Answer:
B
Explanation:
B
how can I become a good science student ?
Answer:
Study hard , focus on your studies and alyways ask questions .
Study, revise, write notes, listen in class, don't let yourself be distracted by others, and do the work in class...maybe join stem or science club if you wanna
Hope this helped you- have a good day bro cya)
A flea can jump with an initial velocity of 2.2 m/s at an angle of 21° with respect to the
horizontal.
Answer:
Explanation:
If no one can see it because the lights were out. Did the flea really jump?
What do you want here?
Max height (2.2sin21)²/ 2(9.8) = 3.2 cm
Time of flight 2(2.2sin21)/ (9.8) = 0.16 s
distance of flight (2.2cos21)(0.16) = 33 cm
A block slides down an incline plane that makes a 30 degree angle with the
horizontal. If the coefficient of kinetic friction is 0.3. Calculate the acceleration of the block.
Hi there!
We know that:
Force due to gravity = Mgsinθ
Force due to friction = μMgcosθ
Let the positive direction be directed in the direction of the block's acceleration, which is downward.
Thus:
ΣF = Mgsinθ - μMgcosθ
Solving for acceleration requires diving all terms by the mass, so:
a = gsinθ - μgcosθ
Substitute in given values. (g = 9.8 m/s²)
a = 9.8sin(30) - 0.3(9.8)cos(30) = 2.354 m/s²
Una masa de aire de 20g absorbe 780 cal. Teniendo en cuenta que su temperatura inicial es de 30°C. Calcular la
temperatura que alcanzo al absorber el calor. Ce:0,24 cal/g °C
Answer:
sorry I don't know the answer
How much time does it take for a school bus traveling at 15 m/s north to get a distance of 600 meters north?
Possible answers:
40 seconds
9,000 seconds
615 seconds
0.025 seconds
Answer:
40s
Explanation:
can anyone heelp me pls pls
Answer:
Explanation:
Answer in the pic.. hope it helps
The seat on a carnival ride is fixed on the end of an 12.60-m-long beam, pivoted at the other end. If the beam sweeps through an angle of 141°, what is the distance through which the rider moves?
The distance through which the rider at the end of the beam moves is;
L = 15.5 m
We are told that the beam on which the carnival ride is fixed is 12.6m in length.
Since the seat is at the end of the beam with the other end pivoted and the beam sweeps through an angle of 141°, then we can say that the radius of this arc formed by the swing is;
Radius; r = 12.6 m
Also, θ = 141°
The distance through which the driver moves will be the length of the arc formed by the beam at angle of 141°.
Formula for length of arc is given as;
L = 2πr(θ/360)
Plugging in the relevant values gives;
L = 2π × 12.6 × 141/360
L = 15.5 m
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The Canadian bobsled team hit the brakes on the sled they are traveling East in so that it decelerates at a rate of 0.43
m/s^2.
a) How long does it take to stop if it travels 85 m before coming to rest?
b) Draw the velocity vector.
c) Draw the acceleration vector.
Answer:
Explanation:
85 = ½(0.43)t²
t = √(2(85)/0.43)
t = 19.883380...
t = 20 s
v→ 8.55 m/s initial, 0 m/s final
a← 0.43 m/s²
Show your workikkkkkkkk
Answer:
Explanation:
F = ma
Assuming the 20° is angle θ measured to the horizontal
mgsinθ - μmgcosθ = ma
g(sinθ - μcosθ) = a
at constant velocity, a = 0
g(sinθ - μcosθ) = 0
sinθ - μcosθ = 0
sinθ = μcosθ
μ = sinθ/cosθ
μ = tanθ
μ = tan20
μ = 0.3639702342...
μ = 0.36
If the law allows abortion based on sex, should we also allow abortion based on race, ethnicity, or skin color? Briefly explain why you believe this is right or wrong.
Answer:
No because you don't have to be black or white you don't have to be a pacific race to just get it like lets say for example a asian person come in and they want to get a abortion but the doctor say no then that person can end up killing her self or when the baby is born she could end you know doing something bad. But no you do not have to be a pacific person to just get it
Explanation:
Which of the following statements about migration is true?
a. Migration is always from one region to another.
b. Animals always migrate within a region.
c. Migration always negatively impacts an ecosystem.
d. Animals migrate for various reasons.
Answer:
A and D
b and C are false
Answer:
D. Animals migrate for various reasons.
Explanation:
Got it right on Edge 2023. : )
ounces is In the apothecary system of measurement, equal to one apothecary pound. a) eight b) 16 c) 12 d) four
How does our body get heat ? Explain in short .
For class 5 plz bro i need help
Answer:
Thermogenesis:Your body's muscles, organs, and brain produce heat in a variety of ways
Explanation:
For example, muscles can produce heat by shivering. Hormonal thermogenesis: Your thyroid gland releases hormones to increase your metabolism. This increases the energy your body creates and the amount of heat it produces
A stimulus that increses the occurance of a response is called
Answer:
reinforcing stimulus
Explanation:
Think its correct
Answer:
reinforcing stimulus
Explanation:
because it increases the occurence of a response
A person is driving a car in a roundabout at 20 m/s so that its centripetal acceleration is 5 m/s2 . How much time it takes to complete 1 circle around the roundabout?
Answer:
Ac = v²/r
where, Ac is centripetal acceleration
v is velocity
r is radius
5 = (20)²/r
r = 400/5
r = 80m
from,
w = 2πf
where, w = angular velocity and f frequency
w = v/r
f = n/T
then,
v = 2πrn ,n = 1 to complete 1 cycle
T
T = 2πr/v
T = 2π*80/20
T = 25.14seconds.
The car would take 25.14s to complete 1 cycle of the roundabout.
The gravitational force between two objects is 2700 N. What will be the gravitational force between the objects if the distance between them triples?
F = GMm/r^2
So F is proportional to 1/r^2
F2 = 2700 x ( 1 / 3^2 ) = 300N
When converted to a household measurement, 9 kilograms is approximately equal to a
Answer:
D) 19.8 lbs
Explanation:
1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.
1kg is also equal to 2.205 lbs. 9*2.205=19.8416
9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system
a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.
This leaves us with 19.8 lbs
HELP! I need some assistance
Answer:
I'm a Filipino hahahah I'm not
Thinking Mathematically: Explore the quantitative dependencies of the acceleration upon the speed and the radius of curvature. Then answer the following questions. a. For the same speed, the acceleration of the object varies _____________ (directly, inversely) with the radius of curvature. b. For the same radius of curvature, the acceleration of the object varies _____________ (directly, inversely) with the speed of the object. c. As the speed of an object is doubled, the acceleration is __________________ (one-fourth, one-half, two times, four times) the original value. d. As the speed of an object is tripled, the acceleration is __________________ (one-third, one-ninth, three times, nine times) the original value. e. As the radius of the circle is doubled, the acceleration is __________________ (one-fourth, one-half, two times, four times) the original value. f. As the radius of the circle is tripled, the acceleration is __________________ (one-third, one-ninth, three times, nine times) the original value.
The expression for the centripetal acceleration allows to find the results for the questions are:
A) The acceleration varies INVERSELY with the radius of curvature.
B) The acceleration varies DIRECTLY with the speed.
C) The acceleration becomes four times greater.
D) The acceleration becomes nine times greater.
E) The acceleration is reduced to half.
F) The acceleration is reduced to a third.
In circular motion there must be an acceleration towards the center of the circle, it is called cenripetal acceleration, in this case all the energy supplied to the system is used to change the direction of the speed even when its magnitude remains constant.
[tex]a_c = \frac{v^2}{r}[/tex]
Where [tex]a_c[/tex] the centripetal acceleration, v is the speed and r the radius of curvature of the circle.
Now we can answer the questions about centripetal acceleration.
A) For the same speed, the acceleration varies INVERSELY with the radius of curvature.
B) For the same radius of curvature the acceleration varies DIRECTLY with the speed.
C) The speed is doubled
v = 2 v₀
[tex]a_c = \frac{(2v_o)^2 }{r}[/tex]
[tex]a_c = 4 \ \frac{v_o^2 }{r}[/tex]
The acceleration becomes four times greater than the original value
D) The speed is tripled
v = 3 v₀
[tex]a_c = 9 \frac{ v_o^2}{r}[/tex]
Acceleration becomes nine times greater than the original
E) the radius of curvature is doubled
r = 2 r₀
[tex]a_c = \frac{v_o^2}{2 r_o }[/tex]
[tex]a_c = \frac{1}{2} a_o[/tex]
Acceleration is reduced to half the original value
F) The radius of curvature is tripled
r = 3 r₀
[tex]a_c = \frac{v_o^2 }{3 r_o} \\ \\a_c = \frac{1}{3} a_o[/tex]
The acceleration is reduced to a third of the initial one.
In conclusion using the expression for the centripetal acceleration we can find the answers for the questions are:
A) The acceleration varies INVERSELY with the radius of curvature.
B) The acceleration varies DIRECTLY with the speed.
C) The acceleration becomes four times greater.
D) The acceleration becomes nine times greater.
E) The acceleration is reduced to half.
F) The acceleration is reduced to a third.
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(a) Define the term ginning? (b) Name the simple device used for spinning?
A simple device used for spinning is a hand spindle also known as takli.
hope it helps
1. As the angle of the ramp is increased, the normal force increases /decreases / remains the same and the friction-force increases /decreases / remains the same. [1 Point] 2. As the angle of the ramp is increased, the force parallel increases /decreases / remains the same. [1 Point] 3. The angle at which the force down the plane was equal to the force of friction (for the cabinet) was _____________. [1 Point] 4. Consider a very low (~ zero) friction, 5.0 kg skateboard on a ramp at an angle of 15o to the horizontal. What would be the net force that would cause acceleration when the skateboard is allowed to move
(1) As the angle of the ramp is increased, the normal force decreases.
(2) As the angle of the ramp is increased, the parallel force increases.
(3) The angle at which the force down the plane was equal to the force of friction is zero degree.
(4) The net force that would cause acceleration is 47.33 N.
Let the angle of inclination of the ramp = θ
(1)
The normal force on an object on the ramp inclined to the ramp is calculated as follows;
[tex]F_n = mgcos (\theta)[/tex]
when θ is 0;
[tex]F_n = mgcos (0)\\\\F_n = mg[/tex]
when θ is 90;
[tex]F_n = mgcos(90)\\\\F_n = 0[/tex]
Thus, as the angle of the ramp is increased, the normal force decreases.
(2)
The parallel force on an object on the ramp inclined to the ramp is calculated as follows;
[tex]F_x = mgsin(\theta)\\\\[/tex]
when θ is 0;
[tex]F_x = mgsin(\theta)\\\\F_x = mgsin(0) \\\\F_x = 0[/tex]
when θ is 90;
[tex]F_x = mgsin(90)\\\\F_x = mg[/tex]
Thus, as the angle of the ramp is increased, the parallel force increases.
(3)
The force of friction is calculated as follows;
[tex]F_n = \mu F_n[/tex]
[tex]F_k = \mu mgcos(\theta)[/tex]
[tex]F_k = \mu mg cos(0)\\\\F_k = \mu mg[/tex]
Thus, the angle is zero degree
(4)
The net force that would cause acceleration is calculated as follows;
[tex]F_k = Fn\\\\F_k = mg cos(\theta)\\\\F_k = 5 \times 9.8 \times cos(15)\\\\F_k = 47.33 \ N[/tex]
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A 3000 kg car stops at a red light, and is rear-ended by a 5000 kg truck traveling at 20m/s. In the collision, the two cars stick together. What is the final speed of the two cars just after the collision in m/s (Numeric Answers only)
Explanation:
this is actually not as simple as it sounds here.
quite some energy is lost in the deformation of the bodies of car and truck, and it also needs more energy to get a standing object going than to accelerate an already moving object.
but assuming the simple described circumstances, then the energy and impulse of the moving truck of 5000 kg is transferred to a new combined system of car and truck of now 5000 + 3000 = 8000 kg.
so, the 20m/s inertia energy of the truck is now distributed to the truck/car combination.
since the same energy has to move now more mass, it is clear that the combined speed will be lower.
20×5000 = x×8000
20×5 = x×8
x = 100/8 = 12.5 m/s
that is the resulting speed of the combined truck/car object.
Energy Transfer and Temperature Quick Check 1 of 41 of 4 Items Question Use the table to answer the question. Sample Observation 1 The drop of food coloring spreads slowly. 2 The drop of food coloring spreads very quickly. A student places a drop of food coloring into two water samples. Her observations are shown in the table. Which statement best explains the observations in the table? (1 point) The water molecules of sample 1 are moving faster. The water molecules of sample 1 are moving faster. The temperature of sample 2 is close to freezing. The temperature of sample 2 is close to freezing. The temperature of sample 2 is higher. The temperature of sample 2 is higher. The water molecules of sample 1 are transferring more kinetic energy. The water molecules of sample 1 are transferring more kinetic energy.
Answer: Measure the initial temperature of the water using the thermometer Poke through a food substance measuring 0.5 grams using the needle with the handle. Turn on fire on the burner. Set the food substance on the needle to fire on the burner. Once the food substance starts to burn, place it under the test tube so the water inside it can absorb heat.
Explanation:
Hope this helps!
The volume of an ideal gas is increased from 0.6 m3 to 2.4 m3 while maintaining a constant pressure of 1000 Pa (1000 N/m2). Determine, in J, the amount of work done by the gas in this expansion.
The amount of work done by the gas in the given expansion is 1800 J.
The given parameters;
initial volume of the ideal gas, V₁ = 0.6 m³final volume of the ideal gas, V₂ = 2.4 m³constant pressure of the gas, P = 1000 PaThe amount of work done by the gas in the given expansion is calculated as follows;
W = PΔV
where;
ΔV is the change in volume of the gasSubstitute the given parameters and solve for the work done;
W = 1000(2.4 - 0.6
W = 1800 J
Thus, the amount of work done by the gas in the given expansion is 1800 J.
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Which term describes energy stored in the bonds between atoms?
A. Nuclear energy
B. Chemical energy
O C. Thermal energy
D. Sound energy
Answer:
B. Chemical energy
Explanation:
chemical energy is the energy stored in the bonds between atoms
four particles connected by rigid rods of negligible mass where y1 = 5.70 m. the origin is at the center of the rectangle. The system rotates in the xy plane about the z axis with and angular speed of 5.60 rad/s. a) calculate the moment of inertia of the system about the z axis. b) Calculate the rotational kinetic energy
The definition of moment of inertia and kinetic energy we can find the results for the questions are:
a) The moment of inertia is: I = 32.49 kg m²
b) The kinetic energy is: K = 509.4 J
a) The moment of inertia is a scalar quantity that has the same function as mass, it is given by
I = m r²
They indicate that the length of the bar is y₁ = 5.70 m, if the two rigid bars form the square that supports the masses, the distance from the center to the end where each mass is:
r = y₁ / 2
r = 5.70 / 2 = 2.85 m
The moment of inertia of the system is.
I = 4 m r²
Let's calculate.
I =4 m 2.85²
I = 32.49m kg m²
If we assume that the mass of each point particle is:
m = 1 kg
I = 32.49 kg m²
b) They ask for the rotational kinetic energy, if the angular velocity is.
w = 5.60 rad / s
The kinetic energy for rotational motion is.
K = ½ I w²
Let's calculate.
K = ½ 32.49 5.60²
K = 509.4 J
In conclusion with the definition of moment of inertia and kinetic energy we can find the results for the questions are:
a) The moment of inertia is: I = 32.49 kg m²
b) The kinetic energy is: K = 509.4 J
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A brick is thrown upward from the top of a building at an angle of 25 degrees to the horizontal with an initial speed of 15 m/s. If the brick is in flight for 4 s before it hits the ground, how tall is the building?
Answer:
First, find the maximum height, which according to the values given, can be stated as:
H=(u²sin²theta)/2g
u=15m/s, theta=25 degrees, g=9.8m/s²
H= (15² * (sin 25)²))/2*9.8
H= (225*0.179)/19.6
H= 40.275/19.6
=2.06m
To find the velocity at maximum height:
Use the formula
v²=u²-2gH
It's minus because the brick was thrown upwards
So plugging everything into the above formula:
v²=15²-2*9.8*2.06
v²=225–40.376
v²=184.624
v=√184.624
v=13.59m/s
A chemical system is considered to have reached dynamic equilibrium when:__________.
a. the frequency of collisions between the reactant molecules is equal to the frequency of collisions between the product molecules.
b. the rate of production of each of the product species is equal to the rate of consumption of each of the reactant species. c. the rate of production of each of the products is equal to the rate of their consumption by the reverse reaction.
d. the sum of the concentrations of each of the reactant species is equal to the sum of the concentrations of each of the product species.
e. the activation energy of the forward reaction is equal to the activation energy of the reverse reaction.
Answer:
D
Explanation:
Sum of the concentrations of each of reactant species is equal to the sum of the concentrations of each of the product species
The function of which system is to transport food, oxygen and enzymes, etc. to all cells and to remove carbon dioxide and wastes from cells?
Answer:
the cardiovascular system
Lab: Motion with Constant Acceleration Assignment: Lab Report
Write your lab report
Someone please help me do this, ill give brainliest
Answer:
Table C:
Fan Speed Observations of Position vs. Time Graphs
Low:
The slope is curved and it increases as you go up . The points start off close but they spread out as the time increases.
Medium:
The speed increases quicker than the graph for low speed. The graph is less curved than the one for low speed. Also, the points spread out faster than they did for low speed as the time increases.
High:
The Graph has a smaller curve then the low and medium speed. Also, the points are the furthest apart. The slope is not as spaced out as it was for the rest of the speed graphs.
Explanation:
hope it helps
Variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.
Objective: The goal of this lab experiment was to investigate the motion of an item with constant acceleration and to examine its velocity as a function of time.
Materials:
Smooth, inclined plane
Cart or tiny wheeled object
Stopwatches and timers
Measuring tape or meterstick
Procedure:
Set up the inclined plane at a 45-degree angle () to the horizontal surface. Check that the plane is smooth and clear of obstacles.
Place the cart or small wheeled object at the bottom of the inclined plane.
Using a meterstick or measuring tape, determine the height (h) and length (L) of the inclined plane.
Ascertain that the cart is at rest at the starting point, which is located at the bottom of the inclined plane.
As soon as the cart is freed and begins to move, start the stopwatch or timer.
Calculate the time (t) it takes the cart to reach each place along the inclined plane. To ensure reliable data gathering, repeat the experiment numerous times.
Determine the time intervals (Δt) between each position for velocity analysis
Data:
Position (m) Time (s) Time Interval (Δt) (s)
0.0 0.00 -
0.5 0.50 0.50
1.0 0.75 0.25
1.5 1.10 0.35
2.0 1.50 0.40
Analysis:
Calculate the average velocity between each position by dividing the position change by the time interval (x/t).
Create a graph that plots average velocity (V_avg) versus time (t).
Results:
A straight line emerges from the graph of average velocity against time, demonstrating that the cart's motion was subject to continuous acceleration along the inclined plane. The slope of the graph reflects the acceleration (a) of the cart.
Conclusion:
The experiment successfully demonstrated motion along an inclined plane with constant acceleration. The graph of average velocity vs time revealed important information about the cart's speed, with a linear relationship suggesting steady acceleration. This experiment emphasizes kinematic principles and the significance of using velocity-time data to understand the motion of objects under constant acceleration.
Hence, variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.
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