 2
Distance = 60 mi
Case 2:
Speed = 60 mi/h
Time = 1 h
Distance =...?
Speed = Distance /Time
60 = Distance /1
Cross multiply
Distance = 60 × 1
Distance = 60 mi
Finally, we shall determine the average speed of the vehicle as follow:
Total distance travelled = 60 + 60
Total distance travelled = 120 mi
Total time = 2 + 1
Total time = 3 h
Average speed =..?
Average speed = Total Distance travelled /Total time
Average speed = 120/3
Average speed = 40 mi/h
Therefore, the average speed of the vehicle is 40 mi/h
In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light? In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light? 214 nm 204 nm 224 nm 100 nm 234 nm
Answer:
The value is [tex]\lambda = 214.3 \ nm [/tex]
Explanation:
From the question we are told that
The slit separation is [tex]d = 3.00 * 10^{-5} m[/tex]
The distance of the screen is [tex]D = 2.00\ m[/tex]
The order of fringe is n = 7
The path difference is [tex]y = 10.0 \ cm = 0.1 \ m[/tex]
Generally the path difference is mathematically represented as
[tex]y = \frac{n * \lambda * D}{ d}[/tex]
=> [tex]0.1 = \frac{7 * \lambda * 2.00 }{ 3.00 * 10^{-5}}[/tex]
=> [tex]\lambda = \frac{0.1 *3.00 * 10^{-5} }{7 * 2.00 }[/tex]
=> [tex]\lambda = \frac{0.1 *3.00 * 10^{-5} }{7 * 2.00 }[/tex]
=> [tex]\lambda = 2.143 *10^{-7} \ m [/tex]
=> [tex]\lambda = 214.3 \ nm [/tex]
Before Collision Consider a system to be one train car moving toward another train car at rest When the train cars collide, the two cars stick together What is the total momentum of the system after the collision? O 800 kg . m/s m, = 600 kg V,= 4 m/s m = 400 kg v2 = 0 m/s 1,600 kg. m/s 0 2,400 kg • m/s 0 4,000 kg . m/s After Collision
Answer:
2,400kg * m/s
Explanation:
You are missing some information in the question but the rest could be found some where else.
The question gives the masses and starting velocity of each car.
Car 1: m = 600kg and sv = 4m/s
Car 2: m 400kg and sv = 0m/s
Find the momentum of both cars.
Car 1: 600 * 4 = 2400
Car 2: 400 * 0 = 0
Add both.
2400 + 0 = 2400
Best of Luck!
Answer: answer C
Explanation:
Your welcome
In order for clouds to form, what must happen first?
Answer:
Step 1: Change Water Vapor into Liquid Water
But in order to grow a cloud, we need to get the water vapor from a gas to its liquid form. Clouds begin to form when a parcel of air rises from the surface up into the atmosphere
Explanation:
