A ball is thrown directly upwards at 25 ms and the same time another ball is released from height of loom. At what height and time will the balls meets?​

A) The rotation rate of the ball in rev/secs is ;  10.79 rev/secs

B) The total kinetic energy of in pound-feet ignoring the finger holes is : 37.6157 pound-feet

Given data :

mass of ball = 12 Ib

diameter of ball = 8.5 inches

Radius = 4.25 inches = 0.10795 m

Time = 5 secs

distance travelled = 60 ft  = 18.288 m

First step : calculate the velocity of ball

V = distance / time

  = 18.288 / 5 = 3.66 m/s

Next step :

angular velocity ( w ) = V / r  

                                  = 3.66 / ( 0.10795 ) = 33.90 rad/sec

convert to rev/sec = 33.90 / π

                               = 10.79 rev/secs

given that ball rolls without slipping

Vcon = Rw

Total K.E = 1/2 IW² + 1/2 mv²

               = 7/10 MR²W²

Total K.E = 7/10 *  5.44 * ( 0.10795 )² * 33.90²

               = 50.99 ≈ 51 J

convert to pound-feet = 37.6157 pound-feet

Hence we can conclude that The rotation rate of the ball in rev/secs is ;  10.79 rev/secs  and The total kinetic energy of in pound-feet ignoring the finger holes is : 37.6157 pound-feet.

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(a) The torque acting on the disk is 66 Nm.

(b) The moment of inertia of the disk is 0.05 kgm².

(c) The angular acceleration is produced by the torque is 1,320 rad/s².

(d) The final angular velocity of the disk is  3,960 rad/s.

(e) The angle of rotation of the disk is 5,940 rad.

The torque acting on the disk is calculated as follows;

τ = Fr

τ = 300 x 0.22

τ = 66 Nm

The moment of inertia of a solid disk is calculated as follows;

I = ¹/₂MR²

I = ¹/₂ x 2 x (0.22)²

I = 0.05 kgm²

The angular acceleration of the disk is calculated as follows;

τ = Iα

[tex]\alpha = \frac{\tau }{I} \\\\\alpha = \frac{66}{0.05} \\\\\alpha = 1,320 \ rad/s^2[/tex]

ωf = ωi + αt

ωf = 0 + (1320 x 3)

ωf = 3,960 rad/s

ωf² = ωi²+ 2αθ

(3,960)² = 0 + 2(1320)θ

θ = (3,960²) / (2 x 1320)

θ = 5,940 rad

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Answer:

Explanation:

The number of mole of the hydrogen sample at 27 C and 750 mmHg pressure is:

[tex]n=\frac{PV}{RT}=\frac{(0.9898\times 10^{5})(5\times 10^{-3})}{(8.314)(27+273)}\approx 0.0198[/tex] mol

This number of mole will be the same although we change the pressure and temperature. For STP (Temperature = 0 C = 273 K, and Pressure = 760 mmHg = 76 cmHg = 1 Bar = 1.01 x [tex]10^{5}[/tex] Pa):

[tex]P'V'=nRT' \rightarrow V'=\frac{nRT'}{P'}=\frac{0.0198(8.314)(273)}{1.01\times 10^{5}}\approx 44.49 \times 10^{-5}[/tex] in [tex]m^{3}[/tex]. But in L, we find that V' = 0.4449 L

Answer:

algebraic sum of moments of all the forces acting on the body about the axis of rotation is zero, the body is in equilibrium. According to the principle of moments, in equilibrium: Sum of anticlockwise Moments = Sum of clockwise moments.

Condition:

For an object to be in equilibrium, it must be experiencing no acceleration.

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Answer:

power is measured in watts and its the messure of work over time.

Explanation:

The force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.

The force exerted on the outside of the wheel can be determined by applying the principle of conservation of angular momentum as shown below.

∑τ = 0

∑τ = R(mg) - r(F)

rF = R(mg)

0.45F = 1.5(21,200 x 9.8)

F = 6.925 x 10⁵ N.

Thus, the force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.

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Answer:

125J

Explanation:

[tex]work \: = force \: \times distance \\ = 25 \times 5 \\ = 125joules[/tex]

Answer:

fluctuations in the levels of female reproductive hormones

Explanation:

Women are more prone to anxiety due to a variety of biological, psychological, and cultural factors. Although the exact cause is unknown, recent research suggests that fluctuations in the levels of female reproductive hormones and cycles play an important role in women's enhanced vulnerability to anxiety.

Answer: D. stress levels, life experiences, and friends’ stresses

Explanation:

Answer:

A

Explanation:

A. it can travel through empty space

(1) The time taken for the drag racer to accelerate is 4.89 s

(2) The speed of the contestant (a) in feet per second is 30.89 ft/s (b) in miles per hr is 21.12 miles per hr.

(1) To calculate the time required to accelerate 18 ft/sec² from rest to a velocity of 60 mph, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

(2) To calculate the speed of the contestant, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

(a) In feet = (9.43/0.3048) = 30.94 ft/s

(b)  in miles per hr = (9.43×2.24) = 21.12 miles per hr

Hence, (1) The time taken for the drag racer to accelerate is 4.89 s (2) The speed of the contestant (a) in feet per second is 30.89 ft/s (b) in miles per hr is 21.12 miles per hr.

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When the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

The frictional force between the block and the horizontal surface is determined by applying Newton's law;

∑F = ma

F - Ff = ma

Ff = F - ma

Ff = 4 - 2(1.2)

Ff = 4 - 2.4

Ff = 1.6 N

When the applied force increases to 5 N, the magnitude of the block's acceleration is calculated as follows;

F - Ff = ma

5 - 1.6 = 2a

3.4 = 2a

a = 3.4/2

a = 1.7 m/s²

Thus, when the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

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Explanation:

[tex]\longmapsto\: \red{ hello \: mate}[/tex]

OPTION (C) 3

is the angle of refraction

Answer:

Option C. 3

Explanation:

Refraction is the change in direction of light passing from one medium to another. Angle 1 and 2 are reflection due to the bouncing of light.

Answer:

i beleave cuz of the Earth is spherical

Explanation:

The pictorial diagram with a rocket launched straight upward, showing the first three positions of the rocket with equal spacing between them, best illustrates projectile motion. In this case, the rocket is projected upward into the air, and its path follows a parabolic trajectory due to the influence of gravity.

Projectile motion refers to the motion of an object that is thrown, launched or otherwise projected into the air and then moves under the influence of gravity alone. In this type of motion, the object moves along a curved path, called a parabola, due to the combined effect of its initial velocity and the force of gravity acting on it.

When a rocket is launched straight upward, it experiences a projectile motion. The rocket's initial velocity is upwards, but gravity causes it to decelerate until it eventually stops at the highest point of its trajectory. The rocket then starts to fall back down, accelerating due to gravity until it reaches the ground. If we take three equal intervals of time, we can show the rocket's positions at those times. Initially, the rocket will be moving upwards with a decreasing velocity, then it will reach its maximum height before falling back down with an increasing velocity.

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Answer: I believe it should be the final answer,

A pictorial diagram of a person hopping sideways at 5 different positions. The start and end positions are on the ground. The third image is the highest off the ground

Explanation:

Answer:

Total displacement will be 120m

Explanation:

Since displacement is shortest distance travelled

Td= 150m east - 30m west ( Since they are opposite in direction)

Td= 120m East

Answer:

Explanation:

You can use [tex]\Delta E=\frac{\hbar c}{\lambda} \rightarrow \lambda =\frac{\hbar c}{E} = \frac{1240 eV.nm}{0.0141 eV} \approx 87943.26[/tex] in nm.

Here the hc = 1240 eV.nm in eV and nanometer unit.

Answer:

ill say math too!

Explanation:

Answer:

 You get up-to-date readings 

Explanation:

Answer:

false

Explanation:

because no machines have 100% efficient

Explanation:

Water is wet, in the sense of being a liquid which flows easily, because its viscosity is low, which is because its molecules are rather loosely joined together.

Answer:

Liquid water is not itself wet, but can make other solid materials wet.

Wetness is the ability of a liquid to adhere to the surface of a solid, so when we say that something is wet, we mean that the liquid is sticking to the surface of a material.

Whether an object is wet or dry depends on a balance between cohesive and adhesive forces. Cohesive forces are attractive forces within the liquid that cause the molecules in the liquid to prefer to stick together. Cohesive forces are also responsible for surface tension. If the cohesive forces are very strong, then the liquid molecules really like to stay close together and they won't spread out on the surface of an object very much. On the contrary, adhesive forces are the attractive forces between the liquid and the surface of the material. If the adhesive forces are strong, then the liquid will try and spread out onto the surface as much as possible. So how wet a surface is depends on the balance between these two forces. If the adhesive forces (liquid-solid) are bigger than the cohesive forces (liquid-liquid), we say the material becomes wet, and the liquid tends to spread out to maximize contact with the surface. On the other hand, if the adhesive forces (liquid-solid) are smaller than the cohesive forces (liquid-liquid), we say the material is dry, and the liquid tends to bead-up into a spherical drop and tries to minimize the contact with the surface.

Water actually has pretty high cohesive forces due to hydrogen bonding, and so is not as good at wetting surfaces as some liquids such as acetone or alcohols. However, water does wet certain surfaces like glass for example. Adding detergents can make water better at wetting by lowering the cohesive forces . Water resistant materials such as Gore-tex fabric is made of material that is hydrophobic (water repellent) and so the cohesive forces within the water (liquid-liquid) are much stronger than the adhesive force (liquid-solid) and water tends to bead-up on the outside of the material and you stay dry.

Answer:

true

Explanation:

Friction helps your vehicle stop quickly. this statement ids true. Hence option A us correct. A vehicle can stop more rapidly because to friction. The brake pads rub on the turning braking discs or drums when the brakes are applied.

The friction slows the moving vehicle down and eventually causes it to halt by converting its kinetic energy into heat energy.  The effectiveness of the braking action will increase with the level of friction between the brake parts. For rapid stops, friction between the tyre and the road is also important.

The vehicle's forward motion is opposed by friction created by the tyres' gripping action on the road surface, which helps in stopping and decelerating. Rapid vehicle stopping would be incredibly difficult and risky without friction.

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Answer:

Explanation:

You can decompose those vectors into their components in x and y direction. For the first vector:

[tex]\vec{r}_{1}=r_{1}\cos 30\hat{i}+r_{1}\sin 30\hat{j}=3.14(\frac{1}{2}\sqrt{3}\hat{i}+\frac{1}{2}\hat{j})=1.57\sqrt{3}\hat{i}+1.57\hat{j}[/tex]

For the second vector:

[tex]\vec{r}_{2}=r_{2}\cos 60\hat{i}-r_{2}\sin60 \hat{j}=1.355\hat{i}-1.355\sqrt{3}\hat{j}[/tex]

The sum of two vectors will be:

[tex]\vec{r}=\vec{r}_{1}+\vec{r}_{2}=(1.57\sqrt{3}+1.355)\hat{i}+(1.57-1.355\sqrt{3})\hat{j}\approx 4.0711\hat{i}-0.77415\hat{j}[/tex]

The magnitude of the sum of two vectors is:

[tex]r=\sqrt{(4.0711)^{2}+(-0.77415)^{2}}\approx 4.14[/tex] meter

Answer:

4.14m

Explanation:

Answer:

The body develops a blood clot over the fractured bone in the first few days of a fracture to protect it and deliver the requisite cells for healing. Then, around the fractured bone, a field of healing tissue grows. This is referred to as a callus.

Explanation:

Answer:

Bone heals by making cartilage to temporarily plug the hole created by the break. This is then replaced by new bone. Many people think of bones as being solid, rigid, and structural. Bone is, of course, key to keeping our bodies upright, but it is also a highly dynamic and active organ

Explanation:

Answer: 3V

Explanation:

If the capacitor is connected to a 3V battery:

[tex]\bold{V = \frac{Q}{C} }[/tex]

The potential difference is also 3V on the capacitor

Answer:

I think that CL IS THE ONLY BEST ANSWER

Explanation:

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE

Answer:

[tex] \fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}[/tex]

Explanation:

Given:

Force between pair of charges= 900 newtons

The distance between the charges = 0.01 meters

Strength of Charge first q1 = 2e-10 Coulomb

To find:

Strength of Charge second q2 = ____ Coulomb?

Solution:

We know that,

Force between two charges separate by distance r is given by the equation,

[tex]|F| = K_e \frac{q1 \cdot \: q2}{ {r}^{2} } \\ 900 =K_e \frac{(2e - 10)\cdot \: q2}{ {0.01}^{2} } \\ 900 \times {10}^{ - 4} = K_e {(2e - 10)\cdot \: q2} \\ q2 = \frac{9 \times {10}^{ - 2} }{(2e - 10) K_e} \\ \\ \fbox{We \: know \: that \: e = 2.71 } \\ substituting \: the \: value \: \\ q2 = \frac{9 \times {10}^{ - 2} }{(2 \times 2.71 - 10)K_e} \\ q2 = \frac{0.09}{ - 4.58 K_e} \\ q2 = \frac{-0.0196}{K_e}\: coulomb[/tex]

[tex] \fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}[/tex]

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Answer:

234 90 +energy

Explanation:

because alpha decrease by 4 2helium

(a) The frequency of the motion after the collision is 0.71 Hz.

(b) The maximum angular displacement of the motion after the collision is 16.3⁰.

The speed of the 2.2 kg ball which was initially 10 cm higher that 2.7 kg ball is calculated as follows;

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 0.1)

v = 1.4 m/s

The final speed of both balls after the collision is determined from the principle of conservation of linear momentum.

Pi = Pf

m₁v₁ + m₂v₂ = vf(m₁ + m₂)

2.2(1.4) + 2.7(0) = vf(2.2 + 2.7)

3.08 = 4.9vf

vf = 3.08/4.9

vf = 0.63 m/s

P.E = K.E

[tex]mgh_f = \frac{1}{2} mv_f^2\\\\h_f = \frac{v_f^2}{2g} \\\\h_f = \frac{(0.63)^2}{2(9.8)} \\\\h_f = 0.02 \ m[/tex]

The maximum angular displacement of the balls after the collision is calculated as follows;

[tex]cos \theta = \frac{L - h_f}{L} \\\\cos\theta = \frac{0.5 - 0.02}{0.5} \\\\cos\theta = 0.96\\\\\theta = cos^{-1}(0.96)\\\\\theta = 16.3 \ ^0[/tex]

[tex]f = \frac{1}{2\pi} \sqrt{\frac{g}{L} } \\\\f = \frac{1}{2\pi } \sqrt{\frac{9.8}{0.5} } \\\\f = 0.71 \ Hz[/tex]

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