9.65180 to the nearest tenth

Answer:

Y=-3

You see y=-3 does pass through 2,3 and is also parallel to y=6

Step-by-step explanation:

please send your teacher some nice greetings from me, as this problem description is very incomplete.

we have to guess and assume a few things.

I assume that for both people there is a function describing how many objects (x and y) are sewn after a given amount of time (t).

and we are only looking at a single work day. and not a week or a year.

so,

x = Taylor(t)

y = Thomas(t)

remember that the domain is the interval or set of valid values for the input variable (the argument of the function). in our case here this is t.

and the range is the interval or set of valid values for the output variable (x and y).

so, the domain for Taylor is the interval of valid work time

[0, 8] in hours. we could also define it in minutes to not get confused, and that would be [0, 480] in minutes.

Taylor's range is then (as he can do 6 per hour = 1 every 10 minutes)

[0, 8×6] or [0, 480/10] = [0, 48].

the domain for Thomas is his valid work time [0, 10] in hours or [0,600] in minutes.

Thomas's range is then (2 per hour or 1 every 30 minutes)

[0, 10×2] or [0, 600/30] = [0, 20]

please pick for the domain the scale (hours or minutes) your teacher prefers. I suspect hours due to the phrasing, but just in case I showed you both.

Domain defines the input interval and range defines the output interval.

Here for both Taylor and Thomas Domain is how many hours they have worked and range for both of them is how many hats and mittens they have produced in their working hour.

Domain defines the input interval and range defines the output interval corresponding to the domain interval.

In the given question domain of Taylor is (0,8) and each hat takes 10 mins or 1/6 hours

in 1/6 hours Taylor makes 1 hat

so, in (1/6 x 6) = 1 hour taylor will make ( 1 x 6 ) = 6 hats

so in 8 hours Taylor will make (8 x 6) = 48 hats

Range of taylor = (0,48).                             .(as in 0 hour he will make 0                                                                                                                                                                                                                                        

                                                                            hats )                                          

Domain of Thomas is 10 hours = (0,10)

Every pair of mittens take 30 minutes or 1/2 hour

so , In 1/2 hour Thomas makes 1 pair of mittens

      In(1/2 x 2 ) = 1 hour he will make (1 x 2)= 2 pair of mittens.

      In 10 hours Thomas will make (2 x 10 ) = 20 pair of mittens.

The range of Thomas is (0,20).                 .(as in 0 hour he can make no                                                                                                                                                                                

                                                                                        pair of mittens)  

Learn more about Domain and Range here :

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#SPJ2                                    

Answer:

0, 4, 6

Step-by-step explanation:

1 * 2 * 3 = 6

2 * 3 * 4 = 24

3 * 4 * 5 = 60

4 * 5 * 6 = 120

5 * 6 * 7 = 210

6 * 7 * 8 = 336

7 * 8 * 9 = 504

etc.

Answer: 0, 4, 6

Answer:

=2x+4

Step-by-step explanation:

Let's simplify step-by-step.

5x+4−3x

=5x+4+−3x

Combine Like Terms:

=5x+4+−3x

=(5x+−3x)+(4)

=2x+4

Answer:

2x+4...

Step-by-step explanation:

Hopefully it helps

De acuerdo con los cálculos realizados en el presente desarrollo, el valor del número menor es 233.

Dado que la suma de cuatro números consecutivos es 938, para determinar cuál es el valor del número menor se debe realizar el siguiente cálculo:

Por lo tanto, el valor del número menor es 233.

Aprende más en https://brainly.com/question/12980784

9514 1404 393

Answer:

  3.5 hours

Step-by-step explanation:

The separation distance is increasing at the rate of 20 mph + 60 mph = 80 mph. It will be 280 miles after ...

  time = distance/rate

  time = (280 mi)/(80 mi/h) = 3.5 h

The two cars will be 280 miles apart after 3 1/2 hours.

Answer:

I think the answer is 1. The problem is unclear though

Hope this helps have a nice day!!!!

Answer:

I don't know what to do sorry

Answer:

9 shrimp per day.

Step-by-step explanation:

63/7=9

9*7=63

come nueve al día

Dividimos 63/7=9

Answer:

10

Step-by-step explanation:

Answer: Its 10, so plot it on 10 in the number line

Step-by-step explanation: Since the subtraction signs cancel out, they make a addition sign. Henceforth its " 3+5+2" which would mean the sum is 10.

Answer:

8/27 ft cubed

Step-by-step explanation:

2/3 cubed = 8/27

8/27 ft cubed

Answer:

-3

Step-by-step explanation:

hope it helps

Answer:

X= -19 ..............

..

Answer:

here is my solution for that problem. i hope it will work.

[tex] = \frac{11}{10} \\ \\ \\ in \: \: alternate \: form \\ \\ 1 \frac{1}{10 \: \: \: } \: \:,1.1[/tex]

Answer:

w = 4

Step-by-step explanation:

6w+2=9w+14

9w-6w=14-2

3w=12

w=12/3

w=4

Answer:

Properties of a Rectangular Prism : A rectangular prism has 8 vertices, 12 sides and 6 rectangular faces. All the opposite faces of a rectangular prism are equal.

Step-by-step explanation:

The answer to the question to how many significant figures could the volume of the pyramid be reported is B. 2 significant figures.

Since in multiplication, we cannot have more significant figures than the number with the least significant figures. So, the number of significant figures in our volume of the pyramid will be 2 since, the length of side of its square base measures 5.6 feet which is one significant figure less than that of its height which is 7.86 feet.

Since volume = area of base × height

volume = 5.6 × 5.6 × 7.86 ft³

So, the answer volume of the pyramid will have 2 significant figures.

The answer to the question to how many significant figures could the volume of the pyramid be reported is B. 2 significant figures.

Learn more about significant figures here:

https://brainly.com/question/23396760

To rationalize essentially means to get rid of the radical.

The trick to all of these it to multiply the top and bottom by a radical that will turn the radical you have into the square root of a perfect square.

Part a: [tex]\dfrac{1}{2\sqrt{5}}[/tex]

One approach that will always work, but not be the smallest radical, is to just multiply by the radical that is already there.

In the case of [tex]\dfrac{1}{2\sqrt{5}}[/tex], you can multiply the top and bottom by [tex]\sqrt{5}[/tex], so you'll really do this:

     [tex]\dfrac{1}{2\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}} = \dfrac{1\cdot\sqrt{5}}{2\sqrt{5}\sqrt{5}}[/tex]

But in the bottom, [tex]\sqrt{5}\cdot\sqrt{5} = \sqrt{25}=5[/tex], so your work finishes out like this:

    [tex]\dfrac{1\cdot\sqrt{5}}{2\sqrt{5}\sqrt{5}} = \dfrac{\sqrt{5}}{2\sqrt{25}} = \dfrac{\sqrt{5}}{2\cdot5} = \dfrac{\sqrt{5}}{10}[/tex]

Part b: [tex]\dfrac{4}{5\sqrt{2}}[/tex]

In the case of [tex]\dfrac{4}{5\sqrt{2}}[/tex], you can multiply the top and bottom by [tex]\sqrt{2}[/tex], so you'll really do this:

     [tex]\dfrac{4}{5\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}[/tex]

But in the bottom, [tex]\sqrt{2}\cdot\sqrt{2} = \sqrt{4}=2[/tex], so your work finishes out like this:

    [tex]\dfrac{4}{5\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}} = \dfrac{4\sqrt{2}}{5\sqrt{4}}=\dfrac{4\sqrt{2}}{5\cdot{2}}=\dfrac{4\sqrt{2}}{10}[/tex]

Sometimes the fraction can be reduced, so this should be reduced to [tex]\dfrac{2\sqrt{2}}{5}[/tex].

Looking at all the others, they'll follow this same approach and they will all reduce at the end.

Here's part c, for one more example.

Part c: [tex]\dfrac{3}{3\sqrt{2}}[/tex]

In the case of [tex]\dfrac{3}{3\sqrt{2}}[/tex], you can multiply the top and bottom by [tex]\sqrt{2}[/tex], but you should also reduce the initial fraction first.

     [tex]\dfrac{3}{3\sqrt{2}} = \dfrac{1}{1\cdot\sqrt{2}} = \dfrac{1}{\sqrt{2}}[/tex]

And now proceed with rationalizing:

    [tex]\dfrac{1}{\sqrt{2}} \cdot\dfrac{\sqrt{2}}{\sqrt{2}}[/tex]

But in the bottom, [tex]\sqrt{2}\cdot\sqrt{2} = \sqrt{4}=2[/tex], so your work finishes out like this:

    [tex]\dfrac{1}{\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}} = \dfrac{1\cdot\sqrt{2}}{\sqrt{4}}=\dfrac{\sqrt{2}}{{2}}[/tex]

And you're done.

Hopefully that helps you finish the rest of those.

To check your answers, here is the answer key for the rest:

part d:[tex]\dfrac{2\sqrt{6}}{5}[/tex]

part e:[tex]\dfrac{4\sqrt{2}}{3}[/tex]

part f:[tex]\dfrac{4\sqrt{5}}{7}[/tex]

part g:[tex]\dfrac{5\sqrt{10}}{3}[/tex]

part d:[tex]\dfrac{5\sqrt{2}}{3}[/tex]

Answer:

Step-by-step explanation:

(a) 1/(2 sqrt5) x (sqrt 5)/(sqrt5) = (sqrt 5)/10

(b) 4/(5bsqrt2) x (sqrt2)/(sqrt2) = (4sqrt2)/10 = (2sqrt2)/5

(c) 3/(3 sqrt2) x (sqrt2)/(sqrt2) =(sqrt2)/2

(d) 12 /(5 sqrt6) x (sqrt6)/(sqrt6) = (12sqrt6)/30 = (2sqrt6)5

(e) 8/(3 sqrt2) x (sqrt2)/(sqrt2) = (8 sqrt2)/6 = (4 sqrt2)/3

(f) 20/(7 sqrt5) x (sqrt5)/(sqrt5) = (20 sqrt5)/35 = (4 sqrt5)/7

(g) 50/(3 sqrt10) x (sqrt10)(sqrt10) = (50 sqrt10)/30 = (5sqrt10)/3

(h) 10/(3 sqrt2) x (sqrt2)/(sqrt2) = (10 sqrt2)6 = (5 sqrt2)/3

Answer:

dont understand

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer:
Each axis has even spacing.

Each point represents a data pair.

I took the test

Answer:

divide 8/3

8/3 = 2

and for -11/3 it = -4 because it would originally = to  -3.66666666667 and u have to round it.

----------------------------------

for the second picture

make it into an improper fraction

-2 1/2 = -5/2

and for 6 1/2 it = to 13/2

now, to plot it on the line you have to divide

divide -5/2 = -2.5

and divide 13/2 = 6.5

------------------------------------

Hope this helps!

The sample space is used to prepare a list of all possible outcomes or element in an experiment. The sample space containing all elements attainable for the number of working pumps at a particular station is listed below :

Let the number of pumps in use at each station be listed on the row and column respectively :

P1/P2_0 _ 1__ 2 __ 3 __ 4 __ 5 __ 6

0__ 0,0 _0,1 _0,2 _0,3 __0,4_ 0,5_0,6

1__ 1,0 __1,1 _1,2 __1,3 __1,4 __1,5_ 1,6

2__2,0 _2,1 _2,2 _2,3 __2,4 __2,5_2,6

3__3,0_3,1 _3,2 _ 3,3 __3,4 __3,5 _3,6

4__4,0_4,1 _4,2 _ 4,3 __4,4 __ 4,5 _4,6

5__5,0_5,1 _5,2 _ 5,3 __5,4 __ 5,5 _5,6

6__6,0_6,1 _6,2 _ 6,3 __6,4 __ 6,5 _6,6

Therefore, all possible outcomes relating to the number of working pumps are available in the sample space created.

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Answer:

43%

Step-by-step explanation:

mark me as brainliest please