8 + (-51 - -101) * 2

Step 1 Divide all terms by a (the coefficient of x2). Step 2 Move the number term (c/a) to the right side of the equation. Step 3 Complete the square on the left side of the equation and balance this by adding the same value to the right side of the equation.

Answer:

to solve quadratic equations you need to first figure out how many terms you have and if you have more than 3, your in luck but the AZB formula will not include the terms 1 2 or 3

Step-by-step explanation:

Answer:

There is no horizontal asymptote

Answer:

1

Step-by-step explanation:

Answer:

it is 169.56

Step-by-step explanation:

Answer:

89.78

Step-by-step explanation:

54 ÷ 2 = 27

27 x 3.14 = 89.78

hope it helps

Answer:

yes this is a function

Step-by-step explanation:

simple method to find if something is a function

if you can draw a vertical line at any point on the graph and get two intersections, it is not a function

Answer:

There is more than one but here are the options. 53, 59, 61, and 67

Answer:

If im correct the value of n should be 3

Step-by-step explanation:

Answer:

The slope is undefined and the equation of the line is x = 9 ⇒ C

Step-by-step explanation:

Let us solve the question

∵ The line is parallel to the y-axis

∵ The y-axis is a vertical line

→ By using the second note above

∴ The slope of the y-axis is undefined

→ By using the first note above

∴ The slope of the line is undefined

→ By using the third note above

∵ The equation of the vertical line is x = a

∵ a is the x-coordinate of a point on the line

∵ The line passes through the point (9, -1)

∴ a = 9

∴ The equation of the line is x = 9

Answer:

6

Step-by-step explanation:

Let the missing side be represented as x.

Applying the triangle proportionality theorem, we have:

[tex] \frac{15}{x} = \frac{14 - 4}{4} [/tex]

Solve for x

[tex] \frac{15}{x} = \frac{10}{4} [/tex]

Cross multiply

[tex] x(10) = 4(15) [/tex]

[tex] 10x = 60 [/tex]

Divide both sides by 10

x = 6

Answer:

23

Step-by-step explanation:

Answer:

We conclude that:

[tex]b=a-cd;\quad \:c\ne \:0[/tex]

Hence, option A is true.

Step-by-step explanation:

Given the expression

[tex]\frac{a-b}{c}=d[/tex]

Solving for b

[tex]\frac{a-b}{c}=d[/tex]

Multiply both sides by c

[tex]\frac{\left(a-b\right)c}{c}=dc;\quad \:c\ne \:0[/tex]

simplify

[tex]a-b=dc;\quad \:c\ne \:0[/tex]

Subtract a from both sides

[tex]a-b-a=dc-a;\quad \:c\ne \:0[/tex]

Simplify

[tex]-b=dc-a;\quad \:c\ne \:0[/tex]

Divide both sides by -1;  c≠0

[tex]\frac{-b}{-1}=\frac{dc}{-1}-\frac{a}{-1};\quad \:c\ne \:0[/tex]

simplify

[tex]b=a-cd;\quad \:c\ne \:0[/tex]

Therefore, we conclude that:

[tex]b=a-cd;\quad \:c\ne \:0[/tex]

Hence, option A is true.

Answer:

what #1 said

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

beacause there are 4 squares for every 6 circles.

Step-by-step explanation:

4s+3L=418 3L=418-4s

5s+3L=464

5s+418-4s=464

5s-4s=46

s=46

4×46+3L=418

184+3L=418

3L=234

L=78

Answer:

someone is in trouble

Step-by-step explanation:

I did that answer because it was help in capitalized letters so i thought someone was in trouble

Answer:

10 oranges

Step-by-step explanation:

Answer:

-1/2

Step-by-step explanation:

You find the change in the y coordinates. 6 -> 5 is -1. Now the same for the x. 2 -> 4 is +2. now place them in a fraction with the y/x -1/2. if both were negative then you would just cancel out the negatives.

Answer:

c=6

Step-by-step explanation:

In order to solve the original equation, we would have to square both sides of the equation:

\begin{aligned}\sqrt{29+4w}&=23-cw\\\\ \left(\sqrt{29+4w}\right)^2&=(23-cw)^2\\\\ 29+4w&=(23-cw)^2\end{aligned}  

29+4w

​  

(  

29+4w

​  

)  

2

29+4w

​  

=23−cw

=(23−cw)  

2

=(23−cw)  

2

​  

However, squaring both sides of an equation can create extraneous solutions! [Why?]

Hint #22 / 4

Let's plug \blueD w=\blueD{5}w=5start color #11accd, w, end color #11accd, equals, start color #11accd, 5, end color #11accd into the last equation we obtained:

\begin{aligned}29+4\blueD w&=(23-c\blueD{w})^2\\\\ 29+4(\blueD 5)&=(23-c(\blueD{5}))^2\\\\ 49&=(23-5c)^2\end{aligned}  

29+4w

29+4(5)

49

​  

=(23−cw)  

2

=(23−c(5))  

2

=(23−5c)  

2

​  

This equation is correct, both when 23-5c=723−5c=723, minus, 5, c, equals, 7 and when 23-5c=-723−5c=−723, minus, 5, c, equals, minus, 7.

However, the original equation is not correct for 23-5c=-723−5c=−723, minus, 5, c, equals, minus, 7, since this way we obtain \sqrt{49}=-7  

49

​  

=−7square root of, 49, end square root, equals, minus, 7.

Hint #33 / 4

Therefore, an extraneous solution is obtained for the ccc-value that makes 23-5c23−5c23, minus, 5, c equal -7−7minus, 7, which is c=6c=6c, equals, 6.

Substituting this back into the original equation gives \sqrt{29+4w}=23-6w  

29+4w

​  

=23−6wsquare root of, 29, plus, 4, w, end square root, equals, 23, minus, 6, w. You can now solve this for www and see for yourselves that w=5w=5w, equals, 5 is indeed extraneous.

Hint #44 / 4

The answer is:

c=6c=6

c = 6, makes w = 5 an extraneous solution of the equation √(29 + 4w) = 23 - cw.

A root of a transformed equation that is not a root of the original equation because it was omitted from the domain of the original equation is referred to as an extraneous solution.

In the question, we are asked to find the value for the constant c, that makes w = 5, an extraneous solution in the equation:

√(29 + 4w) = 23 - cw.

We first try to solve this equation, by squaring both sides,

29 + 4w = (23 - cw)²,

or, 29 + 4w = 23² - 2(23)(cw) + (cw)²,

or, 29 + 4w = 529 - 46cw + c²w²,

Now, we substitute w = 5, in the above equation to get:

29 + 4(5) = 529 - 46c(5) + c²(5)²,

or, 29 + 20 = 529 - 230c + 25c²,

or, 25c² - 230c + 480 = 0.

Solving this by the quadratic formula, we get:

[tex]c = \frac{-(-230)\pm \sqrt{(-230)^{2}-4(25)(480)}}{2(25)}[/tex] ,

or, [tex]c = \frac{230\pm \sqrt{52900-48000}}{50}[/tex] ,

or, [tex]c = \frac{230\pm \sqrt{4900}}{50}[/tex] ,

or, [tex]c = \frac{230\pm 70}{50}[/tex] ,

or, c = 300/50 or 160/50,

or, c = 6 or c = 3.2.

Now, we will check these values in the original equation by keeping w = 5.

When c = 6:

√(29 + 4w) = 23 - cw,

or, √(29 + 4(5)) = 23 - (6)(5),

or, √(29 + 20) = 23 - 30,

or, √49 = -7,

or, 7 = -7, which is not true.

Hence, c = 6 makes w = 5 an extraneous solution.

When c = 3.2,

√(29 + 4w) = 23 - cw,

or, √(29 + 4(5)) = 23 - (3.2)(5),

or, √(29 + 20) = 23 - 16,

or, √49 = 7,

or, 7 = 7, which is true.

Hence, c = 3.2 makes w = 5 a proper solution.

Therefore, c = 6, makes w = 5 an extraneous solution of the equation √(29 + 4w) = 23 - cw.

The question mentioned is not understandable. For proper question, refer to the attachment.

Learn more about extraneous solutions at

https://brainly.com/question/2959656

#SPJ2

Accurate Explanation: Aloha! Basically, as I can see here, you're missing a slope. But you need at least 1 point and a slope in order to write an equation. Hope it helps.

Answer:

hello im good

Step-by-step explanation:

Answer:

4 batches!!

Step-by-step explanation:

apples + blackberries = 16 cups

blackberries = 1 for one batch

apples = 3 for one batch

1 x 4 = 4

3 x 4 = 12

12 + 4 = 16

Answer:

The Correct Answer Is B.) 4 Batches

Step-by-step explanation:

Answer:

m=28

Step-by-step explanation:

0.1(0.5m+6)=2

Distribute

.05m +.6 =2

Subtract .6 from each side  

.05m +.6-.6 = 2-.6

.05m = 1.4

Divide each side by .05

.05m/.05 = 1.4/.05

m = 28

Answer: 4,608

Step-by-step explanation:

9 x 16 = 144 x 32 = 4, 608

Answer:28 inches

Step-by-step explanation:

Answer:

Y=x+6

Step-by-step explanation:

Step-by-step explanation:

x°+y°=90°

mSquare =360°

z°= 360°-(90°+90°+51°)

z°=360°-231°

z°=129°

mTriangle=180°

angle in base of triangle is equal

because this is isosceles triangle

so 2y°+z°=180°

2y°+129=180°

2y°=180°-129°

2y°=51°

y°=51°/2

y°=25.5°

x°+y°=90°

so x°=90°-y°

x°=90°-25.5°

x°=64.5°

final

x=64.5°,y=25.5°,z=129°

Answer:

Menu bar

Step-by-step explanation:

Answer:

The 3rd one

Step-by-step explanation:

Answer:

ratio is a constant since all circles are geometrically similar and linear proportions between any similar geometric figures are constant.

Step-by-step explanation: