a blackbody is at temperature of 500°C . What would be its temperature in Kelvin for it to radiate twice as much energy per second?​

Answer:

4th

Explanation:

Rise and fall of the water level on the sea shore

Answer:

i am just trying it could be wrong too i am not sure about it but according to me the ans is (1)let ice be allowed to float naturally in the water

Explanation:

if u put water in ice or ice in water the temperature of water decreases and then the process gets slower but if u allow to float it then the temperature of water and surrounding air decreases and the heat is lost from air and water both so here the heat is more than only just water here it allows both to give heat and in 2nd option the heat is only lost by water and gained by icehere it allows only water to give heat so the heat is less in surrounding of ice in water so more heat more faster the process therefore i think the 1st option is correct

Answer:

opinion

Explanation:

Answer:

a) The average force that acts on the man is [tex]2.508\times 10^{8}[/tex] newtons.

b) The average force that acts on the man is 1023.673 newtons.

c) The force of the ground on the man is 1612.093 newtons upwards.

Explanation:

a) After a careful reading of the statement we construct the following model by applying Impact Theorem, that is:

[tex]m\cdot \vec v_{A} + \vec F \cdot \Delta t = m\cdot \vec v_{B}[/tex] (Eq. 1)

Where:

[tex]m[/tex] - Mass of the man, measured in kilograms.

[tex]\vec v_{A}[/tex] - Initial velocity of the man, measured in meters per second.

[tex]\vec v_{B}[/tex] - Final velocity of the man, measured in meters per second.

[tex]\Delta t[/tex] - Impact time, measured in seconds.

[tex]\vec F[/tex] - Average net force, measured in newtons.

Now we proceed to clear average net force within expression:

[tex]\vec F \cdot \Delta t = m\cdot (\vec v_{B}-\vec v_{A})[/tex]

[tex]\vec F = \frac{m}{\Delta t}\cdot (\vec v_{B}-\vec v_{A})[/tex] (Eq. 2)

If we know that [tex]m = 60\,kg[/tex], [tex]\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex], [tex]\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex] and [tex]\Delta t = 1\times 10^{-6}\,s[/tex], we obtain the following vector:

[tex]\vec F = \frac{60\,kg}{1\times 10^{-6}\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right][/tex]

[tex]\vec F = 2.508\times 10^{8}\,\hat{j}\,\,\,[N][/tex]

The average force that acts on the man is [tex]2.508\times 10^{8}[/tex] newtons.

(b) If we know that  [tex]m = 60\,kg[/tex], [tex]\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex], [tex]\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex] and [tex]\Delta t = 0.245\,s[/tex], we obtain the following vector:

[tex]\vec F = \frac{60\,kg}{0.245\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right][/tex]

[tex]\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right][/tex]

The average force that acts on the man is 1023.673 newtons.

(c) From Second Newton's Law we find the following equation of equilibrium:

[tex]\vec F = \vec N -\vec W[/tex] (Eq. 3)

Where:

[tex]\vec F[/tex] - Average force that acts on the man, measured in newtons.

[tex]\vec N[/tex] - Force of the ground on the man, measured in newtons.

[tex]\vec W[/tex] - Weight of the man, measured in newtons.

By applying the concept of weight, we expand the previous equation:

[tex]\vec F = \vec N -m\cdot \vec g[/tex] (Eq. 3b)

Where [tex]\vec g[/tex] is the gravitational acceleration, measured in meters per square second.

And then we clear the force of the ground on the man:

[tex]\vec N = \vec F +m\cdot \vec g[/tex] (Eq. 4)

If we get that [tex]\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right][/tex],  [tex]m = 60\,kg[/tex] and [tex]\vec g = 9.807\,\hat{j}\,\,\,\left[\frac{m}{s^{2}} \right][/tex], the average force is:

[tex]\vec N = 1023.673\,\hat{j}\,\,\,[N]+(60\,kg)\cdot (9.807\,\hat{j})\,\,\,\left[\frac{m}{s^{2}} \right][/tex]

[tex]\vec N = 1612.093\,\hat{j}\,\,\,\left[N\right][/tex]

The force of the ground on the man is 1612.093 newtons upwards.

Answer:

Efficiency = 65%

Explanation:

The formula of Efficiency applied to any circumstance is:

Efficiency = Useful Energy / Energy applied

Then replacing the values given its:

Efficiency = 25 J / 32 J

Efficiency = 0.65

0.65 written as percentage is 65%, then:

Efficiency = 65%

As you do 32 joules of work using a pair of scissors and the scissors do 25 joules of work cutting a piece of fabric, the efficiency of the scissors is 78.125%.

Efficiency is the proportion of work done by a machine or throughout a process to the overall amount of energy or heat used.

The ratio of usable output to total input can be used to objectively measure efficiency. The efficiency of the device is defined as the ratio of energy converted to a useable form to the original amount of energy supplied.

Mathematically,

efficiency of a machine = (work output/work input)×100%

Given parameters:

Input work to the pair of scissors= 32 joules.

Output work from the pair of scissors= 25 joules.

Hence,

The efficiency of a machine = (work output/work input)×100%

= ( 25 joule/32joule)×100%

= 78.125%

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Answer:

a. N = 2.49W b.  0.40

Explanation:

a. What is the magnitude of the normal force FNFN between a rider and the wall, expressed in terms of the rider's weight W?

Since the normal force equals the centripetal force on the rider, N = mrω² where r = radius of cylinder = 3.05 m and ω = angular speed of cylinder = 0.450 rotations/s = 0.450 × 2π rad/s = 2.83 rad/s

Now N = mrω² = m(3.05 m) × (2.83 rad/s)² = 24.43m

The rider's weight W = mg = 9.8m

The ratio of the normal force to the rider's weight is

N/W = 24.43m/9.8m = 2.49

So the normal force expressed in term's of the rider's weight is

N = 2.49W

b. What is the minimum coefficient of static friction µsμs required between the rider and the wall in order for the rider to be held in place without sliding down?

The frictional force, F on the rider by the wall of the cylinder equals the weight, W of the rider. F = W.

Since the frictional force F = μN, where μ = coefficient of static friction between rider and wall of cylinder and N = normal force between rider and wall of cylinder.

So, the normal force equals

N = F/μ = W/μ = mg/μ = mrω²

μ  = mg/mrω²

= W/N

= 9.8m/24.43m

= 0.40

Answer:

Explanation:

From  the question we are told that

   The mass of chlorine ion is [tex]m_c  =  35u  =  35 * 1.66*10^{-27} =  5.81*10^{-26}\ kg[/tex]

    The charge is  [tex]q =  5e   = 5 *  1.60 *10^{-19} = 8.0*10^{-19}\ C[/tex]

   The potential difference is  [tex]V  =  250 kV  =  250*10^{3}  \  V[/tex]

    The radius of curvature of the path is  [tex]r = 3.5 \ m[/tex]

Gnerally the magnetic force will cause the speed of the  chlorine ions to change from 0 m/s to [tex]v_y[/tex] m/s along the y -axis but will not affect the velocity along the x-axis

Generally according the law of energy conservation

          [tex]K =  PE[/tex]

Here K is the kinetic energy of the of the chlorine ions which is mathematically represented as

      [tex]K  =  \frac{1}{2} mv^2[/tex]

And  PE is electric potential  energy which is mathematically represented as

       [tex]PE  =   Q *  V[/tex]

So

      [tex] \frac{1}{2} mv^2 =  Q *  V [/tex]

=>   [tex] \frac{1}{2} *  5.81*10^{-26}  *  v^2 =  8.0*10^{-19} *  250*10^{3} [/tex]

=>    [tex] v =  sqrt{6.8847 *10^{12}} [/tex]

=>    [tex] v = 2.634 *10^{6} \ m/s [/tex]

Answer:

31.25m

Explanation:

Given parameters:

   Acceleration due to gravity  = 10m/s²

    Time of drop = 2.5s

Unknown

Height of drop  = ?

Solution:

To solve this problem, we must note that the brick was originally at rest. The appropriate motion equation to solve this is shown below;

          H  = ut + [tex]\frac{1}{2}[/tex]gt²

H is the height

u is the initial velocity

g is the acceleration due to gravity

t is the time taken

          Input the parameters and solve;

      H = 0 +  [tex]\frac{1}{2}[/tex] x 10 x 2.5²

     H = 31.25m

Explanation:

1) N₂ + O₂ → 2 NO

Kc = [NO]² / ([N₂] [O₂])

Set up an ICE table:

[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\N_{2}&0.114&-x&0.114-x\\O_{2}&0.114&-x&0.114-x\\NO&0&+2x&2x\end{array}\right][/tex]

Plug into the equilibrium equation and solve for x.

1.00×10⁻⁵ = (2x)² / ((0.114 − x) (0.114 − x))

1.00×10⁻⁵ = (2x)² / (0.114 − x)²

√(1.00×10⁻⁵) = 2x / (0.114 − x)

0.00316 = 2x / (0.114 − x)

0.00361 − 0.00316x = 2x

0.00361 = 2.00316x

x = 0.00018

The volume is 1.00 L, so the concentrations at equilibrium are:

[N₂] = 0.114 − x = 0.11382

[O₂] = 0.114 − x = 0.11382

[NO] = 2x = 0.00036

2(a) Cl₂ → 2 Cl

Kc = [Cl]² / [Cl₂]

[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\Cl_{2}&2.0&-x&2.0-x\\Cl&0&+2x&2x\end{array}\right][/tex]

1.2×10⁻⁷ = (2x)² / (2 − x)

1.2×10⁻⁷ (2 − x) = 4x²

2.4×10⁻⁷ − 1.2×10⁻⁷ x = 4x²

2.4×10⁻⁷ ≈ 4x²

x² ≈ 6×10⁻⁸

x ≈ 0.000245

2x ≈ 0.00049

2(b) F₂ → 2 F

Kc = [F]² / [F₂]

[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\F_{2}&2.0&-x&2.0-x\\F&0&+2x&2x\end{array}\right][/tex]

1.2×10⁻⁴ = (2x)² / (2 − x)

1.2×10⁻⁴ (2 − x) = 4x²

2.4×10⁻⁴ − 1.2×10⁻⁴ x = 4x²

2.4×10⁻⁴ ≈ 4x²

x² ≈ 6×10⁻⁵

x ≈ 0.00775

2x ≈ 0.0155

F₂ dissociates more, so Cl₂ is more stable at 1000 K.

Answer: (B) Too many to count

Explanation: Have a wonderful day everyone! :D

The exercises that encompasses stretching in the human body is : B) too many to count

exercises can be defined as any activity that puts your muscle to work and helps burn calories in your body.

exercises are one of the keys to staying and living healthy.

exercises are of different types and forms and some encompasses stretching in the human body.

In conclusion, The exercises that encompasses stretching in the human body is too many to count

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Average acceleration is how much the car increases (on average) per second.  So, since it increases by 30 m/s in 8 s, then dividing 30 by 8 will give you an average acceleration of 3.75 m/s^2 (remember that acceleration is ever increasing, so the unit is s^2, not just s)

Answer:

no but yes at the same time

Explanation:

they are going a different direction but they are the same speed.

Answer:

two positively charged objects

Explanation:

Answer:

mass = 5 [kg]

Explanation:

The difference between weight and mass should be clarified, the weight is equal to the product of the mass by the gravity of the place. While the mass will always be conserved regardless of the place, it will never change.

weight = mass * gravity of the place

}Therefore the mass is the same in the earth as in the moon

Answer:

Explanation:

Scientific research conducted by psychologists, organized by topics here, can inform and guide those seeking help with issues that affect their professional lives, family relationships and emotional wellness.Tips for choosing a psychotherapist and answers to financial questions related to therapy.

When faced with important events (stressors) which are threatening or very hard to, psychological symptoms of stress include anxiety and tension, uncontrollable. In general, this refers to high levels of suspicion and mistrust, usually seen in this psychological condition is associated with acute physical sickness

plz mark as brainliest

Answer:

D

Explanation:

when you try to find out if it is positive, the line goes from left to right, and in this question the line is going upward.

Answer: 9 km/h

Explanation:i’m pretty sure

Answer:

Well, it depends on the type of car but a regular car like a toyota 4x4 only goes at 5k/h if the car starts when complete rest

Answer: However, the Internet takes digital photo manipulation.

Explanation: This discussion is not only limited to digital manipulation, but also includes .However, there was no way to take this image in a single exposure .

When faced with limited funding to complete a year-long study on the relationship between certain diseases and people's diets she can best overcome this by conduct smaller studies for more than a one-year period, study only a very small group of people, conduct a study about something else, use data from a similar study and adjust it to fit her study.

The correct answer would be all of the above.

There are several strategies the scientist can consider to overcome this limitation. Each option has its own advantages and potential drawbacks, so the scientist should carefully evaluate which approach aligns best with her research goals and available resources.

1. Conduct smaller studies for more than a one-year period: Instead of one large-scale study, the scientist can break down the research into smaller, more manageable studies. This approach allows for incremental progress, and findings from each smaller study can contribute to the overall understanding of the topic. By conducting multiple studies over an extended period, the scientist can still gather valuable data and draw meaningful conclusions.

2. Study only a very small group of people: Focusing on a small group of participants can reduce costs and streamline data collection and analysis. While the sample size may be limited, the scientist can still gain insights into the relationship between diseases and diet within this specific group. However, generalizing the findings to a larger population may be challenging due to the limited sample size.

3. Conduct a study about something else: If funding limitations prevent the scientist from conducting the intended study, she could consider redirecting her research efforts towards a related but more feasible topic. This allows her to leverage her expertise and resources while still generating valuable scientific knowledge.

4. Use data from a similar study and adjust it to fit her study: The scientist could explore existing datasets or previous studies that are relevant to her research question. By analyzing and adapting this data to fit her study's context, she can gain insights without incurring the costs and time associated with primary data collection. However, it is crucial to ensure that the adjusted data aligns with the specific objectives and parameters of her study.

Ultimately, the scientist should carefully assess the feasibility, potential impact, and trade-offs associated with each option. It may also be beneficial to seek guidance from peers, mentors, or funding agencies to explore alternative funding sources or collaborative opportunities that could support her research goals.

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Explanation:

The Object was at rest. So, Initial Velocity is Zero.

We know that:-

[tex]\sf{Force = Mass \times \dfrac{(v-u)}{t}}[/tex]

Applying it, we get:-

[tex]\sf{Force = 4 \times \dfrac{(20-0)}{2}}[/tex]

[tex]\sf{Force = 2 \times \dfrac{(20)}{2}}[/tex]

[tex]\sf{Force = 2 \times 10}[/tex]

[tex]\sf{Force = 20 \ N \ (Newton)}[/tex]

Hope it helps :)

Answer:

1. W = 8848 J

2. W = 7848 J

3. W = 6848 J

Explanation:

The work (W) can be found using the following equation:

[tex] W = E_{k} + E_{p} [/tex]

Where: E(k) is the kinetic energy and E(p) is the potential energy

Now let's find the work for every stage.

Stage 1:

[tex] W = E_{k} + E_{p} = \frac{1}{2}mv^{2} + mgh [/tex]

Where: m is the mass, g is the gravity, h is the height, v is the speed  

[tex] W = \frac{1}{2}mv^{2} + mgh = \frac{1}{2}80 kg*(5 m/s)^{2} + 80 kg*9.81 m/s^{2}*10 m = 8848 J [/tex]

Stage 2:

[tex] W = E_{k} + E_{p} = 0 + E_{p} [/tex]

The kinetic energy is equal to zero because the acceleration is constant.

[tex] W = E_{p} = mgh = 80 kg*9.81 m/s^{2}*10 m = 7848 J [/tex]

Stage 3:

[tex] W = E_{k} + E_{p} = \frac{1}{2}mv^{2} + mgh = -\frac{1}{2}80 kg*(5 m/s)^{2} + 80 kg*9.81 m/s^{2}*10 m = 6848 J [/tex]      

I hope it helps you!

Answer:

Gamma Rays

Explanation:

Because it has the most energetic radiation and could penetrate through six feet of concrete. It is so strong it can damage your dna.

Answer:

Explanation:

To find the mass of an object given it's acceleration and the force acting on it we use the formula

[tex]mass = \frac{force}{acceleration} \\ [/tex]

From the question

force = 500 N

acceleration = 5.0 m/s²

We have

[tex]mass = \frac{500}{5} \\ [/tex]

We have the final answer as

Hope this helps you

Complete Question

Find the force that must be exerted on the rod to maintain a constant current of 0.173 A in the resistor.

The figure below shows a zero-resistance rod sliding to the right on two zero-resistance rails separated by the distance L = 0.451 m . The rails are connected by a [tex]12.6 \Omega \   resistor[/tex], and the entire system is in a uniform magnetic field with a magnitude of 0.751 T .

The diagram illustrating this question is shown on the first uploaded image

Answer:

The value is  [tex]F =  0.0586 \ N [/tex]

Explanation:

  From the question we are told that  

   The current is  [tex]I  =  0.173 \ A[/tex]

    The length of separation is  [tex]L= 0.451 \ m[/tex]

     The resistance is  [tex]12.6 \Omega[/tex]

    The magnetic field is  [tex]B  =   0.751\  T[/tex]

Generally the force is mathematically represented as

    [tex]F =  BIL sin (\theta )[/tex]

Given that the velocity is perpendicular to magnetic field then [tex]\theta  =  90[/tex]

=>   [tex]sin(90)  =  1[/tex]

So

    [tex]F =  0.751 *0.173  * 0.451 sin (\theta )[/tex]

    [tex]F =  0.751 *0.173  * 0.451 * 1[/tex]

    [tex]F =  0.0586 \ N [/tex]

Answer:

The radius of curvature of the curved path of the airplane is 23784.356 meters (23.784 kilometers).

Explanation:

We assume that airplane can be represented as a particle. The free body diagram of the vehicle is presented below as attachment, whose variables are:

[tex]W[/tex] - Weight of the airplane, measured in newtons.

[tex]F[/tex] - Lift, measured in newtons.

[tex]\theta[/tex] - Banking angle, measured in sexagesimal degrees.

The equations of equilibrium associated with the airplane are, respectively:

[tex]\Sigma F_{r} = F\cdot \sin \theta = m\cdot \frac{v^{2}}{R}[/tex] (Eq. 1)

[tex]\Sigma F_{z} = F\cdot \cos \theta - W = 0[/tex] (Eq. 2)

From (Eq. 2):

[tex]F = \frac{W}{\cos \theta}[/tex]

In (Eq. 1):

[tex]W\cdot \tan \theta = m\cdot \frac{v^{2}}{R}[/tex]

By using the definition of weight, we eliminate the mass of the airplane:

[tex]g\cdot \tan \theta = \frac{v^{2}}{R}[/tex]

Where:

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]v[/tex] - Speed, measured in meters per second.

[tex]R[/tex] - Radius of curvature, measured in meters.

Lastly, we clear the radius of curvature with the expression:

[tex]R = \frac{v^{2}}{g\cdot \tan \theta}[/tex]

If we know that [tex]v = 250\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\theta = 15^{\circ}[/tex], the radius of curvature is:

[tex]R = \frac{\left(250\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot \tan 15^{\circ}}[/tex]

[tex]R = 23784.356\,m[/tex]

The radius of curvature of the curved path of the airplane is 23784.356 meters (23.784 kilometers).

Answer:

50%

Explanation:

       [tex]p_{o} = m* v_{1o} (1)[/tex]

       [tex]v_{f} =\frac{v_{1o}}{2}[/tex]

       [tex]K_{1o} =\frac{1}{2} * m *v_{1o}^{2} (1)[/tex]

       [tex]K_{f} =\frac{1}{2} * 2*m *(\frac{v_{1o}}{2}) ^{2} (2)[/tex]

       [tex]K_{f} =\frac{1}{2} *m *v_{1o} ^{2} *\frac{1}{2} = \frac{K_{1o} }{2}[/tex]

Answer:

Mass of bullet is m=0.01kg

Mass of the block is M=4kg

Coefficient=0.25,distance=20m

So, let the speed of the block just after the bullet embedded in it be V and v be the speed of bullet before striking the block,

By applying conservation of momentum,

mv=(m+M)V

V=

M+m

mv

Explanation:

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The initial velocity of the bullet is 382 m/s

The given parameters;

Apply the principle of conservation of mechanical energy;

The maximum potential energy of the bullet-wood system at the top of the port  = maximum kinetic energy of the system at the base of the port.

[tex]K.E_{max} = P.E_{max}\\\\\frac{1}{2} mv_{max}^2 = mgh_{max}\\\\v^2_{max} = 2gh_{max}\\\\v_{max} = \sqrt{2gh_{max}} \\\\v_{max} = \sqrt{2\times 9.8\times 2} \\\\v_{max} = 6.26 \ m/s[/tex]

Apply the principle of conservation of linear momentum to determine the initial velocity of the bullet;

[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\0.6(0) + 0.01(u_2) = 6.26((0.6 + 0.01)\\\\0.01u_2 = 3.819\\\\u_2 = \frac{3.819}{0.01} \\\\u_2 = 381.9 \ \approx 382 \ m/s[/tex]

Thus, the initial velocity of the bullet is 382 m/s

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